JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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Application +4 | -1

The freezing point on a thermometer is marked as

{20^0}C

and the boiling point as

{150^0}C

. A temperature of

{60^0}C

on this thermometer will be read as

View answer and explanation

Correct option: C

{98^0}

Option C (

{98^0}

) is correct because it is the corresponding temperature on the new scale calculated using the given freezing and boiling points.

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