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JEE • CHEMISTRY • Equilibrium

Equilibrium practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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121 Easy
121 of 161
Application +4 | -1
In the reaction, C(s)+CO2( g)=2CO(g)\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{~g})=2 \mathrm{CO}(\mathrm{g}), the following amounts of substances were formed in 0.2 litre flask at equilibrium, C=0.1\mathrm{C}=0.1 mole, CO=0.05\mathrm{CO}=0.05 mole, CO2=0.06\mathrm{CO}_2=0.06 mole. The equilibrium constant is
View answer and explanation
Correct option: A
0.208
Option A (0.208) is correct because it is calculated using the equilibrium constant expression with the given concentrations.
122 Easy
122 of 161
Analyzing +4 | -1
Statement (S): The acidic nature of some cations is :
Al3+>Be2+>Na+>K+\mathrm{Al}^{3+}>\mathrm{Be}^{2+}>\mathrm{Na}^{+}>\mathrm{K}^{+}

Explanation (E): More is the effective nuclear charge on cation more is its acidic nature.
View answer and explanation
Correct option: C
Both S and E are correct and E is correct explanation for S
Option C (Both S and E are correct and E is correct explanation for S) is correct because the acidic nature of cations increases with increasing effective nuclear charge.
123 Easy
123 of 161
Understanding +4 | -1
H3BO3{\mathrm{H}_3}\mathrm{B}{\mathrm{O}_3} is:
View answer and explanation
Correct option: A
Monobasic and weak Lewis acid
Option A (Monobasic and weak Lewis acid) is correct because H3BO3{\mathrm{H}_3}\mathrm{B}{\mathrm{O}_3} accepts hydroxide ions from water, acting as a weak Lewis acid and releasing a proton.
124 Easy
124 of 161
Understanding +4 | -1
If pressure increases then its effect on given equilibrium

2NO(g)⇋N2(g)+O2(g)2\mathrm{NO}\left( \mathrm{g} \right)\leftrightharpoons{\mathrm{N}_2}\left( \mathrm{g} \right) + {\mathrm{O}_2}\left( \mathrm{g} \right) is shift in
View answer and explanation
Correct option: C
No effect
Option C (No effect) is correct because, according to Le Chatelier's principle, pressure changes have no effect on equilibrium when the number of moles of gaseous reactants equals the number of moles of gaseous products.
125 Easy
125 of 161
Understanding +4 | -1
Which can act as buffer:
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because all the given mixtures (acetic acid/sodium acetate, ammonium chloride/ammonium hydroxide, and HCN/NaCN) are buffer solutions.
126 Easy
126 of 161
Application +4 | -1
The degree of ionisation of an acid HAHA is 0.00001 at 0.1 M0.1 \, \mathrm{M} concentration. Its dissociation constant is
View answer and explanation
Correct option: B
10−1110^{-11}
The correct answer is 10−1110^{-11} because the dissociation constant is calculated using the formula Ka=Cα2K_a = C \alpha^2.
127 Easy
127 of 161
Analyzing +4 | -1
Which species acts as stronger acid than formic acid in aqueous solution?
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Correct option: B
H2SO4{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}
Option B is correct because sulfuric acid is a strong acid that almost completely ionizes in aqueous solution.
128 Easy
128 of 161
Application +4 | -1
For the reaction, H2+I2  ⇋  2HI{\mathrm{H}_2} + {\mathrm{I}_2}\;\leftrightharpoons\;2\mathrm{HI}, the equilibrium concentration of H2,I2  and    HI{\mathrm{H}_2},{\mathrm{I}_2}\;\mathrm{and}\;\;\mathrm{ HI} are 8.0,  3.0  and  28.0  mol/L8.0,\;3.0\mathrm{ }\;and\mathrm{ }\;28.0\mathrm{ }\;mol/L respectively. The equilibrium constant is
View answer and explanation
Correct option: B
32.6632.66
Option B (32.66) is correct because it is the equilibrium constant calculated from the given equilibrium concentrations using the equilibrium expression.
129 Easy
129 of 161
Understanding +4 | -1
In the heterogeneous equilibrium:
CaCO3(s)⇌NH3(g);Kp=4.0×104{CaCO}_3({s}) \rightleftharpoons {NH}_3({g}) ; {K}_{{p}}=4.0 \times 10^4
what would be the effect of addition of CaCO3{CaCO}_3 on the equilibrium concentration of CO2?{CO}_2?
View answer and explanation
Correct option: D
Remains unaffected
Option D (Remains unaffected) is correct because the addition of a solid reactant or product does not affect the equilibrium concentration of gaseous species in a heterogeneous equilibrium.
130 Easy
130 of 161
Analyzing +4 | -1
Nature of 0.1 M solution of sodium bisulphite is
View answer and explanation
Correct option: B
Alkaline
Option B (Alkaline) is correct because sodium bisulphite (NaHSO3NaHSO_3) forms bisulphite ions (HSO3−HSO_3^−) in solution, which can act as a weak acid, but the hydrolysis of SO32−SO_3^{2-} makes the solution alkaline.
131 Easy
131 of 161
Analyzing +4 | -1
Assertion : The value of KK gives us a relative idea about the extent to which a reaction proceeds.

Reason : The value of KK is independent of the stochiometry of reactants and products at the point of equilibrium.
View answer and explanation
Correct option: C
If assertion is true but reason is false.
Option C is correct. The assertion is true because K indicates the extent of a reaction. The reason is false because K is dependent on the stoichiometry of the balanced chemical equation.
132 Easy
132 of 161
Analyzing +4 | -1
Which one of the following statement is not true?
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Correct option: C
The  pH  of  1×10−8  M  HCl  is  8\mathrm{The}\;\mathrm{ pH}\;\mathrm{ of}\;1 \times {10^{ - 8}}\;\mathrm{M}\;\mathrm{ HCl}\;\mathrm{ is}\;8
Option C is correct because the pH of 1 × 10-8 M HCl is not 8. Since HCl is an acid, the pH must be less than 7. The pH will be slightly less than 7 due to the contribution of H+ from water.
133 Easy
133 of 161
Remembering +4 | -1
The pH{pH} value of ordinary water is :
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Correct option: C
5.3
Option B (6.5) is incorrect, Option C (5.3) is the closest to the actual pH of ordinary water which is slightly acidic due to dissolved CO2, but Option A (7) is the pH of pure water, and Option D (7.8) is slightly alkaline. The correct answer is B (6.5)
134 Easy
134 of 161
Understanding +4 | -1
The strongest Lewis base in the following is
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Correct option: A
CH3−\mathrm{CH}_3^ -
Option A (CH3−\mathrm{CH}_3^ -) is correct because CH3−\mathrm{CH}_3^ - is the conjugate base of the very weak acid CH4\mathrm{CH}_4, making it the strongest base among the given options.
135 Easy
135 of 161
Analyzing +4 | -1
Which can act as buffer?
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Correct option: D
All of the above
Option D (All of the above) is correct because all given mixtures can act as buffer solutions, either by containing a weak acid/base and its conjugate or by forming one upon reaction.
136 Easy
136 of 161
Analyzing +4 | -1
The use of methyl orange as an indicator in the volumetric determination of the equivalent weight of a weak acid would lead to:
View answer and explanation
Correct option: A
A low value for the equivalent weight
The correct answer is A (A low value for the equivalent weight) because methyl orange changes color at a lower pH than the equivalence point of a weak acid titration, leading to premature endpoint detection and an underestimation of the volume of titrant required, thus a lower calculated equivalent weight.
137 Easy
137 of 161
Understanding +4 | -1
If pKa\mathrm{p}{K_a} values of four acids are given below at 25∘C25^\circ C, the strongest acid is
View answer and explanation
Correct option: A
2.02.0
Option A (2.0) is correct because a lower pKa\mathrm{p}{K_a} value indicates a stronger acid.
138 Easy
138 of 161
Application +4 | -1
The equilibrium concentration of X,YX, Y and YX2Y X_2 are 4,2 and 2 moles respectively for the equilibrium 2X+Y⇌YX22 X+Y \rightleftharpoons Y X_2. The value of KcK_c is
View answer and explanation
Correct option: B
0.0625
Option B (0.0625) is correct because the equilibrium constant Kc is calculated by dividing the product concentration by the reactant concentrations, each raised to the power of their stoichiometric coefficients.
139 Easy
139 of 161
Understanding +4 | -1
N2( g)+3H2( g)⇌2NH3( g)\mathrm{N}_2(\mathrm{~g})+3 \mathrm{H}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_3(\mathrm{~g})
[ΔH=−93.6 kJ][\Delta \mathrm{H}=-93.6 \mathrm{~kJ}]
The yield of ammonia does not increase when
View answer and explanation
Correct option: B
Pressure is decreased
Option B (Pressure is decreased) is correct because decreasing pressure shifts the equilibrium to the side with more moles of gas, which is the reactants' side, thus decreasing ammonia yield.
140 Easy
140 of 161
Understanding +4 | -1
Which of the following is a Lewis acid?
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Correct option: B
H3O+{\mathrm{H}_3}{\mathrm{O}^ + }
Option B (H3O+{\mathrm{H}_3}{\mathrm{O}^ + }) is correct because it can accept a pair of electrons due to the positive charge, making it a Lewis acid.
141 Easy
141 of 161
Understanding +4 | -1
The hydrolysis constant of a salt of weak acid and weak base is inversely proportional to
View answer and explanation
Correct option: B
Dissociation constant of both weak acid and weak base
Option B is correct because the hydrolysis constant Kh{K_h} is inversely proportional to the product of the dissociation constants of the weak acid (Ka{K_a}) and weak base (Kb{K_b}).
142 Easy
142 of 161
Analyzing +4 | -1
At 30∘C  the  solubility  of Ag2CO3  (Ksp=8×10−12)30^\circ C\;\mathrm{the}\;\mathrm{ solubility}\;\mathrm{ of}\,\mathrm{ A}{\mathrm{g}_2}\mathrm{C}{\mathrm{O}_3}\;\left( {{K_{\mathrm{sp}}} = 8 \times {{10}^{ - 12}}} \right) would be greatest in 1  L1\;L of
View answer and explanation
Correct option: D
0.05  M  NH30.05\;\mathrm{M }\;\mathrm{N}{\mathrm{H}_3}
The correct answer is D (0.05  M  NH30.05\;\mathrm{M }\;\mathrm{N}{\mathrm{H}_3}) because the solubility of Ag2CO3Ag_2CO_3 is greatest in NH3NH_3 due to complex formation, which reduces the concentration of Ag+Ag^+ ions.
143 Easy
143 of 161
Application +4 | -1
An aqueous solution of 0.1  M  NH4Cl0.1\;M\;\mathrm{N}{\mathrm{H}_4}\mathrm{Cl} will have a pHpH closer to:
View answer and explanation
Correct option: D
5.15.1
Option D (5.1) is correct because NH4ClNH_4Cl is a salt of a weak base and a strong acid, which hydrolyzes to produce an acidic solution, resulting in a pH less than 7.
144 Easy
144 of 161
Application +4 | -1
Kc{K}_{{c}} for the reaction N2( g)+O2( g)⇌2NO(g){N}_2({~g})+{O}_2({~g}) \rightleftharpoons 2 {NO}({g}) at 300 K300 {~K} is 4.0×10−6⋅Kp4.0 \times 10^{-6} \cdot {K}_{{p}} for the abovereaction will be (R=2calmol−1 K−1)\left({R}=2 {calmol}^{-1} {~K}^{-1}\right)
View answer and explanation
Correct option: B
4×10−64 \times 10^{-6}
Option B (4×10−64 \times 10^{-6}) is correct because since Δn = 0, Kp = Kc.
145 Easy
145 of 161
Understanding +4 | -1
For the Haber’s process for the formation of NH3\mathrm{N}{\mathrm{H}_3} at 298  K\mathrm{298}\;\mathrm{K} is :
N2+3H2  ⇋2NH3;    ΔH=−460    kJ{\mathrm{N}_2} + 3{\mathrm{H}_2}\;\leftrightharpoons2\mathrm{N}{\mathrm{H}_3};\;\;\Delta H = - 460\;\;\mathrm{kJ}
Which of the following is correct?
View answer and explanation
Correct option: A
The condition for equilibrium is GN2+3GH2=2GNH3,{\mathrm{G}_{{\mathrm{N}_2}}} + 3{\mathrm{G}_{{\mathrm{H}_2}}} = 2{\mathrm{G}_{\mathrm{N}{\mathrm{H}_3}}}, where G\mathrm{G} is Gibbs energy per mole of gaseous species measured at that partial pressure
Option A (The condition for equilibrium is GN2+3GH2=2GNH3{\mathrm{G}_{{\mathrm{N}_2}}} + 3{\mathrm{G}_{{\mathrm{H}_2}}} = 2{\mathrm{G}_{\mathrm{N}{\mathrm{H}_3}}}, where G\mathrm{G} is Gibbs energy per mole of gaseous species measured at that partial pressure) is correct because at equilibrium, the change in Gibbs free energy is zero, meaning the Gibbs free energy of the reactants equals the Gibbs free energy of the products.
146 Easy
146 of 161
Understanding +4 | -1
What would be the effect on addition of CaCO3\mathrm{CaC}{\mathrm{O}_3} on the equilibrium of CaCO3(s)  ⇋  CaO(s)+CO2(g)\mathrm{CaC}{\mathrm{O}_3}\left( s \right)\;\leftrightharpoons\;\mathrm{CaO}\left( s \right) + \mathrm{C}{\mathrm{O}_2}\left( \mathrm{g} \right) in a closed container:
View answer and explanation
Correct option: C
Remains unaffected
Option C (Remains unaffected) is correct because the addition of a solid reactant or product does not change the equilibrium constant, which depends only on the partial pressure of CO2 in this case.
147 Easy
147 of 161
Application +4 | -1
For the reaction, CO(g)+Cl2(g)  ⇋  COCl2(g)\mathrm{CO}\left( \mathrm{g} \right) + \mathrm{C}{\mathrm{l}_2}\left( \mathrm{g} \right)\;\leftrightharpoons\;\mathrm{COC}{\mathrm{l}_2}\left( \mathrm{g} \right) the value of Kp/Kc{K_p}/{K_c} is equal to :
View answer and explanation
Correct option: D
1RT\frac{1}{{RT}}
Option D (1RT\frac{{1}}{{{{RT}}}}) is correct because it is derived from the relationship between Kp and Kc, considering the change in the number of moles.
148 Easy
148 of 161
Application +4 | -1
For an equilibrium reaction involving gases, the forward reaction is 1st order while the reverse reaction is 2nd order. The units of Kb{{K_b}} for the forward equilibrium is:
View answer and explanation
Correct option: A
atm\mathrm{atm}
Option A (atm) is correct because the units of Kp depend on the difference in the stoichiometric coefficients of gaseous products and reactants.
149 Easy
149 of 161
Application +4 | -1
If equilibrium constants of reactions AB and  CD are K1 and  K2AB\,and\,\,CD\,are\,{K_1}\,and\,\,{K_2} respectively, then the equilibrium constant for the reaction D+BA+CD + BA + C will be
View answer and explanation
Correct option: B
1K1K2\frac{1}{{{K_1}{K_2}}}
Option B (1K1K2\frac{1}{{{K_1}{K_2}}}) is correct because the reaction is the reverse of the sum of the reactions with equilibrium constants K1 and K2.
150 Easy
150 of 161
Application +4 | -1
If the pHpH of a solution is 2, its normality will be:
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the normality depends on the acid's nature (strong or weak) and its dissociation.
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