JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

2x = - 1 + \sqrt 3 i

, then the value of

{\left( {1 - {x^2} + x} \right)^6} - {\left( {1 - x + {x^2}} \right)^6}

is equal to

View answer and explanation

Correct option: D

Option D (0) is correct because substituting x = ω (cube root of unity) simplifies the expression to 0.

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{\left| {1 - i} \right|^x} = {2^x}

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z \neq \pm 1

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\left|\sum\limits_{r=1}^n z_r\right|

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\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

\frac{{1 + i\sqrt 3 }}{{\sqrt 3 + i}}