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Calculate for the cell formed by two electrodes
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JEE • CHEMISTRY • ELECTRO CHEMISTRY
Electro chemistry practice · Mixed difficulty
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271
Medium
271 of 396
Application
+4 | -1
In following cell reaction
Calculate for the reaction
Calculate for the reaction
View answer and explanation
Correct option: B
Option B () is correct because it is the result of applying the Nernst equation with the given concentrations and standard potential.
272
Hard
272 of 396
Application
+4 | -1
Calculate for the cell formed by two electrodes
View answer and explanation
Correct option: B
Option B () is correct because the equilibrium constant is calculated from the standard cell potential using the Nernst equation.
273
Medium
273 of 396
Analyzing
+4 | -1
Four successive members of the first row transition elements listed below with atomic numbers. Which one of them is expected to have the highest value is?
View answer and explanation
Correct option: D
Option D is correct because Co (Z = 27) has the highest value due to the stability of Co²⁺.
274
Medium
274 of 396
Application
+4 | -1
If the molar conductivity of is then its dissociation constant will be
[Given
[Given
View answer and explanation
Correct option: D
The correct answer is D (10-5 M) because it is calculated using the formula Ka = Cα^2, where α is the degree of dissociation and C is the concentration.
275
Medium
275 of 396
Application
+4 | -1
In acidic medium is converted to . The quantity of electricity in faraday required to reduce 0.5 mole of to would be
View answer and explanation
Correct option: A
2.5
Option A (2.5) is correct because it is the quantity of electricity in faradays required to reduce 0.5 mole of MnO₄⁻ to Mn²⁺, calculated based on the change in oxidation state.
276
Easy
276 of 396
Analyzing
+4 | -1
values of some redox couples are given below on the basis of these values. Choose the correct option
values:
values:
View answer and explanation
Correct option: D
will reduce
Cu will reduce Br2 because Cu has a lower reduction potential (+0.34) than Br2 (+1.90), making it more likely to be oxidized and thus reduce Br2.
277
Medium
277 of 396
Application
+4 | -1
During the electrolysis of a solution of of charge is passed through the electroplating bath.
The mass of silver deposited at the cathode will be
The mass of silver deposited at the cathode will be
View answer and explanation
Correct option: B
10.8 g
Option B (10.8 g) is correct because it calculates the mass of silver deposited using Faraday's laws of electrolysis.
278
Medium
278 of 396
Application
+4 | -1
The equivalent conductance of an aqueous solution of equivalent acetic acid per litre is equiv at . At infinite dilution value is equiv . Calculate the degree of ionisation and ionisation constant of acetic acid.
View answer and explanation
Correct option: A
Option A (0.1232, ) is correct because it accurately calculates the degree of ionization and ionization constant using the given equivalent conductance values.
279
Easy
279 of 396
Understanding
+4 | -1
The oxidation potential of Mg and Al are + 2.37 and + 1.66 volt respectively. The Mg in chemical reactions :
View answer and explanation
Correct option: B
Will replace Al
Option B (Will replace Al) is correct because Mg has a higher oxidation potential than Al, meaning it is more easily oxidized and can displace Al from its compounds.
280
Medium
280 of 396
Remembering
+4 | -1
Which of the following electrolytes is used in lead storage battery?
View answer and explanation
Correct option: C
38 % solution of
Option C (38 % solution of ) is correct because a 38% solution of sulfuric acid is used as the electrolyte in lead storage batteries.
281
Medium
281 of 396
Application
+4 | -1
On the basis of the information available from the of , the minimum emf required to carry out an electrolysis of is : )
View answer and explanation
Correct option: B
Option B () is correct because the minimum EMF required is calculated from the Gibbs free energy change and the number of electrons transferred in the reaction.
282
Medium
282 of 396
Application
+4 | -1
In a fuel cell hydrogen and oxygen react to produce electricity. In the process hydrogen gas is oxidised at the anode and oxygen at the cathode. If of at STP react in 15 minutes, what is the average current produced ? If the entire current is used for electrodeposition of copper from copper (II) solution, how many grams of copper will be deposited ?
Anode reaction :
Cathode reaction:
Anode reaction :
Cathode reaction:
View answer and explanation
Correct option: A
190
Option A (190) is correct because it is the approximate mass of copper deposited, calculated based on the stoichiometry of the reaction and Faraday's laws of electrolysis.
283
Medium
283 of 396
Analyzing
+4 | -1
Select the correct statement(s) for the given reaction.
View answer and explanation
Correct option: D
None of the above
Option D (None of the above) is correct because the provided statements regarding the electrochemical cell representation, cell potential, and electrode reactions are all incorrect for the given reaction.
284
Medium
284 of 396
Analyzing
+4 | -1
The electrical conductivity of the flowing aqueous solutions is highest for:
View answer and explanation
Correct option: C
Option C () is correct because difluoroacetic acid is the strongest acid among the options due to the electron-withdrawing effect of the two fluorine atoms, leading to the highest electrical conductivity.
285
Medium
285 of 396
Understanding
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cannot be used as a salt bridge for the cell because :
View answer and explanation
Correct option: C
is precipitated
Option C ( is precipitated) is correct because precipitates when reacts with in the cell.
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286
Easy
286 of 396
Application
+4 | -1
A steady current of 30.0 A for 70.2 min corresponds to a
passage of
passage of
View answer and explanation
Correct option: D
1.31 Faradays
Option D (1.31 Faradays) is correct because it is calculated by converting the current and time to charge in Coulombs and then to Faradays.
287
Medium
287 of 396
Application
+4 | -1
A galvanic cell : initially contains and ions. The cell potential after the passage of of current for will be ___ V.
View answer and explanation
Correct option: A
Option A (0.01) is correct because the cell potential is calculated using the Nernst equation after determining the change in concentrations due to the passage of current.
288
Medium
288 of 396
Understanding
+4 | -1
Assertion (A): for weak electrolytes shows a sharp increase, when the electrolytic solution is diluted.
Reason (R): For weak electrolytes degree of dissociation increases with dilution of solution.
Reason (R): For weak electrolytes degree of dissociation increases with dilution of solution.
View answer and explanation
Correct option: A
Assertion and Reason both are correct and Reason is the correct explanation of Assertion.
Option A is correct because as a weak electrolyte is diluted, its degree of dissociation increases, leading to a sharp increase in molar conductivity.
289
Hard
289 of 396
Analyzing
+4 | -1
Consider the following reaction :
When ammonia is added to the solution, pH is raised to 11. Which half-cell reaction is affected by pH and by how much?
When ammonia is added to the solution, pH is raised to 11. Which half-cell reaction is affected by pH and by how much?
View answer and explanation
Correct option: A
will increase by a factor of 0.65 from
The correct answer is A because the oxidation potential of the glucose/gluconic acid half-cell is pH-dependent, and increasing the pH will increase the oxidation potential.
290
Medium
290 of 396
Application
+4 | -1
. What are the values of and ?
View answer and explanation
Correct option: B
Option B () is correct because it represents the coefficients that balance the given redox reaction.
291
Medium
291 of 396
Understanding
+4 | -1
The correct order of molar conductance at infinite dilution of is
View answer and explanation
Correct option: B
Option B is correct because ionic conductance increases with ionic mobility, which is inversely proportional to hydrated size.
292
Medium
292 of 396
Understanding
+4 | -1
cannot be used as a salt bridge for the cell because :
View answer and explanation
Correct option: C
is precipitated
Option C (AgCl is precipitated) is correct because Ag+ ions from AgNO3 react with Cl- ions from KCl to form insoluble AgCl, disrupting the salt bridge function.
293
Hard
293 of 396
Analyzing
+4 | -1
Given, for the couple and for the couple, determine for at ? (Take )
View answer and explanation
Correct option: A
The correct answer is A () because it is calculated using the Nernst equation and the given standard electrode potentials.
294
Medium
294 of 396
Application
+4 | -1
Following is the concentration cell in which electrode is
reversible with respect to anion
The cell reaction is spontaneous, if
reversible with respect to anion
The cell reaction is spontaneous, if
View answer and explanation
Correct option: A
Option A () is correct because the cell reaction is spontaneous when the concentration of the anion at the left electrode is greater than the concentration at the right electrode.
295
Easy
295 of 396
Understanding
+4 | -1
Assertion (A): act as only oxidizing agent.
Reason (R): In is in its highest oxidation state +7.
Reason (R): In is in its highest oxidation state +7.
View answer and explanation
Correct option: A
Both (A) and (R) true and (R) is the correct explanation of (A).
Option A (Both (A) and (R) true and (R) is the correct explanation of (A)) is correct because KMnO4 acts as an oxidizing agent due to Mn being in its highest oxidation state (+7), which allows it to accept electrons and get reduced.
296
Medium
296 of 396
Analyzing
+4 | -1
Assertion: The cell constant of a cell depends upon the nature of the material of the electrodes.
Reason: The observed conductance depends upon the nature of the electrolyte and the concentration of the solution.
Reason: The observed conductance depends upon the nature of the electrolyte and the concentration of the solution.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because the cell constant depends on the geometry of the cell, not the electrode material, and conductance depends on electrolyte nature and concentration.
297
Easy
297 of 396
Application
+4 | -1
The position of some metals in the electrochemical series in decreasing electropositive character is given as . What will happen, if a copper spoon is used to stir a solution of aluminium nitrate?
View answer and explanation
Correct option: D
There is no reaction
Option D (There is no reaction) is correct because copper is below aluminum in the electrochemical series, meaning it cannot displace aluminum from its solution.
298
Easy
298 of 396
Remembering
+4 | -1
The laws of electrolysis were proposed by
View answer and explanation
Correct option: B
Faraday
Option B (Faraday) is correct because Michael Faraday formulated the laws of electrolysis in the 19th century.
299
Medium
299 of 396
Analyzing
+4 | -1
Red hot carbon will remove oxygen from the oxides XO, and YO but not from ZO. Y will remove oxygen from XO. Use this evidence to reduce the order of activity of the three metals X, Y and Z putting the most reactive first:
View answer and explanation
Correct option: B
Z, Y, X
Option B (Z, Y, X) is correct because Z is the most reactive as carbon cannot remove oxygen from ZO, Y is more reactive than X as Y removes oxygen from XO.
300
Easy
300 of 396
Remembering
+4 | -1
Rust is
View answer and explanation
Correct option: C
Option D () is correct because rust is primarily composed of iron(III) oxide () and iron(III) hydroxide ().
Revision notes and key takeaways
Review ELECTRO CHEMISTRY in your textbook or class notes, then use this set to check your understanding.
Showing 271-300 of 396 questions
