Benzaldehyde, when heated with concentrated ${\rm{KOH}}$ solution, gives:

Mixture of ${{\rm{C}}_6}{{\rm{H}}_5}{\rm{COOK}}\,{\rm{\;and\;}}\,\,{{\rm{C}}_6}{{\rm{H}}_5}{\rm{C}}{{\rm{H}}_2}{\rm{OH}}$

${{\rm{C}}_6}{{\rm{H}}_5}{\rm{C}}{{\rm{H}}_2}{\rm{OH}}$

${{\rm{C}}_6}{{\rm{H}}_5}{\rm{COOH}}$

${{\rm{C}}_6}{{\rm{H}}_5}{\rm{COOK}}$

Back to ALDEHYDES & KETONES & CARBOXYLIC ACIDS

Your Progress

0 / 56 Answered

Correct

Incorrect

Accuracy

JEE • CHEMISTRY • ALDEHYDES & KETONES & CARBOXYLIC ACIDS

Aldehydes & ketones & carboxylic acids practice · Easy

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →

Showing 31-56 of 56 questions

Preparing practice and saved progress…

31 Easy

31 of 56

Understanding +4 | -1

Which part of —COOH group is involved in the reaction of acid with metals?

View answer and explanation

Correct option: A

Only H-atom

Option A (Only H-atom) is correct because the reaction of an acid with a metal involves the replacement of the hydrogen atom from the -COOH group with the metal, releasing hydrogen gas.

32 Easy

32 of 56

Remembering +4 | -1

Aldchydes and ketones are prepared by the oxidation of

View answer and explanation

Correct option: A

primary and secondary alcohols

Option A (primary and secondary alcohols) is correct because primary alcohols oxidize to aldehydes, and secondary alcohols oxidize to ketones.

33 Easy

33 of 56

Remembering +4 | -1

Salicylaldehyde forms from phenol by reacting with which reagent?

View answer and explanation

Correct option: B

\mathrm{CHCl}_3, \mathrm{NaOH}

Option B (

\mathrm{CHCl}_3, \mathrm{NaOH}

) is correct because salicylaldehyde is formed from phenol via the Reimer-Tiemann reaction using chloroform and sodium hydroxide.

34 Easy

34 of 56

Remembering +4 | -1

Tollen’s reagent is

View answer and explanation

Correct option: A

\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]N{O_3}

Option A is correct because Tollen's reagent is an ammoniacal silver nitrate solution, specifically [Ag(NH3)2]NO3.

35 Easy

35 of 56

Remembering +4 | -1

Acetaldehyde on oxidation with

{Se{O_2}}

gives:

View answer and explanation

Correct option: C

CHO \cdot CHO

Option C (CHO · CHO) is correct because acetaldehyde oxidation with

Se{O_2}

yields glyoxal.

36 Easy

36 of 56

Understanding +4 | -1

Silver chloride dissolves in excess of

N{H_3}

solution. The cation present in solution is

View answer and explanation

Correct option: C

{\left[ {Ag{{(N{H_3})}_2}} \right]^ + }

Option C (

{\left[ {Ag{{(N{H_3})}_2}} \right]^ + }

) is correct because silver chloride reacts with excess ammonia to form the diamminesilver(I) complex ion,

{\left[ {Ag{{(N{H_3})}_2}} \right]^ + }

37 Easy

37 of 56

Understanding +4 | -1

Benzaldehyde, when heated with concentrated

\mathrm{KOH}

solution, gives:

View answer and explanation

Correct option: D

Mixture of

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{COOK}\,\mathrm{\;and\;}\,\,{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{OH}

Option D is correct because benzaldehyde undergoes Cannizzaro reaction in the presence of concentrated KOH, yielding a mixture of potassium benzoate and benzyl alcohol.

38 Easy

38 of 56

Understanding +4 | -1

Reaction of a carbonyl compound with one of the following reagents involves nucleophilic addition followed by elimination of water. The reagent is:

View answer and explanation

Correct option: D

Hydrazine in presence of feebly acidic solution

Option D (Hydrazine in presence of feebly acidic solution) is correct because hydrazine reacts with carbonyl compounds via nucleophilic addition followed by water elimination to form hydrazones.

39 Easy

39 of 56

Understanding +4 | -1

Ethane can be obtained from ethanal in one step by:

View answer and explanation

Correct option: B

Zn-Hg + conc. HCl

Option B (Zn-Hg + conc. HCl) is correct because Clemmensen reduction uses zinc amalgam and concentrated hydrochloric acid to reduce carbonyl groups (C=O) to methylene groups (CH2).

40 Easy

40 of 56

Remembering +4 | -1

Acetophenone is used in:

View answer and explanation

Correct option: C

Perfumery

Option C (Perfumery) is correct because acetophenone has a pleasant odor and is commonly used as a fragrance component in perfumes.

41 Easy

41 of 56

Understanding +4 | -1

The reaction of acetaldehyde with Tollen’s reagent gives

View answer and explanation

Correct option: D

Acetic acid

Option D (Acetic acid) is correct because acetaldehyde is oxidized to acetic acid when it reacts with Tollen's reagent, which is a mild oxidizing agent.

42 Easy

42 of 56

Remembering +4 | -1

In the

\alpha -

halogenation of aliphatic acids (HVZ reaction) the catalyst used is:

View answer and explanation

Correct option: B

Option B (P) is correct because phosphorus is used as a catalyst in the Hell-Volhard-Zelinsky (HVZ) reaction.

43 Easy

43 of 56

Remembering +4 | -1

Acetaldehyde is used:

View answer and explanation

Correct option: D

All are correct

Option D (All are correct) is correct because acetaldehyde is used in the preparation of dyes, chloral, and paraldehyde.

44 Easy

44 of 56

Understanding +4 | -1

An acyl halide is formed when

\mathrm{PC}{\mathrm{l}_5}

reacts with an:

View answer and explanation

Correct option: A

Acid

Option A is correct because acyl halides are formed when PCl5 reacts with carboxylic acids.

45 Easy

45 of 56

Remembering +4 | -1

Vinegar is a solution of acetic acid which is

View answer and explanation

Correct option: C

6 - 8\mathrm{ }\%

Option C (

6 - 8\mathrm{ }\%

) is correct because vinegar is defined as a 6-8% solution of acetic acid in water.

Explore Other Chapters in CHEMISTRY

View All →

P-BLOCK ELEMENTS 736 MCQs Equilibrium 696 MCQs STRUCTURE OF ATOM 634 MCQs THERMODYNAMICS 536 MCQs CHEMICAL BONDING & MOLECULAR STRUCTURE 514 MCQs SOLUTIONS 480 MCQs

46 Easy

46 of 56

Remembering +4 | -1

Wolff-Kishner’s reaction is:

View answer and explanation

Correct option: A

Reduction of carbonyl compound into hydrocarbons

Option A (Reduction of carbonyl compound into hydrocarbons) is correct because the Wolff-Kishner reaction reduces carbonyl groups (C=O) to methylene groups (CH2).

47 Easy

47 of 56

Analyzing +4 | -1

Statement I : Benzoic acid is stronger than acetic acid
Statement II : Acetate ion is a weaker base than benzoate ion

View answer and explanation

Correct option: A

Only Statement I is correct

Option A (Only Statement I is correct) is correct because benzoic acid is indeed stronger than acetic acid due to the resonance stabilization of the benzoate ion, while the acetate ion is less stabilized.

48 Easy

48 of 56

Analyzing +4 | -1

Assertion: Fehling’s solution can be used to distinguish benzaldehyde from
acetaldehyde.

Reason: The

C—H

bond of

CHO

group in benzaldehyde is stronger than

C—H

bond
of

CHO

group in acetaldehyde.

View answer and explanation

Correct option: A

Both A and R are correct and R is correct explanation of A

The correct answer is A because Fehling's solution can distinguish benzaldehyde from acetaldehyde, and the C-H bond in benzaldehyde's CHO group is indeed stronger than in acetaldehyde's.

49 Easy

49 of 56

Understanding +4 | -1

Carboxylic acids react with diazomethane to yield:

View answer and explanation

Correct option: C

Esters

Option C (Esters) is correct because carboxylic acids react with diazomethane to form methyl esters and nitrogen gas.

50 Easy

50 of 56

Understanding +4 | -1

General formula of saturated carboxylic acid is:

View answer and explanation

Correct option: C

Both (a) and (b)

Option C (Both (a) and (b)) is correct because both formulas represent a saturated carboxylic acid.

51 Easy

51 of 56

Understanding +4 | -1

What is the neutralization equivalent of benzoic acid?

View answer and explanation

Correct option: A

122

Option A (122) is correct because benzoic acid is a monobasic acid, so its molecular weight equals its neutralization equivalent.

52 Easy

52 of 56

Understanding +4 | -1

Aldehyde not showing Cannizaro’s reaction is

View answer and explanation

Correct option: D

Acetaldehyde

Option D (Acetaldehyde) is correct because Cannizzaro's reaction requires the absence of α-hydrogen atoms, and acetaldehyde possesses three α-hydrogen atoms.

53 Easy

53 of 56

Remembering +4 | -1

Which element is not present in Nessler’s reagent?

View answer and explanation

Correct option: B

Oxygen

Option B (Oxygen) is correct because Nessler's reagent is

K_2[HgI_4]

, which does not contain oxygen.

54 Easy

54 of 56

Remembering +4 | -1

Ketone can be obtained by oxidation of:

View answer and explanation

Correct option: B

Secondary alcohol

Option B (Secondary alcohol) is correct because secondary alcohols oxidize to form ketones.

55 Easy

55 of 56

Remembering +4 | -1

In Stephen's reduction, which of the following group is converted to

-\mathrm{CHO}

group?

View answer and explanation

Correct option: C

-\mathrm{CN}

Option C (

-\mathrm{CN}

) is correct because Stephen's reduction specifically reduces nitriles to aldehydes.

56 Easy

56 of 56

Remembering +4 | -1

The group present in waxes are

View answer and explanation

Correct option: B

ester group

Option B (ester group) is correct because waxes are esters of long-chain fatty acids and monohydric alcohols.

Revision notes and key takeaways

Review ALDEHYDES & KETONES & CARBOXYLIC ACIDS in your textbook or class notes, then use this set to check your understanding.

Showing 31-56 of 56 questions

Your Progress

Aldehydes & ketones & carboxylic acids practice · Easy

Explore Other Chapters in CHEMISTRY

Continue Your Practice

Your practice