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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
The area bounded by the xx-axis, the curve y=f(x)y=f(x) and the lines x=1,x=bx=1, x=b is equal to b2+1−2\sqrt{b^2+1}-\sqrt{2} for all b>1b>1, then f(r)f(r) is
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Correct option: D
x1+x2\frac{x}{\sqrt{1+x^2}}
Option D (x1+x2\frac{x}{\sqrt{1+x^2}}) is correct because it is the derivative of x2+1\sqrt{x^2+1}, which is obtained by differentiating the given integral equation with respect to b.

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