${\rm{A}}{{\rm{l}}_2}{{\rm{O}}_3}{\rm{.}}{{\rm{H}}_2}{\rm{O}}$

${\rm{A}}{{\rm{l}}_2}{\left( {{\rm{S}}{{\rm{O}}_4}} \right)_3}$

Solid ${\rm{C}}{{\rm{O}}_2}$ is known as dry ice, because

It evaporates at $ - '{\rm{ }}78^\circ C$ without melting

Its boiling points is more than $199^\circ C$

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JEE • CHEMISTRY • 14 TH GROUP ELEMENTS (P-BLOCK)

14 th group elements (p-block) practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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61 Easy

61 of 85

Remembering +4 | -1

With which of the following metals,

\mathrm{CO}

forms a volatile carbonyl complex?

View answer and explanation

Correct option: C

\mathrm{Ni}

Option C (

\mathrm{Ni}

) is correct because nickel reacts with carbon monoxide to form a volatile carbonyl complex,

\mathrm{Ni(CO)_4}

62 Easy

62 of 85

Understanding +4 | -1

Diamond and graphite both are made of carbon atoms. Diamond is extremely hard whereas graphite is soft. This is because :

View answer and explanation

Correct option: C

Each carbon atom in diamond is chemically bonded to a greater number of neighbouring carbon atoms

Option C (Redox reaction) is correct because Cobalt (Co) is oxidized (loses electrons) and Copper (Cu) is reduced (gains electrons) in the reaction.

63 Easy

63 of 85

Remembering +4 | -1

In petrochemical industry, alcohols are directly converted to gasoline by passing over heated

View answer and explanation

Correct option: D

ZSM-5

Option D (ZSM-5) is correct because ZSM-5 is a zeolite catalyst used to convert alcohols directly into gasoline.

64 Easy

64 of 85

Remembering +4 | -1

An insulator is:

View answer and explanation

Correct option: D

Diamond

Option D (Diamond) is correct because diamond has a very high electrical resistivity, making it an excellent insulator.

65 Easy

65 of 85

Analyzing +4 | -1

Which of the following is not isostructural with

Si{F_4}

View answer and explanation

Correct option: A

S{F_4}

The correct answer is A (SF4) because SiF4, ClO4-, XeO4, and CCl4 are all tetrahedral, while SF4 has a see-saw shape due to the presence of a lone pair on the sulfur atom.

66 Easy

66 of 85

Understanding +4 | -1

Which among the following does not show catenation?

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Correct option: C

\mathrm{Pb}

Option C (

\mathrm{Pb}

) is correct because lead does not exhibit catenation due to its large size and weak bonding.

67 Easy

67 of 85

Remembering +4 | -1

Bell metal is an alloy of :

View answer and explanation

Correct option: B

Cu + Sn

Option B (Cu + Sn) is correct because bell metal is an alloy primarily composed of copper and tin.

68 Easy

68 of 85

Remembering +4 | -1

Silicon is usually found in :

View answer and explanation

Correct option: A

Sand

Option A (Sand) is correct because sand is primarily composed of silica (

\mathrm{SiO}_2

), which is a compound of silicon and oxygen.

69 Easy

69 of 85

Remembering +4 | -1

The main constituents of coal gas are:

View answer and explanation

Correct option: A

\mathrm{C}{\mathrm{H}_4} + \mathrm{CO} + {\mathrm{H}_2}

Option A (

\mathrm{C}{\mathrm{H}_4} + \mathrm{CO} + {\mathrm{H}_2}

) is correct because coal gas primarily consists of methane, carbon monoxide, and hydrogen.

70 Easy

70 of 85

Remembering +4 | -1

In laboratory silicon can be prepared by the reaction

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Correct option: A

Silica with magnesium

Option A (Silica with magnesium) is correct because silicon can be prepared in the laboratory by reducing silica (SiO2) with magnesium.

71 Easy

71 of 85

Remembering +4 | -1

The silicon compound which is used as lubricant and in cosmetic implant is

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Correct option: C

Silicone

The correct answer is C (Silicone) because silicones are widely used as lubricants and in cosmetic implants due to their properties.

72 Easy

72 of 85

Remembering +4 | -1

Which is correct oxidation state of lead?

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Correct option: D

#ERROR!

Option D (+2, +4) is correct because lead exhibits +2 and +4 oxidation states due to the inert pair effect.

73 Easy

73 of 85

Remembering +4 | -1

Glass reacts with HF to produce

View answer and explanation

Correct option: B

\mathrm{Si}{\mathrm{F}_4}

Option B (

\mathrm{Si}{\mathrm{F}_4}

) is correct because silicon dioxide in glass reacts with hydrofluoric acid to form silicon tetrafluoride and water.

74 Easy

74 of 85

Remembering +4 | -1

Carborundum is

View answer and explanation

Correct option: A

\mathrm{SiC}

Option A (

\mathrm{SiC}

) is correct because Carborundum is the common name for silicon carbide, which has the formula

\mathrm{SiC}

75 Easy

75 of 85

Remembering +4 | -1

Which element has a limited coordination number of four?

View answer and explanation

Correct option: B

Option C (Si) is incorrect. Option B (C) is correct because carbon, due to the absence of available d-orbitals in its valence shell, cannot expand its octet and thus has a maximum coordination number of four.

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P-BLOCK ELEMENTS 736 MCQs Equilibrium 696 MCQs STRUCTURE OF ATOM 634 MCQs THERMODYNAMICS 536 MCQs CHEMICAL BONDING & MOLECULAR STRUCTURE 514 MCQs SOLUTIONS 480 MCQs

76 Easy

76 of 85

Understanding +4 | -1

Which is not a characteristic property of carbon?

View answer and explanation

Correct option: C

Availability of d-orbitals for bonding

Option C (Availability of d-orbitals for bonding) is correct because carbon, being a second-period element, does not have d-orbitals available for bonding.

77 Easy

77 of 85

Remembering +4 | -1

The inert form of carbon is:

View answer and explanation

Correct option: A

Diamond

Option A (Diamond) is correct because diamond has a strong, rigid tetrahedral structure, making it chemically inert.

78 Easy

78 of 85

Remembering +4 | -1

Which is not used as pigment in paints?

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Correct option: A

Lead dioxide

Option A (Lead dioxide) is correct because lead dioxide is not typically used as a pigment in paints.

79 Easy

79 of 85

Understanding +4 | -1

The halides of Group 13 elements are

View answer and explanation

Correct option: A

Lewis acids

Option A (Lewis acids) is correct because Group 13 halides have an incomplete octet and can accept electron pairs.

80 Easy

80 of 85

Remembering +4 | -1

Which is not used as a refrigerant?

View answer and explanation

Correct option: D

CO

Option D (

CO

) is correct because

NH_3

CO_2

, and

CCl_2F_2

(Freon) are all commonly used refrigerants, while carbon monoxide (

CO

) is not.

81 Easy

81 of 85

Remembering +4 | -1

Which of the following is used in making printer’s ink, shoe polish, black varnish and paint?

View answer and explanation

Correct option: A

Lamp black

Option A (Lamp black) is correct because it is a fine black pigment produced by the incomplete combustion of heavy petroleum products and is commonly used in printer's ink, shoe polish, black varnish, and paint.

82 Easy

82 of 85

Remembering +4 | -1

In graphite, the sheets are held by :

View answer and explanation

Correct option: C

Van der Waals’ forces

Option C (Van der Waals’ forces) is correct because the sheets of carbon atoms in graphite are held together by weak Van der Waals’ forces.

83 Easy

83 of 85

Remembering +4 | -1

Which compound is solid?

View answer and explanation

Correct option: D

\mathrm{Si}{\mathrm{O}_2}

Option D (

\mathrm{SiO}_2

) is correct because silicon dioxide (

\mathrm{SiO}_2

) exists as a solid with a giant network structure at room temperature.

84 Easy

84 of 85

Remembering +4 | -1

Solid

\mathrm{C}{\mathrm{O}_2}

is known as dry ice, because

View answer and explanation

Correct option: D

It evaporates at

- '\mathrm{ }78^\circ C

without melting

Option D is correct because solid CO2, known as dry ice, undergoes sublimation at -78°C without melting into a liquid state.

85 Easy

85 of 85

Understanding +4 | -1

Fullerenes are the pure form of carbon because

View answer and explanation

Correct option: C

Fullerenes do not have dangling edge or surface bonds

Option C (Fullerenes do not have dangling edge or surface bonds) is correct because the absence of dangling bonds makes fullerenes chemically stable and a pure form of carbon.

Revision notes and key takeaways

Review 14 TH GROUP ELEMENTS (P-BLOCK) in your textbook or class notes, then use this set to check your understanding.

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