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JEE • CHEMISTRY • SOLUTIONS

Solutions practice · Hard

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Showing 61-77 of 77 questions
61 Hard
61 of 77
Application +4 | -1
Two elements AA and BB form compounds having formulae AB2A B_2 and AB4A B_4. When dissolved in 20 g20 \mathrm{~g} benzene, 1 g1 \mathrm{~g} of AB2A B_2 lowers the freezing point by 2.3∘2.3^{\circ} whereas 1.0 g1.0 \mathrm{~g} of AB4A B_4 lowers it by 1.3∘C1.3^{\circ} \mathrm{C}. KfK_f for benzene is 5.1 K mol−1 kg5.1 \mathrm{~K} \mathrm{~mol}^{-1} \mathrm{~kg}. The atomic masses of AA and BB are respectively
View answer and explanation
Correct option: A
25.6,42.625.6,42.6
Option A (25.6, 42.6) is correct because it provides the atomic masses of A and B that satisfy the freezing point depression equations for AB2AB_2 and AB4AB_4.
62 Hard
62 of 77
Application +4 | -1
Two solvents 'AA' and 'BB' have KfK_{\mathrm{f}} values 1.861.86 and 2.79 K mol−1 kg,2.79 \mathrm{~K} \mathrm{~mol}^{-1} \mathrm{~kg}, respectively. A given amount of a substance when dissolved in 500 g500 \mathrm{~g} of 'AA' completely dimerizes and when the same amount of the substance is dissolved in 500 g500 \mathrm{~g} of 'B{B}', the solute undergoes trimerization. The ratio of observed lowering of freezing point in two cases is
View answer and explanation
Correct option: C
1:11: 1
Option A (4) is correct because the ratio of observed lowering of freezing point depends on the van't Hoff factor, which is determined by the degree of association (dimerization and trimerization) in the two solvents.
63 Hard
63 of 77
Analyzing +4 | -1
A 10%10 \% (mass/mass) solution of cane-sugar undergoes partial conversion into glucose and fructose to show inversion of cane-sugar as:
 Sucrose + Water ⟶ Glucose + Fructose. \text { Sucrose + Water } \longrightarrow \text { Glucose + Fructose. }

If the solution boils at 100.27∘C100.27^{\circ} {C} at this state, calculate the average mass of the dissolved material. What fraction of the sugar has inverted? Given Kb{K}_b for H2O{H}_2 {O} is 0.512 K mol−1 kg0.512 {~K} {~mol}^{-1} {~kg}.
View answer and explanation
Correct option: A
210.7
Option A (210.7) is correct because it is obtained by calculating the average mass of the dissolved material using the colligative properties formula and the degree of inversion.
64 Hard
64 of 77
Application +4 | -1
The vapour pressure of chloroform (CHCl3)\left(\mathrm{CHCl}_3\right) and dichloromethane (CH2Cl2)\left(\mathrm{CH}_2 \mathrm{Cl}_2\right) at 298 K298 \mathrm{~K} is 200 mmHg200 \mathrm{~mm} \mathrm{Hg} and 415 mmHg415 \mathrm{~mm} \mathrm{Hg}, respectively. If a solution is prepared by mixing 25.5 g25.5 \mathrm{~g} of CHCl3\mathrm{CHCl}_3 and 40 g40 \mathrm{~g} of CH2Cl2\mathrm{CH}_2 \mathrm{Cl}_2 at 298 K298 \mathrm{~K}, calculate the mole fractions of chloroform in vapour phase.
View answer and explanation
Correct option: A
0.180.18
Option A (0.18) is correct because it is calculated using Raoult's Law and Dalton's Law to find the mole fraction of chloroform in the vapor phase.
65 Hard
65 of 77
Application +4 | -1
The distribution coefficient of I2{\mathrm{I}_2} in between CCl4\mathrm{CC}{\mathrm{l}_4} and H2O{\mathrm{H}_2}\mathrm{O} is 85 in favour of CCl4\mathrm{CC}{\mathrm{l}_4} at 25∘C25^\circ \mathrm{C}. If solubility of I2{\mathrm{I}_2} in H2O{\mathrm{H}_2}\mathrm{O} at 25∘C25^\circ \mathrm{C} is 0.33 g litre−1,the  solubility  of I2\mathrm{litr}{\mathrm{e}^{ - 1}},\mathrm{the \;solubility\; of}\,{\mathrm{I}_2} in CCl4\mathrm{CC}{\mathrm{l}_4} is ……..g litre−1\mathrm{litr}{\mathrm{e}^{ - 1}}.
View answer and explanation
Correct option: A
28.05
Option A (28.05) is correct because, using the distribution coefficient formula, the solubility of I2 in CCl4 is calculated to be 28.05 g/L.
66 Hard
66 of 77
Analyzing +4 | -1
ΔTf/Kf\Delta T_f / K_f has the same value of 1 mol kg−11 \mathrm{~mol} \mathrm{~kg}^{-1} for 8%8 \% AB2A B_2 and 10%A2B10 \% A_2 B by mass of solvent, both AB2A B_2 and A2BA_2 B being non- electrolytes. Atomic masses of AA and BB will be respectively
View answer and explanation
Correct option: C
40,20
Option C (40,20) is correct because solving the simultaneous equations derived from the molality formula yields the atomic masses of A and B as 40 and 20 respectively.
67 Hard
67 of 77
Application +4 | -1
The distribution coefficient of I2{\mathrm{I}_2} in between CCl4\mathrm{CC}{\mathrm{l}_4} and H2O{\mathrm{H}_2}\mathrm{O} is 85 in favour of CCl4\mathrm{CC}{\mathrm{l}_4} at 25∘C25^\circ \mathrm{C}. If solubility of I2{\mathrm{I}_2} in H2O{\mathrm{H}_2}\mathrm{O} at 25∘C25^\circ \mathrm{C} is 0.33 g litre−1,the  solubility  of I2\mathrm{litr}{\mathrm{e}^{ - 1}},\mathrm{the \;solubility\; of}\,{\mathrm{I}_2} in CCl4\mathrm{CC}{\mathrm{l}_4} is ……..g litre−1\mathrm{litr}{\mathrm{e}^{ - 1}}.
View answer and explanation
Correct option: A
28.05
Option A (28.05) is correct because, using the distribution coefficient formula, the solubility of I2 in CCl4 is calculated to be 28.05 g/L.
68 Hard
68 of 77
Application +4 | -1
The elevation in boiling point of a solution of 13.44 g of CuCl2\mathrm{CuC}{\mathrm{l}_2} in 1 kg of water using the following information will be (molecular weight of CuCl2=134.4  and  kb=0.52  Km−1)\mathrm{CuC}{\mathrm{l}_2} = 134.4\;and\;{k_b} = 0.52\;K{m^{ - 1}})
View answer and explanation
Correct option: A
0.160.16
Option A (0.16) is correct because it is the elevation in boiling point calculated using the van't Hoff factor and molality.
69 Hard
69 of 77
Analyzing +4 | -1
Two components A and B form an ideal solution. The mole fractions of AA and BB in ideal solution are XAX_A and XBX_B, while that of in vapour phase, these components have their mole fractions as YA\mathrm{Y}_{\mathrm{A}} and YB\mathrm{Y}_{\mathrm{B}}. Then, the slope and intercept of plot of 1YA\frac{1}{\mathrm{Y}_{\mathrm{A}}} vs. 1XA\frac{1}{\mathrm{X}_{\mathrm{A}}} will be:
View answer and explanation
Correct option: B
PBoPAo,PAo−PBoPAo\frac{\mathrm{P}_{\mathrm{B}}^{\mathrm{o}}}{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}}, \frac{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}-\mathrm{P}_{\mathrm{B}}^{\mathrm{o}}}{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}}
The correct answer is B (PBoPAo,PAo−PBoPAo\frac{\mathrm{P}_{\mathrm{B}}^{\mathrm{o}}}{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}}, \frac{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}-\mathrm{P}_{\mathrm{B}}^{\mathrm{o}}}{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}}) because the equation derived from Raoult's law and Dalton's law of partial pressures gives these slope and intercept values.
70 Hard
70 of 77
Application +4 | -1
Osmotic pressure of 3%3 \% aqueous solution of a non-volatile, non-electrolyte solute AA at 298 K298 \mathrm{~K} is 3.632 atm3.632 \mathrm{~atm}. Thus, its vapour pressure is ( pH2O∘=23.7 mmp_{\mathrm{H}_2 \mathrm{O}}^{\circ}=23.7 \mathrm{~mm} at 298 K298 \mathrm{~K} )
View answer and explanation
Correct option: A
23.64 mm
Option A (23.64 mm) is correct because it is the vapor pressure calculated using Raoult's law and the osmotic pressure to find the molar mass of the solute.
71 Hard
71 of 77
Application +4 | -1
Partition coefficient of benzoic acid-ether-water in favour of ether is 2. A solution containing 8 g/litre benzoic acid in ether layer is shaken with 2 litre water. The concentration of acid in water layer is :
View answer and explanation
Correct option: B
2
Option B (2) is correct because the concentration of acid in the water layer is calculated using the partition coefficient formula.
72 Hard
72 of 77
Application +4 | -1
What is the mass ratio of ethylene glycol (C2H6O2\left(\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}_{2}\right., molar mass =62 g/mol=62 \, \mathrm{g} / \mathrm{mol} ) required for making 500 g500 \, \mathrm{g} of 0.25 molal aqueous solution and 250 mL250 \, \mathrm{mL} of 0.25 molal aqueous solution?
View answer and explanation
Correct option: A
2:12: 1
Option A (2:1) is correct because the mass ratio is determined by calculating the mass of ethylene glycol in each solution and then finding the ratio.
73 Hard
73 of 77
Application +4 | -1
Two liquids A\mathrm{A} and B\mathrm{B}, form an ideal solution. At a specific temperature, the vapour pressure of pure ' A\mathrm{A} ' is 200 mm200 \mathrm{~mm} of Hg{Hg}. While that of pure B\mathrm{B} is 100 mm100 \mathrm{~mm} of Hg{Hg}. The vapour over mixture consists of 50%50 \% moles of A\mathrm{A}, what is the %\% of A\mathrm{A} in the liquid ?
View answer and explanation
Correct option: B
33.33%33.33 \%
Option B (33.33 %) is correct because it is calculated using Raoult's law and Dalton's law for ideal solutions.
74 Hard
74 of 77
Application +4 | -1
At 300 K 36 g300 \mathrm{~K} \,36 \mathrm{~g} of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar4.98 \,\mathrm{bar}. If the osmotic pressure of the solution is 1.52 bar at the same temperature, what would be its concentration?
View answer and explanation
Correct option: A
0.061M0.061 \mathrm{M}
The correct answer is A (0.061 M) because the concentration is calculated using the osmotic pressure formula and the given data.
75 Hard
75 of 77
Application +4 | -1
When 100 ml100\, {ml} of M10H2SO4\frac{{M}}{10} {H}_2 {SO}_4 is mixed with 500 ml500 \,{ml} of M10NaOH\frac{{M}}{10} {NaOH} then nature of resulting solution and normality of excess of reactant left is
View answer and explanation
Correct option: C
Basic, N20\frac{{N}}{20}
Option C (Basic, N20\frac{{N}}{{20}}) is correct because the milliequivalents of NaOH are greater than those of H2SO4, resulting in a basic solution, and the normality of the excess NaOH is calculated correctly.
76 Hard
76 of 77
Application +4 | -1
Calculate the entropy change for vaporisation of water if latent heat of vaporisation for water is 540cal/g540 {cal} / {g}. Given KbK_b for H2O=0.51 K/{H}_2 {O}=0.51 {~K} / molality.
View answer and explanation
Correct option: A
26.33
Option A (26.33) is correct because the entropy change is calculated using the given latent heat of vaporization and boiling point.
77 Hard
77 of 77
Understanding +4 | -1
Which of the aqueous equimolal solution will have its vapour pressure near to solvent?
View answer and explanation
Correct option: A
Urea
Option A (Urea) is correct because urea is a non-electrolyte and does not dissociate in water, resulting in the smallest change in vapor pressure compared to the solvent.
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