The electrolysis of a solution resulted in the formation of ${{\rm{H}}_2}$ at the cathode and ${\rm{C}}{{\rm{l}}_2}$ at the anode. The liquid is:

${{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}$ solution

${\rm{CuC}}{{\rm{l}}_2}$ solution in water

Molar conductivities (${\mathop {\rm{\Lambda }}\limits^ \circ _m}$) at infinite dilution of ${\rm{NaCl}},{\rm{HCl}}$ and ${\rm{C}}{{\rm{H}}_3}{\rm{COONa}}$ are 126.4, 425.9 and 91.0 ${\rm{S {\kern 1pt} {\kern 1pt}c}}{{\rm{m}}^2}{\kern 1pt} {\rm{mo}}{{\rm{l}}^{ - 1}}$ respectively.${\mathop {\rm{\Lambda }}\limits^ \circ _m}$ for ${\rm{C}}{{\rm{H}}_3}{\rm{COOH}}$ will be :

390.5 ${\rm{S {\kern 1pt} {\kern 1pt}c}}{{\rm{m}}^2}{\kern 1pt} {\rm{mo}}{{\rm{l}}^{ - 1}}$

425.5 ${\rm{S {\kern 1pt} {\kern 1pt}c}}{{\rm{m}}^2}{\kern 1pt} {\rm{mo}}{{\rm{l}}^{ - 1}}$

180.5 ${\rm{S {\kern 1pt} {\kern 1pt}c}}{{\rm{m}}^2}{\kern 1pt} {\rm{mo}}{{\rm{l}}^{ - 1}}$

290.8 ${\rm{S {\kern 1pt} {\kern 1pt}c}}{{\rm{m}}^2}{\kern 1pt} {\rm{mo}}{{\rm{l}}^{ - 1}}$

Back to ELECTRO CHEMISTRY

Your Progress

0 / 103 Answered

Correct

Incorrect

Accuracy

JEE • CHEMISTRY • ELECTRO CHEMISTRY

Electro chemistry practice · Easy

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →

Showing 1-30 of 103 questions

1 Easy

1 of 103

Application +4 | -1

An ion is reduced to the element when it absorbs

6 \times {10^{20}}

electrons. The number of equivalents of the ion is :

View answer and explanation

Correct option: C

0.001

Option C (0.001) is correct because 6 × 10²⁰ electrons is equivalent to 0.001 equivalents, using the relationship 6 × 10²³ electrons = 1 equivalent.

2 Easy

2 of 103

Understanding +4 | -1

Statement-1: Salt bridge maintains electrical neutrality in two half cell.

Statement-2: Salt bridge transfer ions of one solution into other solutions.

View answer and explanation

Correct option: C

Statement-1 is true but statement-2 is false

Option C is correct. Statement-1 is true as the salt bridge maintains electrical neutrality. Statement-2 is false because the salt bridge provides ions to each half-cell, not transferring ions from one solution to the other.

3 Easy

3 of 103

Application +4 | -1

Given the limiting molar conductivity as

\Lambda _\mathrm{m}^0\left( {\mathrm{HCl}} \right) = 425.9{\kern 1pt} {\kern 1pt} {\Omega ^{ - 1}}{\kern 1pt} \mathrm{c}{\mathrm{m}^2}{\kern 1pt} \mathrm{mo}{\mathrm{l}^{ - 1}}

\Lambda _\mathrm{m}^0\left( {\mathrm{NaCl}} \right) = 126.4{\kern 1pt} {\kern 1pt} {\Omega ^{ - 1}}{\kern 1pt} \mathrm{c}{\mathrm{m}^2}{\kern 1pt} \mathrm{mo}{\mathrm{l}^{ - 1}}

\Lambda _\mathrm{m}^0\left( {\mathrm{C}{\mathrm{H}_3}\mathrm{COONa}} \right) = 91{\kern 1pt} {\kern 1pt} {\Omega ^{ - 1}}{\kern 1pt} \mathrm{c}{\mathrm{m}^2}{\kern 1pt} \mathrm{mo}{\mathrm{l}^{ - 1}}

The molar conductivity , at infinite dilution, of acetic acid (

\mathrm{in}{\kern 1pt} {\kern 1pt} {\kern 1pt} {\Omega ^{ - 1}}{\kern 1pt} \mathrm{c}{\mathrm{m}^2}{\kern 1pt} \mathrm{mo}{\mathrm{l}^{ - 1}}

) will be

View answer and explanation

Correct option: B

390.5

Option B (390.5) is correct because the molar conductivity of acetic acid at infinite dilution is calculated using Kohlrausch's law of independent migration of ions.

4 Easy

4 of 103

Understanding +4 | -1

Assertion (A): Molar conductivity increases with decrease in concentration for weak electrolytes.

Reason (R): The degree of dissociation increases on dilution for a weak electrolyte.

View answer and explanation

Correct option: A

Both (A) and (R) true and (R) is the correct explanation of (A).

Option A is correct because molar conductivity increases with decreasing concentration for weak electrolytes due to increased dissociation.

5 Easy

5 of 103

Understanding +4 | -1

The electrolysis of a solution resulted in the formation of

{\mathrm{H}_2}

at the cathode and

\mathrm{C}{\mathrm{l}_2}

at the anode. The liquid is:

View answer and explanation

Correct option: C

\mathrm{NaCl}

solution in water

Option C is correct. Electrolysis of NaCl solution produces H2 at the cathode and Cl2 at the anode.

6 Easy

6 of 103

Understanding +4 | -1

Which of the following statements is not correct about an inert electrode in a cell?

View answer and explanation

Correct option: D

It provides surface for redox reaction

Option D is correct because an inert electrode provides a surface for oxidation or reduction, but it doesn't directly participate in a redox reaction itself.

7 Easy

7 of 103

Understanding +4 | -1

The standard reduction potential values of some of the p-block ions are given below. Predict the one with the strongest oxidising capacity.

View answer and explanation

Correct option: D

\mathrm{E}_{\mathrm{Pb}^{4+} / \mathrm{Pb}^{2+}}^{\ominus}=+1.67 \mathrm{~V}

Option D (

\mathrm{E}_{\mathrm{Pb}^{4+} / \mathrm{Pb}^{2+}}^{\ominus}=+1.67 \mathrm{~V}

) is correct because the higher the standard reduction potential, the stronger the oxidizing agent.

8 Easy

8 of 103

Remembering +4 | -1

The acid used in lead storage battery is:

View answer and explanation

Correct option: B

Sulphuric acid

Option B (Sulphuric acid) is correct because sulphuric acid (H2SO4) is the electrolyte used in lead storage batteries.

9 Easy

9 of 103

Understanding +4 | -1

The electrochemical cell stops working after sometimes because

View answer and explanation

Correct option: B

Electrode potential of both the electrodes becomes equal

Option B (Electrode potential of both the electrodes becomes equal) is correct because the cell stops working when the potential difference between the electrodes becomes zero, meaning their electrode potentials are equal.

10 Easy

10 of 103

Understanding +4 | -1

Aqueous solution of which of the following compounds is the best conductor of electric current?

View answer and explanation

Correct option: D

Hydrochloric acid,

\mathrm{HCl}

Option D (Hydrochloric acid,

\mathrm{HCl}

) is correct because it is a strong acid and dissociates completely into ions in aqueous solution.

11 Easy

11 of 103

Application +4 | -1

An ion is reduced to the element when it absorbs

6 \times {10^{20}}

electrons. The number of equivalents of the ion is :

View answer and explanation

Correct option: C

0.001

Option C (0.001) is correct because 6 × 10²⁰ electrons is equivalent to 0.001 equivalents, using the relationship 6 × 10²³ electrons = 1 equivalent.

12 Easy

12 of 103

Application +4 | -1

Molar conductivities (

{\mathop \mathrm{\Lambda }\limits^ \circ _m}

) at infinite dilution of

\mathrm{NaCl},\mathrm{HCl}

and

\mathrm{C}{\mathrm{H}_3}\mathrm{COONa}

are 126.4, 425.9 and 91.0

{\rm{S {\kern 1pt} {\kern 1pt}c}}{\mathrm{m}^2}{\kern 1pt} \mathrm{mo}{\mathrm{l}^{ - 1}}

respectively.

{\mathop \mathrm{\Lambda }\limits^ \circ _m}

for

\mathrm{C}{\mathrm{H}_3}\mathrm{COOH}

will be :

View answer and explanation

Correct option: D

390.5

{\rm{S {\kern 1pt} {\kern 1pt}c}}{\mathrm{m}^2}{\kern 1pt} \mathrm{mo}{\mathrm{l}^{ - 1}}

Option D (390.5 S cm² mol⁻¹) is correct because it is calculated using Kohlrausch's Law of Independent Migration of Ions.

13 Easy

13 of 103

Remembering +4 | -1

The electroplating with chromium is undertaken because :

View answer and explanation

Correct option: C

Chromium gives a protective and decorative coating to the base metal

Option C (Chromium gives a protective and decorative coating to the base metal) is correct because chromium electroplating provides both corrosion resistance and an aesthetically pleasing finish.

14 Easy

14 of 103

Understanding +4 | -1

Which of the following reactions occurs at the cathode?

View answer and explanation

Correct option: D

\mathrm{Cu}^{2+}+2 {e}^{-} \rightarrow \mathrm{Cu}

Option D (

\mathrm{Cu}^{2+}+2 {e}^{-} \rightarrow \mathrm{Cu}

) is correct because reduction occurs at the cathode, and this equation represents the gain of electrons (reduction) by copper ions.

15 Easy

15 of 103

Remembering +4 | -1

A depolariser used in dry cell batteries is :

View answer and explanation

Correct option: B

Manganese dioxide

Option B (Manganese dioxide) is correct because manganese dioxide acts as a depolarizer in dry cell batteries.

Explore Other Chapters in CHEMISTRY

View All →

P-BLOCK ELEMENTS 736 MCQs Equilibrium 696 MCQs STRUCTURE OF ATOM 634 MCQs THERMODYNAMICS 536 MCQs CHEMICAL BONDING & MOLECULAR STRUCTURE 514 MCQs SOLUTIONS 480 MCQs

16 Easy

16 of 103

Analyzing +4 | -1

Two platinum electrodes were immersed in a solution of cupric sulphate and electric current passed through the solution. After sometime, it was found that the colour of copper sulphate disappeared with evolution of gas at the electrode. The colourless solution contains:

View answer and explanation

Correct option: D

Sulphuric acid

Option D (Sulphuric acid) is correct because during electrolysis of

CuSO_4

, copper is deposited at the cathode and oxygen is evolved at the anode, leaving sulphuric acid in the solution.

17 Easy

17 of 103

Understanding +4 | -1

Lithium is generally used as an electrode in high energy density batteries. This is because:

View answer and explanation

Correct option: B

Lithium has quite high negative reduction potential

Option B (Lithium has quite high negative reduction potential) is correct because its high negative reduction potential indicates it is easily oxidized, making it a good electrode material.

18 Easy

18 of 103

Analyzing +4 | -1

Which one of the following solutions has highest conductance power?

View answer and explanation

Correct option: D

0.1M{\kern 1pt} {\kern 1pt} \mathrm{HCl}

Option D (0.1M HCl) has the highest conductance power because HCl is a strong electrolyte and H+ ions have high mobility due to Grotthuss mechanism.

19 Easy

19 of 103

Remembering +4 | -1

If ϕ denotes standard reduction potential, which is true:

View answer and explanation

Correct option: A

E_{\mathrm{cell}}^ \circ = {\phi _R} - {\phi _L}

Option A is correct because the standard cell potential is the difference between the standard reduction potential of the right-hand electrode (cathode) and the left-hand electrode (anode).

20 Easy

20 of 103

Application +4 | -1

{E}_{{Cu}^{2+} / {Cu}}^{\circ}=+0.34 \,{~V}

then reduction potential of

{Cu}^{2+} / {Cu}

electrode at

{pH}=14

\left({K}_{{sp}}\right.

{Cu}({OH})_2=1

\times 10^{-19}

)

View answer and explanation

Correct option: B

-0.22 \,{~V}

Option B (-0.22 V) is correct because it is calculated using the Nernst equation, considering the solubility product of copper(II) hydroxide.

21 Easy

21 of 103

Understanding +4 | -1

When

CuSO_4

is electrolysed using platinum electrodes

View answer and explanation

Correct option: B

Copper is liberated at cathode, oxygen at anode

The correct answer is B (Copper is liberated at cathode, oxygen at anode) because during electrolysis of

CuSO_4

Cu^{2+}

ions are reduced at the cathode and water is oxidized at the anode.

22 Easy

22 of 103

Remembering +4 | -1

Electrolytic conduction is due to migration of :

View answer and explanation

Correct option: C

Ions

Option C (Ions) is correct because electrolytic conduction occurs due to the migration of ions.

23 Easy

23 of 103

Understanding +4 | -1

In a hydrogen-oxygen fuel cell, combustion of hydrogen occurs to

View answer and explanation

Correct option: B

create potential difference between two electrodes

Option B is correct. In a hydrogen-oxygen fuel cell, the combustion of hydrogen is used to create a potential difference between the two electrodes, which drives the electric current.

24 Easy

24 of 103

Understanding +4 | -1

When lead storage battery discharges

View answer and explanation

Correct option: D

{H_2}S{O_4}

is consumed

Option D (

{H_2}S{O_4}

is consumed) is correct because sulfuric acid is used up in the reaction to form lead sulfate during the discharge of the battery.

25 Easy

25 of 103

Understanding +4 | -1

An increase in equivalent conductivity of strong electrolyte with dilution is mainly due to:

View answer and explanation

Correct option: A

Increase in ionic molility ions

The correct answer is A (Increase in ionic molility ions) because the increase in equivalent conductivity of a strong electrolyte with dilution is primarily due to increased ionic mobility.

26 Easy

26 of 103

Remembering +4 | -1

Electrode potential depends upon

View answer and explanation

Correct option: C

Temperature

Option C (Temperature) is correct because the electrode potential is directly related to temperature through the Nernst equation.

27 Easy

27 of 103

Application +4 | -1

When

X

amperes of current is passed through molten

\mathrm{AlC}{\mathrm{l}_3}

for 96.5 s. 0.09 g of aluminium is deposited. What is the value of

X

View answer and explanation

Correct option: A

10\mathrm{ }A

Option A (10 A) is correct because it is calculated using Faraday's laws of electrolysis, relating the mass of aluminum deposited to the current passed.

28 Easy

28 of 103

Understanding +4 | -1

The metal that cannot be obtained by electrolysis of the aqueous solution of its salts is :

View answer and explanation

Correct option: D

Option D (Al) is correct because aluminum is a strong electropositive metal and cannot be obtained by electrolysis of its aqueous salt solution.

29 Easy

29 of 103

Analyzing +4 | -1

Electrolysis of aq. Solution of

\mathrm{LiCl}

shows :

View answer and explanation

Correct option: C

\mathrm{pH} > 7

Option C (

\mathrm{pH} > 7

) is correct because during the electrolysis of aqueous LiCl, water is reduced at the cathode, producing hydroxide ions and increasing the pH.

30 Easy

30 of 103

Application +4 | -1

Maximum number of mole of oxygen gas that can be obtained by the electrolytic decomposition of 90 g of water will be:

View answer and explanation

Correct option: B

2.5

Option B (2.5) is correct because the electrolytic decomposition of 90g of water (5 moles) produces 2.5 moles of oxygen gas, based on the stoichiometry of the reaction.

Revision notes and key takeaways

Review ELECTRO CHEMISTRY in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 103 single-correct-answer MCQs on ELECTRO CHEMISTRY.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

Showing 1-30 of 103 questions

Continue Your Practice

📚 Switch Set (EASY)

Chapter Sets

ALL 396 MCQs EASY 103 MCQs HARD 63 MCQs MEDIUM 230 MCQs

0 /103

0✓ 0✗

0% Accuracy