Let $z,w$ be complex numbers such that $\bar z + \overline {iw} = 0$ and ${\rm{\;arg}}\left( {zw} \right) = \pi $. Then $\arg \left( z \right)$ equals

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

Let

z,w

be complex numbers such that

\bar z + \overline {iw} = 0

and

\mathrm{\;arg}\left( {zw} \right) = \pi

. Then

\arg \left( z \right)

equals

View answer and explanation

Correct option: C

\frac{{3\pi }}{4}

Option C (

\frac{{3\pi }}{4}

) is correct because using the given conditions,

\arg(z)

can be found by relating

\arg(zw)

\arg(z)

and using the property

\arg(-i) = -\frac{\pi}{2}

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