JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Analyzing +4 | -1

If the parabolas

{y^2} = 4x

and

{x^2} = 32y

intersect at

\left( {16,8} \right)

at an angle

\theta ,

then

\theta

is equal to

View answer and explanation

Correct option: A

{\tan ^{ - 1}}\left( {3/5} \right)

Option A (

{\tan ^{ - 1}}\left( {3/5} \right)

) is correct because it is the angle between the tangents to the parabolas at the point of intersection, calculated using the slopes of the tangents.

More Questions from TANGENTS & NORMALS

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z