NEET UG CHEMISTRY MCQ: STRUCTURE OF ATOM

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If the shortest wavelength of H-atom in Lyman series is x, the longest wavelength in Balmer series of

\mathrm{H}{\mathrm{e}^ + }

View answer and explanation

Correct option: D

\frac{{9x}}{5}

Option D (

\frac{{9x}}{5}

) is correct because the shortest wavelength in the Lyman series corresponds to the transition from n=∞ to n=1, and the longest wavelength in the Balmer series of

He^+

corresponds to the transition from n=3 to n=2. By equating the Rydberg formula for both, we can find the relationship between x and the required wavelength.

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Which of the following pairs have identical values of e/m? The correct de Broglie relationship is: Assertion: Unlike sound waves, electromagnetic waves do not require medium and can move in vacuum.

Reason: The oscillating electric and magnetic fields produced by oscillating charged particles are parallel to each other and both are perpendicular to the direction of propagation of the wave. S-I: The

{p}_{{x}}

orbital has maximum electron density along the y axis and its nodal plane is xz plane.

S-II : For a given atom, for all values of

n

, the

{p}

-orbitals have the same shape, but the overall size decreases as '

n

' increases. S-I: Elements like

Rb, Cs, Tl, In, Ga

and

Sc

were discovered when their minerals were analysed by spectroscopic methods.

S-II: The element helium was discovered in the sun by spectroscopic method. In which one of the following, the number of protons is greater than number of neutrons but number of protons is less than the number of electrons?