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JEE • CHEMISTRY • SOLUTIONS

Solutions practice · Mixed difficulty

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121 Medium
121 of 460
Application +4 | -1
Mole fraction of AA vapours above the solution in mixture of A{A} and B(XA=0.4){B}\left({X}_{{A}}=0.4\right) will be
[Given: PA0=100 mmHg{P}_{{A}}^0=100 {~mm} {Hg} and PB0=200 mmHg{P}_{{B}}^0=200 {~mm} {Hg} ]
View answer and explanation
Correct option: C
0.25
Option C (0.25) is correct because it is calculated using Raoult's law and Dalton's law of partial pressures to find the mole fraction of A in the vapor phase.
122 Medium
122 of 460
Application +4 | -1
What is the mole fraction of the solute in a 2.00 m aqueous solution :
View answer and explanation
Correct option: C
0.035
Option C (0.035) is correct because it is the mole fraction calculated using the formula: mole fraction = molality / (molality + 1000/MW_solvent).
123 Easy
123 of 460
Understanding +4 | -1
A solution of acetone in ethanol
View answer and explanation
Correct option: C
Show a positive deviation from Raoult’s law
Option C (Show a positive deviation from Raoult’s law) is correct because the interactions between acetone and ethanol are weaker than their self-interactions, leading to higher vapor pressure.
124 Medium
124 of 460
Application +4 | -1
If osmotic pressure of 4%(w/v)4 \%(\mathrm{w} / \mathrm{v}) solution of sucrose is same as 2%(w/v)2 \%(\mathrm{w} / \mathrm{v}) solution of ' X\mathrm{X} ' find molecular mass of X\mathrm{X}.
View answer and explanation
Correct option: C
171
Option C (171) is correct because it is the calculated molecular mass of X based on the osmotic pressure equality of two solutions.
125 Easy
125 of 460
Analyzing +4 | -1
Which statement is not correct if two immiscible liquids of mol. wt. A and B respectively are mixed in equal amount to have a mixture?
View answer and explanation
Correct option: C
PM=PA∘(XA)l+PB∘(XB)l{P_M} = P_A^ \circ {\left( {{X_A}} \right)_l} + P_B^ \circ {\left( {{X_B}} \right)_l}
Option C (PM=PA∘(XA)l+PB∘(XB)l{P_M} = P_A^ \circ {\left( {{X_A}} \right)_l} + P_B^ \circ {\left( {{X_B}} \right)_l}) is not correct because Raoult's law does not apply to immiscible liquid mixtures.
126 Hard
126 of 460
Application +4 | -1
If sodium sulphate is considered to be completely dissociated into cations and anions in aqueous solution, the change in freezing point of water ΔTf\Delta {T_f}, when 0.01 mole of sodium sulphate is dissolved in 1 kg of water, is (kf=1.86  K  kgmol−1)({k_f} = 1.86\;\mathrm{K}\;\mathrm{kg mo}{\mathrm{l}^{ - 1}})
View answer and explanation
Correct option: B
0.0558  K0.0558\mathrm{ }\;K
Option B (0.0558  K0.0558\mathrm{ }\;K) is correct because it is calculated using the van't Hoff factor and the freezing point depression formula.
127 Medium
127 of 460
Analyzing +4 | -1
Assertion (A) : At equilibrium of Liquid ⇌\rightleftharpoons Vapour, kinetic energy of liquid phase and vapour phase is same.

Reason (R) : Kinetic energy of liquid or vapour is given by 32RT\frac{3}{2} R T for 1 mole.
View answer and explanation
Correct option: C
Both Assertion and Reason are correct and Reason is correct explantion of Assertion
Option C (Both Assertion and Reason are correct and Reason is correct explantion of Assertion) is correct because at equilibrium, the average kinetic energy is the same for both phases, and the reason correctly states the formula for kinetic energy.
128 Medium
128 of 460
Analyzing +4 | -1
Consider the following statements.

I. The PH{P}_{{H}} of a mixture containing 400 ml400\, {ml} of 0.1M H2SO40.1 {M} \,{H}_2 {SO}_4 and 400 ml400 \,{ml} of 0.1 M NaOH0.1 \,{M}\, {NaOH} will be approximately 1.3

II. Ionic product of water is temperature dependent

III. Le-chatelier's principle is applicable to common-ion effect

IV. A mixture of HClO4+NaClO4{HClO}_4+{NaClO}_4 acts as an acidic buffer.

The correct statements are
View answer and explanation
Correct option: D
I, II and III
Option D (I, II and III) is correct because the pH calculation, the temperature dependence of the ionic product of water, and the applicability of Le Chatelier's principle to the common-ion effect are all valid statements.
129 Hard
129 of 460
Analyzing +4 | -1
Assertion: There will not be any change in concentration of an ethanol and water mixture containing 85%85 \% ethanol by volume on boiling.

Reason: It is because azeotropes boil out in constant composition.
View answer and explanation
Correct option: D
Assertion is wrong, but reason is correct statement.
Option D (Assertion is wrong, but reason is correct statement) is correct because an 85% ethanol-water mixture is not an azeotrope and will change concentration upon boiling, while azeotropes do boil at a constant composition.
130 Medium
130 of 460
Application +4 | -1
1 kg1 \mathrm{~kg} of water under a nitrogen pressure of 1 atmosphere dissolves 0.02 gm0.02 \mathrm{~gm} of nitrogen at 293 K. Calculate Henry's law constant :
View answer and explanation
Correct option: A
7.7×104 atm7.7 \times 10^4 \mathrm{~atm}
Option A (7.7×104 atm7.7 \times 10^4 \text{{ atm}}) is correct because Henry's law constant is calculated using the formula P=KH×XP = K_H \times X, where P is the pressure and X is the mole fraction of the gas.
131 Medium
131 of 460
Analyzing +4 | -1
Assertion : Molarity of 0.02 N solution of HNO3\mathrm{HNO}_3 is 0.02 M

Reason : Molarity and Normality of a solution are always equal for any acid.
View answer and explanation
Correct option: C
If Assertion is true but the reason is false
Option C (If Assertion is true but the reason is false) is correct because while the molarity and normality are equal for HNO3, they are not always equal for all acids.
132 Easy
132 of 460
Analyzing +4 | -1
The freezing point of equilibrium solution in aqueous medium will be highest for
View answer and explanation
Correct option: B
C6H12O6\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6
Option B (C6H12O6\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6) is correct because glucose is a non-electrolyte and does not dissociate in water, resulting in the smallest freezing point depression and thus the highest freezing point.
133 Hard
133 of 460
Analyzing +4 | -1
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): At 10∘C,10^\circ C, the density of a 5 M solution of KClKCl [atomic masses of K  &  ClK\,\,\& \,\,Cl are 39 & 35.5 g  mol−1g\,\,mo{l^{ - 1}} respectively] is ′x′  g  ml−1.'x'\,\,g\,\,m{l^{ - 1}}. The solution is cooled to −21∘C.- 21^\circ C. The molality of the solution will remain unchanged.
Reason (R) : The molality of a solution does not change with temperature as mass remains unaffected with temperature.
In the light of the above statements, choose the correct answer from the options given below.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A).
Option A (Both (A) and (R) are true and (R) is the correct explanation of (A)) is correct because molality is independent of temperature, and the assertion is true because the solution doesn't freeze at -21°C.
134 Medium
134 of 460
Application +4 | -1
Solute A associates in water. When 0.7 g of solute A is dissolved in 42.0 g of water, it depresses the freezing point by 0.2 ∘C.0.2\,^\circ C. The percentage association of solute A in water is:
[Given: Molar mass of A=93  g mol−1.{\text{A}} = 93\,\,g\,mo{l^{ - 1}}. Molal depression constant of water is 1.86 K kg mol−1.]1.86\,K\,kg\,mo{l^{ - 1}}.]
View answer and explanation
Correct option: D
0.8
Option A (332 J332 \mathrm{~J}) is correct because it is the sum of the isothermal and adiabatic work done, calculated using the appropriate formulas and given conditions.
135 Medium
135 of 460
Application +4 | -1
Calculate the mass percentage of aspirin (C9H8O4)\left(\mathrm{C}_9 \mathrm{H}_8 \mathrm{O}_4\right) in acetonitrile (CH3CN)\left(\mathrm{CH}_3 \mathrm{CN}\right) when 6.5 g6.5 \mathrm{~g} of C9H8O4\mathrm{C}_9 \mathrm{H}_8 \mathrm{O}_4 is dissolved in 450 g450 \mathrm{~g} of CH3CN\mathrm{CH}_3 \mathrm{CN}.
View answer and explanation
Correct option: A
1.421.42
Option A (1.421.42) is correct because the mass percentage is calculated by dividing the mass of aspirin by the total mass of the solution and multiplying by 100.
136 Hard
136 of 460
Application +4 | -1
The lowering in vapour pressure caused by the addition of 100 g100 \mathrm{~g} of sucrose (molecular mass =342=342) to 1000 g1000 \mathrm{~g} of lowering in water, if the vapour pressure of pure water at 25∘C25^{\circ} \mathrm{C} is 23.8 mm Hg23.8 \mathrm{~mm} \mathrm{~Hg}, is
View answer and explanation
Correct option: B
0.125 mm Hg0.125 \mathrm{~mm} \mathrm{~Hg}
Option B (0.125 mm Hg) is correct because it is calculated using Raoult's law for vapor pressure lowering.
137 Medium
137 of 460
Analyzing +4 | -1
Assertion (A): Respiratory apparatus of scuba divers contain a mixture of N2+O2+He{N}_2+{O}_2+{He}

Reason (R): Solubility of nitrogen in blood is less than that of Helium
View answer and explanation
Correct option: D
A is correct but R is incorrect
Option D is correct because the solubility of nitrogen in blood is higher than that of Helium, not less.
138 Hard
138 of 460
Application +4 | -1
The distribution coefficient of I2{\mathrm{I}_2} in between CCl4\mathrm{CC}{\mathrm{l}_4} and H2O{\mathrm{H}_2}\mathrm{O} is 85 in favour of CCl4\mathrm{CC}{\mathrm{l}_4} at 25∘C25^\circ \mathrm{C}. If solubility of I2{\mathrm{I}_2} in H2O{\mathrm{H}_2}\mathrm{O} at 25∘C25^\circ \mathrm{C} is 0.33 g litre−1,the  solubility  of I2\mathrm{litr}{\mathrm{e}^{ - 1}},\mathrm{the \;solubility\; of}\,{\mathrm{I}_2} in CCl4\mathrm{CC}{\mathrm{l}_4} is ……..g litre−1\mathrm{litr}{\mathrm{e}^{ - 1}}.
View answer and explanation
Correct option: A
28.05
Option A (28.05) is correct because the solubility of I2 in CCl4 is calculated using the distribution coefficient and the solubility in H2O.
139 Easy
139 of 460
Understanding +4 | -1
Solubility of deliquescent substances in water is generally :
View answer and explanation
Correct option: A
High
Option A (High) is correct because deliquescent substances absorb a large amount of water from the atmosphere to form a saturated solution, indicating high solubility.
140 Medium
140 of 460
Application +4 | -1
Equal weight of a solute are dissolved in equal weight of two solvents AA and BB and formed very dilute solution. The relative lowering of vapour pressure for the solution BB has twice the relative lowering of vapour pressure for the solution AA. If MAM_A and MBM_B are the molecular weights of solvents AA and BB respectively, then:
View answer and explanation
Correct option: B
MB=2×MAM_B=2 \times M_A
Option B (MB=2×MAM_B=2 \times M_A) is correct because the relative lowering of vapor pressure is inversely proportional to the molecular weight of the solvent.
141 Medium
141 of 460
Analyzing +4 | -1
Solution A contains 7 g/L of MgCl2MgC{l_2} and solution B contains 7 g/L of NaClNaCl. At room temperature, the osmotic pressure of
View answer and explanation
Correct option: C
Solution B is greater than A
Option A (Solution A is greater than B) is incorrect. Option C (Solution B is greater than A) is correct because NaCl produces more ions in solution than MgCl2, leading to a higher osmotic pressure.
142 Easy
142 of 460
Application +4 | -1
The vapour pressure of a solution at 373 K373 {~K} is 700 mm700 {~mm} of Hg{Hg}. The molality and mole fraction of solute in solution is:
View answer and explanation
Correct option: A
0.0789,4.760.0789,4.76
Option A (0.0789,4.760.0789,4.76) is correct because it correctly calculates the mole fraction and molality of the solute using Raoult's Law.
143 Medium
143 of 460
Application +4 | -1
An aqueous solution of a non-electrolyte boils at 100.52∘C100.52^{\circ} {C}. The freezing point of the solution will be
View answer and explanation
Correct option: B
−1.86∘C-1.86^{\circ} {C}
Option B (−1.86∘C-1.86^{\circ} {C}) is correct because the depression in freezing point is calculated using the molality obtained from the elevation in boiling point.
144 Medium
144 of 460
Analyzing +4 | -1
Assertion (A): The depression in freezing point depends on the amount of the solute and nature of solvent.

Reason (R): For aqueous solutions of different electrolytes, molal depression constant will have different value.
View answer and explanation
Correct option: C
(A) is true but (R) is false
Option C ((A) is true but (R) is false) is correct because the depression in freezing point is a colligative property dependent on the amount of solute and solvent nature, but the molal depression constant is a property of the solvent, not the electrolyte.
145 Easy
145 of 460
Understanding +4 | -1
An example of a solution having liquid in gas is:
View answer and explanation
Correct option: A
Moist air
Option A (Moist air) is correct because it represents a solution where liquid (water) is dispersed in a gas (air).
146 Easy
146 of 460
Application +4 | -1
A solution containing 500 g of a protein per litre is isotonic with a solution containing 3.42 g of sucrose per litre. The molecular mass of protein is :
View answer and explanation
Correct option: D
50000
The correct answer is 50000 because isotonic solutions have the same molar concentration, allowing us to equate the concentrations and solve for the protein's molecular mass.
147 Easy
147 of 460
Understanding +4 | -1
The azeotropic mixture of water and ethonal boils at 78.15∘C78.15^{\circ} \mathrm{C}. When this mixture is distilled, it is possible to obtain:
View answer and explanation
Correct option: D
Neither H2O\mathrm{H}_2 \mathrm{O} nor C2H5OH\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} in their pure state
Option D (Neither H2O\mathrm{H}_2 \mathrm{O} nor C2H5OH\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH} in their pure state) is correct because azeotropes boil at a constant temperature and cannot be separated by simple distillation.
148 Medium
148 of 460
Application +4 | -1
A solution of an organic compound develops an osmotic pressure of 2.07×10−2Nm−22.07 \times 10^{-2} {Nm}^{-2}. If the density of solution is 0.88 gdm−30.88 {~g} {dm}^{-3}, the height which it will develop on separating with its solvent through semipermeable membrane is :
View answer and explanation
Correct option: B
2.40×10−3 m2.40 \times 10^{-3} {~m}
Option B (2.40×10−3 m2.40 \times 10^{-3} {~m}) is correct because it is the height calculated using the osmotic pressure formula π=h⋅d⋅g\pi = h \cdot d \cdot g.
149 Easy
149 of 460
Understanding +4 | -1
The use of common salts, e.g. NaCl or CaCl2NaCl{\text{ or}}\,CaC{l_2} anhydrous is made to clear snow on the roads. This causes:
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because adding salt to snow lowers the freezing point of water, causing the ice to melt at the ambient temperature.
150 Medium
150 of 460
Analyzing +4 | -1
Assertion (A): For two solutions, 0.1 m0.1 \mathrm{~m} aqueous solution of glucose and 0.1 m0.1 \mathrm{~m} acetic acid in benzene, the lowering of vapour pressure is same.

Reason (R): Vapour pressure is always lowered when non-volatile solute is added to water.
View answer and explanation
Correct option: D
A is false, R is true
Statement I is incorrect, and Statement II is correct. Glucose is a non-electrolyte, and acetic acid dimerizes in benzene, leading to different vapor pressure lowering. Vapor pressure is indeed lowered by adding a non-volatile solute.
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