Skip to main content
Back to PRACTICAL CHEMISTRY

Your Progress

0 / 98 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • CHEMISTRY • PRACTICAL CHEMISTRY

Practical chemistry practice · Mixed difficulty

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 1-30 of 98 questions
1 Easy
1 of 98
Remembering +4 | -1
In Carius method for the estimation of sulphur precipitate is formed due to the formation of
View answer and explanation
Correct option: A
BaSO4BaS{O_4}
Option A (BaSO₄) is correct because in the Carius method, sulfur is oxidized to sulfuric acid (H₂SO₄), which then reacts with barium chloride (BaCl₂) to form barium sulfate (BaSO₄) precipitate.
2 Medium
2 of 98
Remembering +4 | -1
Mercurous chloride turns black on treatment with ammonium hydroxide. This is due to the formation of
View answer and explanation
Correct option: C
Hg and HgNH2Cl\mathrm{Hg} \text{ and }\mathrm{HgNH}_2 \mathrm{Cl}
Option C (Hg and HgNH2Cl\mathrm{Hg} \text{ and }\mathrm{HgNH}_2 \mathrm{Cl}) is correct because mercurous chloride reacts with ammonium hydroxide to form a mixture of mercury and mercury(II) amido-chloride, which appears black.
3 Medium
3 of 98
Understanding +4 | -1
While preparing crystals of Mohr's salt, dil. H2SO4\mathrm{H}_2 \mathrm{SO}_4 is added to a mixture of ferrous sulphate and ammonium sulphate, before dissolving this mixture in water, dil. H2SO4\mathrm{H}_2 \mathrm{SO}_4 is added here to:
View answer and explanation
Correct option: A
Prevent the hydrolysis of ferrous sulphate
Option B (ΔH>TΔS\Delta {H} > {T} \Delta {S}) is correct because for a spontaneous reaction, the change in Gibbs free energy must be negative, and in this case, the magnitude of ΔH\Delta H is greater than TΔST \Delta S.
4 Medium
4 of 98
Understanding +4 | -1
Na2CO3Na_2CO_3 cannot be used to identify
View answer and explanation
Correct option: A
CO32−CO_3^{ 2 - }
Option A is correct. Na2CO3Na_2CO_3 cannot be used to identify CO32−CO_3^{2-} because it is the same ion.
5 Medium
5 of 98
Analyzing +4 | -1
A substance on treatment with dil. H2SO4\mathrm{H}_2 \mathrm{SO}_4 liberates a colourless gas which produces (i) turbidity with baryta water and (ii) turns acidified dichromate solution green. The reaction indicates the presence of
View answer and explanation
Correct option: C
SO32−\mathrm{SO}_3^{2-}
The correct answer is C (SO32−\mathrm{SO}_3^{2-}) because the colorless gas that produces turbidity with baryta water (Ba(OH)2\mathrm{Ba(OH)_2}) and turns acidified dichromate green is sulfur dioxide (SO2\mathrm{SO_2}), which is released from sulfite ions (SO32−\mathrm{SO}_3^{2-}).
6 Medium
6 of 98
Remembering +4 | -1
Which of the following situation exists at the equivalence point of a titration.
View answer and explanation
Correct option: D
[H⊕][O⊖H]=10−14\frac{\left[H^{\oplus}\right]}{[\stackrel{\ominus}{O} H]}=10^{-14}
Option B ([H+]=[OH-]) is correct because at the equivalence point in a titration, the concentrations of hydrogen and hydroxide ions are equal, representing a neutral solution.
7 Medium
7 of 98
Remembering +4 | -1
PbCrO4\mathrm{PbCrO}_4 is yellow in colour due to
View answer and explanation
Correct option: B
CrO4−2\mathrm{Cr} \mathrm{O}_4^{-2}
Option B (CrO4−2\mathrm{Cr} \mathrm{O}_4^{-2}) is correct because the chromate ion (CrO4−2\mathrm{Cr} \mathrm{O}_4^{-2}) is responsible for the yellow color of PbCrO4\mathrm{PbCrO}_4.
8 Medium
8 of 98
Remembering +4 | -1
Identify the one which does not come under the chemical methods of quantitative analysis?
View answer and explanation
Correct option: D
Magnetic suceptibility
Option D (Magnetic suceptibility) is correct because magnetic susceptibility is a physical method of quantitative analysis, not a chemical method.
9 Medium
9 of 98
Remembering +4 | -1
Ca,Ba\mathrm{Ca}, \mathrm{Ba} and Sr\mathrm{Sr} ions are precipitated in fifth group as their
View answer and explanation
Correct option: C
Carbonates
Option C (Carbonates) is correct because Ca, Ba, and Sr ions are precipitated as their carbonates in the fifth group of qualitative analysis.
10 Medium
10 of 98
Remembering +4 | -1
The cations are grouped on the basis of
View answer and explanation
Correct option: B
Solubility product of radicals
Option B (Solubility product of radicals) is correct because cations are grouped based on the solubility products of their radicals during qualitative analysis.
11 Medium
11 of 98
Remembering +4 | -1
Mark the compound which turns black with NH4OH:\mathrm{NH}_4 \mathrm{OH}:
View answer and explanation
Correct option: B
Mercurous chloride
Option B (Mercurous chloride) is correct because Hg2Cl2\mathrm{Hg}_2 \mathrm{Cl}_2 reacts with NH4OH\mathrm{NH}_4 \mathrm{OH} to form mercury and Hg(NH2)Cl\mathrm{Hg(NH_2)Cl}, which appears black.
12 Medium
12 of 98
Analyzing +4 | -1
A metal XX on heating with nitrogen gas gives Y.Y. YY on treatment with H2O\mathrm{H}_2 \mathrm{O} gives a colourless gas which on passing through CuSO4\mathrm{CuSO}_4 gives blue solution then YY is
View answer and explanation
Correct option: B
Mg3N2\mathrm{Mg}_3 \mathrm{N}_2
Option B (Mg3N2\mathrm{Mg}_3 \mathrm{N}_2) is correct because magnesium reacts with nitrogen to form magnesium nitride, which then reacts with water to produce ammonia, which gives a blue solution with CuSO4\mathrm{CuSO}_4.
13 Medium
13 of 98
Remembering +4 | -1
Which of the following is insoluble in yellow ammonium polysulphide.
View answer and explanation
Correct option: A
CuS\mathrm{CuS}
Option A (CuS\mathrm{CuS}) is correct because copper sulfide is insoluble in yellow ammonium polysulfide, while the sulfides of arsenic, antimony, and tin dissolve due to the formation of thio salts.
14 Medium
14 of 98
Remembering +4 | -1
On addition of aqueous NaOH\mathrm{NaOH} to salt solution, a white gelatinous precipitate is formed which dissolves in excess of alkali. The salt solution contains
View answer and explanation
Correct option: A
Aluminium ions
Option A (Aluminium ions) is correct because aluminium ions react with NaOH to form a white gelatinous precipitate of aluminium hydroxide, which dissolves in excess NaOH to form sodium aluminate.
15 Medium
15 of 98
Remembering +4 | -1
Which group anions don't give any characteristic gas with dil and con. H2SO4.\mathrm{H}_2 \mathrm{SO}_4.
View answer and explanation
Correct option: C
III Group
Option III Group is correct because the anions in Group III (SO4−2,PO4−3,BO3−2,F−\mathrm{SO}_4^{-2}, \mathrm{PO}_4^{-3}, \mathrm{BO}_3^{-2}, \mathrm{F}^{-}) do not produce characteristic gases with dilute or concentrated H2SO4\mathrm{H}_2 \mathrm{SO}_4.

Explore Other Chapters in CHEMISTRY

View All →
P-BLOCK ELEMENTS 736 MCQs Equilibrium 696 MCQs STRUCTURE OF ATOM 634 MCQs THERMODYNAMICS 536 MCQs CHEMICAL BONDING & MOLECULAR STRUCTURE 514 MCQs SOLUTIONS 480 MCQs
16 Hard
16 of 98
Analyzing +4 | -1
A pale green crystalline inorganic salt (A) dissolves freely in water. It gives a brown precipitate on addition of aqueous NaOH.\mathrm{NaOH}. The solution of (A) also gives a black precipitate on bubbling H2S\mathrm{H}_2 \mathrm{S} in alkaline medium. An aqueous solution of the (A) decolorizes the pink colour of the permanganate solution. The metal in the salt solution is
View answer and explanation
Correct option: D
Iron
Option D (Iron) is correct because the described reactions are characteristic of iron(II) ions in solution.
17 Medium
17 of 98
Remembering +4 | -1
CuSO4\mathrm{CuSO}_4 when reacts with KCN\mathrm{KCN} forms CuCN\mathrm{CuCN} which is insoluble in water, it is soluble in excess of KCN,\text{KCN}, due to formation of the following complex
View answer and explanation
Correct option: B
K3[Cu(CN)4]\text{K}_3\left[\text{Cu}(\text{CN})_4\right]
Option B (K3[Cu(CN)4]\text{K}_3\left[\text{Cu}(\text{CN})_4\right]) is correct because CuCN\text{CuCN} dissolves in excess KCN\text{KCN} to form the complex ion [Cu(CN)4]3−\left[\text{Cu}(\text{CN})_4\right]^{3-}, which is balanced by three potassium ions.
18 Medium
18 of 98
Remembering +4 | -1
Which colour confirms the presence of
phosphorus in organic compound:
View answer and explanation
Correct option: C
yellow
Option C is correct because the presence of phosphorus in an organic compound is confirmed by a yellow precipitate of ammonium phosphomolybdate when reacted with ammonium molybdate.
19 Medium
19 of 98
Remembering +4 | -1
Which of the following statement is incorrect:
View answer and explanation
Correct option: A
Colour of lead sulphide (PbS) precipitate is yellow
Option A (Colour of lead sulphide (PbS) precipitate is yellow) is correct because lead sulphide (PbS) precipitate is black, not yellow.
20 Medium
20 of 98
Analyzing +4 | -1
Given below are two statements one is labelled as Assertion (A) and the other is labeilled as Reason.

Assertion (A): In the titration of HCl against NaOH, phenolphthalein is used as suitable indicator.

Reason (R): Phenolphthalein is pink coloured in basic medium.

In the light of above statements, choose the most appropriate answer from the options given below.
View answer and explanation
Correct option: D
If both (A) and (R) are correct, but (R) is not the
correct explanation of (A)
Option D is correct. Both the assertion that phenolphthalein is used as an indicator in the titration of HCl against NaOH and the reason that phenolphthalein is pink in a basic medium are correct, but the reason is not the correct explanation for the assertion. Phenolphthalein is chosen because its color change occurs near the equivalence point of the titration.
21 Medium
21 of 98
Remembering +4 | -1
Nitrogen in the organic compound can be
determined by
View answer and explanation
Correct option: B
Kjeldhal method
Option B (Kjeldhal method) is correct because the Kjeldahl method is a quantitative method used to determine the nitrogen content in organic and inorganic substances.
22 Medium
22 of 98
Remembering +4 | -1
In organic analysis, Brady’s reagent is used for
the detection of which of the following functional
groups:
View answer and explanation
Correct option: C
Aledhyde/ketones
Option C (Aledhyde/ketones) is correct because Brady's reagent (2,4-dinitrophenylhydrazine) reacts with aldehydes and ketones to form hydrazones, which are typically colored precipitates.
23 Medium
23 of 98
Remembering +4 | -1
An yellow coloured precipitate PbCrO4\mathrm{PbCrO}_4 is insoluble in
View answer and explanation
Correct option: C
CH3COOH\mathrm{CH}_3 \mathrm{COOH}
Option C (CH3COOH\mathrm{CH}_3 \mathrm{COOH}) is correct because PbCrO4\mathrm{PbCrO}_4 is insoluble in acetic acid.
24 Medium
24 of 98
Analyzing +4 | -1
In the separation of Cu2+\mathrm{Cu}^{2+} and Cd2+\mathrm{Cd}^{2+} in 2nd 2^{\text {nd }} group qualitative analysis of cations tetrammine copper (II) sulphate and tetrammine cadmium (II) sulphate react with KCN\text{KCN} to form the corresponding cyano complexes. Which one of the following pairs of the complexes and their relative stability enables the separation of Cu2+\mathrm{Cu}^{2+} and Cd2+?\mathrm{Cd}^{2+}?
View answer and explanation
Correct option: A
K3[Cu(CN)4]\mathrm{K}_3\left[\mathrm{Cu}(\mathrm{CN})_4\right] more stable and K2[Cd(CN)4]\mathrm{K}_2\left[\mathrm{Cd}(\mathrm{CN})_4\right] less stable
Option A (K3[Cu(CN)4] more stable and K2[Cd(CN)4] less stable) is correct because the higher stability of the copper complex and lower stability of the cadmium complex allows for selective precipitation of CdS.
25 Hard
25 of 98
Analyzing +4 | -1
A student is asked to determine the degree of
hydration of a salt by finding the mass of a
clean dried crucible and lid followed by the
mass of the crucible and lid containing a
sample of the salt. The crucible, lid and salt
are heated in a Bunsen burner flame, cooled,
and weighed. If the crucible, lid and salt are
heated only once instead of the recommended
three times, what will be the effect on the
degree of hydration compared with the actual
value?
View answer and explanation
Correct option: B
Too low
The correct answer is B (Too low) because if the salt is heated only once, not all the water of hydration will be driven off, leading to an underestimation of the degree of hydration.
26 Medium
26 of 98
Remembering +4 | -1
MgSO4\mathrm{MgSO}_4 on reaction with NH4OH\mathrm{NH}_4 \mathrm{OH} and Na2HPO4\mathrm{Na}_2 \mathrm{HPO}_4 forms a white crystalline precipitate. What is its formula?
View answer and explanation
Correct option: A
Mg(NH4)PO4\mathrm{Mg}\left(\mathrm{NH}_4\right) \mathrm{PO}_4
Option A (Mg(NH4)PO4\mathrm{Mg(NH_4)PO_4}) is correct because the reaction of MgSO4\mathrm{MgSO_4} with NH4OH\mathrm{NH_4OH} and Na2HPO4\mathrm{Na_2HPO_4} forms a white crystalline precipitate of magnesium ammonium phosphate.
27 Medium
27 of 98
Understanding +4 | -1
Acidic K2Cr2O7\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 reacts with H2S\mathrm{H}_2 \mathrm{S} to produce
View answer and explanation
Correct option: C
S\text{S}
Option C is correct because acidic K2Cr2O7 oxidizes H2S to elemental sulfur (S).
28 Easy
28 of 98
Remembering +4 | -1
The aqueous solution of which salt is coloured
View answer and explanation
Correct option: C
Co(NO3)2\mathrm{Co}\left(\mathrm{NO}_3\right)_2
Option C (Co(NO3)2\mathrm{Co(NO_3)_2}) is correct because Co2+\mathrm{Co^{2+}} has allowed d-d transitions, resulting in a colored aqueous solution.
29 Medium
29 of 98
Understanding +4 | -1
In the preparation of p-nitro acetanilide from aniline, nitration is not done by nitrating mixture (a mixture of con. H2SO4\mathrm{H}_2 \mathrm{SO}_4 and HNO3)\mathrm{HNO}_3) because
View answer and explanation
Correct option: C
−NH2-\mathrm{NH}_2 group gets oxidized
The correct answer is that the −NH2-\mathrm{NH}_2 group gets oxidized because aniline is highly reactive and prone to oxidation under strongly oxidizing conditions like a nitrating mixture.
30 Medium
30 of 98
Remembering +4 | -1
Which is most soluble in water?
View answer and explanation
Correct option: D
AgF\mathrm{AgF}
Option D (AgF) is the most soluble in water because fluorides of silver are more soluble than other halides due to the higher hydration energy of fluoride ions.
Revision notes and key takeaways

Review PRACTICAL CHEMISTRY in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

  • ✓ This set contains 98 single-correct-answer MCQs on PRACTICAL CHEMISTRY.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
Showing 1-30 of 98 questions

Continue Your Practice

📚 More Sets in This Chapter

Try different difficulty levels to master this topic

→ ENGINEERING CHEMISTRY - PRACTICAL CHEMISTRY MCQs (Easy) 5 MCQs → ENGINEERING CHEMISTRY - PRACTICAL CHEMISTRY MCQs (Hard) 9 MCQs → ENGINEERING CHEMISTRY - PRACTICAL CHEMISTRY MCQs (Medium) 84 MCQs
🎯 Next Chapters to Practice

Continue building your subject mastery

→ P-BLOCK ELEMENTS 736 MCQs → Equilibrium 696 MCQs → STRUCTURE OF ATOM 634 MCQs → THERMODYNAMICS 536 MCQs
📚 Switch Set (ALL)
Chapter Sets
ALL 98 MCQs EASY 5 MCQs HARD 9 MCQs MEDIUM 84 MCQs
0 /98
0✓ 0✗
0% Accuracy
Type at least 2 characters or jump directly:
🩺 NEET MCQs 🔬 JEE MCQs 🎯 JEE College Predictor Study guides 📊 Dashboard
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Continue with Free Account →