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JEE • MATHEMATICS • COMPLEX NUMBERS
Complex numbers practice · Easy
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 541-570 of 612 questions
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541
Easy
541 of 612
Application
+4 | -1
The value of is
View answer and explanation
Correct option: C
Option C (-1) is correct. The infinite product of complex numbers in polar form simplifies to cos(π) + isin(π), which equals -1.
542
Easy
542 of 612
Application
+4 | -1
If and respectively denote the moduli of the complex numbers and then the correct one, among the following is
View answer and explanation
Correct option: C
The correct answer is C () because calculating the moduli and comparing them yields this order.
543
Easy
543 of 612
Application
+4 | -1
If is a complex number, then represents
View answer and explanation
Correct option: C
a hyperbola
Option C (a hyperbola) is correct because the equation simplifies to , which represents a hyperbola.
544
Easy
544 of 612
Application
+4 | -1
The argument of is
View answer and explanation
Correct option: A
Option A () is correct because after simplifying the complex number, its argument falls in the second quadrant with a reference angle of .
545
Easy
545 of 612
Analyzing
+4 | -1
If the number is real and positive, then is
View answer and explanation
Correct option: C
Option C () is correct because the expression is real and positive only when is of the form , where is an integer.
546
Easy
546 of 612
Application
+4 | -1
If and , then equals
View answer and explanation
Correct option: A
Option C () is incorrect. The correct answer is not among the options provided. The correct solution involves equating real and imaginary parts and solving for z, which results in z = 1/(2) + i/2.
547
Easy
547 of 612
Application
+4 | -1
If , then the value of is
View answer and explanation
Correct option: A
0
Option A (0) is correct because taking the modulus of both sides of the equation and solving for n results in n = 0.
548
Easy
548 of 612
Application
+4 | -1
If is a complex cube root of unity, then the value of is
View answer and explanation
Correct option: D
0
Option D (0) is correct because the sum of consecutive powers of omega () where the powers differ by 1, and are multiples of 3, is always 0.
549
Easy
549 of 612
Application
+4 | -1
If is a positive integer, then is equal to
View answer and explanation
Correct option: C
Option C () is correct because by converting the complex numbers to polar form and applying De Moivre's theorem, the expression simplifies to .
550
Easy
550 of 612
Application
+4 | -1
If , then the value of is
View answer and explanation
Correct option: B
Option B () is correct because it is the simplified form of the given expression after substituting and using Euler's formula.
551
Easy
551 of 612
Application
+4 | -1
If , then greatest possible value of is
View answer and explanation
Correct option: B
2
Option B (2) is correct because the maximum value of occurs when z is farthest from 7 on the circle, which leads to a value of 2.
552
Easy
552 of 612
Application
+4 | -1
A particle starts from the point . It moves first horizontally away from origin by 5 units and then vertically away from origin by 3 units to reach a point . From , the particle moves units in the direction of the vector and then it moves through an angle in anti-clockwise direction on a circle with centre at origin, to reach a point , then the point is given by
View answer and explanation
Correct option: D
Option D (-6+7 i) is correct because it represents the final position of the particle after all the described movements.
553
Easy
553 of 612
Understanding
+4 | -1
If , then one of the values of is
View answer and explanation
Correct option: A
0
Option A (0) is correct because if , then and have the same argument, so .
554
Easy
554 of 612
Application
+4 | -1
If is a non-real root of , then is equal to
View answer and explanation
Correct option: B
Option B (-1) is correct because after simplifying the powers of z using the fact that z7 = -1, the expression reduces to -1.
555
Easy
555 of 612
Application
+4 | -1
If , then radius of the circle is
View answer and explanation
Correct option: C
Option C () is correct because the equation of the circle can be derived from the given modulus condition, and the radius can be found from the equation of the circle.
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556
Easy
556 of 612
Application
+4 | -1
If are distinct complex numbers with , then value of equals
View answer and explanation
Correct option: A
1
Option A (1) is correct because the expression simplifies to 1 using the property that and .
557
Easy
557 of 612
Application
+4 | -1
If is a cube root of unity and , then equals to
View answer and explanation
Correct option: A
Option A ((1,1)) is correct because simplifying the expression (1+ω)7 using the properties of cube roots of unity leads to 1+ω, thus A=1 and B=1.
558
Easy
558 of 612
Application
+4 | -1
If the cube roots of unity are , then the roots of the equation are
View answer and explanation
Correct option: C
Option D () is correct because by substituting into the equation, we can solve for y and then find the roots in terms of .
559
Easy
559 of 612
Application
+4 | -1
If then belongs to the interval
View answer and explanation
Correct option: B
Option B ([2,∞)) is the correct interval because solving the inequality leads to x being greater than or equal to 2.
560
Easy
560 of 612
Application
+4 | -1
If , then is equal to
View answer and explanation
Correct option: C
The correct answer is C () because, after substituting and simplifying using the properties of complex cube roots of unity, the expression equals .
561
Easy
561 of 612
Application
+4 | -1
The area of the triangle whose vertices are and , where and are complex cube roots of unity, is
View answer and explanation
Correct option: D
Option D () is correct because it is the area of the triangle calculated using the determinant formula with the given vertices.
562
Easy
562 of 612
Application
+4 | -1
If and , then all the values of lie on
View answer and explanation
Correct option: D
the -axis
Option D (the -axis) is correct because the expression simplifies to a purely imaginary number, indicating that all values lie on the Y-axis.
563
Easy
563 of 612
Analyzing
+4 | -1
If , then is equal to
View answer and explanation
Correct option: C
Option C () is correct because taking the modulus squared of both sides of the given equation leads to .
564
Easy
564 of 612
Analyzing
+4 | -1
If , where is a complex number, then values of
View answer and explanation
Correct option: A
12
Option A (12) is correct because by substituting (a complex cube root of unity) into the expression and using the properties of , the sum simplifies to 12.
565
Easy
565 of 612
Application
+4 | -1
The value of is equal to
View answer and explanation
Correct option: B
1
Option B (1) is correct because the expression simplifies down to log base 2 of 2, which equals 1.
566
Easy
566 of 612
Application
+4 | -1
Which of the following is a fourth root of ?
View answer and explanation
Correct option: A
Option A () is correct because it represents the fourth root of the given complex number in polar form.
567
Easy
567 of 612
Application
+4 | -1
If is such that , and , then is equal to
View answer and explanation
Correct option: D
3
Option D (3) is correct because solving the equation |z+1|=αz+β(1+i) for α and β yields α=1 and β=2, so α+β=3.
568
Easy
568 of 612
Understanding
+4 | -1
The points representing complex number for which lie on the locus given by
View answer and explanation
Correct option: C
A straight line
Option D (Perpendicular bisector of line joining z1 and z2) is correct because the given condition implies that the point P is equidistant from z1 and z2, which defines the perpendicular bisector.
569
Easy
569 of 612
Analyzing
+4 | -1
If and , then area of the triangle whose vertices are is
View answer and explanation
Correct option: A
Option A () is correct because the given conditions imply that the vertices form an equilateral triangle with side , and thus the area is .
570
Easy
570 of 612
Analyzing
+4 | -1
If are four complex numbers represented by the vertices of a quadrilateral taken in order such that then the quadrilateral is
View answer and explanation
Correct option: B
A rectangle
Option B is correct because the quadrilateral is a rectangle, as the diagonals bisect each other and one angle is .
Revision notes and key takeaways
Review COMPLEX NUMBERS in your textbook or class notes, then use this set to check your understanding.
Showing 541-570 of 612 questions
