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JEE • CHEMISTRY • ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Organic chemistry-some basic principles and techniques practice · Medium

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Showing 121-150 of 195 questions

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121 Medium
121 of 195
Analyzing +4 | -1
But-2-yne is reacted separately with one mole of Hydrogen as shown below
B‾←liq NH3NaCH3−C+H2≡C−CH3→ΔPd/CA‾\underline B \xleftarrow[{{\text{liq }}N{H_3}}]{{Na}}C{H_3} - \mathop C\limits_{ + {H_2}} \equiv C - C{H_3}\xrightarrow[\Delta ]{{Pd/C}}\underline A
(A) A is more than soluble than B.
(B) The boiling point & melting point of A are higher and lower than B respectively.
(C) A is more polar than B because dipole moment of A is zero.
(D) Br2Br_2 adds easily to B than A.
Identify the incorrect statements from the option given below
View answer and explanation
Correct option: B
B, C & D only
The correct answer is B (B, C & D only) because the boiling point of A (cis-But-2-ene) is higher than B (trans-But-2-ene), A is more polar than B, and Br2Br_2 adds more easily to A than B.
122 Medium
122 of 195
Understanding +4 | -1
Statement I : A tertiary carbocation is more stable than a secondary carbocation which is more stable than a primary carbocation
Statement II : The inductive effects operate through sigma bonds and decrease rapidly with increase in distance between the substituent and the reaction site
View answer and explanation
Correct option: C
Both statements are correct
Option C (Both statements are correct) is correct because tertiary carbocations are indeed more stable due to the inductive effect and hyperconjugation, and the inductive effect diminishes with distance.
123 Medium
123 of 195
Understanding +4 | -1
The production of an optically active compound from a symmetric molecule without resolution in termed as :
View answer and explanation
Correct option: C
Asymmetric synthesis
Option C (Asymmetric synthesis) is correct because asymmetric synthesis is the production of an optically active compound from a symmetric molecule without resolution.
124 Medium
124 of 195
Understanding +4 | -1
Arrange the Anions (p).CH3,  (q).NH2,  (r).OH,  (s).F−(\mathrm{p}). {CH}_3, \, \, (\mathrm{q}). {NH}_2, \, \, (\mathrm{r}). {OH}, \, \, (\mathrm{s}). {F}^{-} in decreasing order of their basic strength
View answer and explanation
Correct option: A
p >> q >> r >> s
Option A (p >> q >> r >> s) is correct because the basic strength of anions is inversely proportional to the acidic strength of their conjugate acids. The conjugate acids are CH4CH_4, NH3NH_3, H2OH_2O, and HFHF, with increasing acidity, thus the basicity decreases in the order given.
125 Medium
125 of 195
Analyzing +4 | -1
Incorrect statement for the use of indicators in acid-base titration is :
View answer and explanation
Correct option: C
Methyl orange may be used for a weak acid vs weak base titration.
The correct answer is C (Methyl orange may be used for a weak acid vs weak base titration) because there is no suitable indicator for weak acid vs weak base titrations.
126 Medium
126 of 195
Analyzing +4 | -1
The number of sp2s{p^2} hybridized carbon atoms present in ‘Aspartame’ are
View answer and explanation
Correct option: C
9
Option C (9) is correct because the structure of Aspartame contains 9 carbon atoms with sp² hybridization.
127 Medium
127 of 195
Understanding +4 | -1
Which of the following would be the best (most reactive) nucleophile in the polar medium?
View answer and explanation
Correct option: A
I−I^{-}
Option A (I−I^{-}) is the best nucleophile in a polar protic medium because larger ions are more polarizable and less solvated, making them more reactive.
128 Medium
128 of 195
Analyzing +4 | -1
Which of the following statement(s) is/are correct ?

(i) A carbon atom having an sps p hybrid orbital is less electronegative than carbon atoms possessing sp2s p^2 or sp3s p^3 hybridised orbitals.

(ii) π\pi-bonds provide the most reactive centres in the molecules containing multiple bonds

(iii) The number of σ\sigma and π\pi bonds in compound CH2=C=CHCH3{CH}_2={C}={CHCH}_3 are 7 and 2 respectively.
View answer and explanation
Correct option: C
(ii) only
The correct answer is C ((ii) only) because π-bonds are indeed reactive centers, while the other statements are incorrect regarding electronegativity and bond counts.
129 Medium
129 of 195
Understanding +4 | -1
Arrange the following free radicals in order of decreasing stability.

Methyl (I), Vinyl (II), Allyl (III), Benzyl (IV)
View answer and explanation
Correct option: D
IV >> III >> I >> II
Option D (IV >> III >> I >> II) is correct because benzyl is most stable due to resonance, followed by allyl, methyl, and then vinyl due to resonance and hyperconjugation.
130 Medium
130 of 195
Application +4 | -1
An organic compound contains C=40%,H=13.33%\mathrm{C}=40 \%, \mathrm{H}=13.33 \% and N=46.67%\mathrm{N}=46.67 \%. Its empirical formula would be
View answer and explanation
Correct option: C
CH4 N\mathrm{CH}_4 \mathrm{~N}
Option C (CH4N) is correct because it represents the simplest whole-number ratio of elements in the compound.
131 Medium
131 of 195
Understanding +4 | -1
Assertion: Gravimetric analysis is a time-consuming method of analysis.

Reason: Gravimetric analysis requires the isolation and weighing of a product formed from the analyte, which can be a time-consuming process.
View answer and explanation
Correct option: B
Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion
The correct answer is B (Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion) because while both statements are true, the reason doesn't fully explain why gravimetric analysis is time-consuming.
132 Medium
132 of 195
Understanding +4 | -1
dd- tartaric acid and ll- tartaric acid are :
View answer and explanation
Correct option: D
Enantiomers
Option D (Enantiomers) is correct because d-tartaric acid and l-tartaric acid are non-superimposable mirror images of each other.
133 Medium
133 of 195
Analyzing +4 | -1
Ammonium salts on heating with slaked lime liberate a colourless gas (X)(X). Identify the incorrect statement for gas (X)(X).
View answer and explanation
Correct option: D
(X)(X) does not give clear solution with Ag2O{Ag}_2{O}
Option D ((X)(X) does not give clear solution with Ag2O{Ag}_2{O}) is correct because ammonia reacts with silver oxide to form a complex, resulting in a clear solution, not a precipitate.
134 Medium
134 of 195
Analyzing +4 | -1
Assertion: Tautomerism is shown by all nitro alkanes.

Reason: Tautomerism is shown only when mobile H{H} is present, so 1∘1^{\circ} and 2∘2^{\circ} nitro alkanes show tautomerism.
View answer and explanation
Correct option: D
If both assertion and reason are false
Option D (If both assertion and reason are false) is correct because not all nitro alkanes show tautomerism, and the presence of alpha-hydrogens is essential for tautomerism.
135 Medium
135 of 195
Understanding +4 | -1
Hyperconjugation is:
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because hyperconjugation involves σ−π\sigma - \pi conjugation, delocalization of σ\sigma and π\pi bonds, and is also known as no-bond resonance.
136 Medium
136 of 195
Remembering +4 | -1
In sodium extract test of organic compounds, the nitrogen of an organic compound is converted into:
View answer and explanation
Correct option: B
Sodium cyanide
Option B (Sodium cyanide) is correct because in the Lassaigne's test, nitrogen in the organic compound is converted to sodium cyanide.
137 Medium
137 of 195
Understanding +4 | -1
Strongest nucleophile among the following is
View answer and explanation
Correct option: D
CH3O−\mathrm{CH}_3 \mathrm{O}^{-}
Option D (CH3O−\mathrm{CH}_3 \mathrm{O}^{-}) is correct because it is a strong nucleophile due to the negative charge and the electron-donating inductive effect of the methyl group, which increases electron density.
138 Medium
138 of 195
Analyzing +4 | -1
Assertion (A): The percentage of oxygen in an organic compound is usually found by difference between the total percentage composition (100) and the percentages of all other elements.

Reason (R): Oxygen is present everywhere.
View answer and explanation
Correct option: A
Both A\mathrm{A} and R\mathrm{R} are correct ; R\mathrm{R} is the correct explanation of AA.
Option A (Both A and R are correct; R is the correct explanation of A) is correct because the percentage of oxygen is often found by difference due to its ubiquitous presence.
139 Medium
139 of 195
Analyzing +4 | -1
An organic compound A is oxidised with Na2O2N{a_2}{O_2} followed by boiling with HNO3HN{O_3}. The resultant solution is then treated with ammonium molybdate to yield a yellow precipitate. Based on above observation, the element present in the given compound is
View answer and explanation
Correct option: B
Phosphorus
Option B (Phosphorus) is correct because the formation of a yellow precipitate with ammonium molybdate indicates the presence of phosphate ions, which originate from phosphorus in the organic compound.
140 Medium
140 of 195
Application +4 | -1
0.5 g of hydrocarbon gave 0.9 g water on combustion. The percentage of carbon hydrocarbon is
View answer and explanation
Correct option: C
80.080.0
Option C (80.0) is correct because it calculates the percentage of carbon by subtracting the percentage of hydrogen from 100%.
141 Medium
141 of 195
Understanding +4 | -1
The correct order of acidic strength is:
View answer and explanation
Correct option: A
CH3CF2COOH>CH3CCl2COOH>CH3CBr2COOHC{H_3}C{F_2}COOH > C{H_3}CC{l_2}COOH > C{H_3}CB{r_2}COOH
The correct answer is CH3CF2COOH>CH3CCl2COOH>CH3CBr2COOHC{H_3}C{F_2}COOH > C{H_3}CC{l_2}COOH > C{H_3}CB{r_2}COOH because the acidity increases with the electron-withdrawing inductive effect (-I effect) of the halogens, and the -I effect decreases down the group (F > Cl > Br).
142 Medium
142 of 195
Understanding +4 | -1
Given below are two statements.
Statement I: The presence of weaker π - \pi {\text{ - }} bonds make alkenes less stable than alkanes.
Statement II: The strength of the double bond is greater than that of carbon-carbon single bond.
In the light of the above statements, choose the correct answer from the options given below.
View answer and explanation
Correct option: A
Both Statement I and Statement II are correct.
Option A (Both Statement I and Statement II are correct) is correct because alkenes are indeed less stable than alkanes due to the weaker pi bond, and the strength of a double bond is greater than that of a single bond.
143 Medium
143 of 195
Remembering +4 | -1
Which of the following chromates is not yellow in colour?
View answer and explanation
Correct option: C
Ag2CrO4\mathrm{Ag}_2 \mathrm{CrO}_4
Option C (Ag2CrO4\mathrm{Ag}_2 \mathrm{CrO}_4) is correct because silver chromate (Ag2CrO4\mathrm{Ag}_2 \mathrm{CrO}_4) is red, while the other chromates listed are yellow.
144 Medium
144 of 195
Analyzing +4 | -1
The compound C4H10O{C_4}{H_{10}}O can show
View answer and explanation
Correct option: D
All of these
The correct answer is D (All of these) because C4H10O{C_4}{H_{10}}O can exhibit metamerism, functional isomerism, and position isomerism.
145 Medium
145 of 195
Analyzing +4 | -1
Which of the following compound is not chiral?
View answer and explanation
Correct option: A
1-Chloropentane
The correct answer is A (1-Chloropentane) because it does not have any chiral carbon atoms, meaning no carbon atom is bonded to four different groups.
146 Medium
146 of 195
Analyzing +4 | -1
How many isomers are possible for the compound having molecular formula C3H5Br3{\mathrm{C}_3}{\mathrm{H}_5}\mathrm{B}{\mathrm{r}_3}?
View answer and explanation
Correct option: A
5
Option A (5) is correct because there are 5 possible isomers for the given molecular formula.
147 Medium
147 of 195
Analyzing +4 | -1
Consider the following:

I. SH− II. F− III. N¨H3 IV. OH− V. OR−\text{I. }\mathrm{S H}^{-} \quad \text{ II. }\mathrm{F}^{-} \quad \text{ III. }{{\ddot{\text{N}}}}{{\text{H}}_3}\quad \text{ IV. }\mathrm{OH}^{-} \quad \text{ V. }\mathrm{OR}^{-}

What is the correct order of decreasing nucleophilicity in water?
View answer and explanation
Correct option: D
III >> I >> V >> IV >> II
Option D (III >> I >> V >> IV >> II) is correct because it reflects the correct order of nucleophilicity considering factors like charge, size, and solvent effects.
148 Medium
148 of 195
Remembering +4 | -1
Fischer projection indicates :
View answer and explanation
Correct option: A
Horizontal substituents above the plane
Option A (Horizontal substituents above the plane) is correct because in Fischer projections, horizontal lines represent bonds coming out of the plane towards the viewer.
149 Medium
149 of 195
Remembering +4 | -1
A Dewar flask is usually used to:
View answer and explanation
Correct option: D
Store liquid air
Option D (Store liquid air) is correct because a Dewar flask is designed to provide excellent thermal insulation, making it suitable for storing extremely cold liquids like liquid air.
150 Medium
150 of 195
Remembering +4 | -1
Racemic mixture is formed by mixing two
View answer and explanation
Correct option: D
Optical isomers
Option D (Optical isomers) is correct because a racemic mixture is formed by mixing equal amounts of two enantiomers, which are optical isomers.
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