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JEE • CHEMISTRY • ALDEHYDES & KETONES & CARBOXYLIC ACIDS

Aldehydes & ketones & carboxylic acids practice · Medium

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91 Medium
91 of 165
Understanding +4 | -1
Acetaldehyde gives orange coloured precipitate on treatment with
View answer and explanation
Correct option: A
2,4 - DNP
Option A (2,4 - DNP) is correct because acetaldehyde reacts with 2,4-Dinitrophenylhydrazine (2,4-DNP) to form an orange-colored precipitate of 2,4-Dinitrophenylhydrazone.
92 Medium
92 of 165
Analyzing +4 | -1
C4H8Cl2(X)→ aq. Acetone C4H8O(Y)→ΔNaOH,I2CHI3+\mathrm{C}_4 \mathrm{H}_8 \mathrm{Cl}_2(\mathrm{X}) \xrightarrow{\text { aq. Acetone }} \mathrm{C}_4 \mathrm{H}_8 \mathrm{O}(\mathrm{Y}) \xrightarrow[\Delta]{\mathrm{NaOH}, \mathrm{I}_2} \mathrm{CHI}_3+ Acid Salt (Z)(\mathrm{Z}). Compound X\mathrm{X} can be:
View answer and explanation
Correct option: C
CH3−C(Cl2)−CH2−CH3\mathrm{CH}_3-\mathrm{C}\left(\mathrm{Cl}_2\right)-\mathrm{CH}_2-\mathrm{CH}_3
The correct answer is C (CH3−C(Cl2)−CH2−CH3\mathrm{CH}_3-\mathrm{C}(\mathrm{Cl}_2)-\mathrm{CH}_2-\mathrm{CH}_3) because it forms a methyl ketone upon reaction with aqueous acetone, which then undergoes the iodoform reaction.
93 Medium
93 of 165
Remembering +4 | -1
Which of the following is Lindlar catalyst?
View answer and explanation
Correct option: B
Partially deactivated palladised charcoal
Option B (Partially deactivated palladised charcoal) is correct because Lindlar's catalyst is palladium on calcium carbonate, poisoned with lead or quinoline, used for the partial reduction of alkynes to cis-alkenes.
94 Medium
94 of 165
Analyzing +4 | -1
Among the following, the most acidic is
View answer and explanation
Correct option: C
Cl2CHCOOH\mathrm{C}{\mathrm{l}_2}\mathrm{CHCOOH}
Option C (Cl2CHCOOH) is correct because the presence of more electron-withdrawing chlorine atoms closer to the carboxylic acid group increases acidity.
95 Medium
95 of 165
Remembering +4 | -1
Acetone is used:
View answer and explanation
Correct option: D
All are correct
Option D (All are correct) is correct because acetone is used as a solvent, in nail polishes, and for storing acetylene under pressure.
96 Medium
96 of 165
Understanding +4 | -1
In which of the following reactions, both oxidized and reduced forms of the same compound are obtained?
View answer and explanation
Correct option: B
Cannizzaro reaction
Option B (Cannizzaro reaction) is correct because it involves the self-oxidation and reduction of an aldehyde without alpha-hydrogens.
97 Medium
97 of 165
Understanding +4 | -1
Identify A and B in the following reaction
CH3−CH3←BCH3COOH→ACH3CH2OH                                  A                                                      B\begin{array}{l} \mathrm{C}{\mathrm{H}_3} - \mathrm{C}{\mathrm{H}_3}\xleftarrow{B}\mathrm{C}{\mathrm{H}_3}\mathrm{COOH}\xrightarrow{A}\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{OH}\\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\mathrm{A}\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\mathrm{B} \end{array}
View answer and explanation
Correct option: C
LiAlH4HI+red  P\mathrm{LiAl}{\mathrm{H}_4}\mathrm{HI} + \mathrm{red}\;\mathrm{ P}
Option C (LiAlH4HI+red  P\mathrm{LiAl}{\mathrm{H}_4}\mathrm{HI} + \mathrm{red}\;\mathrm{ P}) is correct because LiAlH4LiAlH_4 reduces carboxylic acid to alcohol, and HI/red P reduces it to alkane.
98 Medium
98 of 165
Analyzing +4 | -1
Through which of the following reactions number of carbon atoms can be increased in the chain?

(i) Grignard reaction

(ii) Cannizzaro's reaction

(iii) Aldol condensation

(iv) HVZ reaction

Choose the correct option.
View answer and explanation
Correct option: A
Only (iii) and (i)
Option A is correct because Grignard reaction and Aldol condensation are carbon-carbon bond forming reactions, thus increasing the number of carbon atoms in the chain.
99 Medium
99 of 165
Analyzing +4 | -1
Assertion (A): Benzaldehyde is more reactive than ethanal towards nucleophilic attack.

Reason (R): Both benzaldehyde and acetaldehyde have alpha hydrogens.
View answer and explanation
Correct option: D
Both (A) and (R) are false
Option D is correct. Benzaldehyde is less reactive than ethanal towards nucleophilic attack due to steric hindrance, and benzaldehyde does not have alpha hydrogens.
100 Medium
100 of 165
Remembering +4 | -1
Benzaldehyde can be prepared from benzene by passing vapours of ____ and ____ in its solution in presence of catalyst mixture of aluminium chloride and cuprous chloride. The reaction is known is _____
View answer and explanation
Correct option: B
CO,HCl{CO}, {HCl}, Gattermann-Koch reaction
Option B (CO,HCl{CO}, {HCl}, Gattermann-Koch reaction) is correct because the Gattermann-Koch reaction uses carbon monoxide and hydrochloric acid in the presence of a catalyst to convert benzene to benzaldehyde.
101 Medium
101 of 165
Remembering +4 | -1
Salol (phenyl salicylate ) is used as an:
View answer and explanation
Correct option: D
Intestinal antiseptic
Option D (Intestinal antiseptic) is correct because Salol (phenyl salicylate) is used as an intestinal antiseptic due to its ability to break down into salicylic acid and phenol in the intestines.
102 Medium
102 of 165
Analyzing +4 | -1
Statement I: Acetaldehyde cannot be prepared by the Rosenmund reduction.

Statement II: Formyl chloride is unstable at room temperature.
View answer and explanation
Correct option: D
Statement II is correct, Statement I is incorrect.
Statement II is correct, Statement I is incorrect because Rosenmund reduction cannot be used to prepare formaldehyde, not acetaldehyde, due to the instability of formyl chloride.
103 Medium
103 of 165
Understanding +4 | -1
Which of the following compound is least reactive towards hydrolysis?
View answer and explanation
Correct option: A
Acetamide
Option A (Acetamide) is correct because amides are generally less reactive towards hydrolysis compared to acid chlorides, anhydrides, and esters due to resonance stabilization.
104 Medium
104 of 165
Analyzing +4 | -1
2-pentanone and 3-petanone can be distinguished by
View answer and explanation
Correct option: C
Iodoform reaction
Option C (Iodoform reaction) is correct because 2-pentanone has a methyl ketone group (CH₃CO) that reacts with I₂/NaOH to give a positive iodoform test, while 3-pentanone does not.
105 Medium
105 of 165
Understanding +4 | -1
Which will not give acetamide (no heating) on reaction with ammonia?
View answer and explanation
Correct option: A
Acetic acid
Option A (Acetic acid) is correct because acetic acid reacts with ammonia to form ammonium acetate, which requires heating to form acetamide.
106 Medium
106 of 165
Remembering +4 | -1
Rosenmund’s reduction is used for the preparation of
View answer and explanation
Correct option: B
Aldehyde
Option B (Aldehyde) is correct because Rosenmund's reduction is used for the preparation of aldehydes from acyl chlorides.
107 Medium
107 of 165
Understanding +4 | -1
The number of aldehyde isomers for C4H8O{C_4}{H_8}O will be
View answer and explanation
Correct option: C
2
Option C (2) is correct because there are two aldehyde isomers for C4H8O: butanal and 2-methylpropanal.
108 Medium
108 of 165
Remembering +4 | -1
The elimination of CO2\mathrm{C}{\mathrm{O}_2} from a carboxylic acid is known as:
View answer and explanation
Correct option: C
Decarboxylation
Option C (Decarboxylation) is correct because decarboxylation is the process of removing a carboxyl group (COOH) from a molecule, releasing carbon dioxide.
109 Medium
109 of 165
Analyzing +4 | -1
Formaldehyde and formic acid can be distinguished by:
View answer and explanation
Correct option: D
NaHCO3\mathrm{NaHC}{\mathrm{O}_3}
Option D (NaHCO3\mathrm{NaHC}{\mathrm{O}_3}) is correct because formic acid reacts with sodium bicarbonate to produce carbon dioxide gas, while formaldehyde does not.
110 Medium
110 of 165
Application +4 | -1
0.759 g of a silver salt of a dibasic organic acid on ignition left 0.463 g metallic silver. The equivalent weight of acid is:
View answer and explanation
Correct option: A
70
Option A (70) is correct because the equivalent weight of the acid is calculated using the equivalent weights of the silver salt and silver.
111 Medium
111 of 165
Remembering +4 | -1
Ketones can be converted to alkanes directly on reaction with
View answer and explanation
Correct option: C
HI/P4/Δ{HI} / {P}_4 / \Delta
Option C (HI/P4/Δ{HI} / {P}_4 / \Delta) is correct because ketones can be directly converted to alkanes using HI and red phosphorus under heating conditions.
112 Medium
112 of 165
Analyzing +4 | -1
An organic compound is boiled with alcoholic potash. The product is cooled and acidified with HCl. A white solid separates out. The starting compound may be
View answer and explanation
Correct option: A
Ethyl benzoate
Option A (Ethyl benzoate) is correct because it undergoes saponification with alcoholic potash to form potassium benzoate, which upon acidification yields benzoic acid (a white solid).
113 Medium
113 of 165
Understanding +4 | -1
Assertion (A): A bright silver mirror is produced during the warming of an aldehyde with freshly prepared ammoniacal silver nitrate solution.

Reason (R): A bright silver mirror is produced due to the formation of silver metal.
View answer and explanation
Correct option: A
Both A\mathrm{A} and R\mathrm{R} are correct; and R\mathrm{R} is the correct explanation of A\mathrm{A}.
The correct answer is Both A\mathrm{A} and R\mathrm{R} are correct; and R\mathrm{R} is the correct explanation of A\mathrm{A} because the formation of a silver mirror is due to the reduction of silver ions to silver metal by the aldehyde.
114 Medium
114 of 165
Analyzing +4 | -1
The most acidic of the following is
View answer and explanation
Correct option: A
ClCH2COOH\mathrm{ClC}{\mathrm{H}_2}\mathrm{COOH}
Option A (ClCH2COOH\mathrm{ClC}{\mathrm{H}_2}\mathrm{COOH}) is correct because the electron-withdrawing chlorine atom increases the acidity through the -I effect.
115 Medium
115 of 165
Application +4 | -1
Nitration of salicylic acid will give:
View answer and explanation
Correct option: A
2,4,6-trinitophenol
Option A (2,4,6-trinitrophenol) is correct because the -COOH group of salicylic acid is replaced during nitration, leading to the formation of picric acid (2,4,6-trinitrophenol).
116 Medium
116 of 165
Application +4 | -1
The products A and B are
(CH3)3C−CHO→ (ii) H+(i) con.NaOHA+B\left(\mathrm{CH}_3\right)_3 \mathrm{C}-\mathrm{CHO} \xrightarrow[\text { (ii) } \mathrm{H}^{+}]{\text {(i) } \mathrm{con.}{\mathrm{NaOH}}} \mathrm{A}+\mathrm{B}
View answer and explanation
Correct option: C
A=(CH3)3C−CH2−OH,B=(CH3)3C−COOH\mathrm{A}=\left(\mathrm{CH}_3\right)_3 \mathrm{C}-\mathrm{CH}_2-\mathrm{OH}, \mathrm{B}=\left(\mathrm{CH}_3\right)_3 \mathrm{C}-\mathrm{COOH}
Option C (A=(CH3)3C-CH2-OH, B=(CH3)3C-COOH) is correct because the reaction is a Cannizzaro reaction, which produces an alcohol and a carboxylic acid.
117 Medium
117 of 165
Understanding +4 | -1
The strongest acid is:
View answer and explanation
Correct option: D
CHF2COOH\mathrm{CH}{\mathrm{F}_2}\mathrm{COOH}
Option D (CHF2COOH\mathrm{CH}{\mathrm{F}_2}\mathrm{COOH}) is correct because the acidity increases with the number of fluorine atoms due to the strong -I effect of fluorine.
118 Medium
118 of 165
Understanding +4 | -1
The correct order of acidic strengths of the carboxylic acids is
View answer and explanation
Correct option: D
Acetic acid < benzoic acid < formic acid
Option D (Acetic acid < benzoic acid < formic acid) is correct because electron-donating groups decrease acidity, and formic acid is more acidic than benzoic acid due to resonance stabilization.
119 Medium
119 of 165
Understanding +4 | -1
Read the following statements and choose the correct option

(i) The carbonyl carbon atom is sp2\mathrm{sp}^2-hybridised

(ii) The carbonyl carbon is an electrophilic (Lewis acid) centre

(iii) The carbonyl oxygen is a nucleophilic (Lewis base) centre

(iv) Carbonyl compounds are non- polar in nature.
View answer and explanation
Correct option: B
(i), (ii) and (iii) are correct
Option B ((i), (ii) and (iii) are correct) is correct because carbonyl carbon is sp2sp^2 hybridized, electrophilic, and carbonyl oxygen is nucleophilic, while carbonyl compounds are polar.
120 Medium
120 of 165
Understanding +4 | -1
On warming formic acid with ammoniacal silver nitrate, the product formed is:
View answer and explanation
Correct option: B
Metallic silver
Option B (Metallic silver) is correct because formic acid reduces ammoniacal silver nitrate to metallic silver.
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