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JEE • CHEMISTRY • d & f- BLOCK ELEMENTS

D & f- BLOCK ELEMENTS practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 301-330 of 410 questions

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301 Medium
301 of 410
Analyzing +4 | -1
What happens when a molten mixture of K2FeO4\mathrm{K}_2 \mathrm{FeO}_4 and K2CrO4\mathrm{K}_2 \mathrm{CrO}_4 is acidified?
View answer and explanation
Correct option: D
FeO42−\mathrm{FeO}_4{ }^{2-} is reduced to Fe3+\mathrm{Fe}^{3+} liberating O2\mathrm{O}_2
Option D is correct because in acidic conditions, FeO42−FeO_4^{2-} is unstable and gets reduced to Fe3+Fe^{3+} liberating oxygen gas.
302 Medium
302 of 410
Understanding +4 | -1
Among FeSO4⋅7H2O(A),CuSO4⋅5H2O(B)\mathrm{FeSO}_4 \cdot 7 \mathrm{H}_2 \mathrm{O}(A), \mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}(B), ZnSO4⋅7H2O(C),MnSO4⋅4H2O(D)\mathrm{ZnSO}_4 \cdot 7 \mathrm{H}_2 \mathrm{O}(C), \mathrm{MnSO}_4 \cdot 4 \mathrm{H}_2 \mathrm{O}(D) isomorphous salts are
View answer and explanation
Correct option: A
AA and CC
Option A (AA and CC) is correct because FeSO4⋅7H2O\mathrm{FeSO}_4 \cdot 7 \mathrm{H}_2 \mathrm{O} and ZnSO4⋅7H2O\mathrm{ZnSO}_4 \cdot 7 \mathrm{H}_2 \mathrm{O} have similar crystalline form and chemical composition, making them isomorphous.
303 Medium
303 of 410
Remembering +4 | -1
Consider the following statements.

1. The transition metals and their compounds exhibit catalytic property.

II. Transition metals also show paramagnetic behaviour. The correct statement(s) is/are (choose the correct option)
View answer and explanation
Correct option: C
Both I and II
Option C (Both I and II) is correct because transition metals exhibit both catalytic property and paramagnetic behavior.
304 Medium
304 of 410
Remembering +4 | -1
The highest oxidation state exhibited by transition metals is
View answer and explanation
Correct option: B
+8+ 8
Option B (+8+ 8) is correct because Osmium (Os) exhibits the highest oxidation state of +8 in OsO4\mathrm{Os}{\mathrm{O}_4}.
305 Medium
305 of 410
Understanding +4 | -1
When KIKI and CuSO4CuS{O_4} solutions are mixed , it gives
View answer and explanation
Correct option: B
Cu2I2+K2SO4C{u_2}{I_2} + {K_2}S{O_4}
Option B (Cu2I2+K2SO4Cu_2I_2 + K_2SO_4) is correct because when KI and CuSO4CuSO_4 solutions are mixed, Cu2+Cu^{2+} oxidizes I−I^- to I2I_2, which then reacts with more Cu2+Cu^{2+} to form insoluble Cu2I2Cu_2I_2.
306 Medium
306 of 410
Understanding +4 | -1
Europium (Eu) and Terbium (Tb) attain state 4f74 f^7 configuration by exhibiting oxidation states of
View answer and explanation
Correct option: A
#ERROR!
Option C is correct because Europium (Eu) attains a 4f7 configuration by losing two electrons to form Eu+2, and Terbium (Tb) attains a stable state after losing four electrons.
307 Medium
307 of 410
Remembering +4 | -1
Which of the following element is not a member of transition elements?
View answer and explanation
Correct option: C
Ce{Ce}
Option C is correct because Cerium (Ce) belongs to the lanthanide series and is an inner transition element, not a transition element.
308 Medium
308 of 410
Analyzing +4 | -1
The electronic configuration of Cu(II)\mathrm{Cu}(\mathrm{II}) is 3d93 d^9 while that of Cu(I)\mathrm{Cu}(\mathrm{I}) is 3d103 d^{10}. Identify the correct statement.
View answer and explanation
Correct option: B
Cu\mathrm{Cu} (II) is more stable
Option B is correct because Cu(II) is more stable due to its smaller size and higher effective nuclear charge.
309 Easy
309 of 410
Understanding +4 | -1
Which statement about Hg is correct?
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because all the statements about Hg are factual: it's the only liquid metal at room temperature, Hg2+ salts are more stable than Hg22+ salts, and it doesn't form amalgams with iron and platinum.
310 Medium
310 of 410
Understanding +4 | -1
V2O4{V}_2 {O}_4 when dissolve in acids gives
View answer and explanation
Correct option: C
VO2+{VO}^{2+}
The correct answer is C (VO2+{VO}^{2+}) because V2O4V_2O_4 dissolves in acids to form the vanadyl(IV) ion, VO2+VO^{2+}.
311 Easy
311 of 410
Understanding +4 | -1
The product A in the following equation, 2KMnO4→A+MnO2+O22KMn{O_4} \to A + Mn{O_2} + {O_2} is:
View answer and explanation
Correct option: B
K2MnO4{K_2}Mn{O_4}
Option B (K2MnO4{K_2}Mn{O_4}) is correct because the decomposition of KMnO4KMn{O_4} produces K2MnO4{K_2}Mn{O_4}, MnO2Mn{O_2}, and O2{O_2}.
312 Medium
312 of 410
Remembering +4 | -1
The alloy of steel that is used for making automobile parts and utensils is:
View answer and explanation
Correct option: A
Stainless steel
Option A (Stainless steel) is correct because stainless steel is known for its corrosion resistance and is commonly used in automobile parts and utensils.
313 Medium
313 of 410
Understanding +4 | -1
Most of the transition metals are paramagnetic due to the presence of:
View answer and explanation
Correct option: C
Unpaired electrons
Option C (Unpaired electrons) is correct because the presence of unpaired d-electrons in transition metals leads to paramagnetism due to their spin magnetic moments.
314 Medium
314 of 410
Analyzing +4 | -1
Assertion : 1st ionisation potential of mercury is greater than cadmium

Reason : Hg has stable electronic configuration (5d106s2)(5{d^{10}}6{s^2})
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct because while both statements are true, the stable electronic configuration is not the primary reason for mercury's higher ionization potential.
315 Medium
315 of 410
Application +4 | -1
When KMnO4{KMnO}_4 acts as an oxidizing agent and ultimately forms MnO42−,MnO2,Mn2O3{MnO}_4^{2-}, {MnO}_2, {Mn}_2 {O}_3 and Mn2+{Mn}^{2+} then the number of electrons transferred in each case respectively are
View answer and explanation
Correct option: A
1,3,4,51,3,4,5
Option A (1,3,4,51,3,4,5) is correct because it accurately represents the number of electrons transferred in each reduction step of KMnO4{KMnO}_4.
316 Easy
316 of 410
Understanding +4 | -1
The number of incomplete orbitals in inner transition elements is:
View answer and explanation
Correct option: A
3
Option B (90) is correct because 21.6 carat gold is 21.6/24 pure, which equals 90%.
317 Medium
317 of 410
Remembering +4 | -1
5f5f-level is successively filled up in:
View answer and explanation
Correct option: B
Actinoids
Option B (Actinoids) is correct because the 5f orbitals are progressively filled in the actinoid series.
318 Easy
318 of 410
Remembering +4 | -1
Manganese steel contains:
View answer and explanation
Correct option: A
Fe + C + Mn
Option A (Fe + C + Mn) is correct because manganese steel is an alloy of iron, carbon, and manganese, known for its high tensile strength and wear resistance.
319 Hard
319 of 410
Analyzing +4 | -1
I(aq)Θ+MnO4−(aq)→H+x+Mn(aq)+2I(aq)Θ+MnO4−(aq)→ weakly OHΘ neutral ( or )y+MnO2MnO4(aq)−+Mn(aq)+2→ZnSO4z+4H+\begin{aligned} & \mathrm{I}_{(\mathrm{a q})}^{\Theta}+\mathrm{MnO}_4^{-}(\mathrm{a q}) \xrightarrow{\mathrm{H}^{+}} \mathrm{x}+\mathrm{Mn}_{(\mathrm{a q})}^{+2} \\ & \mathrm{I}_{(\mathrm{a q})}^{\Theta}+\mathrm{MnO}_4^{-}(\mathrm{a q}) \xrightarrow[\text { weakly } \mathrm{OH}^{\Theta}]{\text { neutral }(\text { or })} \mathrm{y}+\mathrm{MnO}_2 \\ & \mathrm{MnO}_{4(\mathrm{a q})}^{-}+\mathrm{Mn}_{(\mathrm{a q})}^{+2} \xrightarrow{\mathrm{ZnSO}_4} \mathrm{z}+4 \mathrm{H}^{+} \end{aligned}
products x,y\mathrm{x}, \mathrm{y} and z\mathrm{z} are respectively
View answer and explanation
Correct option: A
I2,IO3−,MnO2\mathrm{I}_2, \mathrm{IO}_3^{-}, \mathrm{MnO}_2
Option A (I2,IO3−,MnO2\mathrm{I}_2, \mathrm{IO}_3^{-}, \mathrm{MnO}_2) is correct because it correctly identifies the products of the redox reactions under different pH conditions.
320 Easy
320 of 410
Understanding +4 | -1
Which one of the following indicates the correct order of atomic size?
View answer and explanation
Correct option: B
Ti<Zr=HfTi < Zr = Hf
Option B (Ti<Zr=HfTi < Zr = Hf) is correct because of the Lanthanoid contraction, which causes Zr and Hf to have similar atomic sizes.
321 Medium
321 of 410
Analyzing +4 | -1
Which of the following statement are correct about Zn,Cd{Zn}, {Cd} and Hg{Hg}?

A. They exhibit high enthalpy of atomization as the dd-subshell is full.

B. Zn{Zn} and Cd{Cd} do not show variable oxidation state while Hg{Hg} shows +I and +II.

C. Compounds of Zn,Cd{Zn}, {Cd} and Hg{Hg} are paramagnetic in nature.

D. Zn,Cd{Zn}, {Cd} and Hg{Hg} are called soft metals.

Choose the most appropriate from the options given below:
View answer and explanation
Correct option: A
B, D only
Option A (B, D only) is correct because Zinc, Cadmium, and Mercury do not have high enthalpy of atomization and their compounds are diamagnetic.
322 Medium
322 of 410
Remembering +4 | -1
Which of the following is correct?
View answer and explanation
Correct option: C
Gun metal: Cu  +  Zn  +  Sn\mathrm{Cu\;} + \mathrm{\;Zn\;} + \mathrm{\;Sn}
Option C (Gun metal: Cu  +  Zn  +  Sn\mathrm{Cu\;} + \mathrm{\;Zn\;} + \mathrm{\;Sn}) is correct because gun metal is an alloy of copper, zinc, and tin.
323 Easy
323 of 410
Remembering +4 | -1
Molten Ag absorbs about ……… times of O2{\mathrm{O}_2}:
View answer and explanation
Correct option: B
20
Option B (20) is the correct answer because molten Ag absorbs approximately 20 times its volume of O2{\mathrm{O}_2}.
324 Medium
324 of 410
Remembering +4 | -1
Copper becomes green when exposed to moist air for a long period. This is due to
View answer and explanation
Correct option: B
the formation of a layer of basic carbonate of copper on the surface of copper.
Option B (the formation of a layer of basic carbonate of copper on the surface of copper) is correct because copper reacts with carbon dioxide and moisture in the air to form a green layer of basic copper carbonate.
325 Medium
325 of 410
Analyzing +4 | -1
In context with the transition elements, which of the following statements is incorrect?
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Correct option: B
In the highest oxidation state, the transition metal shows basic character and form cationic complexes.
Option B is correct because in the highest oxidation state, transition metals tend to form acidic oxides and oxoanions, not basic compounds or cationic complexes.
326 Medium
326 of 410
Analyzing +4 | -1
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : In aqueous solutions Cr2+\mathrm{Cr}^{2+} is reducing while Mn3+\mathrm{Mn}^{3+} is oxidising in nature.

Reason (R) : Extra stability to half filled electronic configuration is observed than incompletely filled electronic configuration.

In the light of the above statement, choose the most appropriate answer from the options given below:
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A is correct because Cr2+ is reducing due to its tendency to form the stable half-filled t2g3 configuration of Cr3+, while Mn3+ is oxidizing due to the formation of the stable d5 configuration of Mn2+.
327 Medium
327 of 410
Understanding +4 | -1
Assertion (A) : Chromium can be used as a protective and non-corrosive plating on other metals.

Reason (R): Due to atmospheric oxidation, chemically a inert layer of Cr2O3\mathrm{Cr}_2 \mathrm{O}_3 is formed.
View answer and explanation
Correct option: B
Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is not the correct explanation of A\mathbf{A}.
Option B is correct because both the assertion and the reason are true, but the reason doesn't fully explain why chromium is used as a protective plating.
328 Medium
328 of 410
Remembering +4 | -1
Which of the following is philosopher’s wool?
View answer and explanation
Correct option: A
ZnO\mathrm{ZnO}
Option A (ZnO\mathrm{ZnO}) is correct because zinc oxide (ZnO\mathrm{ZnO}) is known as philosopher's wool due to its appearance.
329 Medium
329 of 410
Remembering +4 | -1
Which of the following does not react with oxygen directly?
View answer and explanation
Correct option: C
PtPt
Option C (PtPt) is correct because Platinum (PtPt) is a noble metal and does not readily react with oxygen directly.
330 Medium
330 of 410
Understanding +4 | -1
Assertion: Higher oxidation states in transition metals are more covalent than lower oxidation states.

Reason: Higher oxidation states involve more d-electrons than lower oxidation states.
View answer and explanation
Correct option: A
Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.
Option A (Both assertion and reason are correct statements, and reason is the correct explanation of the assertion) is correct because higher oxidation states lead to greater polarization and thus more covalent character.
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