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JEE • MATHEMATICS • COMBINATIONS

Combinations practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 324 questions
61 Easy
61 of 324
Application +4 | -1
If 14Cn=15Cn+16Cn,\frac{1}{{^4{C_n}}} = \frac{1}{{^5{C_n}}} + \frac{1}{{^6{C_n}}}, then value of nn is
View answer and explanation
Correct option: D
2
Option D (2) is correct because substituting n=2 into the given equation satisfies the combinatorial identity.
62 Medium
62 of 324
Application +4 | -1
The number of ways in which an examiner can assign 30 marks to 8 questions, giving not less than 2 marks to any question, is :
]
View answer and explanation
Correct option: C
21C7{ }^{21} C_{7}
Option C (21C7{}^{21}C_7) is correct because after giving each question a minimum of 2 marks, the remaining marks are distributed among the questions, which can be calculated using combinations.
63 Medium
63 of 324
Application +4 | -1
A box contains 5 pairs of shoes. If 4 shoes are selected, then the number of ways in which exactly one pair of shoes obtained is
View answer and explanation
Correct option: A
120
Option A (120) is correct because we choose one pair and then choose two other shoes from the remaining shoes, making sure not to pick another pair.
64 Easy
64 of 324
Application +4 | -1
A committee of 7 has to be formed from 9 boys and 4 girls.

I. In 504 ways, this can be done, when the committee consists of exactly 3 girls.

II. In 588 ways, this can be done, when the committee consists of at least 3 girls.

Choose the correct option.
View answer and explanation
Correct option: C
Both are true
Option C (Both are true) is correct because a committee with exactly 3 girls can be formed in 504 ways, and a committee with at least 3 girls can be formed in 588 ways.
65 Easy
65 of 324
Application +4 | -1
Number if divisors of the form (4n+2),n≥0\left( {4n + 2} \right),n \ge 0 of the integer 240 is
View answer and explanation
Correct option: A
4
Option A (4) is correct because only the divisors 2, 6, 10, and 30 of 240 are of the form 4n+2.
66 Medium
66 of 324
Application +4 | -1
The number of integral solution of the inequality 4<x1+x2+x3+x4<94 < x_1+x_2+x_3+x_4 < 9 where x1,x2,x3,x4≥0x_1, x_2, x_3, x_4 \geq 0
View answer and explanation
Correct option: C
425
The correct answer is C (425) because it is the number of integral solutions to the inequality, calculated by subtracting the number of solutions less than or equal to 4 from the number of solutions less than 9.
67 Medium
67 of 324
Application +4 | -1
7 relatives of a man comprise 4 ladies and 3 gentlemen his wife has also 7 relatives, 3 of them are ladies and 4 gentlemen. In how many ways can they invite a dinner party of 3 ladies and 3 gentlemen so that there are 3 of man’s relative and 3 of the wife’s relative?
View answer and explanation
Correct option: A
485
Option A (485) is correct because it sums the number of ways to invite relatives based on different combinations of ladies and gentlemen from both families.
68 Easy
68 of 324
Application +4 | -1
If   16Cr=  16Cr+1{\;^{16}}{C_r} = {\;^{16}}{C_{r + 1}}, then the value of   rPr−3{\;^r}{P_{r - 3}} is
View answer and explanation
Correct option: D
None of these
Option D, None of these, is correct because the given condition leads to a non-integer value for r, which is not possible for combinations.
69 Easy
69 of 324
Application +4 | -1
A committee of 5 is to be formed from 9 ladies and 8 men. If the committee commands a lady majority, then the number of ways this can be done is
View answer and explanation
Correct option: D
3486
Option D (3486) is correct because it represents the total number of ways to form a committee with a lady majority by considering all possible combinations of ladies and men.
70 Easy
70 of 324
Application +4 | -1
The number of selecting at least 4 candidates from 8 candidates is
View answer and explanation
Correct option: C
163
Option C (163) is correct because it is the sum of combinations of selecting 4, 5, 6, 7, or 8 candidates from 8.
71 Easy
71 of 324
Application +4 | -1
There are 12 pairs of shoes in a box. Then the possible number of ways of picking 7 shoes so that there are exactly two pairs of shoes are
View answer and explanation
Correct option: A
63360
Option A (63360) is correct because it correctly calculates the number of ways to pick 7 shoes with exactly two pairs.
72 Easy
72 of 324
Analyzing +4 | -1
If   nCr−1=36,    nCr=84{\;^n}{C_{r - 1}} = 36,\;{\;^n}{C_r} = 84 and   nCr+1=126{\;^n}{C_{r + 1}} = 126, then the value of rr is
View answer and explanation
Correct option: C
3
Option C (3) is correct because solving the ratios of consecutive binomial coefficients leads to the correct value of r.
73 Easy
73 of 324
Understanding +4 | -1
If a,ba, b and rr are positive integers, then value of aCr+aCr−1bC1+aCr−2bC2+…+bCr is{ }^a C_r+{ }^a C_{r-1}{ }^b C_1+{ }^a C_{r-2}{ }^b C_2+\ldots+{ }^b C_r \text { is}
View answer and explanation
Correct option: C
a+bCr{ }^{a+b} C_r
Option C (a+bCr{ }^{a+b} C_r) is correct because the given expression represents the number of ways to choose r items from a group of a+b items.
74 Medium
74 of 324
Application +4 | -1
From a company of 20 soldiers any 5 are placed on guard, each batch to watch 5 hours. The total number of hours watched by different batches selected is
View answer and explanation
Correct option: C
20C5×5{ }^{20} C_5 \times 5
Option C (20C5×5{}^{20} C_5 \times 5) is correct because it represents the total number of hours watched by different batches, where each batch consists of 5 soldiers and watches for 5 hours.
75 Medium
75 of 324
Application +4 | -1
If r>p>q,r > p > q, the number of different selections of p+qp + q thing taking r at a time, where p things are identical and qq other things are identical, is
View answer and explanation
Correct option: B
p+q−r+1p + q - r + 1
Option B (p+q−r+1p + q - r + 1) is correct because it represents the number of ways to select the items given the constraints.
76 Easy
76 of 324
Application +4 | -1
Eight persons are to be transported from city AA to city BB in three cars of different makes. If each car can accommodate at most three persons, then the number of ways, in which they can be transported, is
View answer and explanation
Correct option: B
3360
Option B (3360) is correct because the number of ways to transport the persons is calculated by distributing them into the cars and considering the order of the cars.
77 Easy
77 of 324
Understanding +4 | -1
The product of nn consecutive natural number is always divisible by
View answer and explanation
Correct option: A
nPn^n{P_n}
Option A (nPn^n{P_n}) is correct because the product of n consecutive natural numbers is always divisible by n! which is equal to nPn^n{P_n}.
78 Easy
78 of 324
Application +4 | -1
There are three pigeon holes marked M,P,C.M, P, C. The number of ways in which we can put 12 letters so that 6 of them are in M,M, 4 are in PP and 2 are in CC is
View answer and explanation
Correct option: B
13860
Option B (13860) is correct because it calculates the number of ways to distribute 12 letters into three pigeon holes with specific numbers of letters in each.
79 Easy
79 of 324
Application +4 | -1
∑0≤i≤j≤10∑10Ci⋅jCi=\sum\limits_{{0 \leq i \leq j \leq 10}} \sum^{10} C_i \cdot{ }^j C_i=
View answer and explanation
Correct option: A
3103^{10}
Option A (3103^{10}) is correct because the summation can be simplified to the binomial expansion of (1+2)10.
80 Easy
80 of 324
Analyzing +4 | -1
If nn is an integer with 0≤n≤11,0 \leq n \leq 11, then the minimum value of n!(11−n)!n !(11-n) ! is attained, when a value of nn is
View answer and explanation
Correct option: B
5
Option B (5) is correct because n!(11−n)!n!(11-n)! is minimized when nn is closest to 112\frac{11}{2}, which is 5.5. Since n must be an integer, n=5 or n=6 will minimize the expression.
81 Easy
81 of 324
Application +4 | -1
The total number of integral solution for x,y,zx, y, z such that xyz=24x y z=24, is
View answer and explanation
Correct option: D
120
Option D (120) is correct because the total number of integral solutions is found by considering both positive and negative factors of 24.
82 Medium
82 of 324
Analyzing +4 | -1
If a, ba,\,b and cc are the greatest values of 19Cp 20Cq^{19}{C_p}{\,^{20}}{C_q} and 21Cr^{21}{C_r} respectively, then
View answer and explanation
Correct option: D
a11=b22=c42\frac{a}{{11}} = \frac{b}{{22}} = \frac{c}{{42}}
Option D (a11=b22=c42\frac{a}{{11}} = \frac{b}{{22}} = \frac{c}{{42}}) is correct because by finding the greatest values of the binomial coefficients, we can establish the ratios between aa, bb, and cc.
83 Easy
83 of 324
Application +4 | -1
∑r=0n(r+3r+1)ncr=7⋅(210)−210\sum\limits_{r=0}^{n}{\left( \frac{r+3}{r+1} \right)} n_{c_r}=\frac{7 \cdot\left(2^{10}\right)-2}{10} then n=n=
View answer and explanation
Correct option: D
9
Option D (9) is correct because by simplifying the summation and comparing it to the given expression, we can solve for n.
84 Easy
84 of 324
Application +4 | -1
The greatest number of points of intersection of nn circles and mm straight lines is
View answer and explanation
Correct option: B
12m(m−1)+n(2m+n−1)\frac{1}{2}m\left( {m - 1} \right) + n\left( {2m + n - 1} \right)
Option B (12m(m−1)+n(2m+n−1)\frac{1}{2}m\left( {m - 1} \right) + n\left( {2m + n - 1} \right)) is correct because it sums the maximum intersections of n circles with each other, m lines with each other, and n circles with m lines.
85 Easy
85 of 324
Application +4 | -1
The number of straight lines can be formed out of 10 points of which 7 are collinear
View answer and explanation
Correct option: C
25
Option C, 25, is correct because we calculate the total number of lines possible and subtract the extra lines formed by the collinear points, then add 1 for the line containing the collinear points.
86 Medium
86 of 324
Application +4 | -1
The number of ways choosing 10 balls from infinite white, red blue and green balls is
View answer and explanation
Correct option: C
286
Option C (286) is correct because it represents the number of non-negative integer solutions to the equation x1 + x2 + x3 + x4 = 10, which can be found using stars and bars method.
87 Easy
87 of 324
Application +4 | -1
The total number of ways in which 11 identical apples can be distributed among 6 children is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the correct answer is   16C5{\;^{16}}{C_5}, which is not among the options.
88 Medium
88 of 324
Application +4 | -1
A student is allowed to select atmost nn books from a collection of (2n+1)(2 n+1) books. If the total number of ways in which he can select atleast one book is 225, then the value of nn is
View answer and explanation
Correct option: C
4
Option C (4) is correct because the given condition leads to the equation 2n+1C1+2n+1C2+…+2n+1Cn=255{ }^{2 n+1} C_1+{ }^{2 n+1} C_2+\ldots+{ }^{2 n+1} C_n=255, which simplifies to 22n=2562^{2n} = 256, giving n=4n=4.
89 Easy
89 of 324
Application +4 | -1
All possible two-factor products are formed from the no numbers 1,2,…,100. The number of factors out of the total obtained which are multiple of 3 is
View answer and explanation
Correct option: C
2739
Option C (2739) is correct because it calculates the total number of two-factor products and subtracts the number of products that are not multiples of 3.
90 Easy
90 of 324
Application +4 | -1
A polygon has 44 diagonals, then the number of its sides are
View answer and explanation
Correct option: A
11
Option A (11) is correct because it is the number of sides that satisfies the equation for the number of diagonals in a polygon.
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