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JEE • MATHEMATICS • DIFFERENTIAL EQUATIONS

Differential equations practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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91 Hard
91 of 975
Application +4 | -1
Let u(x)u(x) and v(x)v(x) are differentiable functions such that u(x)v(x)=7\frac{u(x)}{v(x)}=7. If u′(x)v′(x)=p\frac{u^{\prime}(x)}{v^{\prime}(x)}=p and (u(x)v(x))=q\left(\frac{u(x)}{v(x)}\right)=\mathrm{q}, then p+qp−q\frac{p+q}{p-q} has the value equal to :
View answer and explanation
Correct option: A
1
Option A (1) is correct because after differentiating and simplifying, the value of (p+q)/(p-q) is found to be 1.
92 Medium
92 of 975
Application +4 | -1
Solution of the equation x2y−x3dydx=y4cos⁡x{x^2}y - {x^3}\frac{{dy}}{{dx}} = {y^4}\cos x, when y(0)=1y\left( 0 \right) = 1 is
View answer and explanation
Correct option: B
x3=3y3sin⁡x{x^3} = 3{y^3}\sin x
Option B (x3=3y3sin⁡x{x^3} = 3{y^3}\sin x) is correct because it represents the solution to the given differential equation with the specified initial condition.
93 Medium
93 of 975
Application +4 | -1
The solution of the differential equation dydx=x−y+32(x−y)+5\frac{{dy}}{{dx}} = \frac{{x - y + 3}}{{2\left( {x - y} \right) + 5}} is
View answer and explanation
Correct option: C
2(x−y)+log⁡(x−y+2)=x+c2\left( {x - y} \right) + \log \left( {x - y + 2} \right) = x + c
Option C (2(x−y)+log⁡(x−y+2)=x+c2(x - y) + \log (x - y + 2) = x + c) is correct because it is the solution obtained by substituting v=x−yv = x - y and integrating the resulting equation.
94 Easy
94 of 975
Analyzing +4 | -1
The differential equation dydx=1−y2y\frac{d y}{d x}=\frac{\sqrt{1-y^2}}{y} determines a family of circles with
View answer and explanation
Correct option: C
Fixed radius 1 and variable centre along the xx-axis
Option C (Fixed radius 1 and variable centre along the xx-axis) is correct because the solution to the differential equation represents a family of circles with radius 1 and centers on the x-axis.
95 Easy
95 of 975
Application +4 | -1
The solution of the equation d2ydx2=e−2x\frac{{{d^2}y}}{{d{x^2}}} = {e^{ - 2x}} is
View answer and explanation
Correct option: B
e−2x4+cx+d\frac{{{e^{ - 2x}}}}{4} + cx + d
Option B (e−2x4+cx+d\frac{{{e^{ - 2x}}}}{4} + cx + d) is correct because it is the general solution obtained by integrating the given second-order differential equation twice.
96 Easy
96 of 975
Application +4 | -1
The order and the degree of 2x=edydx2 x=e^{\frac{d y}{d x}} are ..... and ......
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Correct option: A
1,1
Option A is correct because the given equation can be rewritten as dy/dx = log(2x), which is a first-order, first-degree differential equation.
97 Easy
97 of 975
Application +4 | -1
The solution of initial value problem xy′+yx y^{\prime}+y =0,y(2)=−2=0, y(2)=-2 is given by
View answer and explanation
Correct option: A
xy+4=0x y+4=0
Option A (xy+4=0x y+4=0) is correct because it is the solution to the differential equation xy′+y=0x y^{\prime}+y=0 with the initial condition y(2)=−2y(2)=-2.
98 Easy
98 of 975
Application +4 | -1
The solution of differential equation 2xysec⁡2(y2)dydx+y4=ln⁡(x2ey4)2 x y \sec ^2\left(y^2\right) \frac{d y}{d x}+y^4=\ln \left(x^2 e^{y^4}\right) is
View answer and explanation
Correct option: C
tan⁡y2=(ℓln⁡x)2+C\tan y^2=(\ell \ln x)^2+C
Option C (tan⁡y2=(ℓnx)2+C\tan y^2=(\ell n x)^2+C) is correct because it is the solution obtained by substituting y2=ty^2 = t and integrating the resulting differential equation.
99 Easy
99 of 975
Application +4 | -1
The differential equation dydx+y2x2=yx\frac{d y}{d x}+\frac{y^2}{x^2}=\frac{y}{x} has the solution
View answer and explanation
Correct option: A
x=y(log⁡x+C)x=y(\log x+C)
The correct answer is A (x=y(log⁡x+C)x=y(\log x+C)) because it is the solution obtained by solving the given differential equation using the substitution y=vxy=vx.
100 Medium
100 of 975
Application +4 | -1
The solution of the differential equation xdydx+2y=x2x\frac{{dy}}{{dx}} + 2y = {x^2} is
View answer and explanation
Correct option: D
y=x4+c4x2y = \frac{{{x^4} + c}}{{4{x^2}}}
Option D (y=x4+c4x2y = \frac{{{x^4} + c}}{{4{x^2}}}) is correct because it is the solution obtained by solving the given first-order linear differential equation using an integrating factor.
101 Medium
101 of 975
Application +4 | -1
The differential equation dydx=x(1+y2)y(1+x2)\frac{{dy}}{{dx}} = \frac{{x\left( {1 + {y^2}} \right)}}{{y\left( {1 + {x^2}} \right)}} represents a family of
View answer and explanation
Correct option: B
Hyperbola
Option B (Hyperbola) is correct because the separated and integrated differential equation results in a general equation that represents a family of hyperbolas.
102 Medium
102 of 975
Application +4 | -1
If the solution of differential equation dydx=mx+54y+f\frac{d y}{d x}=\frac{m x+5}{4 y+f} represents a circle, then the values of m &m\, \& radius rr of circle respectively satisfies
View answer and explanation
Correct option: A
m=−4,r=14f2+8k+25m=-4, r=\frac{1}{4} \sqrt{f^2+8 k+25}
Option A (m=−4,r=14f2+8k+25m=-4, r=\frac{1}{4} \sqrt{f^2+8 k+25}) is correct because the differential equation represents a circle only when m=−4m = -4, and the radius is correctly calculated based on the equation of the circle.
103 Medium
103 of 975
Application +4 | -1
The general solution of the differential equation ydx−xdy−3x2y2ex3dx=0y d x-x d y-3 x^2 y^2 e^{x^3} d x=0 is ......
View answer and explanation
Correct option: A
x=yex3+cyx=y e^{x^3}+c y
Option A (x=yex3+cyx=y e^{x^3}+c y) is the correct general solution, found by rearranging the equation and integrating.
104 Medium
104 of 975
Application +4 | -1
Solution of the differential equation, sin⁡ydydx=cos⁡y(1−xcos⁡y)\sin y \frac{d y}{d x}=\cos y(1-x \cos y) is
View answer and explanation
Correct option: B
sec⁡y=x+1+ce⁡x\sec y=x+1+\operatorname{ce}^x
Option B (sec⁡y=x+1+ce⁡x\sec y=x+1+\operatorname{ce}^x) is correct because it is the solution obtained after solving the given differential equation using an integrating factor.
105 Easy
105 of 975
Application +4 | -1
The solution of the equation y′=y+1xy^{\prime}=\frac{y+1}{x} is given by
View answer and explanation
Correct option: B
y=Cx−1y=C x-1
The correct answer is B (y=Cx−1y=C x-1) because it is the general solution to the given separable differential equation.
106 Easy
106 of 975
Application +4 | -1
If y=y(x)y=y(x) is a function of xx and y(0)=0y(0)=0, then a solution of the equation dydx−ytan⁡x=sec⁡x\frac{d y}{d x}-y \tan x=\sec xis
View answer and explanation
Correct option: A
y=xsec⁡xy=x \sec x
Option B (y(1+x)=x+cexy(1+x)=x+c e^x) is correct because it represents the general solution of the given differential equation after finding the integrating factor and integrating.
107 Easy
107 of 975
Application +4 | -1
The solution of the differential equation xd2ydx2=1x \frac{d^2 y}{d x^2}=1, given that y=1,dydx=0y=1, \frac{d y}{d x}=0 when x=1x=1, is
View answer and explanation
Correct option: B
y=xlog⁡x−x+2y=x \log x-x+2
Option B (y=xlog⁡x−x+2y=x \log x-x+2) is correct because it is the solution obtained by solving the given second-order differential equation with the given initial conditions.
108 Easy
108 of 975
Application +4 | -1
Solution of differential equations (xcos⁡x−sin⁡x)dx=xysin⁡xdy(x \cos x-\sin x) d x=\frac{x}{y} \sin x d y is
View answer and explanation
Correct option: C
∣sin⁡xxy∣=c\left|\frac{\sin x}{x y}\right|=c
Option C (∣sin⁡xxy∣=c\left|\frac{{\sin x}}{{x y}}\right|=c) is correct because it is the solution obtained after integrating the given differential equation after separation of variables.
109 Medium
109 of 975
Application +4 | -1
Let y=y(x)y = y(x) be the solution of the differential equation dydx=2(y+2sin⁡x−5)x−2cos⁡x\frac{{dy}}{{dx}} = 2(y + 2\sin x - 5)x - 2\cos x such that, y(0)=7.y(0) = 7. Then y(π) y(\pi )\, is equal to
View answer and explanation
Correct option: A
2eπ2+52{e^{{\pi ^2}}} + 5
Option A (2eπ2+52{e^{{\pi ^2}}} + 5) is correct because it is the solution to the given differential equation with the specified initial condition.
110 Medium
110 of 975
Application +4 | -1
The differential equation of the family of ellipse having major and minor axes respectively along the xx and yy-axes and the minor axis is equal to half of the major axis, is
View answer and explanation
Correct option: C
4yy′+x=04yy' + x = 0
Option C (4yy′+x=04yy' + x = 0) is correct because it is the differential equation obtained by eliminating the parameter 'a' from the given family of ellipses.
111 Medium
111 of 975
Understanding +4 | -1
For solving dydx=4x+y+1\frac{{dy}}{{dx}} = 4x + y + 1, suitable substitution is
View answer and explanation
Correct option: D
y+4x+1=vy + 4x + 1 = v
The correct answer is D (y+4x+1=vy + 4x + 1 = v) because it follows the standard substitution method for solving differential equations of the form dydx=f(ax+by+c)\frac{{dy}}{{dx}} = f(ax + by + c).
112 Easy
112 of 975
Application +4 | -1
Solution of the differential equation xdy−ydx=0x\mathrm{ }dy - y\mathrm{ }dx = 0 represents
View answer and explanation
Correct option: D
Straight lines passing through the origin
Option D (Straight lines passing through the origin) is correct because the solution to the differential equation is of the form y = Cx, which represents a family of straight lines passing through the origin.
113 Easy
113 of 975
Application +4 | -1
If dydx = 2x+y−2x2y, y(0) = 1\frac{{dy}}{{dx}}\, = \,\frac{{{2^{x + y}} - {2^x}}}{{{2^y}}},\,y(0)\, = \,1 then y(1)y(1) is equal to
View answer and explanation
Correct option: B
log⁡2(1+e){\log _2}(1 + e)
Option B (log⁡2(1+e){\log _2}(1 + e)) is correct because it is the solution to the differential equation with the given initial condition.
114 Medium
114 of 975
Application +4 | -1
The particular solution of the differential equation dydx+2yx=0\frac{d y}{d x}+\frac{2 y}{x}=0 with initial condition y(1)=1y(1)=1 is
View answer and explanation
Correct option: B
x2y−1x^2 y-1
Option B (x2y=1x^2y = 1) is correct because it is the particular solution obtained by solving the differential equation with the given initial condition.
115 Easy
115 of 975
Understanding +4 | -1
The order and the degree of the differential equation d2ydx2=[y+(dydx)2]14\frac{d^2 y}{d x^2}=\left[y+\left(\frac{d y}{d x}\right)^2\right]^{\frac{1}{4}} are ...... and respectively .
View answer and explanation
Correct option: D
2 and 4
Option D (2 and 4) is correct because after raising both sides to the power of 4, the order is 2 and the degree is 4.
116 Medium
116 of 975
Understanding +4 | -1
Which of the following equation is linear
View answer and explanation
Correct option: C
dydx+yx=log⁡x\frac{d y}{d x}+\frac{y}{x}=\log x
Option C (dydx+yx=log⁡x\frac{{d y}}{{d x}}+\frac{{y}}{{x}}=\log x) is linear because the dependent variable yy and its derivative dydx\frac{{dy}}{{dx}} appear to the first power and are not multiplied together.
117 Easy
117 of 975
Understanding +4 | -1
The differential equation of all circles of radius aa is of order
View answer and explanation
Correct option: A
2
Option A (2) is correct because the general equation of a circle with radius aa has two arbitrary constants, so the order of the differential equation is 2.
118 Medium
118 of 975
Application +4 | -1
A curve y=f(x)y = f\left( x \right) passes through the point P(1,1)P\left( {1,1} \right). The normal to the curve at point PP is a(y−1)+(x−1)=0a\left( {y - 1} \right) + \left( {x - 1} \right) = 0. If the slope of the tangent at any point on the curve is proportional to the ordinate at that point, then the equation of the curve is
View answer and explanation
Correct option: D
y=ea(x−1)y = {e^{a\left( {x - 1} \right)}}
Option D (y=ea(x−1)y = {e^{a\left( {x - 1} \right)}}) is correct because it satisfies the given conditions of passing through (1,1) and having a tangent slope proportional to the ordinate.
119 Medium
119 of 975
Application +4 | -1
If ydx+(x+x2y)dy=0y d x+\left(x+x^2 y\right) d y=0, then x=x=_____
View answer and explanation
Correct option: B
1ylog⁡y−cy\frac{1}{y \log y-c y}
Option B (1ylog⁡y−cy\frac{1}{y \log y-c y}) is correct because it is the solution obtained after integrating the given differential equation and solving for x.
120 Medium
120 of 975
Understanding +4 | -1
The differential equation ydydx+x=ay\frac{{dy}}{{dx}} + x = a (aa is any constant) represents
View answer and explanation
Correct option: B
A set of circles on the xx-axis
Option B (A set of circles on the xx-axis) is correct because the general solution represents circles with centers on the x-axis.
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