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JEE • MATHEMATICS • 2D GEOMETRY SYSTEM

2d geometry system practice · Hard

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Hard
1 of 2
Application +4 | -1
A point moves such that the sum of its distances from two fixed points (ae,0)(a e, 0) and (−ae,0)(-a e, 0) is always 2a2 a. Then equation of its locus is
View answer and explanation
Correct option: A
x2a2+y2a2(1−e2)=1\frac{x^{2}}{a^{2}}+\frac{y^{2}}{a^{2}\left(1-e^{2}\right)}=1
Option A (x2a2+y2a2(1−e2)=1\frac{{x^{2}}}{{a^{2}}}+\frac{{y^{2}}}{{a^{2}\left(1-e^{2}\right)}}=1) is correct because it represents the equation of an ellipse where the sum of distances from two foci is constant.
2 Hard
2 of 2
Application +4 | -1
If equation of three sides of a triangle are x=2,y+1=0x=2, y+1=0 and x+2y=4x+2 y=4 then co-ordinates of circumcentre of this triangle are
View answer and explanation
Correct option: A
(4,0)(4,0)
Option A ((4,0)(4,0)) is correct because it is the circumcenter found by solving the equations formed by the perpendicular bisectors of the sides of the triangle.
Revision notes and key takeaways

Review 2D GEOMETRY SYSTEM in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

  • ✓ This set contains 2 single-correct-answer MCQs on 2D GEOMETRY SYSTEM.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
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