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JEE • CHEMISTRY • SOLUTIONS

Solutions practice · Medium

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91 Medium
91 of 265
Application +4 | -1
A solution containing 8.6 g8.6 \mathrm{~g} urea in one litre was found to be isotonic with a 5%5 \% (mass/volume) solution of an organic non-volatile solute. The molar mass of solute is;
View answer and explanation
Correct option: A
348.83
Option A (348.83) is correct because it is the molar mass of the solute calculated using the isotonic condition and the given concentrations.
92 Medium
92 of 265
Application +4 | -1
What weight of hydrated oxalic acid should be added for complete neutralisation of 100 ml100 \,{ml} of 0.2 N−NaOH0.2 {~N}-{NaOH} solution?
View answer and explanation
Correct option: D
1.26 g1.26 {~g}
Option D (1.26 g1.26 {~g}) is correct because it is the mass of hydrated oxalic acid required for complete neutralization, calculated using the concept of equivalents.
93 Medium
93 of 265
Application +4 | -1
On dissolving 0.5 g0.5 {~g} of a non-volatile non-ionic solute to 39 g39 {~g} of benzene, its vapour pressure decreases from 650 mmHg650 {~mm} {Hg} to 640 mmHg640 {~mm} {Hg}. The depression of freezing point of benzene (in K) upon addition of the solute is..... K.
(Given data : Molar mass and the molal freezing point depression constant of benzene are 78 g mol−178 {~g} {~mol}^{-1} and 5.12 K kg mol−15.12 {~K} {~kg} {~mol}^{-1}, respectively)
View answer and explanation
Correct option: A
1.03
Option A (1.03) is correct because it's the freezing point depression calculated using the colligative properties formula and the given data.
94 Medium
94 of 265
Analyzing +4 | -1
Which of the following mixture of solutions follow the condition Δmix H<0\Delta_{\text {mix }} H<0 and Δmix V<0\Delta_{\text {mix }} V<0 ?

(i) Nitric acid + Water

(ii) Acetic acid + Pyridine

(iii) Ethanol + Water

(iv) Carbon tetra chloride + Chloroform
View answer and explanation
Correct option: D
(i) & (ii) only
The correct answer is D ((i) & (ii) only) because nitric acid + water and acetic acid + pyridine mixtures exhibit negative enthalpy and volume changes upon mixing.
95 Medium
95 of 265
Application +4 | -1
KspK_{s p} (solubility product) of MgS=(Mg2+(S2−))\mathrm{MgS}=\left(\mathrm{Mg}^{2+}\left(\mathrm{S}^{2-}\right)\right) is 1.0×10−61.0 \times 10^{-6}. Thus, elevation in boiling point of saturated solution is (Kb=0.52∘mol−1 kg)\left(K_b=0.52^{\circ} \mathrm{mol}^{-1} \mathrm{~kg}\right)
View answer and explanation
Correct option: D
5.2×10−4 K5.2 \times 10^{-4} \mathrm{~K}
Option D (5.2×10−4 K5.2 \times 10^{-4} \mathrm{~K}) is correct because it's calculated by finding the solubility from Ksp and then using the elevation in boiling point formula.
96 Medium
96 of 265
Remembering +4 | -1
Among the following, the azeotropic mixture is
View answer and explanation
Correct option: A
CCl4+CHCl3\mathrm{CCl}_4+\mathrm{CHCl}_3
Option A (CCl4+CHCl3\mathrm{CCl}_4+\mathrm{CHCl}_3) is correct because CCl4\mathrm{CCl}_4 and CHCl3\mathrm{CHCl}_3 form a non-ideal solution and can exhibit azeotropic behavior.
97 Medium
97 of 265
Analyzing +4 | -1
Assertion : Camphor is used as solvent in the determination of molecular masses of naphthalene, anthracene etc.

Reason : Camphor has high molal elevation constant.
View answer and explanation
Correct option: C
If assertion is true but reason is false.
The correct answer is C because camphor is indeed used as a solvent for molecular mass determination due to its high molal depression constant, not elevation constant.
98 Medium
98 of 265
Analyzing +4 | -1
Consider the following statements about osmotic pressure method of molar mass determination.

I. Molarity of the solution is used instead of molality.

II. Magnitude of osmotic pressure is very large even for dilute solutions.

III. Molar mass of biomolecules can be determined as they are not stable at higher temperatures.

IV. Determine the molar mass of polymer as they have poor solubility.

Which of the above statements are responsible for advantage of osmotic pressure for determination of molar mass over the other colligative properties?
View answer and explanation
Correct option: C
I, II, III and IV
Option C (I, II, III and IV) is correct because all the listed statements contribute to the advantages of using osmotic pressure for molar mass determination.
99 Medium
99 of 265
Analyzing +4 | -1
Assertion (A) : Addition of solvent to a solution always lowers the V.P.

Reason (R) : The increase in relative surface area give rise to an increase in V.P. for a given solution.
View answer and explanation
Correct option: B
Assertion is Wrong but Reason is correct
Option B is correct. Adding a solvent to a solution *increases* the vapor pressure, not lowers it. The reason is correct because increasing the relative surface area allows more solvent molecules to escape into the vapor phase.
100 Medium
100 of 265
Application +4 | -1
The vapour pressure of acetone at 20∘C20^\circ C is 185 torr. When 1.2 g of a non – volatile substance was dissolved in 100 g of acetone at 20∘C,20^\circ C, its vapour pressure was 183 torr. The molar mass (g  mol−1)(\mathrm{g}\,\,\mathrm{mo}{\mathrm{l}^{ - 1}}) of the substance is
View answer and explanation
Correct option: B
64
The correct answer is 64 because the molar mass of the non-volatile substance is approximately 64 g/mol, calculated using Raoult's Law for vapor pressure lowering.
101 Medium
101 of 265
Analyzing +4 | -1
Assertion: The molarity and normality of a solution of sodium carbonate are same.
Reason: Molarity is the product of normality &amp; valency factor.
View answer and explanation
Correct option: D
If both Assertion &amp; Reason are false
The correct answer is If both Assertion & Reason are false because the molarity and normality of sodium carbonate are different, and molarity is not the product of normality and valency factor.
102 Medium
102 of 265
Application +4 | -1
How much water is needed to dilute 10 ml10 {~ml} of 10 N10 {~N} hydrochloric acid to make it exactly decinormal (0.1 N)(0.1 {~N})
View answer and explanation
Correct option: A
990 ml990 \,{ml}
Option A (990 mL) is correct because it is calculated using the dilution formula N1V1=N2V2N_1V_1 = N_2V_2 and then subtracting the initial volume.
103 Medium
103 of 265
Application +4 | -1
Vapour pressure of pure water at 298 K298 \mathrm{~K} is 23.8 mm23.8 \mathrm{~mm}. Thus, vapour pressure of 20%20 \% glucose (weight/volume) solution is (d=0.9971 g mL−1)\left(d=0.9971 \mathrm{~g} \mathrm{~mL}^{-1}\right)
View answer and explanation
Correct option: D
23.217 mm23.217 \mathrm{~mm}
Option D (23.217 mm23.217 \mathrm{~mm}) is correct because it uses Raoult's law to accurately calculate the vapor pressure lowering of the solution.
104 Medium
104 of 265
Application +4 | -1
The freezing point of a solution containing 0.2 g0.2 \mathrm{~g} of acetic acid in 20.0 g20.0 \mathrm{~g} benzene is lowered by 0.45∘C0.45^{\circ} \mathrm{C}. The degree of association of acetic acid in benzene is (Assume acetic acid dimerises in benzene and Kf\mathrm{K}_{\mathrm{f}} for benzene =5.12 K kg mol−1=5.12 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1})
Mobserved\mathrm{M}_{\text {observed}} of acetic acid =113.78=113.78
View answer and explanation
Correct option: A
94.5%94.5 \%
Option A (94.5%94.5 \%) is correct because the degree of association is calculated using the van't Hoff factor and the observed molar mass.
105 Medium
105 of 265
Application +4 | -1
The amount of K2Cr2O7{K}_2 {Cr}_2 {O}_7 (eq. wt. 49.04) required to prepare 100 ml {ml}\, of its 0.05 N0.05 {~N} solution is
View answer and explanation
Correct option: D
0.2452 g0.2452 {~g}
Option D (0.2452 g0.2452 {~g}) is correct because it is the amount of K2Cr2O7 required to prepare 100 ml of 0.05 N solution, calculated using the normality equation.
106 Medium
106 of 265
Analyzing +4 | -1
The amino acid alanine has two isomers, such as
α−alanine\alpha-\text{alanine} and β−alanine.\beta-\text{alanine}. When equal masses of
these two compounds are dissolved in equal mass
of a solvent, the solution of α−alanine\alpha-\text{alanine} freezes at
relatively lower temperature. Which forms of
α−alanine\alpha-\text{alanine} or β−alanine\beta-\text{alanine}, has the larger equilibrium
constant for ionization?
View answer and explanation
Correct option: A
α−alanine\alpha-\text{alanine}
Option A (α−alanine\alpha-\text{alanine}) is correct because a lower freezing point indicates a greater number of particles in solution, implying a larger equilibrium constant for ionization.
107 Medium
107 of 265
Analyzing +4 | -1
S-I: The boiling point of 0.1 M0.1 \, \mathrm{M} urea solution is less than that of 0.1 M KCl0.1 \, \mathrm{M} \, {KCl} solution.

S-II: Elevation of boiling point is directly proportional to the number of moles of non-volatile solute particles present in the solution.
View answer and explanation
Correct option: A
Both S-I and S-II are correct
Option A (Both S-I and S-II are correct) is correct because the boiling point elevation depends on the number of solute particles, and KCl dissociates into more particles than urea.
108 Medium
108 of 265
Application +4 | -1
The molarity of 24.5%24.5 \% (w/w) H2SO4\mathrm{H}_2 \mathrm{SO}_4 solution having density 1.2 g/ml1.2 \mathrm{~g} / \mathrm{ml} is
View answer and explanation
Correct option: B
3 M3 \mathrm{~M}
Option B (3 M) is correct because molarity is calculated using the formula Molarity = (x * d * 10) / M, where x is the percentage by weight, d is the density, and M is the molecular weight.
109 Medium
109 of 265
Application +4 | -1
Which of the following aqueous solution has minimum freezing point?
View answer and explanation
Correct option: B
0.05 m0.05 \mathrm{~m} glucose
Option B (0.05 m0.05 \mathrm{~m} glucose) is correct because a higher effective molality of solute results in a lower freezing point, and glucose does not dissociate.
110 Medium
110 of 265
Application +4 | -1
If the mass percentage (w/w)({w} / {w}) of urea in aqueous solution is 18%18 \% then the molality of the solution is
View answer and explanation
Correct option: D
3.66  m3.66\, {~m}
Option D (3.66 m) is correct because it is the molality calculated from the given mass percentage of urea in the aqueous solution.
111 Medium
111 of 265
Application +4 | -1
Percentage ionization of K3[Fe(CN)6]{K_3}\left[ {Fe{{\left( {CN} \right)}_6}} \right] whose decimolar solution shows an osmotic pressure of 3.94 atm at 300 K is
View answer and explanation
Correct option: C
0.2
Option C (0.2) is incorrect, the correct answer is 20% ionization. The percentage ionization is calculated using the osmotic pressure and Van't Hoff factor.
112 Medium
112 of 265
Application +4 | -1
A certain substance ‘A’ tetramerises in water to the extent of 80%. A solution of 2.5 g of A in 100 g of water lowers the freezing point by 0.3∘C0.3^\circ C. The molar mass of A is
View answer and explanation
Correct option: B
62
Option B (62) is correct because the molar mass is calculated using the colligative property formula for freezing point depression, accounting for the tetramerization of the substance.
113 Medium
113 of 265
Understanding +4 | -1
Osmotic pressure present in the fluid inside the blood cell is equivalent to
View answer and explanation
Correct option: A
0.9%( m/V)NaCl0.9 \%(\mathrm{~m} / V) \mathrm{NaCl} solution
Option A (0.9%( m/V)NaCl0.9 \%(\mathrm{~m} / V) \mathrm{NaCl} solution) is correct because the osmotic pressure of the fluid inside blood cells is isotonic with a 0.9% (m/V) NaCl solution, also known as normal saline.
114 Medium
114 of 265
Application +4 | -1
Mixture of 1 mol1 \mathrm{~mol} benzene (pbenzene∘=42 mm)(p_{\text {benzene}}^{\circ}=42 \mathrm{~mm}) and 2 mol2 \mathrm{~mol} toluene (ptoluene∘=36 mm)\left(p_{\text {toluene}}^\circ=36 \mathrm{~mm}\right) will have
View answer and explanation
Correct option: D
All of the above
The correct answer is 6 because it accurately calculates the number of alcoholic hydrogens based on the volume of hydrogen gas produced at STP.
115 Medium
115 of 265
Analyzing +4 | -1
Which of the following is incorrect?
View answer and explanation
Correct option: C
0.1 m ethanol
Option C (0.1 m ethanol) is correct because ethanol dissociates into ions, leading to a higher number of particles and thus a greater colligative effect compared to the other non-electrolyte solutions.
116 Medium
116 of 265
Application +4 | -1
The vapour pressure of water is 12.3 kPa at 300 K.
What is the vapour pressure of 1 molal aqueous
solution of a non- volatile solute at 300 K?
View answer and explanation
Correct option: B
12.08 kPa
Option B (12.08 kPa) is correct because it is the vapor pressure calculated using Raoult's Law for a non-volatile solute.
117 Medium
117 of 265
Application +4 | -1
The density (in  g  m  L−1)\left( {i\mathrm{n}\;\mathrm{ g}\;\mathrm{m}\;{\mathrm{L}^{ - 1}}} \right) of a 3.60  M{3.60\;M} sulphuric acid solution that is 29  %  H2SO4(molar  mass=98  g  mol−1)29\;\% \;{H_2}S{O_4}\left( {\mathrm{molar}\;\mathrm{ mass} = 98\;\mathrm{g}\;\mathrm{mo}{\mathrm{l}^{ - 1}}} \right) by mass will be
View answer and explanation
Correct option: C
1.22
Option C (1.22) is correct because using the molarity formula, the density of the solution is calculated to be approximately 1.22 g/mL.
118 Medium
118 of 265
Understanding +4 | -1
Assertion: 0.1 M0.1 \mathrm{~M} solution of NaCl\mathrm{NaCl} have low freezing point than 0.1 M0.1 \mathrm{~M} urea solution.

Reason: Van't Hoff factor (No. of particles) for NaCl\mathrm{NaCl} is more than urea.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because NaCl dissociates into two ions, leading to a greater colligative effect (freezing point depression) compared to urea, which does not dissociate.
119 Medium
119 of 265
Application +4 | -1
The vapour pressure of water at 20∘C20^\circ C is 17.54  mm{17.54\;\mathrm{mm}}. When 20 g of a non-ionic, substance is dissolved in 100  g{100\;g} of water, the vapour pressure is lowered by 0.30  mm{0.30\;\mathrm{mm}}. What is the molecular mass of the substance?
View answer and explanation
Correct option: C
210.5
Option C (210.5) is correct because it is the molecular mass calculated using Raoult's law for vapor pressure lowering.
120 Medium
120 of 265
Analyzing +4 | -1
Assertion (A): When methyl alcohol is added to water, boiling point of water increases.

Reason ( R ): When a volatile solute is added to a volatile solvent, elevation in boiling point is observed.
View answer and explanation
Correct option: A
Both A\mathrm{A} and R\mathrm{R} are correct, R\mathrm{R} is the correct explanation of A\mathrm{A}.
Option D is correct because when methyl alcohol is added to water, the boiling point decreases, and the reason provided is correct in general for volatile solutes.
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