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JEE • CHEMISTRY • d & f- BLOCK ELEMENTS

D & f- BLOCK ELEMENTS practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 410 questions

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31 Medium
31 of 410
Understanding +4 | -1
Interstitial compounds are formed when small atoms are trapped inside the crystal lattice of metals. Which of the following are the characteristic properties of interstitial compounds?

I. They have high melting points in comparison to pure metals.

II. They are very hard.

III. They retain metallic conductivity.

IV. They are chemically very reactive.

Choose the correct option.
View answer and explanation
Correct option: A
I, II and III
Option A (I, II and III) is correct because interstitial compounds have high melting points, are very hard, and retain metallic conductivity, but they are chemically inert, not reactive.
32 Medium
32 of 410
Remembering +4 | -1
The composition of duralumin is :
View answer and explanation
Correct option: D
Al(95%),Cu(4%),Mn(0.5%),Mg(0.5%){Al}(95 \%), {Cu}(4 \%), {Mn}(0.5 \%), {Mg}(0.5 \%).
Option D (Al(95%),Cu(4%),Mn(0.5%),Mg(0.5%){Al}(95 \%), {Cu}(4 \%), {Mn}(0.5 \%), {Mg}(0.5 \%)) is correct because this is the standard composition of duralumin, a lightweight and strong aluminum alloy.
33 Medium
33 of 410
Analyzing +4 | -1
A compound of iron exists as a dimer in vapour state. It is hygroscopic in nature and dissolves in water
giving brown acidic solution. The compound is :
View answer and explanation
Correct option: C
FeCl3\mathrm{FeCl}_3
Option C (FeCl3\mathrm{FeCl}_3) is correct because it forms a dimer in the vapor state, is hygroscopic, and dissolves in water to give a brown acidic solution due to the formation of Fe(OH)3\mathrm{Fe(OH)}_3 and HCl\mathrm{HCl}.
34 Medium
34 of 410
Remembering +4 | -1
Most common oxidation states of Ce (cerium) are
View answer and explanation
Correct option: A
+3,+4+ 3,\mathrm{ } + 4
Option A (+3, +4) is correct because Cerium (Ce) exhibits stable oxidation states of +3 and +4 due to its electronic configuration.
35 Medium
35 of 410
Analyzing +4 | -1
A metal which is ‘not’ affected by conc. H2SO4,  HNO3{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4},\mathrm{\;HN}{\mathrm{O}_3} or alkalies forms a compound XX. This compound XX can be used to give a complex which finds its application for toning in photography. The metal is:
View answer and explanation
Correct option: A
Au
Option A (Au) is correct because gold (Au) is inert to concentrated H₂SO₄, HNO₃, and alkalies, and its chloride (AuCl₃) forms a complex used in photography toning.
36 Medium
36 of 410
Remembering +4 | -1
The element californium belongs to the family of:
View answer and explanation
Correct option: A
Actinoid series
The correct answer is A (Actinoid series) because californium (Cf) with atomic number 98 belongs to the actinoid series.
37 Easy
37 of 410
Remembering +4 | -1
Molten Ag absorbs about ……… times of O2{\mathrm{O}_2}:
View answer and explanation
Correct option: B
20
Option B (20) is correct because molten Ag absorbs about 20 times of O2{\mathrm{O}_2}.
38 Easy
38 of 410
Application +4 | -1
The magnetic moment in Bohr's magneton (BM) of [Fe(CN)6]4−\left[{Fe}({CN})_6\right]^{4-} and [PtCl4]2−\left[{PtCl}_4\right]^{2-} respectively are
View answer and explanation
Correct option: D
Zero, Zero
Option D (Zero, Zero) is correct because both complexes are diamagnetic with no unpaired electrons, resulting in a magnetic moment of zero.
39 Medium
39 of 410
Remembering +4 | -1
Which is used as substitute for platinum in jewellery?
View answer and explanation
Correct option: A
Rolled gold
Option A (Rolled gold) is correct because rolled gold is often used as a cheaper alternative to platinum in jewelry.
40 Medium
40 of 410
Analyzing +4 | -1
Which of the following statements is correct?
View answer and explanation
Correct option: D
From a mixed precipitate of AgCl and AgI, ammonia solution dissolves only AgCl
The correct answer is From a mixed precipitate of AgCl and AgI, ammonia solution dissolves only AgCl because AgCl forms a soluble complex with ammonia, while AgI is less soluble and does not dissolve.
41 Medium
41 of 410
Understanding +4 | -1
The catalytic activity of transition metals and their compounds is ascribed mainly to:
View answer and explanation
Correct option: C
Their ability to adopt variable oxidation states
Option C (Their ability to adopt variable oxidation states) is correct because transition metals' catalytic activity stems from their ability to change oxidation states.
42 Easy
42 of 410
Understanding +4 | -1
Which of the following is amphoteric?
View answer and explanation
Correct option: B
CuO\mathrm{CuO}
Option C (V2O5{\mathrm{V}_2}{\mathrm{O}_5}) is correct because vanadium(V) oxide exhibits both acidic and basic properties, making it amphoteric.
43 Medium
43 of 410
Understanding +4 | -1
Assertion: C−O{C}-{O} bond in metal carbonyls is long.

Reason: There is delocalisation of electrons from filled dd orbitals into the empty orbitals on the COCO ligands.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
Option A is correct because back bonding from the metal to CO ligands weakens the C-O bond, making it longer.
44 Medium
44 of 410
Understanding +4 | -1
The product(s) obtained when KMnO4\mathrm{KMnO}_4 and HCl\mathrm{HCl} react together to form H2O\mathrm{H}_2 \mathrm{O} and Cl2\mathrm{Cl}_2 along with:
View answer and explanation
Correct option: C
Both (1) & (2)
Option C (Both (1) & (2)) is correct because the reaction between KMnO4\mathrm{KMnO}_4 and HCl\mathrm{HCl} produces KCl\mathrm{KCl}, MnCl2\mathrm{MnCl}_2, H2O\mathrm{H}_2\mathrm{O}, and Cl2\mathrm{Cl}_2.
45 Easy
45 of 410
Remembering +4 | -1
Zinc reacts with conc. H2SO4{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} to produce:
View answer and explanation
Correct option: A
H2SO4{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}
Option D (None of these) is correct because the reaction of zinc with concentrated sulfuric acid produces zinc sulfate, water, and sulfur dioxide, not sulfuric acid, zinc carbonate, or zinc.
46 Medium
46 of 410
Remembering +4 | -1
Lanthanoids and actinoids resembles in:
View answer and explanation
Correct option: A
Electronic configuration
Option A (Electronic configuration) is correct because lanthanoids and actinoids share similarities in their electronic configurations, particularly in the filling of f-orbitals.
47 Easy
47 of 410
Remembering +4 | -1
The substance that sublimes on heating is:
View answer and explanation
Correct option: C
HgCl2\mathrm{HgC}{\mathrm{l}_2}
Option C (HgCl2\mathrm{HgC}{\mathrm{l}_2}) is correct because mercury(II) chloride (HgCl2\mathrm{HgC}{\mathrm{l}_2}) sublimes upon heating, meaning it transitions directly from a solid to a gas phase.
48 Easy
48 of 410
Remembering +4 | -1
Two of the constituents of German silver are
View answer and explanation
Correct option: C
Cu + Zn
Option C (Cu + Zn) is correct because German silver is an alloy primarily composed of copper, zinc, and nickel.
49 Medium
49 of 410
Remembering +4 | -1
Fool’s gold is
View answer and explanation
Correct option: B
FeS2\mathrm{Fe}{\mathrm{S}_2}
Option B (FeS2\mathrm{Fe}{\mathrm{S}_2}) is correct because Fool's gold is the common name for iron pyrite, which has the formula FeS2FeS_2.
50 Easy
50 of 410
Understanding +4 | -1
Powdered silver ore is treated with NaCN solution and air is bubbled through the mixture to give:
View answer and explanation
Correct option: D
Na[Ag(CN)2]\mathrm{Na}\left[ {\mathrm{Ag}{{\left( {\mathrm{CN}} \right)}_2}} \right]
Option D (Na[Ag(CN)2]\mathrm{Na}\left[ {\mathrm{Ag}{{\left( {\mathrm{CN}} \right)}_2}} \right]) is correct because silver ore reacts with NaCN in the presence of air to form a soluble silver cyanide complex, sodium dicyanoargentate(I).
51 Easy
51 of 410
Remembering +4 | -1
Bronze is a mixture of
View answer and explanation
Correct option: B
Cu+ Sn
Option B (Cu+ Sn) is correct because bronze is an alloy primarily composed of copper (Cu) and tin (Sn).
52 Medium
52 of 410
Analyzing +4 | -1
Assertion : Actinoids can posses +4+4 O.S. more easily then lanthanoid.

Reason: 4f, 5d, 6s have almost same energy levels.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
Option B is correct. Actinoids can exhibit +4 oxidation states more readily than lanthanoids, but the reason provided, while true, is not the correct explanation.
53 Easy
53 of 410
Remembering +4 | -1
Choose the example of paramagnetic substance.
View answer and explanation
Correct option: B
O2{O}_2
Option B (O2{O}_2) is correct because oxygen molecules have two unpaired electrons, making it paramagnetic.
54 Medium
54 of 410
Understanding +4 | -1
Effective magnetic moment of Sc3+\mathrm{S}{\mathrm{c}^{3 + }} ion is
View answer and explanation
Correct option: B
0
Option D (1) is correct because each carbon atom in graphite is sp2 hybridized, leaving one free electron.
55 Medium
55 of 410
Understanding +4 | -1
A\mathrm{A} and B\mathrm{B} formed in the following reactions are:

CrO2Cl2+4NaOH→A+2NaCl+2H2OA+2HCl+2H2O2→B+3H2O\begin{aligned} & \mathrm{CrO}_2 \mathrm{Cl}_2+4 \mathrm{NaOH} \rightarrow \mathrm{A}+2 \mathrm{NaCl}+2 \mathrm{H}_2 \mathrm{O} \\ & \mathrm{A}+2 \mathrm{HCl}+2 \mathrm{H}_2 \mathrm{O}_2 \rightarrow \mathrm{B}+3 \mathrm{H}_2 \mathrm{O} \end{aligned}
View answer and explanation
Correct option: A
A=Na2CrO4, B=CrO5\mathrm{A}=\mathrm{Na}_2 \mathrm{CrO}_4, \mathrm{~B}=\mathrm{CrO}_5
Option A (A=Na2CrO4, B=CrO5\mathrm{A}=\mathrm{Na}_2 \mathrm{CrO}_4, \mathrm{~B}=\mathrm{CrO}_5) is correct because the reaction of chromyl chloride with NaOH forms sodium chromate, and the subsequent reaction with HCl and H2O2 forms chromium pentoxide.
56 Medium
56 of 410
Understanding +4 | -1
An aqueous solution of CuSO4\mathrm{CuS}{\mathrm{O}_4} and NH4OH\mathrm{N}{\mathrm{H}_4}\mathrm{OH} gives a deep blue complex of:
View answer and explanation
Correct option: A
Cuprammonium sulphate
Option A is correct because the deep blue complex formed is cuprammonium sulphate, which has the formula [Cu(NH3)4]SO4.
57 Medium
57 of 410
Understanding +4 | -1
The magnetic nature of elements depends on the presence of unpaired electrons. Identify the configuration of transition element which shows highest magnetic moment.
View answer and explanation
Correct option: B
3d53 d^5
Option B is correct because the 3d53d^5 configuration has the maximum number of unpaired electrons (5), leading to the highest magnetic moment.
58 Medium
58 of 410
Analyzing +4 | -1
Assertion: Europium (II) is more stable than cerium (II).

Reason: Cerium salts are used as catalyst in petroleum cracking.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion) is correct because both the assertion about Europium(II) stability and the reason about Cerium salts being catalysts are true, but unrelated.
59 Easy
59 of 410
Analyzing +4 | -1
The electronic configuration of Cu(II)\mathrm{Cu}(\mathrm{II}) is 3d93 d^9, whereas that of Cu(I)\mathrm{Cu}(\mathrm{I}) is 3d103 d^{10}. Which of the following is correct?
View answer and explanation
Correct option: A
Cu\mathrm{Cu} (II) is more stable
Option A (Cu(II) is more stable) is correct because although Cu(I) has a stable 3d103d^{10} configuration, Cu(II) is more stable in aqueous solution due to its higher hydration energy which compensates for the energy needed for the second ionization.
60 Medium
60 of 410
Understanding +4 | -1
The transition element having least enthalpy of atomisation is
View answer and explanation
Correct option: A
ZnZn
Option D (At high temperature and low pressure) is correct because at high temperature and low pressure, the intermolecular forces and volume occupied by gas molecules become negligible, thus behaving like an ideal gas.
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