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JEE • CHEMISTRY • SOME BASIC CONCEPTS OF CHEMISTRY

Some basic concepts of chemistry practice · Hard

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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61 Hard
61 of 77
Application +4 | -1
A mixture contains 1 mole each of Fe+2\mathrm{Fe}^{+2} and Fe+3\mathrm{Fe}^{+3} ions volume of 1 M KMnO41 \mathrm{~M} \mathrm{~KMnO}_4 required by mxiture in the oxidation of the given mixture is
View answer and explanation
Correct option: B
200 ml200 \mathrm{~ml}
Option B (200 ml200 \mathrm{~ml}) is correct because it is the volume of 1 M KMnO41 \mathrm{~M} \mathrm{~KMnO}_4 required to oxidize the mixture of Fe+2\mathrm{Fe}^{+2} and Fe+3\mathrm{Fe}^{+3} ions.
62 Hard
62 of 77
Analyzing +4 | -1
Assume that the atomic mass of oxygen is 7.7. A sample of 11 g11 \mathrm{~g} of an oxide of uranium contains 10 g10 \mathrm{~g} of uranium. Which of the following formula for the oxide is compatible with the data?
View answer and explanation
Correct option: A
Uranium oxide is UO\text{UO} and the atomic mass of U\mathrm{U} is 70
Option A is correct because the ratio of Uranium to Oxygen is 1:1, which corresponds to the formula UO, and the atomic mass of U is 70.
63 Hard
63 of 77
Application +4 | -1
In the mixture of (NaHCO3+Na2CO3)\left(\mathrm{NaHCO}_3+\mathrm{Na}_2 \mathrm{CO}_3\right), volume of HCl\mathrm{HCl} required is x mLx \mathrm{~mL} with phenolphthalein indicator and y mLy \mathrm{~mL}, with methyl orange indicator in the same titration. Hence, volume of HCl\mathrm{HCl} for complete reaction of Na2CO3\mathrm{Na}_2 \mathrm{CO}_3 is:
View answer and explanation
Correct option: A
2x2 x
Option A (2x2x) is correct because the volume of HCl required for complete reaction of Na2CO3 is twice the volume required to convert it to NaHCO3 using phenolphthalein.
64 Hard
64 of 77
Application +4 | -1
If mass percentage of sulphur in a biomolecule 0.02% then the number of sulphur atoms present in 16 g of biomolecule is
View answer and explanation
Correct option: B
6.02×10196.02 \times {10^{19}}
Option B (6.02×10196.02 \times {10^{19}}) is correct because it is calculated by finding the mass of sulfur and then converting it to the number of atoms.
65 Hard
65 of 77
Application +4 | -1
Mole fraction of the solute in a 1.001.00 molal aqueous solution is
View answer and explanation
Correct option: C
0.01770.0177
The correct answer is C (0.0177) because the mole fraction of the solute is calculated by dividing the moles of solute by the total moles in the solution.
66 Hard
66 of 77
Analyzing +4 | -1
3L mixture of O2(g){O}_2(\mathrm{g}) and N2(g){N}_2(\mathrm{g}) is passed through ozonizer. The gas mixture obtained contains O2,O3{O}_2, {O}_3 and N2{N}_2 gases only. This obtained mixture is passed through alkaline pyrogallol and then through turpentine oil, there were 1100 mL1100 \mathrm{~mL} and 600 mL600 \mathrm{~mL} volume contractions respectively. The volume of O2(g){O}_2(\mathrm{g}) and N2(g){N}_2(\mathrm{g}) in the original mixture respectively is
View answer and explanation
Correct option: D
2 L,1 L2 \mathrm{~L}, 1 \mathrm{~L}
Option D (2 L,1 L2 \mathrm{~L}, 1 \mathrm{~L}) is correct because the volume of O₂ is 2L and the volume of N₂ is 1L, calculated from the volume contractions after passing through alkaline pyrogallol and turpentine oil.
67 Hard
67 of 77
Analyzing +4 | -1
A quantity of 2.3 g2.3 \mathrm{~g} of a mixture of NO2\mathrm{NO}_2 and N2O4\mathrm{N}_2 \mathrm{O}_4 has a pressure of 0.82 atm0.82 \mathrm{~atm}, at temperature T K\text{T K} in a container of volume V\text{V} litres such that the ratio, T : V\text{T : V} is 300:1300: 1 in magnitude. What is the degree of dissociation of N2O4?\mathrm{N}_2 \mathrm{O}_4?
View answer and explanation
Correct option: B
0.33
Option B is correct because the degree of dissociation is calculated using the ideal gas law and the molar mass of the mixture.
68 Hard
68 of 77
Application +4 | -1
A 10 mg effervescent tablet containing sodium bicarbonate and oxalic acid releases 0.25 mL of CO2C{O_2} at T = 298.15 K and p=1p = 1 bar. If molar volume of CO2C{O_2} is 25.0 L under such condition, what is the percentage of sodium bicarbonate in each tablet?
[Molar mass of NaHCO3= 84  g  mol−1]NaHC{O_3} = \,84\,\,g\,\,mo{l^{ - 1}}]
View answer and explanation
Correct option: C
0.84
Option C (0.84) is correct because it is calculated by determining the moles of CO2 released and then using stoichiometry to find the mass percentage of sodium bicarbonate.
69 Hard
69 of 77
Application +4 | -1
A volume of 500 ml500 \mathrm{~ml} of a 0.1 M0.1 \mathrm{~M} solution of AgNO3{AgNO}_3 is added to 500 ml500 \mathrm{~ml} of 0.1 M0.1 \mathrm{~M} solution of KCl.{KCl}. The concentration of nitrate ion in the resulting solution is
View answer and explanation
Correct option: A
0.05 M0.05 \mathrm{~M}
Option A (0.05 M0.05 \mathrm{~M}) is correct because the concentration of nitrate ions is calculated by dividing the moles of nitrate by the total volume.
70 Hard
70 of 77
Application +4 | -1
Common salt obtained from sea-water contains 8.775%NaCl8.775 \% \mathrm{NaCl} by mass. The number of formula units of NaCl\mathrm{NaCl} present in 25 g25 \mathrm{~g} of this salt is :
View answer and explanation
Correct option: B
2.258×10222.258 \times 10^{22} formula units
Option B (2.258×10222.258 \times 10^{22} formula units) is correct because it is calculated by finding the mass of NaCl in the sample, converting it to moles, and then multiplying by Avogadro's number.
71 Hard
71 of 77
Application +4 | -1
Hydrazine N2H4{N}_2 {H}_4 (used as a fuel in rocket system) can be produced according to the following reaction.

ClNH2+2NH3→N2H4+NH4Cl{ClNH}_2+2 {NH}_3 \rightarrow {N}_2 {H}_4+{NH}_4 {Cl}

When 1.0 kg ClNH21.0 \mathrm{~kg} \, {ClNH}_2 is reacted with excess of NH3,{NH}_3, 473 g473 \mathrm{~g} of N2H4{N}_2 {H}_4 is produced. What is the percentage yield?
View answer and explanation
Correct option: A
76.12
Option A (76.12) is correct because the percentage yield is calculated by dividing the actual yield (473 g) by the theoretical yield (621.36 g) and multiplying by 100.
72 Hard
72 of 77
Application +4 | -1
A mixture contains FeSO4\mathrm{FeSO}_4 and Fe2(SO4)3.\mathrm{Fe}_2\left(\mathrm{SO}_4\right)_3. If both FeSO4\mathrm{FeSO}_4 and Fe2(SO4)3\mathrm{Fe}_2\left(\mathrm{SO}_4\right)_3 provide equal number of sulphate ions then, the ratio of Fe2+\mathrm{Fe}^{2+} and Fe3+\mathrm{Fe}^{3+} ions in mixture is
View answer and explanation
Correct option: D
3:23: 2
Option D (3:23: 2) is correct because the ratio of Fe²⁺ to Fe³⁺ ions is determined by the equal number of sulfate ions provided by FeSO₄ and Fe₂(SO₄)₃.
73 Hard
73 of 77
Application +4 | -1
If air contains N2{\mathrm{N}_2} and O2{\mathrm{O}_2} in volume ratio 4:14:1. The average vapour density of air is:
View answer and explanation
Correct option: C
14.4
Option C (14.4) is correct because the average vapor density is calculated from the average molecular weight of the air mixture, considering the volume ratio of nitrogen and oxygen.
74 Hard
74 of 77
Application +4 | -1
The ratio of masses of oxygen and nitrogen of a particular gaseous mixture is 1 : 4. The ratio of number of their molecule is
View answer and explanation
Correct option: B
0.313888889
Option B (07:32) is correct because the ratio of the number of molecules is equal to the ratio of the number of moles, which can be calculated from the given mass ratio and molar masses.
75 Hard
75 of 77
Application +4 | -1
21.75g of MnO2Mn{O_2} on reaction with HCl forms 2.8 L of Cl2(g)C{l_2}\left( g \right) at STP, the percentage purity of MnO2Mn{O_2} is (atomic mass of Mn = 55u)
MnO2+4HCl→MnCl2+Cl2+2H2OMn{O_2} + 4HCl \to MnC{l_2} + C{l_2} + 2{H_2}O
View answer and explanation
Correct option: D
0.5
Option D (0.5) is correct because the percentage purity is calculated by comparing the actual volume of Cl2 produced to the theoretical volume based on the amount of MnO2 used.
76 Hard
76 of 77
Application +4 | -1
A gaseous alkane is exploded with oxygen.
The volume of O2\text{O}_2 for complete combustion to
the volume of CO2\text{CO}_2 formed is in 7:47:4 ratio. The
molecular formula of alkane is
View answer and explanation
Correct option: C
C2H6{{\text{C}}_{2}}{{\text{H}}_{6}}
Option C (C2H6{{\text{C}}_{2}}{{\text{H}}_{6}}) is correct because the ratio of O2 volume to CO2 volume matches the stoichiometry of the combustion reaction for ethane.
77 Hard
77 of 77
Application +4 | -1
Boron has two isotopes boron-10 and boron-11 whose percentage abundances are 19.6%19.6 \% and 80.4%80.4 \% respectively. What is the average atomic mass of boron?
View answer and explanation
Correct option: A
10.804 amu
Option A (10.804 amu) is correct because the average atomic mass is calculated by summing the product of each isotope's mass and its fractional abundance.
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