JEE PHYSICS MCQ: OSCILLATIONS

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Two SHM are represented by equations,

{y_1} = 6\cos \left( {6\pi t + \frac{\pi }{6}} \right),{y_2} = 3\left( {\sqrt 3 \sin 3\pi t + \cos 3\pi t} \right)

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Correct option: A

ratio of their amplitudes is 1

Option A (ratio of their amplitudes is 1) is correct because after simplifying the second equation, the amplitudes of both SHMs are found to be equal.

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a

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its potential energy is

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\left( {{y_1} + {y_2}} \right)