Alcohols & phenols & ethers practice · Mixed difficulty

Option A is correct because the alcohol P is oxidized to a ketone B, which then reacts with Grignard reagent to form a tertiary alcohol after hydrolysis, indicating P must be a secondary alcohol.

Option C (Zymase) is correct because zymase is the enzyme complex that catalyzes the fermentation of glucose and fructose into ethanol.

Option D ($ZnO - C{r_2}{O_3}$) is correct because a mixture of zinc oxide and chromium(III) oxide is used as a catalyst in the synthesis of methanol from carbon monoxide and hydrogen.

Option B is correct because both the assertion and reason are correct, but the reason (sodium methoxide being a strong nucleophile) doesn't explain why tert-butyl methyl ether isn't formed; elimination is favored due to steric hindrance.

Option C (Ethanol) is correct because ethanol, a compound containing a hydroxyl group, is commonly used as a solvent in wood polishes.

Option D (All of these) is correct because $KHS{{O}}_4$, ${{P}}_2{{O}}_5$, and concentrated ${{H}}_2{{SO}}_4$ are all dehydrating agents that can dehydrate glycerol to form acrolein.

Option C ($1^{\circ}, 2^{\circ}$ and $3^{\circ}$ alcohols) is correct because the Lucas test, using Lucas reagent (anhydrous $ZnCl_2$ and HCl), differentiates between primary, secondary, and tertiary alcohols based on the rate of formation of alkyl halides.

Option C ($\mathrm{CH_3OH}$) is correct because carbinol is the trivial name for methanol ($\mathrm{CH_3OH}$).

Option D is correct because phenol is less acidic than carbonic acid ($H_2CO_3$), and phenol does not react with $NaHCO_3$ solution due to its lower acidity.

Option C ($\mathrm{C}_2 \mathrm{H}_5 \mathrm{Cl}+\mathrm{C}_2 \mathrm{H}_5 \mathrm{ONa}$) is correct because Williamson's ether synthesis involves the reaction of a primary alkyl halide with an alkoxide.

Option C (Fermentation) is correct because fermentation by Acetyl bacilli is the process used to obtain acetic acid from ethyl alcohol.

Option B (Phenol) is correct because Carbolic acid is a common name for Phenol (${\mathrm{C}_6}{\mathrm{H}_5}\mathrm{OH}$).

Option C (Glycerol) is correct because Dunstan's test is specifically used to identify the presence of glycerol.