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JEE • MATHEMATICS • 3D GEOMETRY SYSTEM

3d geometry system practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-85 of 85 questions
61 Easy
61 of 85
Understanding +4 | -1
The reflection of the point (α,β,γ)(\alpha, \beta, \gamma) in the XY-plane is
View answer and explanation
Correct option: D
(α,β,−γ)(\alpha, \beta,-\gamma)
Option D (α,β,−γ\alpha, \beta,-\gamma) is correct because reflection in the XY-plane changes the sign of the z-coordinate while leaving the x and y coordinates unchanged.
62 Easy
62 of 85
Application +4 | -1
Assertion: The coordinates of the point which divides the join of A(2,−1,4){A}(2,-1,4) and B(4,3,2){B}(4,3,2) in the ratio 2:32: 3 externally is C(−2,−9,8)C(-2,-9,8)

Reason: If P(x1,y1,z1){P}\left({x}_1, {y}_1, {z}_1\right) and Q(x2,y2,z2){Q}\left({x}_2, {y}_2, {z}_2\right) be two points, and let R{R} be a point on PQ{PQ} produced dividing it externally in the ratio m1:m2{m}_1: {m}_2. Then the coordinates of R{R} are

(m1x2−m2x1m1−m2,m1y2−m2y1m1−m2,m1z2−m2z1m1−m2)\left(\frac{{m}_1 {x}_2-{m}_2 {x}_1}{{m}_1-{m}_2}, \frac{{m}_1 {y}_2-{m}_2 {y}_1}{{m}_1-{m}_2}, \frac{{m}_1 {z}_2-{m}_2 {z}_1}{{m}_{{1}}-{m}_2}\right)
View answer and explanation
Correct option: A
Assertion is correct, reason is correct; reason is a correct explanation for assertion
Option A is correct because the assertion is true, the reason is true, and the reason correctly explains the assertion about external division of a line segment in 3D space.
63 Easy
63 of 85
Application +4 | -1
The ratio in which the xx-axis divides the line segment joining (3,6)\left( {3,6} \right) and (4,−3)\left( {4, - 3} \right) is
View answer and explanation
Correct option: A
2  :12\;:1
Option A (2  :12\;:1) is correct because the x-axis divides the line segment in the ratio of the negative of the y-coordinates, which simplifies to 2  :12\;:1.
64 Easy
64 of 85
Application +4 | -1
The locus of a point PP which divides the line joining (1,0)(1,0) and (2cos⁡θ,2sin⁡θ)(2 \cos \theta, 2 \sin \theta) internally in the ratio 2:32: 3 for all θ\theta is
View answer and explanation
Correct option: B
a circle
Option B (a circle) is correct because the locus of the point P can be shown to satisfy the equation of a circle after eliminating the parameter θ\theta.
65 Easy
65 of 85
Application +4 | -1
The line joining A(bcos⁡α,bsin⁡α)A\left( {b\cos \mathrm{\alpha },b\sin \mathrm{\alpha }} \right) and B(acos⁡β,asin⁡β)B\left( {a\cos \mathrm{\beta },a\sin \mathrm{\beta }} \right) is produced to the point M(x,y)M\left( {x,y} \right) so that AM:MB=b:aAM:MB = b:a, then

xcos⁡(α+β2)+ysin⁡(α+β2)x\cos \left( {\frac{{\mathrm{\alpha } + \mathrm{\beta }}}{2}} \right) + y\sin \left( {\frac{{\mathrm{\alpha } + \mathrm{\beta }}}{2}} \right) is
View answer and explanation
Correct option: B
0
Option B (0) is correct because by using the section formula and trigonometric identities, the expression simplifies to 0.
66 Easy
66 of 85
Application +4 | -1
If the centroid of the triangle formed by the points (0, 0), (cos⁡θ,sin⁡θ)\left( {\cos \mathrm{\theta },\sin \mathrm{\theta }} \right) and (sin⁡θ,  −cos⁡θ)\left( {\sin \mathrm{\theta },\; - \cos \mathrm{\theta }} \right) lies on the line y=2xy = 2x, then θ\mathrm{\theta } is equal to
View answer and explanation
Correct option: C
tan⁡−1(−3){\tan ^{ - 1}}\left( { - 3} \right)
Option C (tan⁡−1(−3){\tan ^{ - 1}}\left( { - 3} \right)) is correct because the centroid coordinates satisfy the equation of the line y = 2x, leading to the solution tan⁡θ=−3\tan{\theta} = -3.
67 Easy
67 of 85
Application +4 | -1
The distance between the parallel lines given by (x+7y)2+42(x+7y)−42=0(x+7 y)^2+4 \sqrt{2}(x+7 y)-42=0 is
View answer and explanation
Correct option: C
2
Option C (2) is correct because the distance between the parallel lines is calculated by rewriting the equation and using the formula for the distance between parallel lines.
68 Easy
68 of 85
Application +4 | -1
If the distance between (2, 3) and (−5,  2)\left( { - 5,\;2} \right) is equal to the distance between (x,  2)\left( {x,\;2} \right) and (1, 3), then the values of xx are
View answer and explanation
Correct option: A
−6,  8- 6,\;8
Option A (-6, 8) is correct because it satisfies the given condition that the distance between (2, 3) and (-5, 2) is equal to the distance between (x, 2) and (1, 3).
69 Easy
69 of 85
Application +4 | -1
The direction ratios of the line x−y+z−5=0=x−3y−6x-y+z-5=0=x-3 y-6 are:
View answer and explanation
Correct option: A
3,1,−23,1,-2
Option A (3,1,−23,1,-2) is correct because it satisfies the condition for the direction ratios of the line formed by the intersection of the two planes.
70 Easy
70 of 85
Application +4 | -1
Let A(a, 0),  B(b, 2b+1)A(a,\,0),\,\,B(b,\,2b + 1) and C(0, b),  b≠0,  ∣b∣≠1C(0,\,b),\,\,b \ne 0,\,\,\left| b \right| \ne 1, be points such that the area of ΔABC\Delta ABC is 1 sq. unit, then the sum of all possible values of aa is
View answer and explanation
Correct option: D
−2b2b+1\frac{{ - 2{b^2}}}{{b + 1}}
Option D (−2b2b+1\frac{{ - 2{b^2}}}{{b + 1}}) is correct because it represents the sum of all possible values of 'a' calculated using the area of the triangle ABC.
71 Easy
71 of 85
Application +4 | -1
The ordered pair (λ,μ)(\lambda, \mu) such that the points (λ,μ,−6),(3,2,−4)(\lambda, \mu,-6),(3,2,-4) and (9,8,−10)(9,8,-10) become collinear is
View answer and explanation
Correct option: B
(5,4)(5,4)
Option B ((5,4)) is correct because for collinear points, the ratios of the differences in their coordinates must be equal.
72 Easy
72 of 85
Application +4 | -1
If the points (−1,2,−3),(4,a,1)(-1,2,-3),(4, a, 1) and (b,8,5)(b, 8,5) are collinear, then aa and bb are respectively equal to
View answer and explanation
Correct option: C
5 and 9
Option C (5 and 9) is correct because collinear points have proportional differences in their coordinates, allowing us to solve for a and b.
73 Easy
73 of 85
Application +4 | -1
Locus of the centroid of triangle whose vertices are (acos⁡  t,  asin⁡t),(bsin⁡t,−bcos⁡t)\left( {a\cos \;t,\;a\sin t} \right),\left( {b\sin t, - b\cos t} \right) and (1,0), where t is a parameter, is
View answer and explanation
Correct option: B
(3x−1)2+(3y)2=a2+b2{\left( {3x - 1} \right)^2} + {\left( {3y} \right)^2} = {a^2} + {b^2}
Option B ((3x−1)2+(3y)2=a2+b2{\left( {3x - 1} \right)^2} + {\left( {3y} \right)^2} = {a^2} + {b^2}) is correct because it represents the locus of the centroid derived from the given vertices.
74 Easy
74 of 85
Application +4 | -1
If the centroid of the triangle formed by the points (a,b),(b,c)\left( {a,b} \right),\left( {b,c} \right) and (c,a)\left( {c,a} \right) is at the origin, then a3+b3+c3={a^3} + {b^3} + {c^3} =
View answer and explanation
Correct option: C
3abc3abc
Option C (3abc3abc) is correct because if the centroid of the triangle is at the origin, then a+b+c=0a + b + c = 0, which implies a3+b3+c3=3abc{a^3} + {b^3} + {c^3} = 3abc.
75 Easy
75 of 85
Application +4 | -1
A(3,2,0),B(5,3,2)A(3,2,0), B(5,3,2) and C(−9,6,−3)C(-9,6,-3) are the vertices of a triangle ABCA B C. If the bisector of ∠ABC\angle A B C meets BC\mathrm{BC} at D\mathrm{D}, then coordinates of DD are
View answer and explanation
Correct option: A
(198,5716,1716)\left(\frac{19}{8}, \frac{57}{16}, \frac{17}{16}\right)
Option A is correct because the coordinates of D are found by using the section formula with the ratio AB:AC.
76 Easy
76 of 85
Application +4 | -1
Locus of centroid of the triangle whose vertices are (acos⁡t,  asin⁡t),  (bsin⁡t,  −bcos⁡t)\left( {a\cos t,\;a\sin t} \right),\;\left( {b\sin t,\; - b\cos t} \right) and (1, 0), where tt is a parameter, is
View answer and explanation
Correct option: B
(3x−1)2+(3y)2=a2+b2{\left( {3x - 1} \right)^2} + {\left( {3y} \right)^2} = {a^2} + {b^2}
Option B ((3x−1)2+(3y)2=a2+b2(3x - 1)^2 + (3y)^2 = a^2 + b^2) is correct because it represents the locus of the centroid, derived by eliminating the parameter t.
77 Easy
77 of 85
Application +4 | -1
The intercepts of the plane 2x−3y+4z=122 x-3 y+4 z=12 on the coordinate axes are given by
View answer and explanation
Correct option: B
6,−4,36,-4,3
Option B (6,−4,36,-4,3) is correct because it represents the points where the plane intersects the x, y, and z axes.
78 Easy
78 of 85
Application +4 | -1
The ratio in which the line x+y=4x + y = 4 divides the line joining the points (1,  −1)\left( {1,\; - 1} \right) and (5, 7) is
View answer and explanation
Correct option: A
1:21:2
Option A (1:21:2) is correct because by using the section formula and substituting the point of intersection into the equation of the line, we find the ratio to be 1:21:2.
79 Easy
79 of 85
Application +4 | -1
The number of lines that can be drawn through the point (4,−5)(4,-5) at a distance 12 from the point (−2,3)(-2,3) is
View answer and explanation
Correct option: A
0
Option A (0) is correct because the distance between the given points is less than the required distance, so no such line can be drawn.
80 Easy
80 of 85
Application +4 | -1
If the vertices AA and BB of a triangle ABCA B C are given by (2,5)(2,5) and (4,−11)(4,-11) and CC moves along the line L1:9x+7y+4=0L_1: 9 x+7 y+4=0, the locus of the centroid of the triangle ABCA B C is a straight line parallel to
View answer and explanation
Correct option: D
L1L_1
Option D (L1L_1) is correct because the locus of the centroid will be a line parallel to the line on which C moves.
81 Easy
81 of 85
Application +4 | -1
The equation of the sphere whose centre has the position vector (3i^+6j^−4k^)(3 \hat{i}+6 \hat{j}-4 \hat{k}) and which touches the plane r⋅(2i^−2j^−k^)=10{r} \cdot(2 \hat{i}-2 \hat{j}-\hat{k})=10 is
View answer and explanation
Correct option: A
∣r−(3i^+6j^−4k^)∣=4|{r}-(3 \hat{i}+6 \hat{j}-4 \hat{k})|=4
Option A (∣r−(3i^+6j^−4k^)∣=4|{r}-(3 \hat{i}+6 \hat{j}-4 \hat{k})|=4) is correct because it represents the equation of the sphere with the given center and radius.
82 Easy
82 of 85
Application +4 | -1
The coordinates of the point of intersection of the line x+11=y+33=z−2−2\frac{x+1}{1}=\frac{y+3}{3}=\frac{z-2}{-2} with the plane 3x+4y+5z=253 x+4 y+5 z=25 are
View answer and explanation
Correct option: B
(5,15,−10)(5,15,-10)
Option B ((5,15,−10)(5,15,-10)) is correct because these coordinates satisfy both the line equation and the plane equation.
83 Easy
83 of 85
Application +4 | -1
If a straight line makes an angle of π4\frac{\pi}{4} with each of xx axis and yy-axis, then the angle made by the line with zz-axis is
View answer and explanation
Correct option: C
π2\frac{\pi}{2}
Option C (π2\frac{{\pi}}{{2}}) is correct because the sum of squares of direction cosines must equal 1.
84 Easy
84 of 85
Application +4 | -1
The projection of the line segment joining the points (−1,0,3)(-1,0,3) and (2,5,1)(2,5,1) on the line whose direction ratios are 6,2,36,2,3, is
View answer and explanation
Correct option: A
227\frac{22}{7}
Option A (227\frac{{22}}{{7}}) is correct because it is the projection of the line segment on the line with given direction ratios.
85 Easy
85 of 85
Analyzing +4 | -1
Points (−2,4,7),(3,−6,−8)(-2,4,7),(3,-6,-8) and (1,−2,−2)(1,-2,-2) are
View answer and explanation
Correct option: A
Collinear
Option A (Collinear) is correct because the ratios of the differences in coordinates are equal, indicating that the points lie on the same line.
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