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JEE • CHEMISTRY • STATES OF MATTER

States of matter practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Easy

1 of 56

Understanding +4 | -1

In deriving the kinetic equation we make use of the root mean square speed of the molecules which is:

View answer and explanation

Correct option: C

The square root of the average of the square of the speed of the molecules

Option C is correct because the root mean square speed is defined as the square root of the average of the squares of the speeds of the molecules.

2 Easy

2 of 56

Remembering +4 | -1

The compressibility factor of an ideal gas is

View answer and explanation

Correct option: A

Option A (1) is correct because the compressibility factor (Z) for an ideal gas is always equal to 1.

3 Easy

3 of 56

Understanding +4 | -1

Critical temperature of a gas is the temperature

View answer and explanation

Correct option: B

Above which it cannot be liquefied

Option B (Above which it cannot be liquefied) is correct because the critical temperature is the temperature above which a gas cannot be liquefied by pressure alone.

4 Easy

4 of 56

Understanding +4 | -1

At constant volume, for a fixed number of mole of a gas, the pressure of the gas increases with rise of temperature due to

View answer and explanation

Correct option: A

Increase in average molecular speed

Option A (Increase in average molecular speed) is correct because, at constant volume and number of moles, an increase in temperature leads to an increase in the average kinetic energy of the gas molecules, resulting in more frequent and forceful collisions with the container walls, hence increasing pressure.

5 Easy

5 of 56

Understanding +4 | -1

The value of Vander Waal’s constant ‘a’ is minimum for

View answer and explanation

Correct option: A

He

Option A (

He

) is correct because the Van der Waals constant 'a' is related to the intermolecular forces, which are weakest for Helium due to its small size and inert nature.

6 Easy

6 of 56

Analyzing +4 | -1

Indicate the incorrect statement for equal volumes of

\mathrm{N}_2(\mathrm{g})

and

\mathrm{CO}_2(\mathrm{g})

at 25 degree Celsius and

1 \mathrm{~atm}

View answer and explanation

Correct option: B

The rms speed remains the same for both

\mathrm{N}_2

and

\mathrm{CO}_2

The incorrect statement is B (The rms speed remains the same for both N2 and CO2) because the rms speed depends on the molar mass, which is different for N2 and CO2.

7 Easy

7 of 56

Understanding +4 | -1

Dipole - dipole forces act between the molecules possessing permanent dipole. Ends of dipoles possess ‘particle charges’. The partial charge is

View answer and explanation

Correct option: C

Less than unit electronic charge

Option C is correct because the partial charges in dipole-dipole interactions are less than a unit electronic charge due to the sharing of electrons in a covalent bond.

8 Easy

8 of 56

Analyzing +4 | -1

Assertion: The pressure of a gas is directly proportional to the density of gas at a constant temperature and molecular mass.

Reason: The molecular weight of a vapour of a substance can be calculated using the expression

M=\frac{d R T}{P}

, where

M

is the molecular weight of the vapour,

d

is its density and

P

is the pressure of the vapour,

{R}

is the gas constant and

{T}

is the temperature.

View answer and explanation

Correct option: A

Assertion is correct, reason is correct; reason is a correct explanation for assertion.

Option A is correct. The ideal gas law can be rearranged to show that pressure is directly proportional to density at constant temperature and molecular mass. The reason provides the correct formula derived from the ideal gas law.

9 Easy

9 of 56

Remembering +4 | -1

The compressibility factor for an ideal gas is

View answer and explanation

Correct option: C

Option C (1) is correct because the compressibility factor (Z) for an ideal gas is always equal to 1, as it perfectly obeys the ideal gas law.

10 Easy

10 of 56

Understanding +4 | -1

Which of the following will increase with the increase in temperature?

View answer and explanation

Correct option: D

Vapour pressure

Option D is correct because vapor pressure increases with temperature as more molecules gain enough kinetic energy to escape into the gas phase.

11 Easy

11 of 56

Remembering +4 | -1

The compressibility factor for an ideal gas is

View answer and explanation

Correct option: B

Option B (1) is correct because the compressibility factor (Z) for an ideal gas is always equal to 1, as it perfectly obeys the ideal gas law.

12 Easy

12 of 56

Understanding +4 | -1

Amongst

N{H_3},P{H_3},As{H_3}

and

Sb{H_3}

the one with highest B.P is

View answer and explanation

Correct option: B

Sb{H_3}

because of higher molecular weight

Option B (

Sb{H_3}

because of higher molecular weight) is correct because, among the given options,

SbH_3

has the highest molecular weight, leading to stronger van der Waals forces and thus a higher boiling point.

13 Easy

13 of 56

Understanding +4 | -1

The beans are cooked earlier in pressure cooker because

View answer and explanation

Correct option: A

Boiling point increases with increasing pressure

Option A (Boiling point increases with increasing pressure) is correct because increasing the pressure in a pressure cooker raises the boiling point of water, allowing the beans to cook at a higher temperature and thus faster.

14 Easy

14 of 56

Application +4 | -1

1000 \mathrm{~mL} {~N}_2(\mathrm{~g})

227^{\circ} \mathrm{C}

is cooled to

27^{\circ} \mathrm{C}

at the same pressure. The new volume becomes

View answer and explanation

Correct option: B

600 \mathrm{~mL}

Option B (600 mL) is correct because the new volume is calculated using Charles's Law, which states that volume is directly proportional to temperature at constant pressure.

15 Easy

15 of 56

Remembering +4 | -1

The compressibility factor ‘z’ for the gas is given by

View answer and explanation

Correct option: B

z = \frac{{P{V_{obs}}}}{{nRT}}

Option B (

z = \frac{{P{V_{obs}}}}{{nRT}}

) is correct because the compressibility factor (z) is defined as the ratio of the observed volume to the ideal volume, which is represented by the formula.

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16 Easy

16 of 56

Remembering +4 | -1

Value of universal gas constant (

R

) depends upon

View answer and explanation

Correct option: D

None of these

Option D (None of these) is correct because the value of the universal gas constant (R) depends only on the units of measurement used for pressure, volume, and temperature, not on the properties of the gas itself.

17 Easy

17 of 56

Understanding +4 | -1

The compressibility factor of a gas is defined as

Z = PV/nRT

. The compressibility factor of an ideal gas is:

View answer and explanation

Correct option: C

Option C (1) is correct because the compressibility factor (Z) for an ideal gas is always 1, as the ideal gas law (PV=nRT) is perfectly obeyed.

18 Easy

18 of 56

Understanding +4 | -1

Abnormal boiling point of a compound is due to

View answer and explanation

Correct option: C

Inter molecular hydrogen bonding

Option C (Inter molecular hydrogen bonding) is correct because it leads to higher boiling points due to increased intermolecular forces.

19 Easy

19 of 56

Understanding +4 | -1

Which statement violates the assumptions of the kinetic theory of gases?

View answer and explanation

Correct option: B

The molecules are at rest

Option B is correct. The kinetic theory of gases assumes that gas molecules are in constant, random motion, not at rest.

20 Easy

20 of 56

Remembering +4 | -1

Which force is strongest?

View answer and explanation

Correct option: B

Ion-ion forces

Option B (Ion-ion forces) is correct because ion-ion forces are electrostatic interactions between charged ions, which are significantly stronger than dipole-dipole, ion-dipole, or ion-induced dipole forces.

21 Easy

21 of 56

Remembering +4 | -1

The temperature at which real gases obey the Boyle’s law over a wide range of pressure is called

View answer and explanation

Correct option: B

Boyle’s temperature

Option B (Boyle’s temperature) is correct because Boyle's temperature is the temperature at which a real gas obeys Boyle's law over a wide range of pressures.

22 Easy

22 of 56

Understanding +4 | -1

Equal volume of different gases at any definite temperature and pressure have

View answer and explanation

Correct option: D

Equal molecules

Option D (Equal molecules) is correct because Avogadro's law states that equal volumes of all gases at the same temperature and pressure contain the same number of molecules.

23 Easy

23 of 56

Application +4 | -1

If the density of certain gas at

30^\circ C

768 torr is

1.35\,\,Kg/{m^3}

its density at STP would be

View answer and explanation

Correct option: A

1.48\,Kg/{m^3}

Option A (

1.48\,Kg/{m^3}

) is correct because it is calculated using the ideal gas law and the relationship between density, pressure, temperature, and molar mass.

24 Easy

24 of 56

Application +4 | -1

Calculate the weight of methane in a 9L cylinder at 16 atm and

27^\circ C

View answer and explanation

Correct option: C

93.6 g

The correct answer is 93.6 g because it is calculated using the ideal gas law, PV = nRT, to find the number of moles and then the mass.

25 Easy

25 of 56

Understanding +4 | -1

The ratio of volume occupied by 1 mole

\mathrm{O}_2

and 1 mole

\mathrm{CO}_2

under identical conditions of temperature and pressure is:

View answer and explanation

Correct option: A

1: 1

Option A (

1: 1

) is correct because, according to Avogadro's law, equal volumes of all gases at the same temperature and pressure contain the same number of molecules, thus the volume ratio is directly proportional to the mole ratio.

26 Easy

26 of 56

Analyzing +4 | -1

Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: Amongst

\mathrm{He}, \mathrm{Ne}, \mathrm{Ar}

and

\mathrm{Kr} ; 1\mathrm{g}

of activated charcoal adsorbs more of

\mathrm{Kr}

.
Reason R: The critical volume

\mathrm{V_c(cm^3 \,mol^{–1}})

and critical pressure

P_c

(atm) is highest for Krypton but the compressibility factor at critical point

Z_c

is lowest for Krypton.
In the light of the above statements, choose the correct answer from the options given below.

View answer and explanation

Correct option: B

A is true but R is false

The correct answer is B (A is true but R is false) because while Kr is adsorbed more, the given reason about critical volume, pressure, and compressibility factor is incorrect.

27 Easy

27 of 56

Remembering +4 | -1

The ratio among most probable velocity, average velocity and root mean square velocity is given by

View answer and explanation

Correct option: D

\sqrt 2 \,\,\,:\,\sqrt {8/\pi } \,:\,\,\sqrt 3

Option D (

\sqrt 2 \,\,\,\:\sqrt {8/\pi } \,:\,\,\sqrt 3

) is correct because the ratio of most probable velocity, average velocity, and root mean square velocity is given by

\sqrt{2} : \sqrt{\frac{8}{\pi}} : \sqrt{3}

28 Easy

28 of 56

Remembering +4 | -1

Gay-Lussac’s law of gaseous volumes is derived from:

View answer and explanation

Correct option: C

Experimental observations

Option C (Experimental observations) is correct because Gay-Lussac's law was formulated based on experimental data and observations of gas behavior under constant temperature and pressure.

29 Easy

29 of 56

Remembering +4 | -1

The units of the Vander Waal’s constant ‘b’ are

View answer and explanation

Correct option: C

{\text{L}}{\text{.mo}}{{\text{l}}^{ - 1}}

Option C (

{\text{L}}{\text{.mo}}{{\text{l}}^{ - 1}}

) is correct because the van der Waals constant 'b' represents the volume per mole of gas molecules.

30 Easy

30 of 56

Remembering +4 | -1

In van der Waal's equation of state of the gas law, the constant '

b

' is a measure of

View answer and explanation

Correct option: A

Volume occupied by the molecules

Option A (Volume occupied by the molecules) is correct because the van der Waals constant 'b' accounts for the finite volume of gas molecules.

Revision notes and key takeaways

Review STATES OF MATTER in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 56 single-correct-answer MCQs on STATES OF MATTER.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

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States of matter practice · Easy

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