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JEE • CHEMISTRY • SOME BASIC CONCEPTS OF CHEMISTRY

Some basic concepts of chemistry practice · Easy

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Showing 61-79 of 79 questions

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61 Easy
61 of 79
Remembering +4 | -1
The net charge on ferrous ion is:
View answer and explanation
Correct option: A
+2+ 2
Option A (+2+ 2) is correct because the ferrous ion is Fe2+\mathrm{Fe}^{2+}, indicating a +2 charge.
62 Easy
62 of 79
Remembering +4 | -1
Which represents per cent by weight?
View answer and explanation
Correct option: A
wt.  of  solutewt.  of  solution×100\frac{{\mathrm{wt}\mathrm{. }\;\mathrm{of}\;\mathrm{ solute}}}{{\mathrm{wt}\mathrm{. }\;\mathrm{of}\;\mathrm{ solution}}} \times 100
Option A is correct because percent by weight is defined as the weight of the solute divided by the weight of the solution, multiplied by 100.
63 Easy
63 of 79
Analyzing +4 | -1
An amount of 5 moles of A,\text{A,} 6 moles of B\text{B} and excess amount of C\mathrm{C} are mixed to produce a final product D\mathrm{D}, according to the following reactions.

A+2B→II+C→B+D\begin{aligned} & \mathrm{A}+2 \mathrm{B} \rightarrow \mathrm{I} \\ & \mathrm{I}+\mathrm{C} \rightarrow \mathrm{B}+\mathrm{D} \end{aligned}

What is the maximum moles of D,\mathrm{D}, which can be produced assuming that the products formed can also be reused in the reactions?
View answer and explanation
Correct option: C
5 moles
Option C (A is true but R is false) is correct because HBF4 is a strong acid, but the given reaction of B(OH)3 with HF doesn't explain why HBF4 is a strong acid.
64 Easy
64 of 79
Application +4 | -1
The volume occupied by one molecule of water (density 1  g  cm−31\;g\;\mathrm{c}{\mathrm{m}^-3} ) is:
View answer and explanation
Correct option: D
3.0×10−23  cm33.0 \times {10^{ - 23}}\;\mathrm{c}{\mathrm{m}^3}
Option D (3.0×10−23  cm33.0 \times {10^{ - 23}}\;\mathrm{c}{\mathrm{m}^3}) is correct because it is derived from dividing the molar volume of water by Avogadro's number.
65 Easy
65 of 79
Application +4 | -1
1 mole of methyl amine on reaction with nitrous acid gives at NTP
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Correct option: B
22.4 L of nitrogen
Option B is correct because 1 mole of methyl amine reacts with nitrous acid to produce 1 mole of nitrogen gas, which occupies 22.4 L at NTP.
66 Easy
66 of 79
Remembering +4 | -1
One mole of a gas is defined as:
View answer and explanation
Correct option: D
The number of molecules in 22.422.4 litre of a gas at STP
Option D (The number of molecules in 22.422.4 litre of a gas at STP) is correct because one mole of any gas occupies 22.4 liters at Standard Temperature and Pressure (STP).
67 Easy
67 of 79
Analyzing +4 | -1
Assertion : Equivalent weight of Cu{Cu} in CuO{CuO} is 63.6 and in Cu2O 31.8{Cu}_2 {O} \,31.8.

Reason : Equivalent weight of an element = Atomic weight of the element  Valency of the element =\frac{\text { Atomic weight of the element }}{\text { Valency of the element }}
View answer and explanation
Correct option: D
If assertion is false but reason is true.
Option D (If assertion is false but reason is true) is correct because the assertion incorrectly states the equivalent weight of Cu in both CuO and Cu2O, while the reason correctly defines equivalent weight.
68 Easy
68 of 79
Analyzing +4 | -1
Assertion : A certain element XX, forms three binary compounds with chlorine containing 59.68%,68.95%59.68 \%, 68.95 \% and 74.75%74.75 \% chlorine respectively. These data illustrate the law of multiple proportions.

Reason : According to law of multiple proportions, the relative amounts of an element combining with some fixed amount of a second element in a series of compounds are the ratios of small whole numbers.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
The correct answer is A (If both assertion and reason are true and the reason is the correct explanation of the assertion) because the law of multiple proportions explains the fixed ratios in which elements combine.
69 Easy
69 of 79
Application +4 | -1
The number of moles of Hydrogen molecules required to produce 20 moles of NH3N{H_3} through Haber’s process
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Correct option: D
30
Option D (30) is correct because the balanced Haber's process equation shows that 3 moles of hydrogen are required for every 2 moles of ammonia produced.
70 Easy
70 of 79
Application +4 | -1
A compound having the empirical formula, C3H4O\mathrm{C}_3 \mathrm{H}_4 \mathrm{O} has a molecular weight of 170±5.170 \pm 5. The molecular formula of the compound is
View answer and explanation
Correct option: D
C9H12O3\mathrm{C}_9 \mathrm{H}_{12} \mathrm{O}_3
Option D (C9H12O3\mathrm{C}_9 \mathrm{H}_{12} \mathrm{O}_3) is correct because the molecular formula is a multiple of the empirical formula, with the multiplier determined by the molecular weight.
71 Easy
71 of 79
Application +4 | -1
Number of Zn{Zn} atoms present in 122 g122 {~g} of ZnO{ZnO} is (Atomic wt. of Zn=65{Zn}=65 )
View answer and explanation
Correct option: C
3NA2\frac{3 N_A}{2}
Option C (3NA2\frac{3 N_A}{2}) is correct because 122 g of ZnO corresponds to 1.5 moles of Zn, which is 1.5 times Avogadro's number.
72 Easy
72 of 79
Application +4 | -1
A compound has an empirical formula C2H4O\mathrm{C}_2 \mathrm{H}_4 \mathrm{O}. An independent analysis gave a value of 132.16 for its molecular mass. What is the correct molecular formula?
View answer and explanation
Correct option: D
C6H12O3\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_3
The correct answer is C6H12O3\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_3. The molecular formula is a multiple of the empirical formula, determined by the ratio of molecular mass to empirical formula mass.
73 Easy
73 of 79
Application +4 | -1
A sample of hydrogen gas is collected and it is observed that it contains only hydrogen and deuterium atoms in the atomic ratio 6000:1.6000: 1. The number of neutrons in 3.0 g3.0 \mathrm{~g} of such a sample should be nearly
View answer and explanation
Correct option: B
3.01×10203.01 \times 10^{20}
Option B (3.01×10203.01 \times 10^{20}) is correct because it calculates the approximate number of neutrons present in the deuterium atoms within the given sample of hydrogen gas.
74 Easy
74 of 79
Application +4 | -1
The chloride of a metal contains 52.8%52.8 \% chlorine by mass. The equivalent weight of metal is
View answer and explanation
Correct option: A
31.7
Option A (31.7) is correct because the equivalent weight of the metal can be calculated using the percentage of chlorine in the metal chloride.
75 Easy
75 of 79
Understanding +4 | -1
The quantity which changes with temperature is 
View answer and explanation
Correct option: C
Molarity
Option C is correct because molarity is defined as moles of solute per liter of solution, and the volume of a solution changes with temperature, thus affecting molarity.
76 Easy
76 of 79
Application +4 | -1
What is the percentage of carbon in calcium carbide (CaC2)(Ca{C_2})
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Correct option: A
37.5
Option A (37.5) is correct because the percentage of carbon in calcium carbide is calculated by dividing the mass of carbon by the molecular mass of calcium carbide and multiplying by 100.
77 Easy
77 of 79
Application +4 | -1
If H2SO4{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} ionises as H2SO4+2H2O→2H3O++SO42{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} + 2{\mathrm{H}_2}\mathrm{O} \to 2{\mathrm{H}_3}{\mathrm{O}^ + } + \mathrm{SO}_4^2, then total number of ions produced by 0.1  M  H2SO4\mathrm{0}\mathrm{.1}\;\mathrm{M}\;{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} will be
View answer and explanation
Correct option: D
1.8×10231.8 \times {10^{23}}
Option D (1.8×10231.8 \times {10^{23}}) is correct because 0.1 M H2SO4H_2SO_4 produces 0.3 M ions, which translates to 1.8×10231.8 \times {10^{23}} ions.
78 Easy
78 of 79
Remembering +4 | -1
The molecular mass of CaSO4⋅2H2O\mathrm{CaSO}_4 \cdot 2 \mathrm{H}_2 \mathrm{O} is

(At. mass of Ca = 40, S = 32)
View answer and explanation
Correct option: C
172 u
Option C (172 u) is correct because the molecular mass is calculated by summing the atomic masses of all atoms in the formula.
79 Easy
79 of 79
Application +4 | -1
Dopamine is a neurotransmitter, a molecule that serves to transmit message in the brain. The chemical formula of dopamine is C8H11O2 N.\mathrm{C}_8 \mathrm{H}_{11} \mathrm{O}_2 \mathrm{~N}. How many moles are there in 1 g1 \mathrm{~g} of dopamine?
View answer and explanation
Correct option: A
0.006540.00654
Option A (0.00654) is correct because it is calculated by dividing the given mass by the molar mass of dopamine.
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