Skip to main content
Back to HALOALKANES AND HALO ARENES

Your Progress

0 / 95 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • CHEMISTRY • HALOALKANES AND HALO ARENES

Haloalkanes and halo arenes practice · Medium

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 61-90 of 95 questions

Preparing practice and saved progress…

61 Medium
61 of 95
Remembering +4 | -1
he catalyst used in the preparation of an alkyl chloride by the action of dry HCl on an alcohol is
View answer and explanation
Correct option: C
anhy.  ZnCl2\mathrm{anhy}.\mathrm{\;ZnC}{\mathrm{l}_2}
Option C (anhy.  ZnCl2\mathrm{anhy}.\mathrm{\;ZnC}{\mathrm{l}_2}) is correct because anhydrous zinc chloride is a common catalyst used in the reaction of alcohols with dry HCl to form alkyl chlorides (Lucas reagent).
62 Medium
62 of 95
Remembering +4 | -1
Wurtz’s reaction involves the reduction of alkyl halide with
View answer and explanation
Correct option: D
Na in ether
Option D (Na in ether) is correct because Wurtz reaction involves the reaction of alkyl halides with sodium metal in dry ether to form higher alkanes.
63 Medium
63 of 95
Application +4 | -1
C6H5CH2Br→2. H3O+1. Mg,  EtherX{C_6}{H_5}C{H_2}Br\xrightarrow[{2.\,{H_3}{O^ + }}]{{1.\,Mg,\,\,{\text{Ether}}}}X
The product (X)({X}) is :-
View answer and explanation
Correct option: B
C6H5CH3{C}_6 {H}_5 {CH}_3
Option B (C6H5CH3{C}_6 {H}_5 {CH}_3) is correct because the Grignard reagent formed from C6H5CH2Br{C_6}{H_5}C{H_2}Br reacts with water to produce toluene (C6H5CH3{C}_6 {H}_5 {CH}_3).
64 Medium
64 of 95
Remembering +4 | -1
If chloroform is left open in air in the presence of sunlight, it gives
View answer and explanation
Correct option: B
carbonyl chloride
Option B (carbonyl chloride) is correct because chloroform reacts with oxygen in the presence of sunlight to produce phosgene (carbonyl chloride) and hydrochloric acid.
65 Medium
65 of 95
Understanding +4 | -1
Aryl halides can not be prepared by the reaction of aryl alcohols with PCl3,PCl5{PCl}_3, {PCl}_5 or SOCl2{SOCl}_2 because
View answer and explanation
Correct option: B
Carbon-oxygen bond in phenols has a partial double bond character.
Option B (Carbon-oxygen bond in phenols has a partial double bond character) is correct because the resonance in aryl alcohols (phenols) gives the C-O bond a partial double bond character, making it stronger and harder to break.
66 Medium
66 of 95
Analyzing +4 | -1
Which one of the following is most reactive towards aqueous NaOHNaOH?
View answer and explanation
Correct option: B
C6H5CH2Cl{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{Cl}
Option B (C6H5CH2Cl{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{Cl}) is correct because the chlorine atom is attached to a benzylic carbon, which is more reactive towards nucleophilic substitution with aqueous NaOH compared to aryl halides.
67 Medium
67 of 95
Analyzing +4 | -1
Which one of the following halides will not undergo oxidation with dimethyl sulfoxide?
View answer and explanation
Correct option: B
C4H6−C(CH3)2−Br\mathrm{C}_4 \mathrm{H}_6-\mathrm{C}\left(\mathrm{CH}_3\right)_2-\mathrm{Br}
Option B (C4H6-C(CH3)2-Br) is correct because tertiary alkyl halides do not react with DMSO.
68 Medium
68 of 95
Understanding +4 | -1
In SN1{SN}^1 reaction, the recemization takes place. It is due to
View answer and explanation
Correct option: D
Both (1) and (2)
Option D (Both (1) and (2)) is correct because SN1 reactions proceed through a carbocation intermediate, which can be attacked from either side, leading to both inversion and retention of configuration, resulting in racemization.
69 Medium
69 of 95
Analyzing +4 | -1
Statement I : Reaction of 2-bromo-3-mehylbutane with ethanol gives 2-ethoxy-3-methylbutane
Statement II : 1, 4-Hydride shift occurs and forms the unexpected product
View answer and explanation
Correct option: D
Statement II is correct but statement I is incorrect
Option D is correct. Statement I is incorrect because the reaction likely proceeds via an SN1 mechanism with carbocation rearrangement, leading to a different product. Statement II is correct because a hydride shift can occur.
70 Medium
70 of 95
Understanding +4 | -1
For a given alkyl group, the densities/b. p./m. p. are in the order:
View answer and explanation
Correct option: D
RCl<RBr<RIR\mathrm{Cl} < R\mathrm{Br} < R\mathrm{I}
Option D (RCl<RBr<RIR\mathrm{Cl} < R\mathrm{Br} < R\mathrm{I}) is correct because the densities, boiling points, and melting points of alkyl halides increase with increasing molecular weight due to stronger intermolecular forces.
71 Medium
71 of 95
Analyzing +4 | -1
2-chlorobutane obtained by chlorination of butane, will be:
View answer and explanation
Correct option: B
Racemic form
Option B (Racemic form) is correct because the chlorination of butane at the 2-position creates a chiral center, resulting in a racemic mixture.
72 Medium
72 of 95
Remembering +4 | -1
The catalyst used in the preparation of an alkyl chloride by the action of dry HCl{HCl} on an alcohol is
View answer and explanation
Correct option: C
Anhydrous ZnCl2{ZnCl}_2
Option C (Anhydrous ZnCl2{ZnCl}_2) is correct because anhydrous zinc chloride acts as a Lewis acid catalyst in the reaction of alcohols with dry HCl to form alkyl chlorides (Groove's process).
73 Medium
73 of 95
Understanding +4 | -1
Out of the following which is most and least reactive towards nucleophilic substitution respectively?
CH3CO∣∣OCH2−CH3,CH3−CO∣∣−Cl{\text{C}}{{\text{H}}_3}\mathop {\text{C}}\limits^{\begin{array}{cccccccccccccccccccc} {\text{O}} \\ {||} \end{array}} {\text{OC}}{{\text{H}}_2} - {\text{C}}{{\text{H}}_3}, {\text{C}}{{\text{H}}_3} - \mathop {\text{C}}\limits^{\begin{array}{cccccccccccccccccccc} {\text{O}} \\ {||} \end{array}} - {\text{Cl}}

CH3−CO∣∣−NH−CH3,CH3−CO∣∣−O−CO∣∣−CH3{\text{C}}{{\text{H}}_3} - \mathop {\text{C}}\limits^{\begin{array}{cccccccccccccccccccc} {\text{O}} \\ {||} \end{array}} - {\text{NH}} - {\text{C}}{{\text{H}}_3}, {\text{C}}{{\text{H}}_3} - \mathop {\text{C}}\limits^{\begin{array}{cccccccccccccccccccc} {\text{O}} \\ {||} \end{array}} - {\text{O}} - \mathop {\text{C}}\limits^{\begin{array}{cccccccccccccccccccc} {\text{O}} \\ {||} \end{array}} - {\text{C}}{{\text{H}}_3}
View answer and explanation
Correct option: D
CH3COCl,CH3CONHCH3\mathrm{CH}_3 \mathrm{COCl}, \mathrm{CH}_3 \mathrm{CONHCH}_3
Option D (CH3COCl,CH3CONHCH3\mathrm{CH}_3 \mathrm{COCl}, \mathrm{CH}_3 \mathrm{CONHCH}_3) is correct because acid chlorides are the most reactive towards nucleophilic substitution, and amides are the least reactive.
74 Medium
74 of 95
Analyzing +4 | -1
S-I: CHI3CHI_3 gives a precipitate with AgNO3{AgNO}_3 solution on heating but not CHCl3{CHCl}_3

S-II: C−IC-I bond is quite weak as compared to C−Cl{C}-{Cl} bond
View answer and explanation
Correct option: A
Both S-I and S-II are correct
Option A (Both S-I and S-II are correct) is correct because CHI3CHI_3 gives a precipitate with AgNO3{AgNO}_3 on heating due to the weaker C−IC-I bond compared to C−Cl{C}-{Cl} bond in CHCl3CHCl_3.
75 Medium
75 of 95
Remembering +4 | -1
Fires result from the combustion of alkali metals can be extinguished by:
View answer and explanation
Correct option: A
CCl4\mathrm{CC}{\mathrm{l}_4}
Option A (CCl₄) is correct because carbon tetrachloride (CCl₄) is a non-flammable liquid that can extinguish fires involving alkali metals by smothering the fire and preventing oxygen from reaching the metal.
76 Medium
76 of 95
Understanding +4 | -1
The hydrogen atom in chloroform is:
View answer and explanation
Correct option: A
Acidic
Option A is correct because the hydrogen atom in chloroform is acidic due to the electron-withdrawing effect of the chlorine atoms.
77 Medium
77 of 95
Analyzing +4 | -1
Its exposure in air causes impaired hearing and vision. Higher level exposure causes nausea and numbness in fingers and toes. Direct skin contact causes intense burning and mild redness of skin and even burn cornea. Which of the following solvents is responsible for it?
View answer and explanation
Correct option: A
Methylene chloride
Option A (Methylene chloride) is correct because its exposure symptoms match the description given in the question.
78 Medium
78 of 95
Analyzing +4 | -1
Which one of the following is excellent substrate for SN2\mathrm{SN}^2 reaction?
View answer and explanation
Correct option: D
CH3−CO∣∣−CH2Br{\text{C}}{{\text{H}}_3} - \mathop {\text{C}}\limits^{\begin{array}{cccccccccccccccccccc} {\text{O}} \\ {||} \end{array}} - {\text{C}}{{\text{H}}_2}{\text{Br}}
Option D (CH3−CO∣∣−CH2Br{\text{C}}{{\text{H}}_3} - \mathop {\text{C}}\limits^{\begin{array}{cccccccccccccccccccc} {\text{O}} \\ {||} \end{array}} - {\text{C}}{{\text{H}}_2}{\text{Br}}) is the excellent substrate for SN2\mathrm{SN}^2 reaction because the presence of a strong -I group on the alpha-carbon stabilizes the transition state.
79 Medium
79 of 95
Remembering +4 | -1
Ethyl ortho formate is formed by heating ………… with sodium ethoxide.
View answer and explanation
Correct option: A
CHCl3\mathrm{CHC}{\mathrm{l}_3}
Option A is correct. Ethyl orthoformate is formed by heating chloroform (CHCl3\mathrm{CHC}{\mathrm{l}_3}) with sodium ethoxide.
80 Medium
80 of 95
Remembering +4 | -1
Which of the following compounds is an example of Freon?
View answer and explanation
Correct option: D
C2Cl2 F2\mathrm{C}_2 \mathrm{Cl}_2 \mathrm{~F}_2
Option D (C2Cl2 F2\mathrm{C}_2 \mathrm{Cl}_2 \mathrm{~F}_2) is correct because Freons are chlorofluorocarbons, and this compound contains both chlorine and fluorine.
81 Medium
81 of 95
Understanding +4 | -1
Arrange the following in the increasing order of ease of dehydrohalogenation
CH3CH2Cl,CH3CH(Cl)CH3,(CH3)3CCl\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Cl}, \mathrm{CH}_3 \mathrm{CH}(\mathrm{Cl}) \mathrm{CH}_3,\left(\mathrm{CH}_3\right)_3 \mathrm{CCl}
View answer and explanation
Correct option: A
CH3CH2Cl<CH3CH(Cl)CH3<(CH3)3CCl\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Cl} < \mathrm{CH}_3 \mathrm{CH}(\mathrm{Cl}) \mathrm{CH}_3 < \left(\mathrm{CH}_3\right)_3 \mathrm{CCl}
Option A (CH3CH2Cl<CH3CH(Cl)CH3<(CH3)3CCl\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Cl} < \mathrm{CH}_3 \mathrm{CH}(\mathrm{Cl}) \mathrm{CH}_3 < (\mathrm{CH}_3)_3 \mathrm{CCl}) is correct because the ease of dehydrohalogenation follows the stability of the carbocation formed, which is tertiary > secondary > primary.
82 Medium
82 of 95
Analyzing +4 | -1
Arrange the compound of each set in order of reactivity towards SN2S{N^2} displacement

a) 1-Bromo butane \quad \quad b) 1-Bromo-2,2-dimethyl propane

c) 1-Bromo-2-methyl butane \quad d) 1-Bromo-3-methyl butane
View answer and explanation
Correct option: B
a > d > c > b
Option B (a > d > c > b) is correct because SN2S{N^2} reactivity depends on steric hindrance, with less hindered primary alkyl halides reacting faster.
83 Medium
83 of 95
Understanding +4 | -1
Which one of the following compound is obtained when grignard reagent (CH3MgBr)\left(\mathrm{CH}_3 \mathrm{MgBr}\right) is treated with water?
View answer and explanation
Correct option: D
Methane
Option D (Methane) is correct because Grignard reagents react with water to form alkanes, and in this case, methylmagnesium bromide reacts to form methane.
84 Medium
84 of 95
Remembering +4 | -1
When chloroform is exposed to light and damp air, it
gives (among other products):
View answer and explanation
Correct option: B
Carbonyl chloride
Option B (Carbonyl chloride) is correct because chloroform reacts with oxygen in the presence of light to form carbonyl chloride (phosgene).
85 Medium
85 of 95
Remembering +4 | -1
Which of the following represents Westrosol ?
View answer and explanation
Correct option: D
CCl2=CHClCC{l_2} = CHCl
Option D (CCl2=CHClCC{l_2} = CHCl) is correct because Westrosol is the common name for trichloroethylene, which has the formula CCl2=CHClCC{l_2} = CHCl.
86 Medium
86 of 95
Analyzing +4 | -1
On mixing a certain alkane with chlorine and irradiating it with ultraviolet light, it forms only one monochloroalkane.
View answer and explanation
Correct option: D
NeoNeo-pentane
Option D (NeoNeo-pentane) is correct because it's the only alkane that yields only one monochloroalkane due to all its hydrogen atoms being equivalent.
87 Medium
87 of 95
Remembering +4 | -1
The reaction :

C2H5OH+SOCl2⟶ Pyridine C2H5Cl+SO2+HCl{C}_2 {H}_5 {OH}+{SOCl}_2 \stackrel{\text { Pyridine }}{\longrightarrow} {C}_2 {H}_5 {Cl}+{SO}_2+{HCl}
is known as
View answer and explanation
Correct option: C
Darzen's procedure
Option C (Darzen's procedure) is correct because the reaction of an alcohol with thionyl chloride (SOCl₂) in the presence of pyridine to form an alkyl chloride is known as the Darzen's procedure.
88 Medium
88 of 95
Understanding +4 | -1
Propyl iodide and isopropyl iodide are:
View answer and explanation
Correct option: D
Position isomers
The correct answer is D (Position isomers) because propyl iodide and isopropyl iodide differ only in the position of the iodine atom on the carbon chain.
89 Medium
89 of 95
Understanding +4 | -1
Assertion : Alkyl halides are not soluble in water.

Reason : Alkyl halide does not form H-Bonds with water molecule although alkyl halide is polar in nature.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
Option A is correct because both the assertion and reason are true, and the reason correctly explains why alkyl halides are insoluble in water.
90 Medium
90 of 95
Analyzing +4 | -1
Which one of the following is most reactive towards nucleophilic substitution reaction?
View answer and explanation
Correct option: D
ClCH2−CH=CH2{ClCH}_2-{CH}={CH}_2
Option D (ClCH2−CH=CH2{ClCH}_2-{CH}={CH}_2) is correct because the carbocation formed after the departure of Cl is allylic and resonance stabilized, making it more reactive towards nucleophilic substitution.
Revision notes and key takeaways

Review HALOALKANES AND HALO ARENES in your textbook or class notes, then use this set to check your understanding.

Showing 61-90 of 95 questions

Your practice

0 / 95 answered · 95 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.