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JEE • CHEMISTRY • SOLID STATE

Solid state practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 98 questions
61 Medium
61 of 98
Analyzing +4 | -1
Select the incorrect statement among the following
View answer and explanation
Correct option: D
Ni(s){Ni}(\mathrm{s}) is repelled from magnetic field and is antiferromagnetic in nature
The correct answer is D (Ni(s){Ni}(\mathrm{s}) is repelled from magnetic field and is antiferromagnetic in nature) because Nickel (Ni) is ferromagnetic, not antiferromagnetic, and is attracted to magnetic fields, not repelled.
62 Medium
62 of 98
Application +4 | -1
A compound alloy of gold and CuCu crystallises in a cubic lattice in which the gold atoms occupy the lattice points at the corners of a cube and the copper atoms occupy the centres of each of the cube faces. What is the empirical formula of this compound?
View answer and explanation
Correct option: A
AuCu3\mathrm{AuC}{\mathrm{u}_3}
The correct answer is A (AuCu3\mathrm{AuC}{\mathrm{u}_3}) because the gold atoms at the corners contribute 1 atom per unit cell, and the copper atoms at the face centers contribute 3 atoms per unit cell.
63 Medium
63 of 98
Understanding +4 | -1
The effective number of carbon atoms in a unit cell of diamond is
View answer and explanation
Correct option: C
4
Option B (8) is incorrect. The correct answer is A (6). The effective number of carbon atoms in a unit cell of diamond is 8.
64 Medium
64 of 98
Remembering +4 | -1
The statement that, “It is possible to choose along the three co-ordinate axes unit distance a,b,ca,b,c not necessarily of the same length, such that the ratio of there intercepts of any plane in the crystal is given by in ma:nb:pcma:nb:pc where m,n,pm,n,p are either integral whole numbers including infinity or fraction of whole number” is known as :
View answer and explanation
Correct option: A
Hauy’s law of rationality of indices
Option A (Hauy’s law of rationality of indices) is correct because the statement describes Hauy's law.
65 Medium
65 of 98
Remembering +4 | -1
Which of crystal systems contains the maximum number of Bravais lattices?
View answer and explanation
Correct option: D
Orthorhombic
Option D (Orthorhombic) is correct because the orthorhombic crystal system has four Bravais lattices: primitive, body-centered, face-centered, and end-centered.
66 Medium
66 of 98
Application +4 | -1
Silver metal crystallises in a cubic closed packing arrangement with the edge of the unit cell a=407 pm{a}=407\, \mathrm{pm}. The radius of silver atom is (X+3.9)pm(X+3.9) \mathrm{pm}. Find the value of XX.
View answer and explanation
Correct option: A
140
The correct answer is A (140) because the radius of the silver atom is calculated using the face-centered cubic (fcc) relationship between the edge length and the radius.
67 Medium
67 of 98
Application +4 | -1
If a crystal lattice of a compound, each corner of a cube is enjoyed by sodium, each edge of a cube has oxygen and centre of a cube is enjoyed by tungsten (W)(W), then give its formula
View answer and explanation
Correct option: B
NaWO3\mathrm{NaW}{\mathrm{O}_3}
Option B (NaWO3\mathrm{NaW}{\mathrm{O}_3}) is correct because it represents the correct ratio of Na, W, and O atoms based on their positions in the crystal lattice.
68 Medium
68 of 98
Remembering +4 | -1
Which of the following substance possess antiferromagnetic property?
View answer and explanation
Correct option: D
MnO{MnO}
Option D (MnO{MnO}) is correct because manganese(II) oxide (MnO{MnO}) exhibits antiferromagnetic properties due to the antiparallel alignment of magnetic moments.
69 Medium
69 of 98
Application +4 | -1
An AB{AB} solid has CsCl{CsCl} type of structure, where A{A} occupies corner. If the atoms from corners along one of the body diagonal are removed, the formula of the solid would be
View answer and explanation
Correct option: C
A3B4{A}_3 {B}_4
Option A (A3B4{A}_3 {B}_4) is correct because removing two A atoms from the corners changes the ratio of A to B in the unit cell.
70 Medium
70 of 98
Remembering +4 | -1
A crystal of Fe3O4\mathrm{F}{\mathrm{e}_3}{\mathrm{O}_4} is :
View answer and explanation
Correct option: A
Paramagnetic
The correct answer is A (Paramagnetic) because Fe3O4Fe_3O_4 (magnetite) exhibits ferrimagnetism, which is a form of paramagnetism, due to the unequal alignment of magnetic moments in its crystal structure.
71 Medium
71 of 98
Remembering +4 | -1
The number of octahedral sites per sphere in a fcc structure is
View answer and explanation
Correct option: A
1
Option A (1) is correct because in an FCC structure, the number of octahedral sites is equal to the number of atoms in the unit cell, which is 4. Since there are 4 spheres, there is 1 octahedral site per sphere (4/4 = 1).
72 Medium
72 of 98
Remembering +4 | -1
The range of radius ratio (cationic to anionic) for an octahedral arrangement of ions in an ionic solid is
View answer and explanation
Correct option: D
0.414−0.7320.414-0.732
Option D (0.414−0.7320.414-0.732) is correct because the radius ratio for an octahedral arrangement of ions falls within this range.
73 Medium
73 of 98
Remembering +4 | -1
Which one of the following statements about packing in solids is incorrect?
View answer and explanation
Correct option: C
Void space in hcp mode of packing is 32%32 \%.
Option C (Void space in hcp mode of packing is 32%32 \%.) is correct because the void space in hcp is 26%, not 32%.
74 Medium
74 of 98
Analyzing +4 | -1
Assertion (A): In NaCl{NaCl} crystal each Na+{Na}^{+}ion is touching 6 Cl−6 \, {Cl}^{-}ions but these Cl−{Cl}^{-}ions do not touch each other.

Reason (R): The radius ratio is greater than 0.414 required for exact fitting.
View answer and explanation
Correct option: A
Both (A) and (R) are correct and (R) is the correct explanation of (A)
Option A is correct because in NaCl crystal, each Na+ ion is indeed touching 6 Cl- ions, and these Cl- ions do not touch each other due to the radius ratio being greater than 0.414, which is the correct explanation.
75 Medium
75 of 98
Remembering +4 | -1
p-type semiconductor is formed when germanium is doped with
View answer and explanation
Correct option: C
Aluminium
Option C (Aluminium) is correct because doping germanium with a group 13 element like aluminum creates a p-type semiconductor.
76 Medium
76 of 98
Remembering +4 | -1
In a monoclinic unit cell the relation of sides and
angles are respectively:
View answer and explanation
Correct option: C
a≠b≠c   and   α=γ=90∘≠βa \ne b \ne c\,\,\,{\text{and}}\,\,\,\alpha = \gamma = 90^\circ \ne \beta
Option C is correct because in a monoclinic unit cell, the sides are unequal (a≠b≠ca \ne b \ne c) and two angles are 90 degrees (α=γ=90∘\alpha = \gamma = 90^\circ) while the third angle is not (β≠90∘\beta \ne 90^\circ).
77 Medium
77 of 98
Application +4 | -1
A compound of ‘A’ and ‘B’ crystallises in a cubic lattice in which ‘A’ atoms occupy the lattice points at the corners of the cube. The ‘B’ atoms occupy the centre of each face of the cube. The probable empirical formula of the compound is
View answer and explanation
Correct option: D
AB3A{B_3}
Option D (AB3A{B_3}) is correct because the number of A atoms is 1 and the number of B atoms is 3 in the unit cell.
78 Medium
78 of 98
Understanding +4 | -1
The number of equidistance oppositely charged ions in a sodium chloride crystal is
View answer and explanation
Correct option: C
6
Option C (6) is correct because in a sodium chloride (NaCl) crystal, each Na+Na^+ ion is surrounded by 6 equidistant Cl−Cl^- ions, and vice versa.
79 Medium
79 of 98
Understanding +4 | -1
Among the following species, the one which become paramagnetic on heating at 850 K850 {~K} is
View answer and explanation
Correct option: D
Both (1) and (3)
Option D (Both (1) and (3)) is correct because ferrimagnetic substances like Fe3O4 and ZnFe2O4 lose their ferrimagnetism and become paramagnetic upon heating above their Curie temperature.
80 Medium
80 of 98
Application +4 | -1
The pyknometric density of sodium chloride crystal is 2.165×103  kg  m−32.165 \times {10^3}\;\mathrm{kg}\;{\mathrm{m}^{ - 3}} while is X-ray density is 2.178×103  kg  m−32.178 \times {10^3}\;\mathrm{kg}\;{\mathrm{m}^{ - 3}}. The fraction of the unoccupied sites in sodium chloride crystal is :
View answer and explanation
Correct option: D
5.96×10−35.96 \times {10^{ - 3}}
Option D (5.96×10−35.96 \times {10^{ - 3}}) is correct because it accurately calculates the fraction of unoccupied sites based on the difference between pyknometric and X-ray densities.
81 Medium
81 of 98
Understanding +4 | -1
Assertion : Stability of a crystal is reflected in the magnitude of its melting point.

Reason : The stability of a crystal depends upon the strength of the interparticle attractive force.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.
Option A is correct because the stability of a crystal is directly related to its melting point, which depends on the strength of interparticle attractive forces.
82 Medium
82 of 98
Analyzing +4 | -1
Assertion (A) Both Frenkel and Schottky defects are stoichiometric defects.

Reason (R) Both defects change the density of the crystalline solid.
View answer and explanation
Correct option: C
If Assertion is true but Reason is false.
Option C is correct because both Frenkel and Schottky defects are stoichiometric, but only Schottky defects affect the density of the crystal.
83 Medium
83 of 98
Remembering +4 | -1
Order of packing efficiency is
View answer and explanation
Correct option: D
HCP ≈\approx FCC > BCC > Simple cubic
Option D (HCP ≈\approx FCC > BCC > Simple cubic) is correct because it represents the correct order of packing efficiency for the given crystal structures.
84 Medium
84 of 98
Remembering +4 | -1
Structure similar to zinc blende is found in
View answer and explanation
Correct option: C
CuCl\mathrm{CuCl}
Option C (CuCl\mathrm{CuCl}) is correct because CuCl has a structure similar to zinc blende.
85 Medium
85 of 98
Application +4 | -1
How many number of atoms are there in a cube based unit cell having one atom on each corner and two atoms on each body diagonal of cube
View answer and explanation
Correct option: D
9
Option D (9) is correct because it correctly accounts for the contribution of atoms at the corners and along the body diagonals of the cube.
86 Medium
86 of 98
Remembering +4 | -1
In zinc blende structure, the coordination number of Zn2+\mathrm{Z}{\mathrm{n}^{2 + }} ion is
View answer and explanation
Correct option: B
4
Option B (4) is correct because in the zinc blende (ZnS) structure, each Zn2+Zn^{2+} ion is tetrahedrally coordinated to four S2−S^{2-} ions, and vice versa.
87 Medium
87 of 98
Application +4 | -1
The number of unit cells in the Ca atom lies on the surface of a cubic crystal that is 1.0 cm1.0 \mathrm{~cm} in length is
View answer and explanation
Correct option: B
9.17×10229.17 \times 10^{22}
Option B (9.17×10229.17 \times 10^{22}) is correct because it calculates the number of unit cells by dividing the volume of the crystal by the volume of a single unit cell.
88 Medium
88 of 98
Understanding +4 | -1
The ratio of cationic radius to anionic radius in an ionic crystal is greater than 0.732. Its coordination number is
View answer and explanation
Correct option: D
8
Option D (8) is correct because a radius ratio greater than 0.732 indicates a coordination number of 8, corresponding to a body-centered cubic structure.
89 Medium
89 of 98
Analyzing +4 | -1
Which of the following statements is/are not true?
View answer and explanation
Correct option: D
Non – stoichiometric defects do not alter the density of the solid
Option D (Non – stoichiometric defects do not alter the density of the solid) is not true because non-stoichiometric defects involve either excess metal ions or metal deficiencies, which *do* alter the density of the solid.
90 Medium
90 of 98
Application +4 | -1
In a solid ′AB′'AB' having the NaCl structure ′A′'A' atoms occupy the corners of the cubic unit cell. If all the face centred atoms along one of the axes are removed then the resultant stoichiometry of the solid is
View answer and explanation
Correct option: C
A3B4{A_3}{B_4}
The correct answer is A (13.15 M13.15 \mathrm{~M}) because it is calculated using the density, percentage strength, and molar mass of HCl.
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