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JEE • CHEMISTRY • STATES OF MATTER

States of matter practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 262 questions
211 Hard
211 of 262
Application +4 | -1
As the temperature is raised from 200C to 400C{20^0}C\,\mathrm{to}\,{40^0}C the average kinetic energy of neon atoms changes by a factor of which of the following?
View answer and explanation
Correct option: C
313/293\sqrt {313/293}
Option B (313/293\sqrt{{313/293}}) is correct because the average kinetic energy is directly proportional to the absolute temperature.
212 Medium
212 of 262
Understanding +4 | -1
If saturated vapours are compressed slowly at constant temperature to half the initial volume, the vapour pressure will
View answer and explanation
Correct option: D
Remains unchanged
Option D (Remains unchanged) is correct because at constant temperature, the vapor pressure of a saturated vapor remains constant regardless of volume changes.
213 Medium
213 of 262
Understanding +4 | -1
Statement I: The order of viscosities of hexane, water glycerol is hexane << water << glycerol.

Statement II: Hexane has weakest intermolecular force and glycerol the strongest.
View answer and explanation
Correct option: A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I.
Option A (Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I) is correct because viscosity is directly related to intermolecular forces, with stronger forces leading to higher viscosity.
214 Medium
214 of 262
Understanding +4 | -1
Vapour pressure of liquid does/do not depend(s) on
View answer and explanation
Correct option: A
Surface area
Option A (Surface area) is correct because the vapor pressure of a liquid depends on temperature and the nature of the liquid, but not on the surface area of the liquid.
215 Medium
215 of 262
Analyzing +4 | -1
Which of the following statements is not true?
View answer and explanation
Correct option: B
The square of the mean speed of the molecules is equal to the mean squared speed at a certain temperature
Option B (The square of the mean speed of the molecules is equal to the mean squared speed at a certain temperature) is not true because the root mean square speed is not the same as the square of the average speed.
216 Medium
216 of 262
Analyzing +4 | -1
Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason
R.
Assertion A: Activated charcoal adsorbs SO2\mathrm{SO}_2 more efficiently than CH4\mathrm{CH}_4.

Reason R: Gases with lower critical temperatures are readily adsorbed by activated charcoal.
In the light of the above statements, choose the correct answer from the options given below.
View answer and explanation
Correct option: C
A\mathbf{A} is correct but R\mathbf{R} is not correct.
Option C is correct. Assertion A is correct because activated charcoal adsorbs SO2 more efficiently due to its polarity, but Reason R is incorrect because gases with higher critical temperatures are more readily adsorbed.
217 Easy
217 of 262
Remembering +4 | -1
Joule-Thomson expansion of an ideal gas is an
View answer and explanation
Correct option: C
Isoenthalpic process
Option C (Isoenthalpic process) is correct because Joule-Thomson expansion occurs at constant enthalpy.
218 Medium
218 of 262
Understanding +4 | -1
A bottle of dry ammonia and a bottle of dry hydrogen chloride connected through a long tube are opened simultaneously at both ends. The white ammonium chloride ring first formed will be
View answer and explanation
Correct option: B
Near the hydrogen chloride bottle.
Option B (Near the hydrogen chloride bottle) is correct because ammonia diffuses faster than hydrogen chloride due to its lower molecular weight, so the ring forms closer to the HCl source.
219 Hard
219 of 262
Application +4 | -1
What is the temperature at which the kinetic energy of 0.3 mole of helium is equal to the kinetic energy of 0.4 mole of argon at 400 K?
View answer and explanation
Correct option: C
533K533\mathrm{ }K
Option C (533K533\mathrm{ }K) is correct because it is calculated by equating the kinetic energies of helium and argon.
220 Easy
220 of 262
Remembering +4 | -1
The speed possessed by majority of gaseous molecules is:
View answer and explanation
Correct option: B
Most probable speed
Option B (Most probable speed) is correct because the most probable speed is the speed possessed by the majority of gaseous molecules.
221 Medium
221 of 262
Understanding +4 | -1
S-I: CH4,CO2\mathrm{CH}_4, \mathrm{CO}_2 has value of Z\mathrm{Z} (compressibility factor) less than one at 0∘C0^{\circ} \mathrm{C}.

S-II: Z<1\text{Z} < 1 is due to the attractive forces dominate among the molecules.
View answer and explanation
Correct option: A
Both statements are correct and statement-II is correct explanation of statement-I
Option D (S-I is incorrect and S-II is correct) is correct because CH4CH_4 and CO2CO_2 have Z > 1 at 0°C, and Z < 1 is indeed due to dominant attractive forces.
222 Medium
222 of 262
Understanding +4 | -1
Where is the pressure less than 1 atm?
View answer and explanation
Correct option: B
At a place where water boils at 90∘C90^{\circ} \mathrm{C}
Option B (At a place where water boils at 90°C) is correct because the boiling point of water decreases as pressure decreases. Water boils at 100°C at 1 atm.
223 Medium
223 of 262
Application +4 | -1
Equal masses of O2{O}_2 and CH4{CH}_4 have been taken in same container of volume V{V} at 25∘C25^{\circ} {C}. The ratio of volume of gases effuses out initially from vessel is
View answer and explanation
Correct option: B
2:4\sqrt{2}: 4
Option B (2:4\sqrt{2}: 4) is correct because the ratio of effusion rates is inversely proportional to the square root of the molar masses.
224 Medium
224 of 262
Understanding +4 | -1
Energy of sublimation of solid helium is much lower than that of ice because
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because the lower sublimation energy of solid helium is due to weak van der Waals forces compared to the strong hydrogen bonding in ice, which also melts at a higher temperature.
225 Hard
225 of 262
Analyzing +4 | -1
Most probable velocity (ump)\left(u_{\mathrm{mp}}\right), average velocity (uav)\left(u_{\mathrm{av}}\right) and root mean square velocity (urms)\left(u_{\mathrm{rms}}\right) of a sample of argon are equal, then
View answer and explanation
Correct option: C
Trms <Tav <Tmp T_{\text {rms }} < T_{\text {av }} < T_{\text {mp }}
The correct answer is C (Trms <Tav <Tmp T_{\text {rms }} < T_{\text {av }} < T_{\text {mp }}) because the temperatures are related to the velocities by constants, and the given velocities are equal.
226 Medium
226 of 262
Application +4 | -1
The temperature of a gas in a closed container is 27∘C27^{\circ} \mathrm{C}. If the temperature is raised to 327∘C327^{\circ} \mathrm{C}, the pressure exerted is
View answer and explanation
Correct option: B
doubled
Option B (doubled) is correct because, according to Gay-Lussac's Law, pressure is directly proportional to temperature when volume is constant. Doubling the absolute temperature doubles the pressure.
227 Easy
227 of 262
Understanding +4 | -1
The density of a gas is equal to? (P = pressure; V = volume; T = temperature, R = gas constant, n = number of moles and M = molecular wt.)
View answer and explanation
Correct option: B
PM/RT
Option B (PM/RT) is correct because the density of a gas can be derived from the ideal gas law, PV = nRT, where n = mass/molecular weight.
228 Medium
228 of 262
Analyzing +4 | -1
Assertion (A): Compressibility factor for hydrogen varies with pressure with positive slope at all pressures.

Reason (R): Even at low pressures, repulsive forces dominate hydrogen gas.
View answer and explanation
Correct option: A
Assertion is correct, reason is correct; reason is a correct explanation for assertion
Option A (Assertion is correct, reason is correct; reason is a correct explanation for assertion) is correct because hydrogen's compressibility factor increases with pressure due to repulsive forces dominating even at low pressures.
229 Medium
229 of 262
Application +4 | -1
At what temperature is the rms speed of hydrogen molecules the same as that of oxygen molecules at 1327  ∘C1327\,\,^\circ C ?
View answer and explanation
Correct option: B
100K100\mathrm{ }K
Option B (100K100\mathrm{ }K) is correct because the temperature is calculated by equating the rms speeds of hydrogen and oxygen molecules.
230 Hard
230 of 262
Remembering +4 | -1
The mean free path (λ)\left( \lambda \right) of a gas sample is given by:
View answer and explanation
Correct option: B
λ=12πσ2N\lambda = \frac{1}{{\sqrt 2 \pi {\sigma ^2}N}}
Option B (λ=12πσ2N\lambda = \frac{{1}}{{\sqrt 2 \pi {{\sigma }^2}N}}) is correct because it represents the correct formula for the mean free path of a gas molecule.
231 Medium
231 of 262
Application +4 | -1
Calculate the radius of He atoms if its Vander Waal&rsquo;s constant &lsquo;b&rsquo; is 24 ml mol−1mo{l^{ - 1}}: (Note mlml =cubic centimeter)
View answer and explanation
Correct option: A
1.355 A∘1.355\,{A^ \circ }
Option A (1.355 A∘1.355\,{A^ \circ }) is correct because it is obtained by using the Vander Waals constant 'b' in the relevant formula and solving for the radius.
232 Medium
232 of 262
Understanding +4 | -1
A gas such as carbon monoxide would be most likely to obey the ideal gas law at:
View answer and explanation
Correct option: C
High temperatures and low pressures
Option C (High temperatures and low pressures) is correct because real gases behave most ideally under conditions of high temperature and low pressure, where intermolecular forces are minimized.
233 Easy
233 of 262
Understanding +4 | -1
A gas can be liquefied at temperature T and pressure P provided
View answer and explanation
Correct option: B
T<TcT < Tc and P>PcP > Pc
Option B is correct because a gas can be liquefied at a temperature below its critical temperature (Tc{T_c}) and a pressure above its critical pressure (Pc{P_c}).
234 Medium
234 of 262
Remembering +4 | -1
In Vander Wal’s equation, the constant ‘b’ is the measure of:
View answer and explanation
Correct option: D
Volume occupied by the molecules
The correct answer is D (Volume occupied by the molecules) because the constant 'b' in the van der Waals equation accounts for the finite volume of gas molecules.
235 Medium
235 of 262
Remembering +4 | -1
The critical temperature of a gas is related to van der Waal’s constants as
View answer and explanation
Correct option: C
Tc=8a27bRT_c=\frac{8 {a}}{27 {bR}}
Option C (Tc=8a27bRT_c=\frac{8 {a}}{27 {bR}}) is correct because the critical temperature (TcT_c) is related to the van der Waals constants 'a' and 'b' and the gas constant R by the formula Tc=8a27bRT_c=\frac{8 {a}}{27 {bR}}.
236 Medium
236 of 262
Application +4 | -1
The rates of diffusion of O2{\mathrm{O}_2} and H2{\mathrm{H}_2} at same PP and TT are in the ratio:
View answer and explanation
Correct option: A
1:41:4
Option A (1:41:4) is correct because the ratio of diffusion rates is inversely proportional to the square root of the ratio of their molar masses.
237 Medium
237 of 262
Application +4 | -1
A human adult breathes in approximately 0.50 dm30.50 \mathrm{~dm}^3 of air at 1.00 bar1.00 \mathrm{~bar} with each breath. If an air tank holds 100 dm3100 \mathrm{~dm}^3 of air at 200 bar,200 \mathrm{~bar}, how many breathes the tank will supply?
View answer and explanation
Correct option: A
40,000 breaths40,000 \text{ breaths}
Option A (40,000 breaths) is correct because it is calculated using Boyle's law to find the total volume of air at 1 bar and then dividing by the volume per breath.
238 Medium
238 of 262
Application +4 | -1
The density of gas is found to be 1.41 g/L1.41 \mathrm{~g} / \mathrm{L} at 700 mm Hg700 \mathrm{~mm} \mathrm{~Hg} pressure and 350 K350 \mathrm{~K} temperature. Gas can be
View answer and explanation
Correct option: B
CO2\mathrm{CO}_2
Option B (CO2) is correct because the molar mass calculated from the given density, pressure, and temperature is approximately 44 g/mol, which corresponds to carbon dioxide.
239 Medium
239 of 262
Analyzing +4 | -1
Assertion: Dalton's law of partial pressure is a special case of Raoult's law.

Reason: Dalton's law applies only to ideal gas mixtures, whereas Raoult's law applies to solutions.
View answer and explanation
Correct option: B
Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion
Option B is correct. Both the assertion and the reason are true, but the reason does not correctly explain the assertion.
240 Medium
240 of 262
Understanding +4 | -1
If volume containing gas is compressed to half, how many moles of gas remained in the vessel?
View answer and explanation
Correct option: C
Same
Option C (Same) is correct because compressing the gas to half the volume does not change the number of moles of the gas present, assuming no gas is added or removed.
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