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JEE • MATHEMATICS • 3D GEOMETRY SYSTEM

3d geometry system practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 85 questions
31 Easy
31 of 85
Understanding +4 | -1
If the vertices P,  Q,  R  P,\;Q,\;R\; of a Δ  PQR\Delta \;PQR are rational points, which of the following points of the Δ  PQR\Delta \;PQR is (are) always rational points?

(A rational point is a point both of whose coordinates are rational numbers)
View answer and explanation
Correct option: A
Centroid
Option A (Centroid) is correct because the centroid's coordinates are the average of the vertices' coordinates, and the average of rational numbers is always rational.
32 Easy
32 of 85
Application +4 | -1
A straight line which makes an angle of 60∘60^{\circ} with each of yy and zz-axis, inclines with xx-axis at an angle
View answer and explanation
Correct option: D
45∘45^{\circ}
Option D (45∘45^{\circ}) is correct because it satisfies the direction cosine relationship: cos⁡2α+cos⁡2β+cos⁡2γ=1\cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma = 1.
33 Easy
33 of 85
Application +4 | -1
The equation of the line passing through the point with position vector 2i^−3j^−5k^2 \hat{i}-3 \hat{j}-5 \hat{k} and perpendicular to the plane r⋅(6i^−3j^−5k^)+2=0{r} \cdot(6 \hat{i}-3 \hat{j}-5 \hat{k})+2=0 is
View answer and explanation
Correct option: A
r=2i^−3j^−5k^+λ(−6i^+3j^+5k^){r}=2 \hat{i}-3 \hat{j}-5 \hat{k}+\lambda(-6 \hat{i}+3 \hat{j}+5 \hat{k})
Option A (r=2i^−3j^−5k^+λ(−6i^+3j^+5k^){r}=2 \hat{i}-3 \hat{j}-5 \hat{k}+\lambda(-6 \hat{i}+3 \hat{j}+5 \hat{k})) is correct because it represents the equation of the line passing through the given point and perpendicular to the given plane.
34 Easy
34 of 85
Application +4 | -1
The equation of straight line passing through the points (a,b,c)(a, b, c) and (a−b,b−c,c−a)(a-b, b-c, c-a), is
View answer and explanation
Correct option: B
x−ab=y−bc=z−ca\frac{x-a}{b}=\frac{y-b}{c}=\frac{z-c}{a}
Option B (x−ab=y−bc=z−ca\frac{x-a}{b}=\frac{y-b}{c}=\frac{z-c}{a}) is correct because it represents the equation of a line passing through two points (a, b, c) and (a-b, b-c, c-a) in 3D space.
35 Easy
35 of 85
Application +4 | -1
The coordinates of the centroid of a triangle having its circumcentre and orthocentre at (7/2,  5/2)\left( {7/2,\;5/2} \right) and (2,1)\left( {2,1} \right) respectively, are
View answer and explanation
Correct option: A
(3,  2)\left( {3,\;2} \right)
Option A (3,  2)\left( {3,\;2} \right) is correct because the centroid divides the line joining the orthocentre and circumcentre in the ratio 2:1.
36 Easy
36 of 85
Application +4 | -1
A variable line through the point (15,15)\left( {\frac{1}{5},\frac{1}{5}} \right) cuts the coordinate axes in the points
AA and BB. If the point PP divides ABAB internally in the ratio 3:1, then the locus of PP is
View answer and explanation
Correct option: B
y+3x=20xyy + 3x = 20xy
Option B (y+3x=20xyy + 3x = 20xy) is correct because by finding the equation of a line passing through (1/5, 1/5) and using the section formula to express the coordinates of point P in terms of the intercepts, the locus of P can be derived as y+3x=20xyy + 3x = 20xy.
37 Easy
37 of 85
Application +4 | -1
The xyx y-plane divides the line joining the points (−1,3,4)(2,−5,6)(-1,3,4)(2,-5,6)
View answer and explanation
Correct option: B
externally in the ratio 2:32: 3
Option B is correct because the xy-plane divides the line externally in the ratio found by setting the z-coordinate of the division point to zero.
38 Easy
38 of 85
Understanding +4 | -1
The number of straight lines that are equally inclined to three dimensional coordinate axes, is
View answer and explanation
Correct option: B
4
Option D (8) is correct because there are four possible sets of direction cosines with equal inclination to the three axes, considering both positive and negative values.
39 Easy
39 of 85
Application +4 | -1
A point P moves on the line 2x−3y+4=02x - 3y + 4 = 0. If Q(1, 4) and R(3, -2) are fixed points, then the locus of the centroid of ΔPQR\Delta PQR is a line
View answer and explanation
Correct option: A
with slope 23\frac{2}{3}
Option A (Both P(3) and P(5) are true) is correct because substituting n=3 and n=5 into the expression yields prime numbers.
40 Easy
40 of 85
Application +4 | -1
If the three points (0, 1), (0,  −1)\left( {0,\; - 1} \right) and (x,  0)\left( {x,\;0} \right) are vertices of an equilateral triangle, then the values of xx are
View answer and explanation
Correct option: B
3,  −3\sqrt 3 ,\; - \sqrt 3
Option B (√3, -√3) is correct because the distance between each pair of points must be equal for an equilateral triangle.
41 Easy
41 of 85
Application +4 | -1
The equation of the plane through the points (2,3,1)(2,3,1) and (4,−5,3)(4,-5,3) and parallel to xx-axis is
View answer and explanation
Correct option: C
y+4z−7=0y+4 z-7=0
Option C (y+4z−7=0y+4z-7=0) is correct because it represents the equation of the plane passing through the given points and parallel to the x-axis.
42 Easy
42 of 85
Application +4 | -1
If projection of a line on x,yx, y and zz axis are 6,2 and 3 respectively, then direction cosines of the line are
View answer and explanation
Correct option: A
⟨67,27,37⟩\left\langle\frac{6}{7}, \frac{2}{7}, \frac{3}{7}\right\rangle
Option A is correct because the direction cosines are found by dividing the projections by the magnitude of the vector.
43 Easy
43 of 85
Application +4 | -1
The locus of a point which divides the line segment joining the point (0,−1)\left( {0, - 1} \right) and a point on the parabola, x2=4y,{x^2} = 4y, internally in the ratio 1 : 2, is
View answer and explanation
Correct option: C
9x2−12y=89{x^2} - 12y = 8
Option C (9x2−12y=89{x^2} - 12y = 8) is correct because it represents the locus of the point that divides the line segment in the given ratio.
44 Easy
44 of 85
Application +4 | -1
The equation of the plane that passes through (2,−3,1)(2,-3,1) and is perpendicular to the line joining the points (3(3, 4,−1)4,-1) and (2,−1,5)(2,-1,5) is
View answer and explanation
Correct option: A
x+5y−6z+19=0x+5 y-6 z+19=0
Option A (x+5y−6z+19=0x+5y-6z+19=0) is correct because it is the equation of the plane passing through the given point and perpendicular to the line joining the other two points.
45 Easy
45 of 85
Application +4 | -1
The equation of the plane through (2,3,4)(2,3,4) and parallel to the plane x+2y+4z=5x+2 y+4 z=5 is
View answer and explanation
Correct option: A
x+2y+4z=24x+2 y+4 z=24
Option A (x+2y+4z=24x+2 y+4 z=24) is correct because it represents a plane parallel to the given plane and passing through the specified point.
46 Easy
46 of 85
Analyzing +4 | -1
In a three dimensional co-ordinate system, P,QP, Q and RR are images of a point A(a,b,c)A(a, b, c) in the xy,yzx y, y z and zxz x planes, respectively. If GG is the centroid of triangle PQRP Q R, then area of triangle AOGA O G is ( OO is the origin)
View answer and explanation
Correct option: A
0
Option A (0) is correct because the centroid G lies on the line OA, making the area of triangle AOG zero.
47 Easy
47 of 85
Application +4 | -1
Chord AB{AB} is a diameter of the sphere ∣r−2i^−j^+6k^∣|{r}-2 \hat{i}-\hat{j}+6 \hat{k}| =18=\sqrt{18}. If the coordinates of A{A} are (3,2,−2)(3,2,-2), then the coordinates B{B} are
View answer and explanation
Correct option: B
(1,0,−10)(1,0,-10)
Option B ((1,0,-10)) is correct because it represents the coordinates of point B, which is diametrically opposite to point A on the sphere.
48 Easy
48 of 85
Application +4 | -1
Equation of a line passing through the intersection of the lines 7x−y+2=07 x-y+2=0 and x−3y+6=0x-3 y+6=0 parallel to xx-axis is
View answer and explanation
Correct option: A
y=2y=2
Option A (y=2) is correct because it represents a line parallel to the x-axis passing through the intersection point of the two given lines.
49 Easy
49 of 85
Application +4 | -1
The centroid of a triangle is (2, 7) and two of its vertices are (4, 8) and (−2,  6)\left( { - 2,\;6} \right). The third vertex is
View answer and explanation
Correct option: B
(4, 7)
Option B ((4, 7)) is correct because the centroid coordinates are the average of the vertex coordinates. Solving for the third vertex gives (4, 7).
50 Easy
50 of 85
Application +4 | -1
The centriod of the triangle ABCABC, where A≡(2,3),B≡(8,10)A \equiv \left( {2,3} \right),B \equiv \left( {8,10} \right) and C≡(5,5)C \equiv \left( {5,5} \right) is
View answer and explanation
Correct option: A
(5, 6)
Option A ((5, 6)) is correct because the centroid of a triangle is the average of the coordinates of its vertices.
51 Easy
51 of 85
Application +4 | -1
If lines x−12=y+13=z−14\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4} and x−31=y−k2=z1\frac{x-3}{1}=\frac{y-k}{2}=\frac{z}{1} intersect, then the value of kk is
View answer and explanation
Correct option: B
92\frac{9}{2}
Option B (92\frac{9}{2}) is correct because it satisfies the condition for the intersection of two lines in 3D space, making the determinant zero.
52 Easy
52 of 85
Analyzing +4 | -1
Three distinct points A,  BA,\;B and CC given in the two dimensional coordinate plane such that the ratio of the distance of any one of them from the point (1, 0) to the distance from the point (−1,  0)\left( { - 1,\;0} \right) is equal to 13\frac{1}{3}. Then , the circumcentre of the triangle ABCABC is at the point
View answer and explanation
Correct option: A
(54,  0)\left( {\frac{5}{4},\;0} \right)
Option A ((54,  0)\left( {\frac{{5}}{{4}},\;0} \right)) is correct because the circumcenter of the triangle lies at the center of the circle defined by the given condition.
53 Easy
53 of 85
Analyzing +4 | -1
Four lines drawn from the vertices of any tetrahedron to the centroid of the opposite faces meet in a point whose distance from each vertex is kk times the distance from each vertex to the opposite face, where kk is
View answer and explanation
Correct option: C
34\frac{3}{4}
Option C (34\frac{3}{4}) is correct because the centroid of a tetrahedron divides the line joining a vertex to the centroid of the opposite face in the ratio 3:1.
54 Easy
54 of 85
Application +4 | -1
If the coordinates of the vertices of a ΔABC\Delta A B C are A(−1,3,2),B(2,3,5)A(-1,3,2), B(2,3,5) and C(3,5,−2)C(3,5,-2), then ∠A\angle A is equal to
View answer and explanation
Correct option: C
90∘90^{\circ}
Option C (90∘90^{\circ}) is correct because the sides of the triangle satisfy the Pythagorean theorem, indicating a right angle at A.
55 Easy
55 of 85
Application +4 | -1
If the projection of a line segment on x,yx, y and zz axes are respectively 3,4 and 5 , then the length of the line segment is
View answer and explanation
Correct option: B
525 \sqrt{2}
Option B (525 \sqrt{2}) is correct because the length of the line segment is the square root of the sum of the squares of its projections on the axes.
56 Easy
56 of 85
Application +4 | -1
If the origin is the centroid of a ΔABC\Delta A B C having vertices A(a,1,3),B(−2,b,−5)A(a, 1,3), B(-2, b,-5) and C(4,7,c)C(4,7, c), then
View answer and explanation
Correct option: A
a=−2a=-2
Option A (a=−2a=-2) is correct because the centroid of a triangle is the average of the coordinates of its vertices, and the origin (0,0,0) is given as the centroid.
57 Easy
57 of 85
Application +4 | -1
Given that A(3,2,−4),B(5,4−6){A}(3,2,-4), {B}(5,4-6) and C(9,8,−10){C}(9,8,-10) are collinear. Ratio in which BB divides ACAC is 1:m1:{m}. The value of m{m} is
View answer and explanation
Correct option: A
2
Option A (2) is correct because B divides AC in the ratio 1:2, calculated using the section formula for collinear points.
58 Easy
58 of 85
Analyzing +4 | -1
Vertices of a variable triangle are (3,4),(5cos⁡θ,5sin⁡θ)(3,4),(5 \cos \theta, 5 \sin \theta) and (5sin⁡θ,−5cos⁡θ)(5 \sin \theta,-5 \cos \theta), where θ∈R\theta \in R. Locus of its orthocentre is
View answer and explanation
Correct option: D
x2+y2−6x−8y−25=0x^2+y^2-6 x-8 y-25=0
Option D (x2+y2−6x−8y−25=0x^2+y^2-6 x-8 y-25=0) is correct because it represents the locus of the orthocenter derived from the given vertices and their relationships to the circumcenter and centroid.
59 Easy
59 of 85
Application +4 | -1
If the projections of a line on the axes are 6,2,36,2,3, then its direction cosines are
View answer and explanation
Correct option: D
67,27,37\frac{6}{7}, \frac{2}{7}, \frac{3}{7}
Option D (67,27,37\frac{{6}}{{7}}, \frac{{2}}{{7}}, \frac{{3}}{{7}}) is correct because it represents the direction cosines calculated from the given projections on the axes.
60 Easy
60 of 85
Application +4 | -1
The locus of a points which moves such that the sum of the squares of its distance from three vertices of the triangle is constant is a/an
View answer and explanation
Correct option: A
Circle
Option A (Circle) is correct because the locus of the point satisfying the given condition results in the equation of a circle.
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