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JEE • MATHEMATICS • DEFINITE INTEGRATION

Definite integration practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 301-330 of 995 questions

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301 Medium
301 of 995
Application +4 | -1
∫0102[tan⁡−1x]dx=(\int\limits_{0}^{102}\left[\tan ^{-1} x\right] {dx}=(where [x][x] is the largest integer not exceeding x)x)
View answer and explanation
Correct option: A
102−tan⁡1102-\tan 1
Option A (102−tan⁡1102-\tan 1) is correct because the integral can be split into two parts based on the value of the greatest integer function, and then evaluated.
302 Easy
302 of 995
Application +4 | -1
∫2k  (2x+1)  dx=6\int \nolimits_2^k \,\,\left( {2x + 1} \right)\,\,dx = 6, then kk is equal to
View answer and explanation
Correct option: D
3\mathrm{3}
Option A (12log⁡tan⁡(x2+π12)+c\frac{1}{2}\log \tan \left( {\frac{x}{2}\\ + \\ \frac{\pi }{{12}}} \right) + c) is correct because the integral can be solved by rewriting the denominator and using trigonometric identities.
303 Easy
303 of 995
Application +4 | -1
∫−10  dxx2+2x+2\int \nolimits_{ - 1}^0 \,\,\frac{{dx}}{{{x^2} + 2x + 2}} is equal to
View answer and explanation
Correct option: B
π/4\mathrm{\pi }/4
Option B (π4\frac{\mathrm{\pi }}{4}) is correct because the definite integral of dxx2+2x+2\frac{{dx}}{{{x^2} + 2x + 2}} from -1 to 0 is π4\frac{\pi}{4}.
304 Easy
304 of 995
Analyzing +4 | -1
The value of the integral ∫0π  sin⁡  k   xsin⁡  x  dx\int \limits_0^\pi \,\,\frac{{\sin \,\,k\,\;x}}{{\sin \,\,x}}\,\,dx is an even integer) is equal to
View answer and explanation
Correct option: D
0\mathrm{0}
Option D (0\mathrm{0}) is correct because the integral evaluates to 0 due to the symmetry of the sine function.
305 Easy
305 of 995
Application +4 | -1
The value of ∫01  dxx  +  1  −  x2\int \nolimits_0^1 \,\,\frac{{dx}}{{x\,\, + \,\,\sqrt {1\,\, - \,\,{x^2}} }} is
View answer and explanation
Correct option: D
π4\frac{\mathrm{\pi }}{4}
Option D (π4\frac{\mathrm{\pi }}{4}) is correct because the integral is solved using a trigonometric substitution, and the result is π4\frac{\pi}{4}.
306 Easy
306 of 995
Application +4 | -1
The value of ∫−13  ( ∣x−2∣+ [x] )  dx\int \limits_{ - 1}^3 \,\,\left( {\,\left| {x - 2} \right| + \,\left[ x \right]\,} \right)\,\,dx is ( [x]\left[ x \right] stands for greatest integer less than or equal to xx)
View answer and explanation
Correct option: A
7\mathrm{7}
Option A (7) is correct because it is the result of evaluating the definite integral by splitting the integral at the points where the absolute value and greatest integer functions change their behavior.
307 Easy
307 of 995
Application +4 | -1
If f(x)=∫−1x  ∣ t ∣  dtf\left( x \right) = \int \nolimits_{ - 1}^x \,\,\left| {\,t\,} \right|\,\,dt, then for any x≥0,  f(x)x \ge 0,\,\,f\left( x \right) is equal to
View answer and explanation
Correct option: B
12  (1  +  x2)\frac{1}{2}\,\,\left( {1\,\, + \,\,{x^2}} \right)
Option B is correct because the integral of the absolute value function is split into two parts and then evaluated.
308 Easy
308 of 995
Application +4 | -1
The value of ∫0π/2  sin⁡8  x dx\int \nolimits_0^{\pi /2} \,\,{\sin ^8}\,\,x\,dx is
View answer and explanation
Correct option: A
105  π32  (4  !)\frac{{105\,\,\pi }}{{32\,\,\left( {4\,\,!} \right)}}
Option A is correct because the integral is evaluated using Walli's formula, resulting in the given expression.
309 Easy
309 of 995
Application +4 | -1
The value of ∫01  log⁡  [x]  dx\int \nolimits_0^1 \,\,\log \,\,\left[ x \right]\,\,dx is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the logarithm of 0 is undefined, making the integral undefined.
310 Medium
310 of 995
Application +4 | -1
lim⁡x→∞  πn  {sin⁡  πn  +  sin⁡  2 πn  +…+  sin⁡  (n−1)πn}\lim\limits_{x \to \infty } \,\,\frac{\pi }{n}\,\,\left\{ {\sin \,\,\frac{\pi }{n}\,\, + \,\,\sin \,\,\frac{{2\,\pi }}{n}\,\, + \ldots + \,\,\sin \,\,\frac{{\left( {n - 1} \right)\pi }}{n}} \right\} equals
View answer and explanation
Correct option: C
2
Option C (2) is correct because the limit of the Riemann sum can be expressed as a definite integral, which evaluates to 2.
311 Easy
311 of 995
Analyzing +4 | -1
If f(x)=2−x cos⁡ x2+ x cos⁡ xf(x) = \frac{{2 - x\,\cos \,x}}{{2 + \,x\,\cos \,x}} and g(x)=log⁡e x,  (x > 0)g(x) = {\log _e}\,x,\,\,(x\, > \,0) then the value of the integral ∫−π/4π/4 g(f(x))dx\int_{ - \pi /4}^{\pi /4} \, g(f(x))dx is
View answer and explanation
Correct option: D
log⁡e1{\log _e}1
Option D (log⁡e1{\log _e}1) is correct because the integral evaluates to 0, which is the natural logarithm of 1.
312 Easy
312 of 995
Application +4 | -1
Let f:(0,∞)→Rf:(0, \infty) \rightarrow \mathbf{R} and let
F(x)=∫0xf(t)dtF(x)=\int\limits_{0}^x f(t) d t

If F(x2)=x2(1+x)F\left(x^2\right)=x^2(1+x), then f(4)f(4) equals
View answer and explanation
Correct option: C
4
Option C (4) is correct because by using the fundamental theorem of calculus and differentiating the given equation, we can find f(4).
313 Easy
313 of 995
Application +4 | -1
If g(x)=∫0xcos⁡4t dtg(x)=\int\limits_{0}^x \cos ^4 t \mathrm{~d} t then g(x+π)g(x+\pi) equals
View answer and explanation
Correct option: A
g(x)+g(π)g(x)+g(\pi)
Option A (g(x)+g(π)) is correct because the integral from 0 to x+π can be split into integrals from 0 to π and π to x+π, and a substitution can be used to show the latter equals g(x).
314 Easy
314 of 995
Application +4 | -1
If n∈Nn \in N, then ∫−nn(−1)[x]dx\int\limits_{{-n}}^n(-1)^{[x]} d x equals
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the integrand is an odd function, and the integral of an odd function over a symmetric interval is zero.
315 Easy
315 of 995
Application +4 | -1
The value of ∫−13{∣x−2∣+[x]}dx\int\limits_{{-1}}^3\{|x-2|+[x]\} d x, where [x][x] denotes the greatest integer less than or equal to xx is
View answer and explanation
Correct option: B
7
Option B (7) is correct because the integral is evaluated by splitting it into intervals based on the absolute value and greatest integer functions.
316 Easy
316 of 995
Application +4 | -1
The value of ∫−π/2π/2sin⁡2x1+2xdx\int\limits_{{-\pi / 2}}^{\pi / 2} \frac{\sin ^2 x}{1+2^x} d x is :
View answer and explanation
Correct option: C
π4\frac{\pi}{4}
Option C (π4\frac{\pi}{4}) is correct because the integral is solved using the property of definite integrals and trigonometric identities.
317 Medium
317 of 995
Analyzing +4 | -1
For any integer nn, the integral
∫0π  ecos⁡2x  cos⁡3(2n+1)  x    dx  \int \nolimits_0^\pi \,\,{e^{{{\cos }^2}x}}\,\,{\cos ^3}\left( {2n + 1} \right)\,\,x\,\,\;dx\; has the value
View answer and explanation
Correct option: C
0\mathrm{0}
Option C (0) is correct because the integrand is an odd function with respect to x = π/2, making the integral over the interval [0, π] equal to zero.
318 Easy
318 of 995
Understanding +4 | -1
∫−100100  f  (x)  dx\int \nolimits_{ - 100}^{100} \,\,f\,\,\left( x \right)\,\,dx is equal to
View answer and explanation
Correct option: D
∫−100100  f(−x)  dx\int \nolimits_{ - 100}^{100} \,\,f\left( { - x} \right)\,\,dx
Option D (∫−100100 f(−x) dx\int \nolimits_{ - 100}^{100} \,f\left( { - x} \right)\,dx) is correct because substituting x=−tx = -t results in the same integral.
319 Easy
319 of 995
Application +4 | -1
∫0[x]/38x2[3x]dx\int_0^{[x] / 3} \frac{8^x}{2^{[3 x]}} d x where [⋅][\cdot] denotes the greatest integer function, is equal to
View answer and explanation
Correct option: D
[x]ln⁡8\frac{[x]}{\ln 8}
The correct answer is D ([x]ln⁡8\frac{[x]}{\ln 8}) because after simplifying the integrand and using the properties of the greatest integer function, the integral evaluates to [x]ln⁡8\frac{[x]}{\ln 8}.
320 Easy
320 of 995
Understanding +4 | -1
∫−11x17cos⁡4xdx=\int\limits_{{-1}}^1 x^{17} \cos ^4 x d x=
View answer and explanation
Correct option: C
0
Option C (0) is correct because the integrand is an odd function, and the integral of an odd function over a symmetric interval is zero.
321 Easy
321 of 995
Application +4 | -1
The correct evaluation of ∫0π/2∣sin⁡(x−π4)∣dx\int\limits_{0}^{\pi / 2}\left|\sin \left(x-\frac{\pi}{4}\right)\right| d x is
View answer and explanation
Correct option: B
2−22-\sqrt{2}
Option B (2−22-\sqrt{{2}}) is correct because it is the result of evaluating the definite integral of the absolute value of a sine function over the given interval.
322 Easy
322 of 995
Analyzing +4 | -1
Given ∫12ex2dx=a\int\limits_{1}^2 e^{x^2} d x=a, the value of ∫ee4log⁡ex dx\int\limits_{e}^{e^4} \sqrt{\log _e x} \,d x, is
View answer and explanation
Correct option: D
2e4−e−a2 e^4-e-a
Option D (2e4−e−a2 e^4-e-a) is correct because it is obtained by using substitution and integration by parts on the given integral.
323 Easy
323 of 995
Application +4 | -1
∫−11log⁡2−x2+xdx=\int\limits_{{-1}}^1 \log \frac{2-x}{2+x} d x=
View answer and explanation
Correct option: D
0
Option D (0) is correct because the integrand is an odd function, and the integral is evaluated over a symmetric interval [-1, 1].
324 Medium
324 of 995
Application +4 | -1
The number of integral solutions of the equation 4∫0∞ln⁡tdtx2+t2−πln⁡2=0;x>04 \int_0^{\infty} \frac{\ln t d t}{x^2+t^2}-\pi \ln 2=0 ; x>0, is
View answer and explanation
Correct option: C
2
Option C is correct because solving the integral equation leads to two integral solutions for x, which are 2 and 4.
325 Easy
325 of 995
Application +4 | -1
∫0∞  [[x  +  1]ex]  dx\int \nolimits_0^\infty \,\,\left[ {\frac{{\left[ {x\,\, + \,\,1} \right]}}{{{e^x}}}} \right]\,\,dx (where [  ⋅  ]\left[ {\,\, \cdot \,\,} \right] denotes greatest integer function) is equal to
View answer and explanation
Correct option: A
0\mathrm{0}
Option A (0) is correct because the expression inside the greatest integer function is always less than 1, making the greatest integer function equal to 0.
326 Medium
326 of 995
Application +4 | -1
∫03  3x  +  1x2  +  9  dx\int \nolimits_0^3 \,\,\frac{{3x\,\, + \,\,1}}{{{x^2}\,\, + \,\,9}}\,\,dx is equal to
View answer and explanation
Correct option: A
log⁡  (2  2)  +  π12\log \,\,\left( {2\,\,\sqrt 2 } \right)\,\, + \,\,\frac{\mathrm{\pi }}{{12}}
Option A (log⁡  (2  2)  +  π12\log \,\,\left( {2\,\,\sqrt 2 } \right)\,\, + \,\,\frac{\mathrm{\pi }}{{12}}) is correct because it is the result of correctly splitting the integral and evaluating each part.
327 Medium
327 of 995
Application +4 | -1
The value of the integral ∫−11log⁡(x+x2+1)dx\int\limits_{{-1}}^1 \log \left(x+\sqrt{x^2+1}\right) d x, is
View answer and explanation
Correct option: A
0
Option A (0) is correct because the integrand is an odd function and the limits of integration are symmetric about the origin.
328 Medium
328 of 995
Application +4 | -1
The value of the integral ∫−ππ(cos⁡  ax  −  sin⁡  bx)2dx\int \limits_{ - \pi }^\pi {\left( {\cos \,\,ax\,\, - \,\,\sin \,\,bx} \right)^2}dx, where (aa and bb integers), is
View answer and explanation
Correct option: D
2 π2\,\pi
Option D (2 π2\,\pi) is correct because it involves integrating trigonometric functions over a symmetric interval, utilizing their properties.
329 Medium
329 of 995
Application +4 | -1
∫0π/3cos⁡x+sin⁡x1+sin⁡2xdx\int_0^{\pi / 3} \frac{\cos x+\sin x}{\sqrt{1+\sin 2 x}} d x is
View answer and explanation
Correct option: D
π3\frac{\pi}{3}
Option D (π3\frac{{\pi}}{{3}}) is correct because the integral simplifies to ∫0π/3dx\int_0^{\pi / 3} dx, which evaluates to π3\frac{{\pi}}{{3}}.
330 Easy
330 of 995
Analyzing +4 | -1
The value of ∫−11{1+x+x2−1−x+x2} dx\int\limits_{{-1}}^1 \{\sqrt{1+x+x^2}-\sqrt{1-x+x^2}\}\ d x, is
View answer and explanation
Correct option: A
0
Option A (0) is correct because the integrand is an odd function integrated over a symmetric interval.
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