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JEE • CHEMISTRY • d & f- BLOCK ELEMENTS
D & f- BLOCK ELEMENTS practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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31
Medium
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Understanding
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Interstitial compounds are formed when small atoms are trapped inside the crystal lattice of metals. Which of the following are the characteristic properties of interstitial compounds?
I. They have high melting points in comparison to pure metals.
II. They are very hard.
III. They retain metallic conductivity.
IV. They are chemically very reactive.
Choose the correct option.
I. They have high melting points in comparison to pure metals.
II. They are very hard.
III. They retain metallic conductivity.
IV. They are chemically very reactive.
Choose the correct option.
View answer and explanation
Correct option: A
I, II and III
Option A (I, II and III) is correct because interstitial compounds have high melting points, are very hard, and retain metallic conductivity, but they are chemically inert, not reactive.
32
Medium
32 of 410
Remembering
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The composition of duralumin is :
View answer and explanation
Correct option: D
.
Option D () is correct because this is the standard composition of duralumin, a lightweight and strong aluminum alloy.
33
Medium
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Analyzing
+4 | -1
A compound of iron exists as a dimer in vapour state. It is hygroscopic in nature and dissolves in water
giving brown acidic solution. The compound is :
giving brown acidic solution. The compound is :
View answer and explanation
Correct option: C
Option C () is correct because it forms a dimer in the vapor state, is hygroscopic, and dissolves in water to give a brown acidic solution due to the formation of and .
34
Medium
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Remembering
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Most common oxidation states of Ce (cerium) are
View answer and explanation
Correct option: A
Option A (+3, +4) is correct because Cerium (Ce) exhibits stable oxidation states of +3 and +4 due to its electronic configuration.
35
Medium
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Analyzing
+4 | -1
A metal which is ‘not’ affected by conc. or alkalies forms a compound . This compound can be used to give a complex which finds its application for toning in photography. The metal is:
View answer and explanation
Correct option: A
Au
Option A (Au) is correct because gold (Au) is inert to concentrated H₂SO₄, HNO₃, and alkalies, and its chloride (AuCl₃) forms a complex used in photography toning.
36
Medium
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Remembering
+4 | -1
The element californium belongs to the family of:
View answer and explanation
Correct option: A
Actinoid series
The correct answer is A (Actinoid series) because californium (Cf) with atomic number 98 belongs to the actinoid series.
37
Easy
37 of 410
Remembering
+4 | -1
Molten Ag absorbs about ……… times of :
View answer and explanation
Correct option: B
20
Option B (20) is correct because molten Ag absorbs about 20 times of .
38
Easy
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Application
+4 | -1
The magnetic moment in Bohr's magneton (BM) of and respectively are
View answer and explanation
Correct option: D
Zero, Zero
Option D (Zero, Zero) is correct because both complexes are diamagnetic with no unpaired electrons, resulting in a magnetic moment of zero.
39
Medium
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Remembering
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Which is used as substitute for platinum in jewellery?
View answer and explanation
Correct option: A
Rolled gold
Option A (Rolled gold) is correct because rolled gold is often used as a cheaper alternative to platinum in jewelry.
40
Medium
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Analyzing
+4 | -1
Which of the following statements is correct?
View answer and explanation
Correct option: D
From a mixed precipitate of AgCl and AgI, ammonia solution dissolves only AgCl
The correct answer is From a mixed precipitate of AgCl and AgI, ammonia solution dissolves only AgCl because AgCl forms a soluble complex with ammonia, while AgI is less soluble and does not dissolve.
41
Medium
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Understanding
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The catalytic activity of transition metals and their compounds is ascribed mainly to:
View answer and explanation
Correct option: C
Their ability to adopt variable oxidation states
Option C (Their ability to adopt variable oxidation states) is correct because transition metals' catalytic activity stems from their ability to change oxidation states.
42
Easy
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Understanding
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Which of the following is amphoteric?
View answer and explanation
Correct option: B
Option C () is correct because vanadium(V) oxide exhibits both acidic and basic properties, making it amphoteric.
43
Medium
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Understanding
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Assertion: bond in metal carbonyls is long.
Reason: There is delocalisation of electrons from filled orbitals into the empty orbitals on the ligands.
Reason: There is delocalisation of electrons from filled orbitals into the empty orbitals on the ligands.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
Option A is correct because back bonding from the metal to CO ligands weakens the C-O bond, making it longer.
44
Medium
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Understanding
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The product(s) obtained when and react together to form and along with:
View answer and explanation
Correct option: C
Both (1) & (2)
Option C (Both (1) & (2)) is correct because the reaction between and produces , , , and .
45
Easy
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Remembering
+4 | -1
Zinc reacts with conc. to produce:
View answer and explanation
Correct option: A
Option D (None of these) is correct because the reaction of zinc with concentrated sulfuric acid produces zinc sulfate, water, and sulfur dioxide, not sulfuric acid, zinc carbonate, or zinc.
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46
Medium
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Remembering
+4 | -1
Lanthanoids and actinoids resembles in:
View answer and explanation
Correct option: A
Electronic configuration
Option A (Electronic configuration) is correct because lanthanoids and actinoids share similarities in their electronic configurations, particularly in the filling of f-orbitals.
47
Easy
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Remembering
+4 | -1
The substance that sublimes on heating is:
View answer and explanation
Correct option: C
Option C () is correct because mercury(II) chloride () sublimes upon heating, meaning it transitions directly from a solid to a gas phase.
48
Easy
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Remembering
+4 | -1
Two of the constituents of German silver are
View answer and explanation
Correct option: C
Cu + Zn
Option C (Cu + Zn) is correct because German silver is an alloy primarily composed of copper, zinc, and nickel.
49
Medium
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Remembering
+4 | -1
Fool’s gold is
View answer and explanation
Correct option: B
Option B () is correct because Fool's gold is the common name for iron pyrite, which has the formula .
50
Easy
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Understanding
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Powdered silver ore is treated with NaCN solution and air is bubbled through the mixture to give:
View answer and explanation
Correct option: D
Option D () is correct because silver ore reacts with NaCN in the presence of air to form a soluble silver cyanide complex, sodium dicyanoargentate(I).
51
Easy
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Remembering
+4 | -1
Bronze is a mixture of
View answer and explanation
Correct option: B
Cu+ Sn
Option B (Cu+ Sn) is correct because bronze is an alloy primarily composed of copper (Cu) and tin (Sn).
52
Medium
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Analyzing
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Assertion : Actinoids can posses O.S. more easily then lanthanoid.
Reason: 4f, 5d, 6s have almost same energy levels.
Reason: 4f, 5d, 6s have almost same energy levels.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
Option B is correct. Actinoids can exhibit +4 oxidation states more readily than lanthanoids, but the reason provided, while true, is not the correct explanation.
53
Easy
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Remembering
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Choose the example of paramagnetic substance.
View answer and explanation
Correct option: B
Option B () is correct because oxygen molecules have two unpaired electrons, making it paramagnetic.
54
Medium
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Understanding
+4 | -1
Effective magnetic moment of ion is
View answer and explanation
Correct option: B
0
Option D (1) is correct because each carbon atom in graphite is sp2 hybridized, leaving one free electron.
55
Medium
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Understanding
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and formed in the following reactions are:
View answer and explanation
Correct option: A
Option A () is correct because the reaction of chromyl chloride with NaOH forms sodium chromate, and the subsequent reaction with HCl and H2O2 forms chromium pentoxide.
56
Medium
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Understanding
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An aqueous solution of and gives a deep blue complex of:
View answer and explanation
Correct option: A
Cuprammonium sulphate
Option A is correct because the deep blue complex formed is cuprammonium sulphate, which has the formula [Cu(NH3)4]SO4.
57
Medium
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Understanding
+4 | -1
The magnetic nature of elements depends on the presence of unpaired electrons. Identify the configuration of transition element which shows highest magnetic moment.
View answer and explanation
Correct option: B
Option B is correct because the configuration has the maximum number of unpaired electrons (5), leading to the highest magnetic moment.
58
Medium
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Analyzing
+4 | -1
Assertion: Europium (II) is more stable than cerium (II).
Reason: Cerium salts are used as catalyst in petroleum cracking.
Reason: Cerium salts are used as catalyst in petroleum cracking.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion) is correct because both the assertion about Europium(II) stability and the reason about Cerium salts being catalysts are true, but unrelated.
59
Easy
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Analyzing
+4 | -1
The electronic configuration of is , whereas that of is . Which of the following is correct?
View answer and explanation
Correct option: A
(II) is more stable
Option A (Cu(II) is more stable) is correct because although Cu(I) has a stable configuration, Cu(II) is more stable in aqueous solution due to its higher hydration energy which compensates for the energy needed for the second ionization.
60
Medium
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Understanding
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The transition element having least enthalpy of atomisation is
View answer and explanation
Correct option: A
Option D (At high temperature and low pressure) is correct because at high temperature and low pressure, the intermolecular forces and volume occupied by gas molecules become negligible, thus behaving like an ideal gas.
Revision notes and key takeaways
Review d & f- BLOCK ELEMENTS in your textbook or class notes, then use this set to check your understanding.
Showing 31-60 of 410 questions
