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JEE • CHEMISTRY • Equilibrium
Equilibrium practice · Medium
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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331
Medium
331 of 401
Application
+4 | -1
Equal volumes of two solutions of a strong acid having are mixed together. The of the resulting solution is
View answer and explanation
Correct option: B
3.26
Option B (3.26) is correct because it's the calculated pH of the mixture of two strong acid solutions using the average hydrogen ion concentration.
332
Medium
332 of 401
Understanding
+4 | -1
Which of the following salts when dissolved in water will hydrolyze?
View answer and explanation
Correct option: C
Option C () is correct because ammonium chloride is a salt of a weak base (ammonium hydroxide) and a strong acid (hydrochloric acid), and therefore undergoes hydrolysis in water.
333
Medium
333 of 401
Application
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Some solid ammonium carbonate is take in a evacuated vessel and the vessel is sealed after a very long time a constant pressure of is observed due to dissociation of the solid into and gas. Calculate the dissociation constant of solid.
View answer and explanation
Correct option: A
Option A () is correct because it is calculated by determining the partial pressures of the products and then using them to calculate the equilibrium constant Kp.
334
Medium
334 of 401
Analyzing
+4 | -1
equilibrium constant
equilibrium constant
The equilibrium constant for the following reaction will be:
equilibrium constant
The equilibrium constant for the following reaction will be:
View answer and explanation
Correct option: C
Option C is correct because the equilibrium constant for the overall reaction is obtained by dividing the equilibrium constant of the second reaction by that of the first.
335
Medium
335 of 401
Understanding
+4 | -1
What is the best description of the change that occurs when is dissolved in water?
View answer and explanation
Correct option: B
Oxide ion accepts sharing in a pair of electrons
Option C (Oxide ion donates a pair of electrons) is correct because when Na₂O dissolves in water, the oxide ion (O²⁻) acts as a Lewis base and donates a pair of electrons to a water molecule, forming hydroxide ions (OH⁻).
336
Medium
336 of 401
Understanding
+4 | -1
Favorable condition for product formation in the given reaction.
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Correct option: A
High pressure
Option A (High pressure) is correct because the forward reaction decreases the number of moles of gas, so high pressure favors product formation according to Le Chatelier's principle.
337
Medium
337 of 401
Analyzing
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Assertion :- Solubility of sparingly soluble salt increases with increase in temperature.
Reason :- Enthalpy of solution is negative for all salts.
Reason :- Enthalpy of solution is negative for all salts.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C is correct because the assertion is true (solubility of sparingly soluble salts generally increases with temperature), but the reason is false (enthalpy of solution can be positive or negative).
338
Medium
338 of 401
Application
+4 | -1
A solution of ammonium acetate is diluted by adding of water. The of the resulting solution will be of acetic acid is equal to of )
View answer and explanation
Correct option: D
Option D () is correct because ammonium acetate is a salt of a weak acid and a weak base, and since pKa = pKb, the pH is 7.
339
Medium
339 of 401
Application
+4 | -1
A volume of of solution is mixed with of solution. Calculate the of the resulting solution. The value of of
View answer and explanation
Correct option: A
9.9
Option A (9.9) is correct because the pH of the buffer solution is calculated using the Henderson-Hasselbalch equation.
340
Medium
340 of 401
Application
+4 | -1
of ammonium sulphate is mixed with of calcium nitrate. The ionic product of will be: for
View answer and explanation
Correct option: A
Option A () is correct because the calculated ionic product is less than the given solubility product, indicating that a precipitate will not form.
341
Medium
341 of 401
Application
+4 | -1
What should be the of solution to dissolve the
[Given,
[Given,
View answer and explanation
Correct option: C
5
Option C (5) is correct because the pH must be greater than or equal to 4.253 to dissolve the precipitate, making pH 5 the appropriate choice.
342
Medium
342 of 401
Application
+4 | -1
of mixture of acetic acid and sodium acetate required of for neutralization of the acid and of of the acid is what is the of the mixture?
View answer and explanation
Correct option: A
Option A (5.05) is correct because it accurately calculates the pH of the buffer solution using the Henderson-Hasselbalch equation.
343
Medium
343 of 401
Application
+4 | -1
of pure is dissolved in of distilled water. The of the solution is:
View answer and explanation
Correct option: B
10
Option B (10) is correct because it is calculated by first finding the molarity of the NaOH solution, then calculating the pOH, and finally determining the pH.
344
Medium
344 of 401
Analyzing
+4 | -1
Assertion (A): pH value of solution is less than that of acetic acid of the some concentration.
Reason (R): Inequimolar solution, the number of titrable protons present in is less than that present in acetic acid.
Reason (R): Inequimolar solution, the number of titrable protons present in is less than that present in acetic acid.
View answer and explanation
Correct option: C
Assertion is true but Reason is false
Option C is correct. HCl is a strong acid and dissociates completely, resulting in a lower pH than acetic acid, which is a weak acid. The reason is incorrect because HCl has more titrable protons.
345
Medium
345 of 401
Understanding
+4 | -1
From a weak acid of , the range of practically possible buffer solution is
View answer and explanation
Correct option: A
5 to 7
Option A is correct because the pH range of a buffer solution is typically , so for a weak acid with , the pH range is 5 to 7.
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346
Medium
346 of 401
Application
+4 | -1
The solubility of in is of )
View answer and explanation
Correct option: B
Option B () is correct because the solubility product expression is used to calculate the solubility of AgCl in the presence of a common ion.
347
Medium
347 of 401
Understanding
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The correct statement about buffer solution is:
View answer and explanation
Correct option: C
It shows little change in on adding small amount of an acid or base
Option C is correct because a buffer solution resists changes in pH upon the addition of small amounts of acid or base.
348
Medium
348 of 401
Understanding
+4 | -1
According to Bronsted-Lowry concept, the correct order of relative strength of bases follows the order:
View answer and explanation
Correct option: C
Option C is correct. The order of relative base strength is determined by the strength of their conjugate acids, with weaker acids corresponding to stronger bases. OH- is the strongest base, followed by CH3COO-, and then Cl-.
349
Medium
349 of 401
Application
+4 | -1
5 moles of are mixed with 3 moles of . At equilibrium for the reaction, 2 moles of are formed. The equilibrium constant for the reaction will be
View answer and explanation
Correct option: A
Option A () is correct because the equilibrium constant is calculated as the ratio of the concentration of products to reactants at equilibrium, which in this case is .
350
Medium
350 of 401
Remembering
+4 | -1
If is in the range of _____ appreciable concentrations of both reactants and products are present.
View answer and explanation
Correct option: B
to
Option B ( to ) is correct because when the equilibrium constant is within this range, the reaction mixture contains appreciable amounts of both reactants and products.
351
Medium
351 of 401
Analyzing
+4 | -1
(A): If solubility of is mole/litre, its solubility product will be
(R): Solubility product of is given by expression
(R): Solubility product of is given by expression
View answer and explanation
Correct option: D
Both (A) and (R) is false
Option D is correct because both the assertion and the reason are false. The solubility product of is , and the expression for is .
352
Medium
352 of 401
Application
+4 | -1
What is the ion concentration of a solution prepared by dissolving of (Atomic weight of ) in ?
View answer and explanation
Correct option: D
Option D () is correct because the hydrogen ion concentration is calculated using the ion product of water ().
353
Medium
353 of 401
Application
+4 | -1
A buffer solution is prepared by mixing 0.1 M ammonia and 1.0 M ammonium chloride. At 298 K, the The pH of the buffer is
View answer and explanation
Correct option: D
8
Option D (8) is correct because it is calculated using the Henderson-Hasselbalch equation for a buffer solution, considering the pKb of ammonia and the concentrations of ammonia and ammonium chloride.
354
Medium
354 of 401
Application
+4 | -1
The equilibrium shows that is times the value of at a particular temperature . Then (in ) is:
View answer and explanation
Correct option: C
300
Option A ( ) is correct because it's the degree of association calculated using the van't Hoff factor and the freezing point depression.
355
Medium
355 of 401
Application
+4 | -1
The number of ions present in 1 ml of a solution having is
View answer and explanation
Correct option: C
Option C () is correct because it calculates the number of H+ ions from pH and converts concentration to number of ions in 1 ml.
356
Medium
356 of 401
Analyzing
+4 | -1
At , the solubility of will be maximum in -
View answer and explanation
Correct option: D
Option D () is correct because the solubility of increases in due to the formation of a complex ion, while it decreases in and due to the common ion effect.
357
Medium
357 of 401
Analyzing
+4 | -1
Assertion (A): The degree of dissociation of is more in a solution which is basic than in water.
Reason (R): of increases in basic solution.
Reason (R): of increases in basic solution.
View answer and explanation
Correct option: C
(A) is true but (R) is false
Option C ((A) is true but (R) is false) is correct because the degree of dissociation increases in a basic solution, but the Ka value remains constant as it's a characteristic of the acid.
358
Medium
358 of 401
Application
+4 | -1
When 0.5 mole of is placed in a reaction vessel and heated at of the decomposes to . Calculate value of at , for the reaction : .
View answer and explanation
Correct option: A
50
The correct answer is A (50) because Kp is calculated using the equilibrium constant Kc and the ideal gas constant R, along with the temperature and change in moles.
359
Medium
359 of 401
Analyzing
+4 | -1
What are the product formed when Deuterium is added equilibrium reaction of and ?
(i)
(ii)
(iii)
(iv)
(i)
(ii)
(iii)
(iv)
View answer and explanation
Correct option: D
All of these
The correct answer is D (All of these) because in a dynamic equilibrium, all possible isotopic combinations can form.
360
Medium
360 of 401
Analyzing
+4 | -1
Which of the following statements are correct ?
(i) The extent of dissociation of an acid depends on the strength and polarity of the bond (where is an electronegative element.)
(ii) As the strength of bond increases, the energy required to break the bond decreases.
(iii) As the electronegativity difference between the atoms and increases, acidity increases
(i) The extent of dissociation of an acid depends on the strength and polarity of the bond (where is an electronegative element.)
(ii) As the strength of bond increases, the energy required to break the bond decreases.
(iii) As the electronegativity difference between the atoms and increases, acidity increases
View answer and explanation
Correct option: C
(i) and (iii)
Option C ((i) and (iii)) is correct because the extent of dissociation depends on the H-A bond strength and polarity, and acidity increases with increasing electronegativity difference.
Revision notes and key takeaways
Review Equilibrium in your textbook or class notes, then use this set to check your understanding.
Showing 331-360 of 401 questions
