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JEE • CHEMISTRY • STATES OF MATTER
States of matter practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 151-180 of 262 questions
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151
Medium
151 of 262
Application
+4 | -1
2 moles of and 1 mole of are taken in a container of capacity 8.21 lit at to produce . Find the total pressure after the reaction.
View answer and explanation
Correct option: A
3 atm
Option D (2 atm) is incorrect. Option A (3 atm) is correct because it is the total pressure calculated after the reaction, considering the remaining NH3 gas.
152
Hard
152 of 262
Application
+4 | -1
An open vessel containing air is heated from 300 K to 400 K. The fraction of air originally present which goes out of it is:
View answer and explanation
Correct option: B
Option B () is correct because it represents the fraction of air that escapes the vessel when heated from 300 K to 400 K, calculated using the ideal gas law.
153
Medium
153 of 262
Application
+4 | -1
The ratio of the root mean square velocity of at and that of at is
View answer and explanation
Correct option: C
1
Option C (1) is correct because the ratio of RMS velocities is calculated using the formula and simplifies to 1.
154
Medium
154 of 262
Application
+4 | -1
Active mass of 14 grams of Nitrogen at STP is ''. Active mass of 8 grams of oxygen at STP is ''. Ratio of to is
View answer and explanation
Correct option: A
Option A (1:1) is correct because the active mass of any gas at STP is directly proportional to the number of moles, and the ratio of moles is proportional to the ratio of active masses.
155
Medium
155 of 262
Analyzing
+4 | -1
S-I: Compressibility factor for hydrogen varies with pressure with positive slope at all pressures at .
S-II: Even at low pressures, repulsive forces dominate hydrogen gas at .
S-II: Even at low pressures, repulsive forces dominate hydrogen gas at .
View answer and explanation
Correct option: A
Both statements are correct and statement-II is correct explanation of statement-I
Option A (Both statements are correct and statement-II is correct explanation of statement-I) is correct because the compressibility factor for hydrogen increases with pressure due to the dominance of repulsive forces.
156
Medium
156 of 262
Application
+4 | -1
The density of a gas is 4 times to that of a gas If the molecular mass of is what is the molecular mass of
View answer and explanation
Correct option: A
Option A () is correct because the molecular mass of B is one-fourth of the molecular mass of A, derived from the ideal gas law and the given density relationship.
157
Medium
157 of 262
Analyzing
+4 | -1
Assertion (A): Different gases at the same conditions of temperature and pressure have same root mean square speed.
Reason (R): Average kinetic energy of a gas is directly proportional to temperature in kelvin scale.
Reason (R): Average kinetic energy of a gas is directly proportional to temperature in kelvin scale.
View answer and explanation
Correct option: D
Assertion is incorrect, reason is correct
The correct answer is D (Assertion is incorrect, reason is correct) because the root mean square speed depends on the molar mass of the gas, and the average kinetic energy is directly proportional to temperature.
158
Medium
158 of 262
Application
+4 | -1
A bottle of dry and bottle of dry connected through a long tube are opened simultaneously at both ends, the white ring first formed will be:
View answer and explanation
Correct option: B
Near the bottle
Option B (Near the bottle) is correct because diffuses faster than HCl due to its lower molecular weight, leading to the ring forming closer to the HCl bottle.
159
Medium
159 of 262
Application
+4 | -1
A glass bulb of capacity is filled by helium gas at pressure. Due to a leakage the gas leaks out. What is the volume of gas leaked if the final pressure in container is
View answer and explanation
Correct option: A
Option A () is correct because it is the volume of gas leaked calculated using Boyle's law.
160
Medium
160 of 262
Application
+4 | -1
A quantity of gas is collected in a graduated tube over the mercury. The volume of gas at is and the level of mercury in the tube is above the outside mercury level. The barometer reads 750 torr. Hence, volume at STP is approximately
View answer and explanation
Correct option: B
Option B (40 mL) is correct because the volume at STP is calculated using the combined gas law, accounting for the difference in mercury levels and converting to standard conditions.
161
Medium
161 of 262
Application
+4 | -1
Equal masses of and methane have been taken in a container of volume at temperature in identical conditions. The ratio of the volumes of gases : methane would be :
View answer and explanation
Correct option: C
Option C () is correct because the ratio of volumes is directly proportional to the number of moles, and the number of moles is inversely proportional to the molecular mass.
162
Medium
162 of 262
Application
+4 | -1
Equal masses of and are mixed in an empty container at . The fraction of the total pressure exerted by is
View answer and explanation
Correct option: B
Option B () is correct because the mole fraction of H2 is calculated as moles of H2 divided by the total moles, and then used to find the partial pressure fraction.
163
Easy
163 of 262
Application
+4 | -1
Relative density of a volatile substance with respect to is 8. Its molecular weight would be
View answer and explanation
Correct option: C
256
Option C (256) is correct because the molecular weight is calculated using the relative density with respect to .
164
Medium
164 of 262
Remembering
+4 | -1
S.I units of gas constant R is
View answer and explanation
Correct option: C
Option C () is correct because it represents the value of the gas constant R in S.I. units (Joules per Kelvin per mole).
165
Easy
165 of 262
Application
+4 | -1
The minimum pressure required to compress of air at to at is
View answer and explanation
Correct option: C
Option C (8 atm) is correct because it is the pressure calculated using Boyle's Law, which states that for a fixed amount of gas at constant temperature, the pressure and volume are inversely proportional.
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166
Medium
166 of 262
Analyzing
+4 | -1
Assertion: The molecules of the dissolved gas present in a liquid gain kinetic energy as temperature is raised.
Reason : Gases tends to be more soluble in liquids as the temperature is raised.
Reason : Gases tends to be more soluble in liquids as the temperature is raised.
View answer and explanation
Correct option: C
If Assertion is correct but Reason is incorrect.
Option C is correct because the assertion is true, but the reason is false. Gases become less soluble as temperature increases.
167
Hard
167 of 262
Application
+4 | -1
To an evacuated vessel with movable piston under external pressure of 1 atm, 0.1 mole of He and 1.0 mole of an unknown compound (vapour pressure 0.68 atm at ) are introduced. Considering the ideal gas behaviour, the total volume (in litre) of the gases at is close to
View answer and explanation
Correct option: C
7
Option C (7) is correct because the partial pressure of He is calculated, and then using the ideal gas law, the volume is found to be approximately 7L.
168
Medium
168 of 262
Application
+4 | -1
At the top of the mountain the thermometer reads and the barometer reads of . At the bottom of the mountain the temperature is and pressure is of . Density of air at the top with that at the bottom is
View answer and explanation
Correct option: B
The correct answer is B (1.04: 1) because the density of a gas is directly proportional to pressure and inversely proportional to temperature, allowing for a direct comparison between the top and bottom of the mountain.
169
Medium
169 of 262
Application
+4 | -1
A flask contains of a gas of relative molecular mass 120 at a pressure of was evacuated by means of a pump until the pressure was . Which of the following is the best estimate of the number of molecules left in the flask .
View answer and explanation
Correct option: B
Option B () is correct because it is calculated using the ratio of pressures to find the number of moles remaining and then multiplying by Avogadro's number.
170
Easy
170 of 262
Remembering
+4 | -1
The compressibility factor for an ideal gas is
View answer and explanation
Correct option: B
1
Option B (1) is correct because the compressibility factor (Z) for an ideal gas is always equal to 1, indicating ideal behavior.
171
Medium
171 of 262
Remembering
+4 | -1
“One gram molecule of a gas at N.T.P occupies 22.4 lit” This fact was derived from
View answer and explanation
Correct option: B
Avogadro’s hypothesis
Option B (Avogadro’s hypothesis) is correct because Avogadro's hypothesis states that equal volumes of all gases, at the same temperature and pressure, have the same number of molecules, leading to the 22.4 L molar volume at NTP.
172
Medium
172 of 262
Understanding
+4 | -1
With increase of pressure, the mean free path
View answer and explanation
Correct option: A
Decreases
Option A (Decreases) is correct because as pressure increases, the molecules are closer together, leading to more frequent collisions and a shorter mean free path.
173
Medium
173 of 262
Application
+4 | -1
If temperature of 1 mole of gas is increased by calculate the change in kinetic energy of the system
View answer and explanation
Correct option: A
Option A () is correct because it is the change in kinetic energy calculated using the formula KE = (3/2)RT.
174
Medium
174 of 262
Remembering
+4 | -1
The temperature at which a real gas obeys the ideal gas laws over a wide range of pressure is
View answer and explanation
Correct option: B
Boyle temperature
Option B (Boyle temperature) is correct because Boyle temperature is the temperature at which a real gas obeys the ideal gas law over a wide range of pressures.
175
Easy
175 of 262
Understanding
+4 | -1
The interaction force present between molecules are
View answer and explanation
Correct option: C
London forces
Option C (London forces) is correct because H2 is a nonpolar molecule, and the only intermolecular forces present are London dispersion forces.
176
Medium
176 of 262
Application
+4 | -1
Find the ratio of moles of to after fifth diffusion steps if their initially mole ratio is
View answer and explanation
Correct option: A
Option A () is correct because it is calculated using Graham's law of diffusion after 5 diffusion steps.
177
Easy
177 of 262
Understanding
+4 | -1
Vander waal constant “b” is very high for the following gas
View answer and explanation
Correct option: A
Option A () is correct because the van der Waals constant 'b' is directly proportional to the size/volume of the gas molecule.
178
Medium
178 of 262
Application
+4 | -1
The relative rates of diffusion of and are
View answer and explanation
Correct option: A
1.0043
Option A (1.0043) is correct because the relative rates of diffusion are inversely proportional to the square root of their molar masses.
179
Medium
179 of 262
Understanding
+4 | -1
The van der Waals’ equation for a real gas is given by the formula are the pressure, volume, temperature and the number of moles of the gas. Which one is the correct interpretation for the parameter a?
View answer and explanation
Correct option: C
The parameter accounts for intermolecular interaction’s present in the molecule
Option C (The parameter accounts for intermolecular interaction’s present in the molecule) is correct because the 'a' parameter in the van der Waals equation accounts for the attractive intermolecular forces between gas molecules.
180
Medium
180 of 262
Application
+4 | -1
A mixture of Ne and Ar kept in a closed vessel at has a total K.E. . The total mass of and is . Find mass % of in gaseous mixture at .
View answer and explanation
Correct option: D
28.3
Option D (28.3) is correct because it is the mass percentage of Ne calculated from the total kinetic energy and total mass of the mixture.
Revision notes and key takeaways
Review STATES OF MATTER in your textbook or class notes, then use this set to check your understanding.
Showing 151-180 of 262 questions
