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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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A minute spherical air bubble is rising slowly through a column of mercury contained in a deep jar. If the radius of the bubble at a depth of 100 cm100 \mathrm{~cm} is 0.1 mm0.1 \mathrm{~mm}, calculate its depth where its radius is 0.126 mm0.126 \mathrm{~mm}, given that the surface tension of mercury is 567 dyne/cm567 \mathrm{~dyne} / \mathrm{cm}. Assume that the atmospheric pressure is 76 cm76 \mathrm{~cm} of mercury.
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Correct option: A
9.48 cm9.48 \mathrm{~cm}
Option A (9.48 cm9.48 \mathrm{~cm}) is correct because it is calculated by applying Boyle's law and considering the pressure due to depth and surface tension.

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