In the manufacture of ammonia by Haber’s process, ${{\rm{N}}_2}\left( {\rm{g}} \right) + 3{{\rm{H}}_2}\;\leftrightharpoons\;2{\rm{N}}{{\rm{H}}_3}\left( {\rm{g}} \right) + 92.3\;{\rm{kJ}}$ Which of the following condition is unfavourable?

Removing ammonia as it is formed

The most favourable condition for the manufacture of ${\rm{N}}{{\rm{H}}_3}$ is

high temperature and high pressure

low temperature and low pressure

high temperature and low pressure

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JEE • CHEMISTRY • Equilibrium

Equilibrium practice · Easy

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Practice format and chapter quiz

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Showing 151-161 of 161 questions

151 Easy

151 of 161

Understanding +4 | -1

A cylinder provided with a piston has some

\mathrm{PCl}_5

which is in equilibrium with

\mathrm{PCl}_3

and

\mathrm{Cl}_2

. The system is compressed with the help of piston. Indicate the correct statement.

View answer and explanation

Correct option: C

\mathrm{PCl}_3

and

\mathrm{Cl}_2

will combine to form

\mathrm{PCl}_5

The correct answer is C. Compressing the system favors the reverse reaction, combining

PCl_3

and

Cl_2

to form

PCl_5

152 Easy

152 of 161

Understanding +4 | -1

Which one of the following species acts as both Bronsted acid and base?

View answer and explanation

Correct option: C

\mathrm{HPO}_4^{2 - }

Option C (

\mathrm{HPO}_4^{2 - }

) is correct because it can both accept a proton (acting as a base) and donate a proton (acting as an acid).

153 Easy

153 of 161

Remembering +4 | -1

Soda water has a pH value:

View answer and explanation

Correct option: A

Less than 7

Option A (Less than 7) is correct because soda water contains dissolved CO2, which forms carbonic acid, making it acidic.

154 Easy

154 of 161

Understanding +4 | -1

According to Le-chatelier's principle, adding heat to a solid

\rightleftharpoons

liquid equilibrium will cause the

View answer and explanation

Correct option: D

Amount of solid to decrease

Option D (Amount of solid to decrease) is correct because, according to Le Chatelier's principle, adding heat to an endothermic equilibrium (solid to liquid) will shift the equilibrium towards the liquid phase, thus decreasing the amount of solid.

155 Easy

155 of 161

Analyzing +4 | -1

Which of the following will not function as a buffer solution?

(i)

\mathrm{NaCl}

and

\mathrm{NaOH}

(ii)

\mathrm{NaOH}

and

\mathrm{N}{\mathrm{H}_4}\mathrm{OH}

(iii)

\mathrm{C}{\mathrm{H}_3}\mathrm{COON}{\mathrm{H}_4}

and

\mathrm{HCl}

(iv) Borax and boric acid

View answer and explanation

Correct option: A

(i), (ii), (iii)

Option D ((i), (ii), (iii), (iv)) is incorrect, it should be Option A ((i), (ii), (iii)). NaCl and NaOH, NaOH and NH4OH, and CH3COONH4 and HCl will not function as buffer solutions because they do not contain a weak acid/base and its conjugate.

156 Easy

156 of 161

Understanding +4 | -1

In the manufacture of ammonia by Haber’s process,

{\mathrm{N}_2}\left( \mathrm{g} \right) + 3{\mathrm{H}_2}\;\leftrightharpoons\;2\mathrm{N}{\mathrm{H}_3}\left( \mathrm{g} \right) + 92.3\;\mathrm{kJ}

Which of the following condition is unfavourable?

View answer and explanation

Correct option: A

Increasing the temperature

Option A (Increasing the temperature) is correct because the reaction is exothermic, and increasing the temperature will shift the equilibrium to the left, disfavouring the formation of ammonia.

157 Easy

157 of 161

Application +4 | -1

A buffer mixture of acetic acid and potassium acetate has

\mathrm{pH} = 5.24.

The ratio of

\left[ {\mathrm{C}{\mathrm{H}_3}\mathrm{CO}{\mathrm{O}^ - }} \right]/\left[ {\mathrm{C}{\mathrm{H}_3}\mathrm{COOH}} \right]

in this buffer is,

\left( {\mathrm{p}{K_a} = 4.74} \right):

View answer and explanation

Correct option: A

3:1

Option A (3:1) is correct because it represents the ratio of [CH₃COO⁻]/[CH₃COOH] calculated using the Henderson-Hasselbalch equation.

158 Easy

158 of 161

Application +4 | -1

A weak acid HX has the dissociation constant

1 \times {10^{ - 5}}\;M

. It forms a salt

\mathrm{Na}X

on reaction with alkali. The degree of hydrolysis of

0.1\;M

solution of

\mathrm{Na}X

View answer and explanation

Correct option: B

0.01\%

Option B (

0.01\%

) is correct because it is the degree of hydrolysis calculated using the hydrolysis constant and the concentration of the salt.

159 Easy

159 of 161

Application +4 | -1

Water in equilibrium with air contains

4.4 \times 10^{-5} \%

\mathrm{CO}_2.

The resulting carbonic acid

\left(\mathrm{H}_2 \mathrm{CO}_3\right)

gives the solution a hydronium ion concentration of

2.0 \times 10^{-6} \mathrm{M}

about 20 times greater than that of pure water. What is the

\mathrm{pH}

of the solution at

298 \, \mathrm{K} ?\, (\log 4.4=0.64, \log 2=0.3)

View answer and explanation

Correct option: B

5.7

Option B (5.7) is correct because the pH is calculated directly from the given hydronium ion concentration.

160 Easy

160 of 161

Understanding +4 | -1

The

{K_C}

for

{H_2}(g) + {I_2}(g)2HI(g)

is 64, if the volume of the container is reduced to one-half of its
original volume, the value of equilibrium constant will be

View answer and explanation

Correct option: B

Option B (64) is correct because the equilibrium constant, Kc, is independent of volume changes for the given reaction.

161 Easy

161 of 161

Understanding +4 | -1

The most favourable condition for the manufacture of

\mathrm{N}{\mathrm{H}_3}

View answer and explanation

Correct option: D

low temperature and high pressure

Option D (low temperature and high pressure) is correct because the forward reaction in the synthesis of ammonia is exothermic and involves a decrease in volume, favoring low temperature and high pressure according to Le Chatelier's principle.

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