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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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The velocity of water in a river is 15 m/s15 \mathrm{~m} / \mathrm{s} near the surface. If the river is 5 m5 \mathrm{~m} deep, find the shearing stress between the horizontal layers of water. The coefficient of viscosity of water =10−2=10^{-2} poise.
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Correct option: C
3×10−3 N/m23 \times 10^{-3} \mathrm{~N} / \mathrm{m}^2
Option C (3×10−3 N/m23 \times 10^{-3} \mathrm{~N} / \mathrm{m}^2) is correct because it is calculated using the formula for shearing stress involving viscosity and velocity gradient.

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