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JEE • CHEMISTRY • HALOALKANES AND HALO ARENES

Haloalkanes and halo arenes practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 35 questions
1 Easy
1 of 35
Remembering +4 | -1
An alkyl halide reacts with metallic sodium in dry ether. The reaction is known as :
View answer and explanation
Correct option: C
Wurtz reaction
The correct answer is C (Wurtz reaction) because the reaction of an alkyl halide with metallic sodium in dry ether is the Wurtz reaction.
2 Easy
2 of 35
Application +4 | -1
Friedel-Craft’s reaction of bromobenzene with methyl iodide gives:
View answer and explanation
Correct option: C
o− and p−o - \,\mathrm{and}\,p -bromotoluene
Option C (o− and p−o - \,\mathrm{and}\,p -bromotoluene) is correct because the methyl group attaches at the ortho and para positions due to the directing effect of the bromo group.
3 Easy
3 of 35
Remembering +4 | -1
The reaction of C6H5 N2+Cl−\mathrm{C}_6 \mathrm{H}_5 \mathrm{~N}_2^{+} \mathrm{Cl}^{-}with CuCl\mathrm{CuCl} gives
View answer and explanation
Correct option: A
C6H5Cl\mathrm{C}_6 \mathrm{H}_5 \mathrm{Cl}
The correct answer is A (C₆H₅Cl) because the reaction of C₆H₅N₂⁺Cl⁻ with CuCl/HCl is the Sandmeyer reaction, which yields chlorobenzene.
4 Easy
4 of 35
Remembering +4 | -1
Which of the following is an example of aryl alkyl halide?
View answer and explanation
Correct option: D
Benzyl chloride
Option D (Benzyl chloride) is correct because benzyl chloride has a chlorine atom (halogen) attached to a carbon that is directly bonded to an aromatic ring (aryl group), making it an aryl alkyl halide.
5 Easy
5 of 35
Understanding +4 | -1
Vicinal and geminal dihalides can be distinguished by:
View answer and explanation
Correct option: A
KOH(aq.)\left( {aq.} \right)
Option A (KOH(aq.)) is correct because it can differentiate vicinal and geminal dihalides based on the different products formed during hydrolysis.
6 Easy
6 of 35
Application +4 | -1
The major product formed in the following reaction :

CH3CH(Cl)CH2−CH2OH⟶ aq. KOH{CH}_3 {CH}({Cl}) {CH}_2-{CH}_2 {OH} \stackrel{\text { aq. } {KOH}}{\longrightarrow} is :
View answer and explanation
Correct option: D
CH3−CH∣OH−CH2−CH2OHC{H_3} - \mathop {CH}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {OH} \end{array}} - C{H_2} - C{H_2}OH
Option D (CH3−CH∣OH−CH2−CH2OHC{H_3} - \mathop {CH}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {OH} \\ \end{array}} - C{H_2} - C{H_2}OH) is correct because the aqueous KOH will substitute the chlorine atom with a hydroxyl group.
7 Easy
7 of 35
Understanding +4 | -1
C−X{C}-{X} bond is strongest in
View answer and explanation
Correct option: C
CH3F{CH}_3 {F}
Option C (CH3F{CH}_3 {F}) is correct because the C-F bond is the strongest due to the small size and high electronegativity of fluorine, leading to a shorter and stronger bond.
8 Easy
8 of 35
Analyzing +4 | -1
CH3−CH3∣C∣CH3−Br+KOH(aq)→CH3−CH3∣C∣CH3−OH+KBrC{H_3} - \begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \\ C \\ | \\ {C{H_3}} \end{array} - Br + KOH\left( {aq} \right) \to C{H_3} - \begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \\ C \\ | \\ {C{H_3}} \end{array} - OH + KBr Above reaction is
View answer and explanation
Correct option: A
SN1S{N^1}
Option A is correct because the reaction proceeds via a SN1 mechanism due to the formation of a stable tertiary carbocation intermediate.
9 Easy
9 of 35
Remembering +4 | -1
Which one of the following has antiseptic property?
View answer and explanation
Correct option: C
Triiodomethane
Option C (Triiodomethane) is correct because triiodomethane (iodoform) decomposes to release iodine, which has antiseptic properties.
10 Easy
10 of 35
Application +4 | -1
The number of stereoisomers of compound

CH3−CH=CH−CHBr−CH3\mathrm{C}{\mathrm{H}_3}-\mathrm{CH} = \mathrm{CH}-\mathrm{CHBr}-\mathrm{C}{\mathrm{H}_3} would be:
View answer and explanation
Correct option: D
4
The correct answer is D (4). The compound has one chiral center and exhibits cis/trans isomerism around the double bond, leading to 4 stereoisomers.
11 Easy
11 of 35
Analyzing +4 | -1
Assertion (A): Electrophilic substitution reactions in haloarene occur slowly and under drastic conditions.

Reason (R): Haloarenes are highly active as compared to benzene.
View answer and explanation
Correct option: C
A is correct; R is incorrect
The correct answer is C (A is correct; R is incorrect) because haloarenes are less reactive than benzene due to the -I effect of the halogen.
12 Easy
12 of 35
Remembering +4 | -1
Iodoform is obtained when ethanol is heatd with
View answer and explanation
Correct option: B
I2{\mathrm{I}_2} and aq. KOH
Option B (I2{\mathrm{I}_2} and aq. KOH ) is correct because the reaction of ethanol with iodine and aqueous KOH produces iodoform due to the formation of hypoiodite ion, which acts as an oxidizing agent.
13 Easy
13 of 35
Understanding +4 | -1
Which among MeX,RCH2X,R2CHX\mathrm{MeX}, \mathrm{RCH}_2 \mathrm{X}, \mathrm{R}_2 \mathrm{CHX} and R3CX\mathrm{R}_3 \mathrm{CX} is most reactive towards SN2\mathrm{S}_{\mathrm{N}} 2 reaction?
View answer and explanation
Correct option: A
MeX\mathrm{MeX}
Option A (MeX\mathrm{MeX}) is correct because it experiences the least steric hindrance, making it the most reactive in SN2S_N2 reactions.
14 Easy
14 of 35
Remembering +4 | -1
Which compound is used in cooling?
View answer and explanation
Correct option: D
CCl2F2\mathrm{CC}{\mathrm{l}_2}{\mathrm{F}_2}
Option D (CCl2F2\mathrm{CC}{\mathrm{l}_2}{\mathrm{F}_2}) is correct because Dichlorodifluoromethane (Freon-12) is commonly used as a refrigerant in cooling systems.
15 Easy
15 of 35
Analyzing +4 | -1
Consider the reaction:

(i) (CH3)2CH−CH2Br⟶C2H5OH(CH3)2CH−CH2OC2H5+HBr\left({CH}_3\right)_2 {CH}-{CH}_2 {Br} \stackrel{{C}_2 {H}_5 {OH}}{\longrightarrow}\left({CH}_3\right)_2 {CH}-{CH}_2 {OC}_2 {H}_5+{HBr}

(ii) (CH3)2CH−CH2Br⟶C2H5O−(CH3)2CH−CH2OC2H5+Br−\left({CH}_3\right)_2 {CH}-{CH}_2 {Br} \stackrel{{C}_2 {H}_5 {O}^{-}}{\longrightarrow}\left({CH}_3\right)_2 {CH}-{CH}_2 {OC}_2 {H}_5+{Br}^{-}

The mechanisms of reaction (i) and (ii) are respectively :-
View answer and explanation
Correct option: D
SN2{S}{{N}^2} and SN2{S}{{N}^2}
Option B (SN1{S}{{N}^1} and SN2{S}{{N}^2}) is correct because reaction (i) with C2H5OHC_2H_5OH favors SN1S_N1 due to the formation of a carbocation, while reaction (ii) with C2H5O−C_2H_5O^- favors SN2S_N2 due to the strong nucleophile.

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16 Easy
16 of 35
Analyzing +4 | -1
Assertion : CHCl3{CHCl}_3 is more acidic than CHF3{CHF}_3.

Reason : The conjugate base of CHCl3{CHCl}_3 is more stable than CHF3{CHF}_3.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A is correct because both the assertion and reason are true, and the reason correctly explains why chloroform is more acidic than fluoroform due to the greater stability of its conjugate base.
17 Easy
17 of 35
Remembering +4 | -1
The reaction between a primary amine, chloroform and
few drops of alcoholic KOH is known as:
View answer and explanation
Correct option: B
Carbylamine reaction
Option B (Carbylamine reaction) is correct because the reaction between a primary amine, chloroform, and alcoholic KOH is known as the Carbylamine reaction, which produces an isocyanide.
18 Easy
18 of 35
Understanding +4 | -1
Dehydrohalogenation in haloalkanes produces:
View answer and explanation
Correct option: B
A double bond
Option B (A double bond) is correct because dehydrohalogenation, which is the removal of a hydrogen and a halogen from a haloalkane, results in the formation of a double bond.
19 Easy
19 of 35
Remembering +4 | -1
For the carbylamine reaction we need hot alcoholic KOH and:
View answer and explanation
Correct option: D
Any monoalkyl amine and trichloro methane
Option D (Any monoalkyl amine and trichloro methane) is correct because the carbylamine reaction involves a primary amine, chloroform (trichloromethane), and a base like KOH.
20 Easy
20 of 35
Understanding +4 | -1
Ammonolysis of alkyl halides followed by the treatment with NaOHNaOH solution can be used to prepare primary, secondary and tertiary amines. The purpose of NaOHNaOH in the reaction is
View answer and explanation
Correct option: C
to remove acidic impurities
Option C is correct because NaOH is a base and is used to neutralize the acidic impurities (HX) formed during the ammonolysis of alkyl halides.
21 Easy
21 of 35
Remembering +4 | -1
Benzylidene chloride is
View answer and explanation
Correct option: C
C6H5CHCl2C_6H_5CHCl_2
Option C (C6H5CHCl2C_6H_5CHCl_2) is correct because Benzylidene chloride has the formula C6H5CHCl2C_6H_5CHCl_2.
22 Easy
22 of 35
Remembering +4 | -1
Which of the following can be used as local anaesthetic?
View answer and explanation
Correct option: C
C2H5Cl{C_2}{H_5}Cl
Option C (C2H5Cl{C_2}{H_5}Cl) is correct because alkyl chlorides, such as ethyl chloride, are known to be used as local anesthetics.
23 Easy
23 of 35
Understanding +4 | -1
The carbon atom to which the halogen is attached can be
View answer and explanation
Correct option: D
Both (1) and (2)
Option D is correct because the carbon atom to which a halogen is attached can be either sp2sp^2 hybridized (as in vinylic and aryl halides) or sp3sp^3 hybridized (as in alkyl, allylic, and benzylic halides).
24 Easy
24 of 35
Understanding +4 | -1
The hydrolysis of alkyl halides by aqueous NaOH is best termed as :
View answer and explanation
Correct option: D
Nucleophilic substitution reaction
Option D (Nucleophilic substitution reaction) is correct because the hydroxide ion (OH-) from NaOH acts as a nucleophile, substituting the halide (X) in the alkyl halide.
25 Easy
25 of 35
Remembering +4 | -1
Solvent which is used in the synthesis of chlorofluorocarbons
View answer and explanation
Correct option: C
Carbon tetrachloride
Option C (Carbon tetrachloride) is correct because carbon tetrachloride is used as a solvent in the synthesis of chlorofluorocarbons.
26 Easy
26 of 35
Analyzing +4 | -1
Chlorine is most reactive towards NaOH in:
View answer and explanation
Correct option: D
C6H5CH2Cl{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{Cl}
Option D is correct because the benzyl carbonium ion formed after the removal of chlorine is the most stable due to resonance stabilization, making it most reactive towards NaOH.
27 Easy
27 of 35
Understanding +4 | -1
Which reagent is useful in increasing the carbon chain of an alkyl halide?
View answer and explanation
Correct option: B
KCN
Option B (KCN) is correct because KCN provides the cyanide ion which acts as a nucleophile and increases the carbon chain of the alkyl halide via an SN2 reaction.
28 Easy
28 of 35
Remembering +4 | -1
Lacrymator or tear gas is:
View answer and explanation
Correct option: C
C6H5COCH2Cl{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{COC}{\mathrm{H}_2}\mathrm{Cl}
Option C (C6H5COCH2Cl{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{COC}{\mathrm{H}_2}\mathrm{Cl}) is correct because phenacyl chloride (C6H5COCH2Cl{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{COC}{\mathrm{H}_2}\mathrm{Cl}) is a well-known lachrymator or tear gas.
29 Easy
29 of 35
Remembering +4 | -1
The general molecular formula of alkyl halides is ______ .
View answer and explanation
Correct option: D
CnH2n+1XC _{ n } H _{2 n +1} X
Option D (CnH2n+1XC _{ n } H _{2 n +1} X) is correct because alkyl halides are derived from alkanes by replacing one hydrogen atom with a halogen atom.
30 Easy
30 of 35
Understanding +4 | -1
S-I: CCl4{CCl}_4 and H2O{H}_2 {O} are immiscible.

S-II: CCl4{C C l}_4 is a polar solvent.
View answer and explanation
Correct option: C
S-I is correct but S-II is wrong
Option C (S-I is correct but S-II is wrong) is correct because CCl4{CCl}_4 and H2O{H}_2 {O} are immiscible, and CCl4{CCl}_4 is non-polar, not polar.
Revision notes and key takeaways

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Key Takeaways

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