The number of geometrical isomers in case of a compound with the structure, ${\rm{C}}{{\rm{H}}_3}{\rm{\;}}-{\rm{CH}} = {\rm{CH}}-{\rm{CH}} = {\rm{CH}}-{{\rm{C}}_2}{{\rm{H}}_5}$ are .

Back to ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

NEET UG CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

1 Medium

1 of 1

Application +4 | -1

The number of geometrical isomers in case of a compound with the structure,

\mathrm{C}{\mathrm{H}_3}\mathrm{\;}-\mathrm{CH} = \mathrm{CH}-\mathrm{CH} = \mathrm{CH}-{\mathrm{C}_2}{\mathrm{H}_5}

are .

View answer and explanation

Correct option: A

Four

Option A (Four) is correct because the compound has two double bonds, each capable of exhibiting cis/trans isomerism, leading to a total of four geometrical isomers.

NEET UG CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

More Questions from ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES