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JEE • CHEMISTRY • STATES OF MATTER

States of matter practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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181 Medium
181 of 185
Application +4 | -1
Among the following which gases are heavier than air
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Correct option: B
Moist O2{O_2}
Option B (Moist O2{O_2}) is correct because the presence of water vapor increases the effective molecular weight compared to dry air.
182 Medium
182 of 185
Remembering +4 | -1
Which of the following represent standard state?
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Correct option: A
298 K,1298 \mathrm{~K}, 1 bar
Option A (298 K,1298 \mathrm{~K}, 1 bar) is correct because the standard state is defined as 298 K (25°C) and 1 bar pressure.
183 Medium
183 of 185
Understanding +4 | -1
On mixing 10 mL of toluene with 10 mL of benzene, the total volume of the solution is
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Correct option: C
=20  mL  = 20\,\,\mathrm{mL}\,\,
Option C (= 20 mL) is correct because toluene and benzene form an ideal solution, meaning there is no volume change upon mixing.
184 Medium
184 of 185
Understanding +4 | -1
Ratio of Boyle temperature and critical temperature for a gas is
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Correct option: B
278\frac{27}{8}
Option B (27/8) is correct because the Boyle temperature is a/Rb and the critical temperature is 8a/27Rb, so their ratio is 27/8.
185 Medium
185 of 185
Application +4 | -1
1 mole of SO2{SO}_2 gas occupies a volume of 350  mL350 \,\mathrm{~mL} at 300  K300\, {~K} and 50  atm50 \,{~atm} pressure. The value of compressibility factor of the gas is
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Correct option: A
0.71
Option A (0.71) is correct because it is calculated using the compressibility factor formula, Z = PV/nRT.
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