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JEE • CHEMISTRY • SOME BASIC CONCEPTS OF CHEMISTRY

Some basic concepts of chemistry practice · Mixed difficulty

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Showing 361-390 of 436 questions

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361 Medium
361 of 436
Understanding +4 | -1
The molar solution of H2SO4H_2SO_4 is equal to :
View answer and explanation
Correct option: A
N/2 solution
Option A (N/2 solution) is correct because the molarity of H2SO4 is half its normality since it is a dibasic acid with two replaceable hydrogen atoms.
362 Medium
362 of 436
Analyzing +4 | -1
Assertion (A) : 20g20 \mathrm{g} of 50%50 \% pure CaCO3\mathrm{CaCO}_3 on heating gave 2.24 L CO2\mathrm{CO}_2 at STP and 15.6 g15.6 \mathrm{~g} non-volatile residue.

CaCO3⟶ΔCaO+CO2\mathrm{CaCO}_3 \stackrel{\Delta}{\longrightarrow} \mathrm{CaO}+\mathrm{CO}_2
Reason (R): Pure CaCO3\mathrm{CaCO}_3 is 10 g10 \mathrm{~g} which gave 4.4 g4.4 \mathrm{~g} CO2(=0.1 mol=2.24 L\mathrm{CO}_2(=0.1 \mathrm{~mol}=2.24 \mathrm{~L} at STP )) and 15.6 g15.6 \mathrm{~g} residue is left.
View answer and explanation
Correct option: A
Both A\mathbf{A} and R\mathbf{R} are true and R\mathbf{R} is the correct explanation of A\mathbf{A}.
The correct answer is A because both the assertion and the reason are true, and the reason correctly explains why the given amount of impure CaCO3 produces 2.24 L of CO2 at STP.
363 Easy
363 of 436
Application +4 | -1
Number of Zn{Zn} atoms present in 122 g122 {~g} of ZnO{ZnO} is (Atomic wt. of Zn=65{Zn}=65 )
View answer and explanation
Correct option: C
3NA2\frac{3 N_A}{2}
Option C (3NA2\frac{3 N_A}{2}) is correct because 122 g of ZnO corresponds to 1.5 moles of Zn, which is 1.5 times Avogadro's number.
364 Medium
364 of 436
Application +4 | -1
0.20.2 g of a sample of H2O2{\mathrm{H}_2}{\mathrm{O}_2} required 1010 mL of NKMnO4N\mathrm{KMn}{\mathrm{O}_4} in a titration in the presence of H2SO4.{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}\mathrm{.}. Purity of H2O2{\mathrm{H}_2}{\mathrm{O}_2} is :
View answer and explanation
Correct option: B
85%85\%
Option B (85%85\%) is correct because the purity is calculated by determining the mass of H2O2 that reacted with KMnO4 and then finding the percentage of that mass in the original sample.
365 Medium
365 of 436
Application +4 | -1
The moles of K2Cr2O7\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 are required to react completely with 2.4 mol2.4 \mathrm{~mol} of CuS\mathrm{CuS} in hot acidic medium
View answer and explanation
Correct option: B
3.23.2
Option B (3.2) is correct because the number of moles of K2Cr2O7 required is calculated using the n-factor method, equating the equivalents of K2Cr2O7 and CuS.
366 Medium
366 of 436
Analyzing +4 | -1
Assertion: Components of a homogeneous mixture cannot be separated by using physical methods.

Reason: Composition of homogeneous mixture is uniform throughout as the components react to form a single compound.
View answer and explanation
Correct option: D
If both assertion and reason is false
Option D (If both assertion and reason is false) is correct because components of a homogeneous mixture can be separated by physical methods, and the components do not react to form a single compound.
367 Medium
367 of 436
Application +4 | -1
What volume of 0.1 MKMnO4M\mathrm{KMn}{\mathrm{O}_4} is needed to oxidise 100 mg of FeC2O4\mathrm{Fe}{\mathrm{C}_2}{\mathrm{O}_4} in acidic solution?
View answer and explanation
Correct option: A
4.1 mL
Option A (4.1 mL) is correct because the volume of KMnO4 needed is calculated by equating the milliequivalents of KMnO4 and FeC2O4.
368 Medium
368 of 436
Analyzing +4 | -1
0.10.1 mole 3POx_3 \mathrm{PO}_x is completely neutralised by 5.6 g KOH5.6 \mathrm{~g} \mathrm{~KOH} then the true statement is:
View answer and explanation
Correct option: C
x=2x=2 and given acid does not form acid salt
The correct answer is C (x=2x=2 and given acid does not form acid salt) because the neutralization reaction requires 0.1 mole of KOH to neutralize 0.1 mole of H3POx, indicating a monobasic acid.
369 Medium
369 of 436
Application +4 | -1
The percentage by volume of C3H8\mathrm{C}_3 \mathrm{H}_8 in a mixture of C3H8,CH4\mathrm{C}_3 \mathrm{H}_8, \mathrm{CH}_4 and CO\mathrm{CO} is 36.5.36.5. The volume of CO2\mathrm{CO}_2 produced when 100 ml100 \mathrm{~ml} of the mixture is burnt in excess of O2\mathrm{O}_2 is
View answer and explanation
Correct option: B
173 ml173 \mathrm{~ml}
Option B (173 ml173 \mathrm{~ml}) is correct because the total volume of CO2 produced is the sum of the CO2 from propane and methane combustion.
370 Medium
370 of 436
Analyzing +4 | -1
Statement I: Molecular mass of cane sugar (C12H22O11)\left( {{C_{12}}{H_{22}}{O_{11}}} \right) is 182 amu182 \, \text{amu}

Statement II: Mole of cane sugar contains 6.022×10236.022 \times 10^{23} molecules of cane sugar.
View answer and explanation
Correct option: D
Statement II is correct but statement I is incorrect
The correct answer is D (Statement II is correct but statement I is incorrect) because the molecular mass of cane sugar is 342 amu, and one mole contains Avogadro's number of molecules.
371 Medium
371 of 436
Analyzing +4 | -1
Assertion: H3BO3\mathrm{H}_3 \mathrm{BO}_3 is monobasic Lewis acid but salt Na3BO3\mathrm{Na}_3 \mathrm{BO}_3 exist.
Reason: H3BO3\mathrm{H}_3 \mathrm{BO}_3 reacts with NaOH\mathrm{NaOH} to give Na3BO3\mathrm{Na}_3 \mathrm{BO}_3.
View answer and explanation
Correct option: A
Assertion is correct but Reason is wrong
Option A (Assertion is correct but Reason is wrong) is correct because boric acid is a monobasic Lewis acid, and sodium borate exists, but boric acid doesn't react with NaOH to directly give Na3BO3.
372 Hard
372 of 436
Application +4 | -1
If mass percentage of sulphur in a biomolecule 0.02% then the number of sulphur atoms present in 16 g of biomolecule is
View answer and explanation
Correct option: B
6.02×10196.02 \times {10^{19}}
Option B (6.02×10196.02 \times {10^{19}}) is correct because it is calculated by finding the mass of sulfur and then converting it to the number of atoms.
373 Easy
373 of 436
Application +4 | -1
A compound has an empirical formula C2H4O\mathrm{C}_2 \mathrm{H}_4 \mathrm{O}. An independent analysis gave a value of 132.16 for its molecular mass. What is the correct molecular formula?
View answer and explanation
Correct option: D
C6H12O3\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_3
The correct answer is C6H12O3\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_3. The molecular formula is a multiple of the empirical formula, determined by the ratio of molecular mass to empirical formula mass.
374 Easy
374 of 436
Application +4 | -1
A sample of hydrogen gas is collected and it is observed that it contains only hydrogen and deuterium atoms in the atomic ratio 6000:1.6000: 1. The number of neutrons in 3.0 g3.0 \mathrm{~g} of such a sample should be nearly
View answer and explanation
Correct option: B
3.01×10203.01 \times 10^{20}
Option B (3.01×10203.01 \times 10^{20}) is correct because it calculates the approximate number of neutrons present in the deuterium atoms within the given sample of hydrogen gas.
375 Medium
375 of 436
Application +4 | -1
Total no. of electrons present in 48 g Mg2+48 \mathrm{~g} \mathrm{~Mg}^{2+} are:
View answer and explanation
Correct option: C
20NA20 N_A
Option C (20NA20 N_A) is correct because it accurately calculates the total number of electrons in 48g of Mg2+ considering the electronic configuration of Mg2+.
376 Medium
376 of 436
Application +4 | -1
10 gCaCO310 \mathrm{~g} \mathrm{CaCO}_3 were dissolved in 250 mL250 \mathrm{~mL} of 100M100 \mathrm{M} HCl\mathrm{HCl} or the solution was boiled. What volume of 2MKOH2 \mathrm{M} \mathrm{KOH} would be required to equivalence point after boiling? Assume no change in volume during boiling.
View answer and explanation
Correct option: B
25 mL25 \mathrm{~mL}
Option B (25 mL) is correct because it is the volume of KOH required to neutralize the remaining HCl after the reaction with CaCO₃.
377 Hard
377 of 436
Application +4 | -1
Mole fraction of the solute in a 1.001.00 molal aqueous solution is
View answer and explanation
Correct option: C
0.01770.0177
The correct answer is C (0.0177) because the mole fraction of the solute is calculated by dividing the moles of solute by the total moles in the solution.
378 Hard
378 of 436
Analyzing +4 | -1
3L mixture of O2(g){O}_2(\mathrm{g}) and N2(g){N}_2(\mathrm{g}) is passed through ozonizer. The gas mixture obtained contains O2,O3{O}_2, {O}_3 and N2{N}_2 gases only. This obtained mixture is passed through alkaline pyrogallol and then through turpentine oil, there were 1100 mL1100 \mathrm{~mL} and 600 mL600 \mathrm{~mL} volume contractions respectively. The volume of O2(g){O}_2(\mathrm{g}) and N2(g){N}_2(\mathrm{g}) in the original mixture respectively is
View answer and explanation
Correct option: D
2 L,1 L2 \mathrm{~L}, 1 \mathrm{~L}
Option D (2 L,1 L2 \mathrm{~L}, 1 \mathrm{~L}) is correct because the volume of O₂ is 2L and the volume of N₂ is 1L, calculated from the volume contractions after passing through alkaline pyrogallol and turpentine oil.
379 Medium
379 of 436
Application +4 | -1
The mole fraction of CH3OH\mathrm{CH}_3 \mathrm{OH} in its 32% (w/w)32 \% \,(\mathrm{w} / \mathrm{w}) aqueous solution is nearly
View answer and explanation
Correct option: C
0.210.21
Option C (0.21) is correct because the mole fraction is calculated by dividing the moles of methanol by the total moles of the solution.
380 Medium
380 of 436
Application +4 | -1
5000 mL5000 \mathrm{~mL} of 0.6 M H2SO40.6 \mathrm{~M} \mathrm{~H}_2 \mathrm{SO}_4 acid is mixed with 2 L2 \mathrm{~L} of 98% (w / V) of H2SO4\mathrm{H}_2 \mathrm{SO}_4 (specific gravity 1.84). If the specific gravity of the resulting mixture is 1.4, what is the molarity of the mixture? (Given that the specific gravity of 0.6 M H2SO40.6 \mathrm{~M} \mathrm{~H}_2 \mathrm{SO}_4 is 1.02 and also consider there is no loss of mass due to mixing.)
View answer and explanation
Correct option: B
3.6674 M3.6674 \mathrm{~M}
Option B (3.6674 M3.6674 \mathrm{~M}) is correct because it is calculated using the total moles of H2SO4 and the total volume of the mixture.
381 Medium
381 of 436
Analyzing +4 | -1
Statement I: When a hydrocarbon is burnt and the products of combustion are cooled to the original temperature and pressure, a contraction in volume occurs.

Statement II: The contraction in volume is solely due to the liquefaction of water vapours.
View answer and explanation
Correct option: C
If Statement I is CORRECT, but Statement II is INCORRECT
Option C is correct. Statement I is correct because combustion of hydrocarbons usually results in a contraction in volume. Statement II is incorrect because the contraction is due to the change in the number of moles of gaseous substances, not solely the liquefaction of water.
382 Medium
382 of 436
Analyzing +4 | -1
Which of the following pairs contains equal number of atoms?
View answer and explanation
Correct option: A
11.2 cc (STP) of nitrogen and 0.015 g of nitric oxide
The correct answer is A because both 11.2 cc of nitrogen and 0.015 g of nitric oxide contain the same number of atoms.
383 Medium
383 of 436
Analyzing +4 | -1
Maximum magnitude of work done is obtained during the hydrolysis of 1 mol1 \mathrm{~mol} of
View answer and explanation
Correct option: A
Al4C3\mathrm{Al}_4 \mathrm{C}_3
Option A (Al4C3) is correct because its hydrolysis produces the largest volume of gas (methane), resulting in the maximum magnitude of work done.
384 Medium
384 of 436
Application +4 | -1
A compound contains 90 % C and 10 % H. The empirical formula of the compound is
View answer and explanation
Correct option: C
C3H4{C_3}{H_4}
Option C (C3H4{C_3}{H_4}) is correct because it represents the simplest whole-number ratio of carbon to hydrogen atoms based on the given percentages.
385 Medium
385 of 436
Analyzing +4 | -1
Which of the following has greatest no. of atoms
View answer and explanation
Correct option: A
1g of butane (C4H10)({C_4}{H_{10}})
Option A (1g of butane (C4H10)({C_4}{H_{10}})) is correct because it has the highest number of atoms due to its lower molar mass and higher atomicity compared to the other options.
386 Medium
386 of 436
Analyzing +4 | -1
A gas mixture contains CH4\mathrm{CH}_4 and C3H6.\mathrm{C}_3 \mathrm{H}_6. When this mixture undergo cracking into C(s)\mathrm{C}(\mathrm{s}) and H2(g),\mathrm{H}_2(\mathrm{g}), the total number of moles of H2(g)\mathrm{H}_2(\mathrm{g}) obtained is 42. If the total volume of the initial gas mixture at 1.5 atm1.5 \mathrm{~atm} and 27∘C27^{\circ} \mathrm{C} is 246.0 L,246.0 \mathrm{~L}, then what is the mole per cent of CH4\mathrm{CH}_4 gas in the initial mixture?
View answer and explanation
Correct option: A
20%20 \%
Option A (20%) is correct because by setting up and solving a system of equations based on the cracking reactions and the ideal gas law, the mole percent of CH4 is found to be 20%.
387 Medium
387 of 436
Understanding +4 | -1
Statement I : 1 mole of H2SO4{H_2}S{O_4} is neutralised by 2 mol of NaOH but 1 equivalent of H2SO4{H_2}S{O_4} is neutralised by 1 equivalent of NaOH
Statement II : Equivalent amount of H2SO4{H_2}S{O_4} is the quantity that is equal to 1 g H and hence, each mol of H2SO4{H_2}S{O_4} is equal to 2 equivalents of H2SO4{H_2}S{O_4}
Which statement(s) is/are correct ?
View answer and explanation
Correct option: C
Both I and II
Option C (Both I and II) is correct because 1 mole of H2SO4 requires 2 moles of NaOH for neutralization, and the equivalent amount of H2SO4 is indeed the quantity that is equal to 1 g H, meaning each mole of H2SO4 is equal to 2 equivalents.
388 Medium
388 of 436
Application +4 | -1
The total number of valence electrons in 33.6 g N3−33.6 \mathrm{~g} \mathrm{~N}_3^{-} ion is
View answer and explanation
Correct option: C
12.8 NA12.8 \mathrm{~N}_{\mathrm{A}}
The correct answer is 12.8 NA because the total number of valence electrons in 33.6 g of N3- ion is 12.8 times Avogadro's number, calculated based on the molar mass and valence electrons of N3-.
389 Medium
389 of 436
Application +4 | -1
The strengths of 5.6 volume hydrogen peroxide (of density 1 g/mL ) in terms of mass percentage and molarity (M),(M), respectively are (Take molar mass of hydrogen peroxide as 34 g/mol
View answer and explanation
Correct option: C
1.7 and 0.5
Option C (1.7 and 0.5) is correct because the mass percentage and molarity are correctly calculated based on the volume strength of hydrogen peroxide.
390 Medium
390 of 436
Application +4 | -1
For the reaction, 2Fe3++Sn2+→2Fe2++Sn4+2\mathrm{F}{\mathrm{e}^{3 + }} + \mathrm{S}{\mathrm{n}^{2 + }} \to 2\mathrm{F}{\mathrm{e}^{2 + }} + \mathrm{S}{\mathrm{n}^{4 + }} The normality of SnCl2\mathrm{SnC}{\mathrm{l}_2} (mol.wt. = 189.7) solution prepared by dissolving 47.5 g in acid solution and diluting with H2O{\mathrm{H}_2}\mathrm{O} to a total of 2.25 litre is :
View answer and explanation
Correct option: A
0.222NN
Option A (0.222NN) is correct because the normality is calculated by dividing the given mass by the equivalent weight and the volume of the solution.
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Review SOME BASIC CONCEPTS OF CHEMISTRY in your textbook or class notes, then use this set to check your understanding.

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