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JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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Application +4 | -1
The one which has lowest ox. no. of Hg:
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Correct option: D
Hg2Cl2\mathrm{H}{\mathrm{g}_2}\mathrm{C}{\mathrm{l}_2}
Option D (Hg2Cl2\mathrm{H}{\mathrm{g}_2}\mathrm{C}{\mathrm{l}_2}) is correct because in this compound, mercury exists as Hg22+, giving it an oxidation state of +1.

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