JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Application +4 | -1

The curve

y-e^{x y}+x=0

has a vertical tangent at the point:

View answer and explanation

Correct option: D

(1,0)

Option D ((1,0)) is correct because at this point the derivative dx/dy equals zero, indicating a vertical tangent.

More Questions from TANGENTS & NORMALS

Practice All Chapter MCQs →

a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z

{x^2} = 4\left( {y + 1} \right)

{x^2} = - 4\left( {y + 1} \right)