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JEE • CHEMISTRY • STRUCTURE OF ATOM

Structure of atom practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 361-390 of 592 questions

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361 Hard
361 of 592
Application +4 | -1
Bohr’s radius of 2nd orbit of Be3+\mathrm{B}{\mathrm{e}^{3 + }} is equal to that of
View answer and explanation
Correct option: D
First orbit of hydrogen
Option D (First orbit of hydrogen) is correct because the Bohr radius of the 2nd orbit of Be3+ is equal to the Bohr radius of the first orbit of hydrogen.
362 Medium
362 of 592
Application +4 | -1
The magnetic moment of a particular ion is 262 \sqrt{6} B.M.B.M. The ion is
View answer and explanation
Correct option: D
Co3+{Co}^{3+}
Option D (Co3+{Co}^{3+}) is correct because the ion with 4 unpaired electrons has a magnetic moment of approximately 262 \sqrt{6} B.M.
363 Medium
363 of 592
Application +4 | -1
A bulb emits light of λ=4500 A∘\lambda=4500 ~\mathop {\text{A}}\limits^ \circ. The bulb is rated as 150 watt and 8%8 \% of the energy is emitted as light. How many photons are emitted by the bulb per second?
View answer and explanation
Correct option: A
27.2×101827.2 \times 10^{18}
Option A (27.2×101827.2 \times 10^{18}) is correct because it is the number of photons emitted per second, calculated using the energy of one photon and the total energy emitted as light.
364 Easy
364 of 592
Application +4 | -1
The wavelength (in cm) of second line in the Lyman series of hydrogen atomic spectrum is
View answer and explanation
Correct option: A
8R9\frac{{8R}}{9}
Option B (98R\frac{9}{{8R}}) is correct because it uses the Rydberg formula to calculate the wavelength of the second line in the Lyman series.
365 Easy
365 of 592
Application +4 | -1
An electron moves around the nucleus in a circle of radius rr. Assuming that the uncertainty of the momentum of electron is of the same order as momentum itself, the momentum of the electron would be
View answer and explanation
Correct option: A
h4πr\frac{h}{4 \pi r}
Option A (h4πr\frac{h}{4 \pi r}) is correct because it is derived from the Heisenberg uncertainty principle, relating the uncertainty in position and momentum.
366 Easy
366 of 592
Remembering +4 | -1
According to Bohr's postulates which quantity can take up only discrete values:
View answer and explanation
Correct option: B
Angular momentum
Option B (Angular momentum) is correct because, according to Bohr's postulates, the angular momentum of an electron in an orbit is quantized and can only take discrete values.
367 Medium
367 of 592
Remembering +4 | -1
The work-function for photoelectric effect :
View answer and explanation
Correct option: C
Is different for different metals
Option C (Is different for different metals) is correct because the work function depends on the metal's electronic structure and the energy required to remove an electron.
368 Easy
368 of 592
Remembering +4 | -1
The total number of orbitals possible for principle quantum number n is
View answer and explanation
Correct option: B
  n2   \,\,{n^{2\,\,\,}}
Option B (n2  }n^{2\,\,\}}) is correct because the total number of orbitals possible for a principal quantum number n is n2n^2.
369 Easy
369 of 592
Understanding +4 | -1
The number of d-electrons retained in Fe2+\mathrm{F}{\mathrm{e}^{2 + }}(At. No. Fe=26) ions is
View answer and explanation
Correct option: D
6
Option D (6) is correct because Fe2+\mathrm{F}{\mathrm{e}^{2 + }} has lost two electrons from the 4s orbital, leaving 6 electrons in the 3d orbitals.
370 Easy
370 of 592
Understanding +4 | -1
The five dd-orbitals are designated as dxy,dyz,dxz,dx2−y2d_{x y}, d_{y z}, d_{x z}, d_{x^2-y^2} and dz2d_{z^2}. Choose the correct statement.
View answer and explanation
Correct option: C
The shapes of the first four orbitals are similar but that of the fifth orbital is different
The correct answer is D (Ths shapes of all five dd-orbitals are different) because the dz2d_{z^2} orbital has a different shape compared to the other four dd-orbitals.
371 Hard
371 of 592
Understanding +4 | -1
The mass defect of the nuclear reaction: 5B8→4Be8+e+{ }_5 {B}^8 \rightarrow{ }_4 {Be}^8+{e}^{+}is
View answer and explanation
Correct option: D
m={m}= At. mass of 5B8−{ }_5 {B}^8- At. mass of 4Be8+{ }_4 {Be}^8+ mass of two electron
Option D (m={m}= At. mass of 5B8−{ }_5 {B}^8- At. mass of 4Be8+{ }_4 {Be}^8+ mass of two electron) is correct because the mass defect calculation must account for the positron emission, which effectively removes an electron mass from the product.
372 Medium
372 of 592
Application +4 | -1
Thewavelength of a 150 g150 \mathrm{~g} rubber ball moving with a velocity of 50 ms−150 {~ms}^{-1} is :
View answer and explanation
Correct option: D
8.83×10−33 cm8.83 \times 10^{-33} {~cm}
Option D (8.83×10−33 cm8.83 \times 10^{-33} {~cm}) is correct because it is calculated using the de Broglie wavelength formula with the given mass and velocity.
373 Easy
373 of 592
Application +4 | -1
Which one of the following sets of ions represents a collection of iso electronic species
View answer and explanation
Correct option: B
CN−,C22−,N2C{N^ - },C_2^{2 - },{N_2}
Option B (CN−,C22−,N2C{N^-}, C_2^{2 - },{N_2}) is correct because all three species have the same number of electrons (14).
374 Easy
374 of 592
Understanding +4 | -1
Which of the following combination of quantum number is allowed
View answer and explanation
Correct option: B
nlms200−1/2\begin{array}{cccccccccccccccccccc} n&l&m&s\\ 2&0&0&{ - 1/2} \end{array}
Option B is correct because it represents a valid set of quantum numbers following the rules: n>0n > 0, 0≤l<n0 \le l < n, −l≤m≤l-l \le m \le l, and s=±12s = \pm \frac{1}{2}.
375 Medium
375 of 592
Understanding +4 | -1
The threshold energy is given as E0{E_0} and radiation of energy EE falls on metal, then K.E is given as
View answer and explanation
Correct option: B
E−E0E - {E_0}
Option B (E−E0E - {E_0}) is correct because the kinetic energy (K.E) is the difference between the incident energy (E) and the threshold energy (E0{E_0}).
376 Medium
376 of 592
Understanding +4 | -1
Which of the following does not represent the mathematical expression for the Heisenberg uncertainty principle.
View answer and explanation
Correct option: D
ΔE⋅Δx≥h4π\Delta E \cdot \Delta x \ge \frac{h}{{4\pi }}
Option C (Δx×Δt≥h4π\Delta x \times \Delta t \ge \frac{h}{{4\pi }}) is correct because the Heisenberg uncertainty principle relates uncertainty in position and momentum, or energy and time, not position and time.
377 Medium
377 of 592
Analyzing +4 | -1
The atomic weight of an element is double of its atomic number. If there are four electrons in 2p2 p orbital, the element is isotonic with
View answer and explanation
Correct option: B
7 N15{ }_7 {~N}^{15}
Option B (+0.5 kcal eq⁻¹) is correct because the enthalpy of dissociation of CH₃COOH can be calculated from the difference between the neutralization enthalpies of a strong acid/strong base and a weak acid/strong base reaction.
378 Medium
378 of 592
Remembering +4 | -1
Many types of electromagnetic radiations, differ from one another in wavelength (or frequency) constitute a spectrum known as
View answer and explanation
Correct option: A
Electromagnetic spectrum
Option A (Electromagnetic spectrum) is correct because the electromagnetic spectrum encompasses the range of all types of electromagnetic radiation, differing in wavelength and frequency.
379 Medium
379 of 592
Understanding +4 | -1
Statement-I : The K.E of photo electrons depend on energy and frequency of incident light
Statement-II : The number of photo electrons emitted depend on intensity of incident light
View answer and explanation
Correct option: A
Both statements are true
Option A is correct because the kinetic energy of photoelectrons depends on the energy and frequency of incident light, and the number of photoelectrons emitted depends on the intensity of incident light.
380 Easy
380 of 592
Remembering +4 | -1
Arrange the following in terms of penetrating power. α\alpha-rays, β\beta-rays, γ\gamma-rays
View answer and explanation
Correct option: B
α<β<γ\alpha<\beta<\gamma
Option B (α<β<γ\alpha<\beta<\gamma) is correct because gamma rays have the highest penetrating power, followed by beta particles, and then alpha particles.
381 Medium
381 of 592
Analyzing +4 | -1
In a sample of hydrogen atoms, all the atoms are in a particular excited state. If the emission spectrum of this sample has only 4 spectral lines in the visible region, then the total number of spectral lines in IR region possible from that state is
View answer and explanation
Correct option: A
6
Option A (6) is correct because if there are 4 spectral lines in the visible region ending at n=2, then the initial state is n=6. The number of IR lines (transitions to n>2) can then be calculated.
382 Medium
382 of 592
Application +4 | -1
If the ratio of radii of two shells of a H\mathrm{H}-like species is 25:6425: 64, then the ratio of the velocities will be
View answer and explanation
Correct option: D
8:58: 5
Option A (4) is correct because 1 mole of sodium hypophosphite reacts with excess silver nitrate to produce 4 moles of silver.
383 Medium
383 of 592
Application +4 | -1
Which of the following levels of H{H} and He+{He}^{+}have same energy respectively ?

(A) 1,2

(B) 3,4

(C) 2, 4

(D) 3,6
View answer and explanation
Correct option: D
A, C and D
Option A, C and D are correct because they satisfy the condition where the energy levels of H and He+ are the same, which means n(He+) = 2 * n(H).
384 Easy
384 of 592
Remembering +4 | -1
Which quantum number is not related with Schrodinger equation
View answer and explanation
Correct option: D
Spin
Option D (Spin) is correct because the spin quantum number is not directly derived from the Schrodinger equation but is introduced to account for the intrinsic angular momentum of an electron.
385 Medium
385 of 592
Application +4 | -1
The orbital angular momentum for an electron revolving in an orbit is h2πl(l+1).\frac{h}{{2\pi }}\sqrt {l\left( {l + 1} \right)} .. Thus momentum for a s-electron is:
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the orbital angular momentum depends on the quantum number l, which is 0 for an s-electron, resulting in zero angular momentum.
386 Medium
386 of 592
Application +4 | -1
A golf ball has a mass of 40 g and a speed of 45 m/s. It the speed can be measured within accuracy of 2% the uncertainity in the position is
View answer and explanation
Correct option: B
1.46×10−33m1.46 \times {10^{ - 33}}m
Option B (1.46×10−33m1.46 \times {10^{ - 33}}m) is correct because it is calculated using the Heisenberg uncertainty principle.
387 Medium
387 of 592
Understanding +4 | -1
Consider the following statements obtained after solving the Schrodinger equation for hydrogen atom,

I. we get the possible energy levels that the electron can occupy.

II. the atomic orbital is the wave function (ψ)(\psi) for an electron in an atom.

The correct statement(s) is/are
View answer and explanation
Correct option: C
Both I and II
Option C (Both I and II) is correct because both statements accurately describe the results of solving the Schrodinger equation for the hydrogen atom.
388 Medium
388 of 592
Analyzing +4 | -1
Statement (S): dd-orbitals are five fold non-degenerate in presence of magnetic field.

Explanation (E): In presence of magnetic field the energy of orbitals becomes altogether different.
View answer and explanation
Correct option: C
Both S and E are correct and E is correct explanation of S
Option C is correct because both the statement and explanation are true, and the explanation correctly describes why d-orbitals are non-degenerate in the presence of a magnetic field.
389 Easy
389 of 592
Application +4 | -1
A photon of radiation of wavelength 4000 A∘4000 ~\mathop {\text{A}}\limits^ \circ has an energy EE. The wavelength of photon of radiation having energy 0.5E0.5 E will be
View answer and explanation
Correct option: B
8000 A∘8000 ~\mathop {\text{A}}\limits^ \circ
Option B (8000 Å) is correct because energy and wavelength are inversely proportional, so halving the energy doubles the wavelength.
390 Easy
390 of 592
Analyzing +4 | -1
Which has minimum number of unpaired d-electrons?
View answer and explanation
Correct option: C
Co2+\mathrm{C}{\mathrm{o}^{2 + }}
Option B is correct because Co3+ (d6) has the minimum number of unpaired d-electrons (0 in strong field, 4 in weak field) compared to the other options.
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