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JEE • MATHEMATICS • COMBINATIONS

Combinations practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 236 questions

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91 Easy
91 of 236
Application +4 | -1
In a network of railways, a small island has 15 stations. The number of different types of tickets to be printed for each class, if every station must have tickets for other station, are
View answer and explanation
Correct option: B
210
Option B (210) is correct because it calculates the total number of different types of tickets needed, considering tickets are required for travel in both directions between each pair of stations.
92 Easy
92 of 236
Application +4 | -1
There are two urns. Urn AA has 3 distinct red balls and urn BB has 9 distinct blue balls. From each urn, two balls are taken out at random and then transferred to the other. The number of ways in which this can be done, is
View answer and explanation
Correct option: C
108
Option C (108) is correct because it is the product of the number of ways to choose 2 balls from each urn.
93 Easy
93 of 236
Application +4 | -1
If   8Cr−  7C3=  7C2{\;^8}{C_r} - {\;^7}{C_3} = {\;^7}{C_2}, then rr is equal to
View answer and explanation
Correct option: A
3
Option A (3) is correct because solving the given combinatorial equation using the combination formula leads to r = 3.
94 Easy
94 of 236
Application +4 | -1
5-digit numbers are formed using 2, 3, 5, 7, 9 without repeating the digits. If pp is the number of such numbers that exceeds 20000 and qq be the number of those that lie between 30000 and 90000 then p:qp : q is:
View answer and explanation
Correct option: B
5:35:3
Option B (5:35:3) is correct because p is the total number of 5-digit numbers formed, and q is the number of those numbers that fall between 30000 and 90000, leading to the ratio 5!: (3 * 4!).
95 Easy
95 of 236
Application +4 | -1
A binary sequence is an array of 0's and 1's. The number of n−n - digit binary sequence which contain even number of 0's is
View answer and explanation
Correct option: A
2n−1{2^{n - 1}}
Option A (2n−1{2^{n - 1}}) is correct because the number of n-digit binary sequences with an even number of 0's is given by the sum of binomial coefficients corresponding to even numbers, which simplifies to 2n−1{2^{n - 1}}.
96 Easy
96 of 236
Understanding +4 | -1
The number of diagonals in a polygon of mm sides is
View answer and explanation
Correct option: C
12!m(m−3)\frac{1}{{2!}}m\left( {m - 3} \right)
Option C is correct because the number of diagonals in a polygon with m sides is given by mC2 - m, which simplifies to m(m-3)/2.
97 Easy
97 of 236
Application +4 | -1
If in a chess tournament each contestant plays once against each of the other and in all 45 games are played, then the number of participants is
View answer and explanation
Correct option: B
10
Option B (10) is correct because the number of participants is found by solving the combination equation   nC2=45{{\;^n}{C_2}} = 45, which results in n=10n = 10.
98 Easy
98 of 236
Application +4 | -1
The number of positive integers satisfying the inequality n+1Cn−2−n+1Cn−1≤100{ }^{n+1} C_{n-2}-{ }^{n+1} C_{n-1} \leq 100 is
View answer and explanation
Correct option: B
8
Option B (8) is correct because it determines the number of positive integers that satisfy the given inequality involving combinations.
99 Easy
99 of 236
Application +4 | -1
The maximum of points in to which 4 circles and 4 straight lines intersect is
View answer and explanation
Correct option: B
50
Option B (50) is correct because it sums the maximum intersection points between lines, circles, and lines with circles.
100 Easy
100 of 236
Application +4 | -1
The greatest possible number of points of intersection of 8 straight lines and 4 circle is
View answer and explanation
Correct option: D
104
Option D, 104, is correct because we calculate the intersections of lines with lines, circles with circles, and lines with circles, then sum them up.
101 Easy
101 of 236
Application +4 | -1
The number of ways in which 20 letters x1,x2,…x10,y1,y2,…,y10x_1, x_2, … x_{10}, y_1, y_2, …, y_{10} be arranged in a line so that suffixes of the letters xx and also those of yy are respectively in ascending order of magnitude is
View answer and explanation
Correct option: D
184756
Option D (184756) is correct because it represents the number of ways to choose 10 positions for the x's (or y's) out of 20, with the order of the suffixes already determined.
102 Easy
102 of 236
Application +4 | -1
  nCr+2  nCr−1+  nCr−2{\;^n}{C_r} + 2{\;^n}{C_{r - 1}} + {\;^n}{C_{r - 2}} is equal to
View answer and explanation
Correct option: C
  n+2Cr{\;^{n + 2}}{C_r}
Option C (  n+2Cr{\;^{n + 2}}{C_r}) is correct. This is derived by applying the combination identity   nCr+  nCr−1=  n+1Cr{\;^n}{C_r} + {\;^n}{C_{r - 1}} = {\;^{n + 1}}{C_r} twice.
103 Easy
103 of 236
Application +4 | -1
The number of positive odd divisors of 216 is
View answer and explanation
Correct option: A
4
Option B (810) is correct because it calculates the total number of 2-digit and 3-digit numbers that can be formed using the given digits with repetition allowed.
104 Easy
104 of 236
Application +4 | -1
If nC4,nC5,  and  nC6{}^n{C_4},{}^n{C_5},\mathrm{ }\,\,\mathrm{and }\,\,{}^n{C_6} are in AP, then n can be
View answer and explanation
Correct option: C
14
Option C (14) is correct because it satisfies the condition for terms in an arithmetic progression (AP) involving combinations.
105 Easy
105 of 236
Application +4 | -1
From 12 books, the difference between number of ways a selection of 5 books when one specified book is always excluded and one specified book is always included, is
View answer and explanation
Correct option: C
132
The correct answer is 132 because it is the difference between the number of ways to select 5 books with one specified book excluded and one specified book included.
106 Easy
106 of 236
Application +4 | -1
If   35Cn+7=  35C4  n−2{\;^{35}}{C_{n + 7}} = {\;^{35}}{C_{4\;n - 2}}, then all the values of nn are given by
View answer and explanation
Correct option: B
3,6
Option B (3,6) is correct because it solves for n using the property that if nCr = nCs, then r = s or r + s = n.
107 Easy
107 of 236
Application +4 | -1
The number of ways in which two teams AA and BB of 11 players each can be made up from 22 players so that two particular players are on the opposite sides is
View answer and explanation
Correct option: A
369512
Option A (369512) is correct because it calculates the number of ways to form two teams with two specific players on opposite sides by choosing the remaining players from the remaining pool.
108 Easy
108 of 236
Application +4 | -1
The interior angles of a regular polygon measure 1600{160^0} each. The number of diagonals of the polygon are
View answer and explanation
Correct option: C
135
Option C (135) is correct because it is the number of diagonals calculated using the formula after finding the number of sides of the polygon.
109 Easy
109 of 236
Application +4 | -1
The number of integral points on the hyperbola x2−y2=(2000)2x^{2}-y^{2}=(2000)^{2} is (an integral point is a point both of whose co-ordinates are integer)
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Correct option: A
98
Option A (98) is correct because it represents the number of integral points on the given hyperbola.
110 Easy
110 of 236
Application +4 | -1
The straight lines I1,I2,I3{I_1},{I_2},{I_3} are parallel and lie in the same plane. A total numbers of mm points are taken on I1,n{I_1},n points on I2,k{I_2},k points on I3{I_3}. The maximum number of triangles formed with vertices at these points is
View answer and explanation
Correct option: B
  m+n+kC3−mC3−nC3−kC3{\;^{m + n + k}}{C_3}{ - ^m}{C_3}{ - ^n}{C_3}{ - ^k}{C_3}
Option B (  m+n+kC3−mC3−nC3−kC3{\;^{m + n + k}}{C_3}{ - ^m}{C_3}{ - ^n}{C_3}{ - ^k}{C_3}) is correct because it subtracts the number of ways to choose 3 points on the same line from the total number of ways to choose 3 points.
111 Easy
111 of 236
Analyzing +4 | -1
The number of times the digit 3 will be written when listing the integers from 1 to 1000 , is
View answer and explanation
Correct option: C
300
The correct answer is C (300) because when listing integers from 1 to 1000, the digit 3 appears 300 times in the ones, tens, and hundreds places.
112 Easy
112 of 236
Application +4 | -1
A class consists of 4 boys and gg girls. Every Sunday five students, including at least three boys go for a picnic to Appu Ghar, a different group being sent every week. During, the picnic, the class teacher gives each girl in the group a doll. If the total number of dolls distributed was 85, then value of gg is
View answer and explanation
Correct option: D
5
Option D (5) is correct because it satisfies the equation derived from the total number of dolls distributed based on the given conditions.
113 Easy
113 of 236
Application +4 | -1
Out of 6 boys and 4 girls, a group of 7 is to be formed. In how many ways can this be done, if the group is to have a majority of boys?
View answer and explanation
Correct option: D
100
Option D (100) is correct because the total number of ways is the sum of the combinations where boys are in majority.
114 Easy
114 of 236
Application +4 | -1
The number of group that can be made from5 different green balls, 4 different blue balls and 3 different red balls, if at latest 1 green and 1 blue ball is to be included, is
View answer and explanation
Correct option: B
3720
Option B (3720) is correct because it calculates the number of ways to select at least one green and one blue ball, along with any number of red balls.
115 Easy
115 of 236
Application +4 | -1
Sita has 5 coins each of the different denomination. The number different sums of money she can form is
View answer and explanation
Correct option: C
31
Option C (31) is correct because it represents all possible non-empty subsets of the 5 coins.
116 Easy
116 of 236
Analyzing +4 | -1
A person wishes to make up as many different parties as he can out of his 20 friends such that each party consists of the same number of persons. The number of friends he should invite at a time, is
View answer and explanation
Correct option: B
10
Option B (10) is correct because the maximum number of parties is formed when the number of friends invited is half the total number of friends, which maximizes the binomial coefficient.
117 Easy
117 of 236
Application +4 | -1
The value of 50C4+∑r=1656−rC3{ }^{50} C_4+\sum\limits_{{r=1}}^6{ }^{56-r} C_3 is
View answer and explanation
Correct option: B
56C4{ }^{56} C_4
The correct answer is 56C4{ }^{56} C_4 because it is the result of applying the identity nCr+nCr−1=n+1Cr{ }^n C_r + { }^n C_{r-1} = { }^{n+1} C_r repeatedly to simplify the summation.
118 Easy
118 of 236
Application +4 | -1
  nCr+2  nCr−1+  nCr−2{\;^n}{C_r} + 2{\;^n}{C_{r - 1}} + {\;^n}{C_{r - 2}} is equal to
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the simplified expression is   n+2Cr{\;^{n + 2}}{C_r}, which is not among the given options.
119 Easy
119 of 236
Application +4 | -1
Number of diagonals of a polygon are 65 , then the number of sides of polygon are
View answer and explanation
Correct option: C
13
Option C (13) is correct because the number of sides of a polygon with 65 diagonals can be found by solving the equation n(n-3)/2 = 65.
120 Easy
120 of 236
Application +4 | -1
The value of 50C4+∑r=1656−rC3{ }^{50} C_{4}+\sum_{r=1}^{6}{ }^{56-r} C_{3} is
View answer and explanation
Correct option: D
56C4{ }^{56} C_{4}
Option D (56C4{}^{56}C_4) is correct because applying the identity nCr+nCr−1=n+1Cr{}^{n}C_r + {}^{n}C_{r-1} = {}^{n+1}C_r repeatedly simplifies the expression to 56C4{}^{56}C_4.
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