JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Analyzing +4 | -1

z^{2}+z+1=0

, where

\mathrm{z}

is complex number, then the value of

\left(z+\frac{1}{z}\right)^{2}+\left(z^{2}+\frac{1}{z^{2}}\right)^{2}+\left(z^{3}+\frac{1}{z^{3}}\right)^{2}+\ldots \ldots .+\left(z^{6}+\frac{1}{z^{6}}\right)^{2}

View answer and explanation

Correct option: D

Option D (12) is correct because by finding the value of z and then substituting it into the expression, we can find the value of the given sum.

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