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JEE • MATHEMATICS • COMBINATIONS
Combinations practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 211-240 of 324 questions
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211
Easy
211 of 324
Application
+4 | -1
A person is permitted to select at least one and at most coins from a collection of (distinct) coins. If the total number of ways in which he can select coins is 255, then equals
View answer and explanation
Correct option: A
4
Option A (4) is correct because solving the binomial equation derived from the problem statement leads to n=4.
212
Easy
212 of 324
Application
+4 | -1
If , then is equal to
View answer and explanation
Correct option: C
36
Option C (36) is correct because it uses the combination identity to find the value of x.
213
Easy
213 of 324
Application
+4 | -1
The total number of positive integral solutions such that is
View answer and explanation
Correct option: D
30
Option D (30) is correct because it correctly counts the number of positive integral solutions for the given equation.
214
Medium
214 of 324
Application
+4 | -1
The number of positive integers satisfying the inequality is
View answer and explanation
Correct option: C
7
Option C (7) is correct because it represents the number of positive integers that satisfy the given inequality.
215
Easy
215 of 324
Application
+4 | -1
Let the number of elements in sets and be five and two respectively. Then the number of subsets of each having at least 3 and at most 6 elements is
View answer and explanation
Correct option: C
792
The correct answer is 792 because it's the sum of the number of subsets of with 3, 4, 5, and 6 elements, calculated using combinations.
216
Medium
216 of 324
Application
+4 | -1
In how many ways can Rs 16 be divided into 4 persons when none of them get less than Rs 3?
View answer and explanation
Correct option: B
35
Option B (35) is correct because it represents the number of ways to distribute the remaining amount after giving each person the minimum required amount.
217
Easy
217 of 324
Application
+4 | -1
If and , then the value of is equal to
View answer and explanation
Correct option: C
3
Option C (3) is correct because by setting up ratios of consecutive combinations and solving the resulting system of equations, we find that r = 3.
218
Easy
218 of 324
Application
+4 | -1
In a college examination, a candidates is required to answer 6 out of 10 questions which are divided into two sections each containing 5 questions. Further the candidate is not permitted to attempt more than 4 questions from either of the section. The number of ways in which he can make up a choice of 6 questions, is
View answer and explanation
Correct option: A
200
Option A (200) is correct because it sums the ways to choose 4 questions from one section and 2 from the other, and vice versa, along with choosing 3 from each section.
219
Easy
219 of 324
Application
+4 | -1
A father with 8 children takes 3 at a time to the zoological garden, as often as he can without taking the same 3 children together more than once. The number of times he will go to the garden, is
View answer and explanation
Correct option: B
56
Option B (56) is correct because it calculates the number of ways to choose 3 children out of 8, which is a combination problem.
220
Medium
220 of 324
Analyzing
+4 | -1
The packs of 52 cards are shuffled together. The number of ways in which a man can be dealt 26 cards so that he does not get two cards of the same suit and same denomination, is
View answer and explanation
Correct option: A
The correct answer is A () because it accounts for choosing 26 cards out of 52 and then considering that each card can come from either of the two packs.
221
Easy
221 of 324
Application
+4 | -1
Consider 26 tangent lines to an ellipse. The lines separate the plane into several regions, some enclosed and others un- bounded. Then the number of unbounded regions is
View answer and explanation
Correct option: B
52
Option B (52) is correct because each tangent line creates two unbounded regions.
222
Medium
222 of 324
Application
+4 | -1
The set is to be partitioned into three sets of equal size
Thus,
The number of ways to partition is
Thus,
The number of ways to partition is
View answer and explanation
Correct option: C
Option C () is correct because it represents the number of ways to divide the set into three equal subsets without considering the order of the subsets.
223
Easy
223 of 324
Application
+4 | -1
There are 20 lines numbered as . All the odd numbered lines intersect at a point and all the even numbered lines are parallel. Find the maximum number of point of intersections.
View answer and explanation
Correct option: A
101
Option A (101) is correct because with 10 parallel lines and 10 concurrent lines, the maximum number of intersection points is achieved when each parallel line intersects all concurrent lines, plus the single intersection point of the concurrent lines themselves.
224
Easy
224 of 324
Application
+4 | -1
If 7 points out of 12 are in the same straight line, then the number of triangles formed is
View answer and explanation
Correct option: C
185
Option C (185) is correct because we subtract the number of degenerate triangles formed by the collinear points from the total possible triangles.
225
Easy
225 of 324
Understanding
+4 | -1
Consider the following statements.
I. If there are different objects, then , .
II. If there are different objects, then
Choose the correct option.
I. If there are different objects, then , .
II. If there are different objects, then
Choose the correct option.
View answer and explanation
Correct option: B
Both are true
Option B (Both are true) is correct because both statements I and II represent fundamental properties of combinations.
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226
Easy
226 of 324
Application
+4 | -1
The number of ways in which one can select three distinct integers between 1 and 30, both inclusive, whose sum is even, is
View answer and explanation
Correct option: D
2030
Option D (2030) is correct because we consider the cases where all three integers are even or one is even and the other two are odd.
227
Easy
227 of 324
Application
+4 | -1
In a Mathematics paper there are three sections containing 4, 5 and 6 questions respectively. From each section 3 questions are to be answered. In how many ways can be selection of questions be made?
View answer and explanation
Correct option: B
800
Option B (800) is correct because it calculates the product of the number of ways to choose 3 questions from each section.
228
Easy
228 of 324
Application
+4 | -1
A box contains two white balls, three black balls and four red balls. In how many ways can three balls be drawn from the box, if at least one black ball is to be included in the draw?
View answer and explanation
Correct option: A
64
Option A (64) is correct because we consider all possible combinations of 3 balls with at least one black ball.
229
Easy
229 of 324
Understanding
+4 | -1
There are 10 lamps in a hall. Each one of them can be switched on independently. The number of ways in which the hall can be illuminated, is
View answer and explanation
Correct option: C
1023
Option C is correct because each lamp has two states (on or off), and we subtract 1 to exclude the case where all lamps are off, resulting in 210 - 1 = 1023.
230
Medium
230 of 324
Application
+4 | -1
For , let denote the greatest integer , then value of is
View answer and explanation
Correct option: C
Option D (-135) is correct because it is the sum of the greatest integer function values for the given series.
231
Easy
231 of 324
Application
+4 | -1
A lady given a dinner party for six guest. The number of ways in which they may be selected from among ten friends, if two of the friends will not, attends the party together is
View answer and explanation
Correct option: B
140
Option B (140) is correct because it accounts for the constraint that two friends will not attend the party together.
232
Medium
232 of 324
Analyzing
+4 | -1
Six cards and six envelopes are numbered 1, 2, 3, 4, 5, 6 and cards are to be placed in envelopes so that each envelope contains exactly one card and no card is placed in the envelope bearing the same number and moreover the card numbered 1 is always placed in envelope numbered 2. Then, the number of ways it can be done is
View answer and explanation
Correct option: C
53
Option C (53) is the correct answer. The problem involves derangements with a constraint, and the formula for derangements needs to be adjusted to account for the condition that card 1 is always in envelope 2.
233
Easy
233 of 324
Application
+4 | -1
The number of ways of selecting 10 balls from unlimited number of red, black, white and green balls is
View answer and explanation
Correct option: A
286
Option A (286) is correct because it represents the number of non-negative integer solutions to the equation x1 + x2 + x3 + x4 = 10.
234
Easy
234 of 324
Analyzing
+4 | -1
If then equals
View answer and explanation
Correct option: A
100
Option A (100) is correct because after simplifying the summation using combinatorial identities and the formula for the sum of cubes, we find that k = 100.
235
Easy
235 of 324
Application
+4 | -1
The number of ways in which thirty five apples can be distributed among 3 boys so that each can have any number of apples, is
View answer and explanation
Correct option: B
666
Option B (666) is correct because it uses the formula for distributing identical objects among distinct groups, which is .
236
Medium
236 of 324
Application
+4 | -1
if and only if:
View answer and explanation
Correct option: D
Option D is correct because it correctly identifies the range of k based on the properties of binomial coefficients and the given equation.
237
Easy
237 of 324
Application
+4 | -1
The smallest value of satisfying the inequlity is
View answer and explanation
Correct option: D
8
Option D (8) is correct because it is the smallest integer value of x that satisfies the given inequality after simplifying the combination terms.
238
Easy
238 of 324
Application
+4 | -1
In the next world cup of cricket there will be 12 teams, divided equally in two groups. Teams of each group will play a match against each other. From each group 3 top teams will qualify for the next round. In this round each team will play against others once.
Four top teams of this round will qualify for the semi- final round, where each team will play against the others once. Two top teams of this round will go to the final round, where they will play the best of three matches. The minimum number of matches in the next world cup will be
Four top teams of this round will qualify for the semi- final round, where each team will play against the others once. Two top teams of this round will go to the final round, where they will play the best of three matches. The minimum number of matches in the next world cup will be
View answer and explanation
Correct option: B
53
Option B (53) is correct because it sums the matches in each round: group stage, second round, semi-final, and final.
239
Easy
239 of 324
Application
+4 | -1
The maximum number of points of intersection of 6 circles is
View answer and explanation
Correct option: D
30
Option D (30) is correct because each pair of circles can intersect at a maximum of two points, and we need to consider all possible pairs.
240
Easy
240 of 324
Application
+4 | -1
There are 15 points in a plane, no two of which are in a straight line except 4, all of which are in a straight line. The number of triangles that can be formed by using these 15 points is
View answer and explanation
Correct option: C
451
Option C (451) is correct because it calculates the total number of possible triangles minus the number of degenerate triangles formed by the 4 collinear points.
Revision notes and key takeaways
Review COMBINATIONS in your textbook or class notes, then use this set to check your understanding.
Showing 211-240 of 324 questions
