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JEE • CHEMISTRY • STRUCTURE OF ATOM

Structure of atom practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 571-592 of 592 questions
571 Easy
571 of 592
Application +4 | -1
The de Broglie's wavelength of electron present in first Bohr orbit of H\mathrm{H} atom is
View answer and explanation
Correct option: B
2π×0.529 A∘2 \pi \times 0.529 \, \mathop {\text{A}}\limits^ \circ
The correct answer is B; 2π×0.529 A∘2 \pi \times 0.529 \, \mathop{{\text{A}}}\limits^ \circ. The de Broglie wavelength is equal to the circumference of the first Bohr orbit.
572 Medium
572 of 592
Application +4 | -1
Determine the wavelength of a photon of electromagnetic radiation having energy 2.99×1012 erg mol−1(h=6.625×10−34 Js)2.99 \times 10^{12} \mathrm{~erg} \mathrm{~mol}^{-1} \left(\mathrm{h}=6.625 \times 10^{-34} \mathrm{~Js}\right).
View answer and explanation
Correct option: A
4000 A∘4000 ~\mathop {\text{A}}\limits^ \circ
Option A (4000 A∘4000 ~\mathop {\text{A}}\limits^ \circ) is correct because it is the wavelength calculated using the energy of the photon and Avogadro's number.
573 Easy
573 of 592
Application +4 | -1
If a species has 16 protons, 18 electrons and 16 neutrons. Find the species and its charge
View answer and explanation
Correct option: D
S2−\mathrm{S}^{2-}
Option D (S2−\mathrm{S}^{2-}) is correct because the species has 16 protons (Sulfur), and 18 electrons, indicating a 2- charge.
574 Medium
574 of 592
Understanding +4 | -1
The magnetic quantum number for valency electron of sodium is:
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the valence electron of sodium is in the 3s orbital, which has l=0, and therefore m=0.
575 Easy
575 of 592
Application +4 | -1
The time period of revolution of electron in H\mathrm{H}-atom is directly proportional to
View answer and explanation
Correct option: C
r3/2r^{3 / 2}
The correct answer is C (r3/2r^{3 / 2}) because the time period of revolution is proportional to n³ and the radius is proportional to n², therefore T is proportional to r(3/2).
576 Medium
576 of 592
Application +4 | -1
If the magnitude of uncertainties in position (Δx)(\Delta {x}) and momentum (Δp)(\Delta {p}) are equal then which of the following relation is correct?
View answer and explanation
Correct option: A
Δv=1 mh4π\Delta {v}=\frac{1}{{~m}} \sqrt{\frac{{h}}{4 \pi}}
Option A (Δv=1 mh4π\Delta {v}=\frac{1}{{~m}} \sqrt{\frac{{h}}{4 \pi}}) is correct because it correctly applies the Heisenberg uncertainty principle with equal uncertainties in position and momentum.
577 Easy
577 of 592
Understanding +4 | -1
For sets of values of quantum numbers (n,1, m(\mathrm{n}, 1, \mathrm{~m} and s)\mathrm{s}) are given below. Which of these does not provide a permissible solution of the wave equation?
View answer and explanation
Correct option: B
3,3,1,−123,3,1,-\frac{1}{2}
Option B (3,3,1,−123,3,1,-\frac{1}{2}) is correct because the value of 'l' must be less than 'n'. In this case, n=3 and l=3, which is not permissible.
578 Easy
578 of 592
Understanding +4 | -1
State the number of protons, neutrons and electrons in C14\mathrm{C}^{14}.
View answer and explanation
Correct option: A
6, 8, 2006
Option A (6, 8, 6) is correct because Carbon-14 (C14C^{14}) has 6 protons (atomic number), 8 neutrons (mass number - atomic number), and 6 electrons (equal to the number of protons in a neutral atom).
579 Medium
579 of 592
Application +4 | -1
What is the potential energy of electron in 3
orbit of H-atom ?
View answer and explanation
Correct option: A
−3.02 eV-3.02 \mathrm{~eV}
Option A (−3.02 eV-3.02 \mathrm{~eV}) is correct because the potential energy is twice the total energy, and the total energy of an electron in the 3rd orbit of a hydrogen atom is -1.51 eV, so the potential energy is 2 * -1.51 eV = -3.02 eV.
580 Medium
580 of 592
Understanding +4 | -1
Radial nodes present in 3s3 \mathrm{s} and 2p2 \mathrm{p}-orbitals are respectively
View answer and explanation
Correct option: B
2, 0
Option B (2, 0) is correct because the number of radial nodes is calculated using the formula n - l - 1, where n is the principal quantum number and l is the azimuthal quantum number.
581 Medium
581 of 592
Application +4 | -1
In H-atom, if ‘x’ is the radius of the first orbit, de-Broglie wavelength of an electron in 3rd orbit is
View answer and explanation
Correct option: B
6 πx6\,\pi x
Option B (6πx) is correct because the de-Broglie wavelength is related to the radius of the orbit and the orbit number.
582 Medium
582 of 592
Application +4 | -1
The energy difference will be minimum for which of the following energy levels of H\mathrm{H}-atom?
View answer and explanation
Correct option: B
n=3n=3 and n=4n=4
Option B (n=3 and n=4) is correct because the energy difference between higher energy levels in the H-atom decreases as n increases, making the difference between n=3 and n=4 the smallest among the options.
583 Medium
583 of 592
Analyzing +4 | -1
The value of charge on the oil droplets experimentally observed were −1.6×10−19- 1.6 \times {10^{ - 19}} and −4×10−19- 4 \times {10^{ - 19}} coulomb. The value of the electronic charge, indicated by these results is:
View answer and explanation
Correct option: D
−0.8×10−19- 0.8 \times {10^{ - 19}}
The correct answer is 1.6×10−191.6 \times {10^{ - 19}} because the greatest common divisor of the observed charges is 1.6×10−191.6 \times 10^{-19} C.
584 Medium
584 of 592
Analyzing +4 | -1
Statement (S): The magnetic moment of Mg\mathrm{Mg}-atom is more than K\mathrm{K}-atom as the former has two electrons in outermost shell.

Explanation (E): The magnetic moment of N\mathrm{N}-atom is more than magnetic moment of O\mathrm{O}-atom and former has more number of unpaired electrons.
View answer and explanation
Correct option: B
S is wrong but E is correct
Option B (S is wrong but E is correct) is correct because the magnetic moment depends on unpaired electrons, and the explanation about N and O is accurate.
585 Medium
585 of 592
Application +4 | -1
If the speed of the electron in the first Bohr orbit of hydrogen atom be ' xx ' then the speed of electron in the third Bohr orbit is
View answer and explanation
Correct option: B
x3\frac{x}{3}
Option B (x3\frac{x}{3}) is correct because the speed of an electron in a Bohr orbit is inversely proportional to the principal quantum number (n).
586 Medium
586 of 592
Understanding +4 | -1
Which of the following set of quantum numbers is impossible for an electron in an atom?
View answer and explanation
Correct option: D
n=4,ℓ=2,m=−3,s=−12{n}=4, \ell=2, {m}=-3, {s}=-\frac{1}{2}
Option D (n=4,ℓ=2,m=−3,s=−12{n}=4, \ell=2, {m}=-3, {s}=-\frac{{1}}{{2}}) is impossible because for ℓ=2\ell=2, the possible values of m are -2, -1, 0, 1, 2. m cannot be -3.
587 Easy
587 of 592
Application +4 | -1
According to Bohr’s theory, the angular momentum of an electron in 5th orbit is
View answer and explanation
Correct option: B
2.5 h/π2.5\,h/\pi
Option B (2.5 h/π2.5\,h/\pi) is correct because, according to Bohr's theory, the angular momentum of an electron in the nth orbit is given by n∗h/2πn*h/2\pi, and for the 5th orbit, it's 5h/2π=2.5h/π5h/2\pi = 2.5h/\pi.
588 Medium
588 of 592
Understanding +4 | -1
When atomic orbitals are filled according to the Aufbau principle. The 6p6 \mathrm{p} orbitals are filled immediately after the:
View answer and explanation
Correct option: B
5d5 \mathrm{d}
Option B (5d) is correct because, according to the Aufbau principle, the 6p orbitals are filled immediately after the 5d orbitals, as the (n+l) value for 5d is slightly lower.
589 Medium
589 of 592
Analyzing +4 | -1
Which of the following electron transition in hydrogen atom will require largest amount of energy?
View answer and explanation
Correct option: A
From n=1 to n=2
Option A (From n=1 to n=2) is correct because the energy required for the transition is inversely proportional to the square of the initial and final energy levels, and this transition has the largest energy difference.
590 Medium
590 of 592
Understanding +4 | -1
The representation of the ground state electronic configuration of He by box-diagram as is wrong because it violates
View answer and explanation
Correct option: C
Pauli exclusion principle
The correct answer is C (Pauli exclusion principle) because the given box diagram violates the Pauli exclusion principle, which states that no two electrons in an atom can have the same set of four quantum numbers.
591 Hard
591 of 592
Application +4 | -1
Photons having energy equivalent to binding energy of 4th 4^{\text {th }} state of He+\mathrm{He}^{+}ion is used on the metal surface of work function 1.4eV1.4 \mathrm{eV}. If electrons are further accelerated through
the potential difference of 4 V4 \mathrm{~V} then the minimum value of de-Broglie wavelength associated with the electron is
View answer and explanation
Correct option: C
5 A5 \mathrm{~A}
Option C (5 A) is correct because the de-Broglie wavelength is calculated using the total kinetic energy of the electron.
592 Easy
592 of 592
Application +4 | -1
The wavelength (in cm) of second line in the Lyman series of hydrogen atomic spectrum is
View answer and explanation
Correct option: A
8R9\frac{{8R}}{9}
Option B (98R\frac{9}{{8R}}) is correct because it uses the Rydberg formula to calculate the wavelength of the second line in the Lyman series.
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